I've got this string, but I need to remove specific things out of it...
Original String: hr-165-34.sh-290-92.ch-215-84.hd-180-1.lg-280-64.
The string I need: sh-290-92.ch-215-84.lg-280-64.
I need to remove hr-165-34. and hd-180-1.
!
EDIT: Ahh ive hit a snag!
the string always changes, so the bits i need to remove like "hr-165-34." always change, it will always be "hr-SOMETHING-SOMETHING."
So the methods im using wont work!
Thanks
Depends on why you want to remove exactly those Substrigs...
If you always want to remove exactly those substrings, you can use str_replace
If you always want to remove the characters at the same position, you can use substr
If you always want to remove substrings between two dots, that match certain criteria, you can use preg_replace
$str = 'hr-165-34.sh-290-92.ch-215-84.hd-180-1.lg-280-64';
$new_str = str_replace(array('hr-165-34.', 'hd-180-1.'), '', $str);
Info on str_replace.
The easiest and quickest way of doing this is to use str_replace
$ostr = "hr-165-34.sh-290-92.ch-215-84.hd-180-1.lg-280-64";
$nstr = str_replace("hr-165-34.","",$ostr);
$nstr = str_replace("hd-180-1.","",$nstr);
<?php
$string = 'hr-165-34.sh-290-92.ch-215-84.hd-180-1.lg-280-64';
// define all strings to delete is easier by using an array
$delete_substrings = array('hr-165-34.', 'hd-180-1.');
$string = str_replace($delete_substrings, '', $string);
assert('$string == "sh-290-92.ch-215-84.lg-280-64" /* Expected result: string = "sh-290-92.ch-215-84.lg-280-64" */');
?>
Ive figured it out!
$figure = $q['figure']; // hr-165-34.sh-290-92.ch-215-84.hd-180-1.lg-280-64
$s = $figure;
$matches = array();
$t = preg_match('/hr(.*?)\./s', $s, $matches);
$s = $figure;
$matches2 = array();
$t = preg_match('/hd(.*?)\./s', $s, $matches2);
$s = $figure;
$matches3 = array();
$t = preg_match('/ea(.*?)\./s', $s, $matches3);
$str = $figure;
$new_str = str_replace(array($matches[0], $matches2[0], $matches3[0]), '', $str);
echo($new_str);
Thanks guys!
Related
I'm trying to get all numeric before space/alpha in PHP string.
Example:
<?php
//string
$firstStr = '12 Car';
$secondStr = '412 8all';
$thirdStr = '100Pen';
//result I need
firstStr = 12
SecondStr = 412
thirdStr = 100
How do I can get all the number of a string just like example above?
I've an idea to get the position of first Alpha, then get all numeric before that position.
I've successfully get the position using
preg_match('~[a-z]~i', $value, $match, PREG_OFFSET_CAPTURE);
But I'm not done yet to get the numeric before the posisition.
How do I can do that, or anybody know how to fix my idea?
Anyhelp will be appreciated.
You don't need to use regex for strings like the examples you've shown, or any functions at all for that matter. You can just cast them to ints.
$number = (int) $firstStr; // etc.
The PHP rules for string conversion to number will handle it for you.
However, because of those rules, there are some other types of strings that this won't work for. For example, '-12 Car' or '412e2 8all'.
If you do use a regex, be sure to anchor it to the beginning of the string with ^ or it will match digits anywhere in the string as the other regex answers here do.
preg_match('/^\d+/', $string, $match);
$number = $match[0] ?? '';
Here's an extremely hackish approach that will work in most situations:
$s = "1001BigHairyCamels";
$n = intval($s);
$my_number = str_replace($n, '', $s);
$input = '100Pen';
if (preg_match('~(\d+)[ a-zA-Z]~', $input, $m)) {
echo $m[1];
}
This function will do the job!
<?php
function getInt($str){
preg_match_all('!\d+!', $str, $matches);
return $matches[0][0];
}
$firstStr = '12 Car';
$secondStr = '412 8all';
$thirdStr = '100Pen';
echo 'firstStr = '.getInt($firstStr).'<br>';
echo 'secondStr = '.getInt($secondStr).'<br>';
echo 'thirdStr = '.getInt($thirdStr);
?>
Say I have the following string
$str = "once in a great while a good-idea turns great";
What would be the best solution to creating an array with the array key being the string count of where the word(s) starts?
$str_array['0'] = "once";
$str_array['5'] = "in";
$str_array['8'] = "a";
$str_array['10'] = "great";
$str_array['16'] = "while";
$str_array['22'] = "a";
$str_array['24'] = "good-idea";
$str_array['34'] = "turns";
$str_array['40'] = "great";
As simple as the following:
str_word_count($str, 2);
what str_word_count() does is
str_word_count() — Return information about words used in a string
str_word_count() with 2 as the second argument to get the the offset; and you'd probably need to use the 3rd argument to include hyphen as well as letters in words
$str = "once in a great while a good-idea turns great";
print_r(str_word_count($str, 2));
demo:
http://sandbox.onlinephpfunctions.com/code/9e1afc68725c1472fc595b54c5f8a8abf4620dfc
Try this:
$array = preg_split("/ /",$str,-1,PREG_SPLIT_OFFSET_CAPTURE);
$str_array = Array();
foreach($array as $word) $str_array[$word[1]] = $word[0];
EDIT: Just saw Mark Baker's answer. Probably a better option than mine!
You can use preg_split (with the PREG_SPLIT_OFFSET_CAPTURE option) to split the string on the space, then use the offset it gives you to make a new array.
$str = "once in a great while a good-idea turns great";
$split_array = preg_split('/ /', $str, -1, PREG_SPLIT_OFFSET_CAPTURE);
$str_array = array();
foreach($split_array as $split){
$str_array[$split[1]] = $split[0];
}
How can I use str_replace method for replacing a specified portion(between two substrings).
For example,
string1="www.example.com?test=abc&var=55";
string2="www.example.com?test=xyz&var=55";
I want to replace the string between '?------&' in the url with ?res=pqrs&. Are there any other methods available?
You could use preg_replace to do that, but is that really what you are trying to do here?
$str = preg_replace('/\?.*?&/', '?', $input);
If the question is really "I want to remove the test parameter from the query string" then a more robust alternative would be to use some string manipulation, parse_url or parse_str and http_build_query instead:
list($path, $query) = explode('?', $input, 2);
parse_str($query, $parameters);
unset($parameters['test']);
$str = $path.'?'.http_build_query($parameters);
Since you're working with URL's, you can decompose the URL first, remove what you need and put it back together like so:
$string1="www.example.com?test=abc&var=55";
// fetch the part after ?
$qs = parse_url($string1, PHP_URL_QUERY);
// turn it into an associative array
parse_str($qs, $a);
unset($a['test']); // remove test=abc
$a['res'] = 'pqrs'; // add res=pqrs
// put it back together
echo substr($string1, 0, -strlen($qs)) . http_build_query($a);
There's probably a few gotchas here and there; you may want to cater for edge cases, etc. but this works on the given inputs.
Dirty version:
$start = strpos($string1, '?');
$end = strpos($string1, '&');
echo substr($string1, 0, $start+1) . '--replace--' . substr($string1, $end);
Better:
preg_replace('/\?[^&]+&/', '?--replace--&', $string1);
Depending on whether you want to keep the ? and &, the regex can be mofidied, but it would be quicker to repeat them in the replaced string.
Think of regex
<?php
$string = 'www.example.com?test=abc&var=55';
$pattern = '/(.*)\?.*&(.*)/i';
$replacement = '$1$2';
$replaced = preg_replace($pattern, $replacement, $string);
?>
I have a string that looks a little like this, world:region:bash
It divides folder names, so i can create a path for FTP functions.
However, i need at some points to be able to remove the last part of the string, so, for example
I have this world:region:bash
I need to get this world:region
The script wont be able to know what the folder names are, so some how it needs to be able to remove the string after the last colon.
$res=substr($input,0,strrpos($input,':'));
I should probably highlight that strrpos not strpos finds last occurrence of a substring in given string
$tokens = explode(':', $string); // split string on :
array_pop($tokens); // get rid of last element
$newString = implode(':', $tokens); // wrap back
You may want to try something like this:
<?php
$variable = "world:region:bash";
$colpos = strrpos($variable, ":");
$result = substr($variable, 0, $colpos);
echo $result;
?>
Or... if you create a function using this information, you get this:
<?php
function StrRemoveLastPart($string, $delimiter)
{
$lastdelpos = strrpos($string, $delimiter);
$result = substr($string, 0, $lastdelpos);
return $result;
}
$variable = "world:region:bash";
$result = StrRemoveLastPart($variable, ":");
?>
Explode the string, and remove the last element.
If you need the string again, use implode.
$items = array_pop(explode(':', $the_path));
$shotpath = implode(':', $items);
Use regular expression /:[^:]+$/, preg_replace
$s = "world:region:bash";
$p = "/:[^:]+$/";
$r = '';
echo preg_replace($p, $r, $s);
demo
Notice how $ which means string termination, is made use of.
<?php
$string = 'world:region:bash';
$string = implode(':', explode(':', $string, -1));
I have a small problem. I am tryng to convert a string like "1 234" to a number:1234
I cant't get there. The string is scraped fro a website. It is possible not to be a space there? Because I've tried methods like str_replace and preg_split for space and nothing. Also (int)$abc takes only the first digit(1).
If anyone has an ideea, I'd be greatefull! Thank you!
This is how I would handle it...
<?php
$string = "Here! is some text, and numbers 12 345, and symbols !£$%^&";
$new_string = preg_replace("/[^0-9]/", "", $string);
echo $new_string // Returns 12345
?>
intval(preg_replace('/[^0-9]/', '', $input))
Scraping websites always requires specific code, you know how you receive the input - and you write code that is required to make it usable.
That is why first answer is still str_replace.
$iInt = (int)str_replace(array(" ", ".", ","), "", $iInt);
$str = "1 234";
$int = intval(str_replace(' ', '', $str)); //1234
I've just came into the same issue, however the answer that was provided wasn't covering all the different cases I had...
So I made this function (the idea popped in my mind thanks to Dan) :
function customCastStringToNumber($stringContainingNumbers, $decimalSeparator = ".", $thousandsSeparator = " "){
$numericValues = $matches = $result = array();
$regExp = null;
$decimalSeparator = preg_quote($decimalSeparator);
$regExp = "/[^0-9$decimalSeparator]/";
preg_match_all("/[0-9]([0-9$thousandsSeparator]*)[0-9]($decimalSeparator)?([0-9]*)/", $stringContainingNumbers, $matches);
if(!empty($matches))
$matches = $matches[0];
foreach($matches as $match):
$numericValues[] = (float)str_replace(",", ".", preg_replace($regExp, "", $match));
endforeach;
$result = $numericValues;
if(count($numericValues) === 1)
$result = $numericValues[0];
return $result;
}
So, basically, this function extracts all the numbers contained inside of a string, no matter how many text there is, identifies the decimal separator and returns every extracted number as a float.
One can specify what decimal separator is used in one's country with the $decimalSeparator parameter.
Use this code for removing any other characters like .,:"'\/, !##$%^&*(), a-z, A-Z :
$string = "This string involves numbers like 12 3435 and 12.356 and other symbols like !## then the output will be just an integer number!";
$output = intval(preg_replace('/[^0-9]/', '', $string));
var_dump($output);