I'm having two text fields with same name, Using .show & .hide i'm displaying individually.
<input value="first value" type="hidden" name="current_comapany" id="field1">
<input type="text" name="current_comapany" id="field2">
If i use print_r($_POST); I'm always getting below result,
Array
(
[current_comapany] =>
)
Is there any way to pass value ?
I am assuming that you want $_POST['current_company'] to have the value of the one field that is visible when the form is submitted.
To do that, disable the element you hide and enable the one you show with jQuery. For example:
$("input").first().prop("disabled", true); // no need to .hide(), type=hidden
$("input").last().show().prop("disabled", false);
and to toggle again:
$("input").first().prop("disabled", false);
$("input").last().hide().prop("disabled", true);
You can keep doing this as long as you like; disabling the elements keeps their values, it just means that they will not be submitted to the server.
Related
Please see this link
http://thedesigningworld.com/bea
Here's a Small form contains 8-9 fields + a group of checkboxes
I want to save all details in DB + want to display in a table in proper manner, but it not works properly
Here's the code which i used
for($i=0;$i<count($_POST[wert1]);$i++)
{
if($_POST[wert1][$i]!= "")
{
$check1[] =$_POST['wert1'][$i]; } }
$new1=implode(',', $check1);
$result = "INSERT into table1(check1) values($new1)";
$result = mysqli_query($con, $result);
So i've one doubt that for each checkbox row, should i need to define same array name or different like here i used array name as wert1[] for first row
Checkbox values are not transmitted if the box is not checked.
If you have influence, you could put a hidden input field of the same name before the checkbox and the value "0", like:
<input type="hidden" name="checkbox_name" value="0" />
<input type="checkbox" name="checkbox_name" value="1">Some Text</input>
In you example site, you're using array notation, which is basically a good thing. However, you have not given an index so you might not recognize missing elements.
Hi lets say I'm showing a numeric value in an element (not sure what element to use), what i want to achieve is once the numeric value is clicked (Thinking of onclick="this.form.submit();" or submit button) it will submit different designated value from the numeric value let us say. Apple then my sql query would retrieve apple and use it. NOTE: I have multiple numeric values and multiple designated values for each numeric value as an example it looks like this:
(numeric value) = (designated value)
15123 = apple
24151 = orange
39134 = peach
Here so far is what i have.
<input type='submit' name='searchthem' placeholder='<?php echo $numeric_value; ?>'
value='apple'>
** NOTE i have multiple numeric values with different designated value
And this is the SQL in the same page:
SELECT * from tbl_fruits where fruit_name='".$_POST['searchthem']."' ;
Would appreciate some help and ideas, If there is confusion please comment so i may further clarify.
Use select element and just submit the form so that it can process the values. if you wish to use AJAX, use some javascript and output the result in the browser.
If I understand your problem correctly you should add an array for the definition terms and do it like this:
<input type="hidden" name="searchterm" value="<?php echo $numeric_value; ?>" />
<input type='submit' name='send' value="<?php echo $names[$numeric_value]; ?>" />
Then in PHP switch through the values:
switch($_POST['searchterm']){
case(15123) $term = 'apple';break;
case(24151) $term = 'ornage';break;
case(39134) $term = 'peach';break;
}
This will secure your SQL query, too. [Beware: Never use unfiltered input (i.e. $_POST in your example) from the browser in SQL queries!]
The problem I am having is that my ecommerce script allows people to add products to their store. However, those products can have variants... like Color and those variants can have options, like Black, White, and Blue for example. The problem I am having is how exactly do I determine how many options they have entered. Eventually I will have a javascript function add a new input field if they click "add option" but for now I just made 3 input fields like so:
Variant Title:<input type="text" name="variant_title"><br>
Variant Option: <input type="text" name="variant_option_1"><br>
Variant Option: <input type="text" name="variant_option_2"><br>
Variant Option: <input type="text" name="variant_option_3"><br>
Now what I don't know how to do is loop through all the variant_options and if they are not empty add them to a database. I don't want to hard code it in with the names because I don't know how many options they will choose per variant.
I tried doing this:
$i = 1;
while($this->input->post('variant_option_$i') != '')
{
$variant_options[] = $this->post->input('variant_option_$i');
$i++;
}
But that does not seem to work, as the variant title gets added to the database, however the options do not.
The only thing I need a solution to is to how to actually grab those fields all at once. I was thinking a foreach loop but im not sure.
Thank you.
I would use an array of input fields instead:
Variant Title:<input type="text" name="variant_title"><br>
Variant Option: <input type="text" name="variant_option[]"><br>
Variant Option: <input type="text" name="variant_option[]"><br>
Variant Option: <input type="text" name="variant_option[]"><br>
Then check for the values like:
if (is_array($this->input->post('variant_option')):
foreach ($this->input->post('variant_option') as $value):
$variant_options[] = $value; // loop through...
endforeach;
endif;
This is more of a technique question rather than maybe code. I am having a php form with many fields (items to select). Naturally some of the items might be selected and some not. How do I know which ones are selected when i post the data from page 1 to page 2? I thought of testing each one if empty or not, but there are just too many fields and it doesn't feel at all efficient to use or code.
Thanks,
UPDATE EDIT:
I've tried the following and maybe it will get me somewhere before I carry on testing the repliers solutions...
<html>
<body>
<form name="test" id="name" action="testprocess.php" method="POST">
<input type="text" name="choices[shirt]">
<input type="text" name="choices[pants]">
<input type="text" name="choices[tie]">
<input type="text" name="choices[socks]">
<input type="submit" value="submit data" />
</form>
</body>
</html>
and then second page:
<?php
$names = $_POST['choices'];
echo "Names are: <br>";
print_r($names);
?>
This gives out the following:
Names are: Array ( [shirt] => sdjalskdjlk [pants] => lkjlkjlk [tie]
=> jlk [socks] => lkjlkjl )
Now what I am going to try to do is iterate over the array, and since the values in my case are numbers, I will just check which of the fields are > 0 given the default is 0. I hope this works...if not then I will let you know :)
I think what you're looking for is this:
<form action="submit.php" method="POST">
<input type="checkbox" name="checkboxes[]" value="this" /> This
<input type="checkbox" name="checkboxes[]" value="might" /> might
<input type="checkbox" name="checkboxes[]" value="work" /> work
<input type="submit" />
</form>
And then in submit.php, you simply write:
<?php
foreach($_POST['checkboxes'] as $value) {
echo "{$value} was checked!";
}
?>
The square brackets in the name of the checkbox elements tell PHP to put all elements with this name into the same array, in this case $_POST['checkboxes'], though you could call the checkboxes anything you like, of course.
You should post your code so we would better understand what you want to do.
But from what I understood you are making a form with check boxes. If you want to see if the check boxes are selected, you can go like this:
if(!$_POST['checkbox1'] && !$_POST['checkbox2'] && !$_POST['checkbox3'])
This looks if all the three check boxes are empty.
Just an idea:
Create a hidden input field within your form with no value. Whenever any of the forms fields is filled/selected, you add the name attribute of that field in this hidden field (Field names are saved with a comma separator).
On doing a POST, you can read this variable and only those fields present in this have been selected/filled in the form.
Hope this helps.
Try this.....
<?php
function checkvalue($val) {
if($val != "") return true;
else return false;
}
if(isset($_POST['submit'])) {
$values = array_filter(($_POST), "checkvalue");
$set_values = array_keys($values);
}
?>
In this manner you can get all the values that has been set in an array..
I'm not exactly sure to understand your intention. I assume that you have multiple form fields you'd like to part into different Web pages (e.g. a typical survey form).
If this is the case use sessions to store the different data of your forms until the "final submit button" (e.g. on the last page) has been pressed.
How do I know which ones are selected when i post the data from page 1 to page 2?
is a different question from how to avoid a large POST to PHP.
Assuming this is a table of data...
Just update everything regardless (if you've got the primary / unique keys set correctly)
Use Ajax to update individual rows as they are changed at the front end
Use Javascript to set a flag within each row when the data in that row is modified
Or store a representation of the existing data for each row as a hidden field for the row, on submission e.g.
print "<form....><table>\n";
foreach ($row as $id=>$r) {
print "<tr><td><input type='hidden' name='prev[$id]' value='"
. md5(serialize($r)) . "'>...
}
...at the receiving end...
foreach ($_POST['prev'] as $id=>$prev) {
$sent_back=array( /* the field values in the row */ );
if (md5(serialize($sent_back)) != $prev) {
// data has changed
update_record($id, $sent_back);
}
}
I put a variable (price) to a html form from database.
then user changes the price and submit the form and variable is updated in database.
I want to keep previous value (last state and show it in the form) but if I update the form variable keeps updating.
What is best way to remember previous value of variable (in array for example) ?
If you're updating this data in an actual Database, you should create a parallel table that holds the value of the previous row.
Otherwise, if you're updating only an array, you can just create a copy prior to updating the array: http://codepad.org/SvlasJ7f
<?php
$array = array('Old Value');
$lastarray = '';
updateArray($array,'New Value');
function updateArray(&$a,$v) {
$GLOBALS[lastarray] = $a;
$a = array($v);
}
?>
If you want to retain the LAST value AND display it on the screen, combine the two! Just display the previous value, in a readonly input field in your form. That way, you will still have the previous value every time the form is submitted.
<form action="process.php" method="POST">
<input type="text" name="Current" value="...">
<input type="text" name="Last" value="..." readonly="readonly">
</form>
Or am I missing something?