How should I make this SQL Query more efficent - php

Question

I am searching up a database to find the past 7 days worth of data, accumulated.
It works perfectly, but I currently have seven editions of the same code - so I want to loop it somehow, however if I do that, how do I loop it correctly and name the variables. Aside from naming the variables (day_X_) I think I should be able to loop it 7 times fairly easily...
// Get the current day
$graph_day_1_date_lower = date('Y-m-d') . " 00:00";
$graph_day_1_date_upper = date('Y-m-d') . " 23:59";
$graph_day_1_name = date('D') . " (Today)";
/* Successes */
$graph_day_1 = mysqli_query($con,
"SELECT COUNT(`id`) AS num FROM `hidden`
WHERE submittedtime >= '$graph_day_1_date_lower'
AND submittedtime < '$graph_day_1_date_upper'
AND u_s_code='C001'")
or die(mysqli_error($con));
$graph_day_1_row = mysqli_fetch_assoc($graph_day_1);
$graph_day_1_count = $graph_day_1_row['num'];
$graph_total_count = $graph_day_1_count;
/* Errors */
$graph_e_day_1 = mysqli_query($con,
"SELECT COUNT(`id`) AS num FROM `hidden`
WHERE submittedtime >= '$graph_day_1_date_lower'
AND submittedtime < '$graph_day_1_date_upper'
AND u_s_code='E001'")
or die(mysqli_error($con));
$graph_e_day_1_row = mysqli_fetch_assoc($graph_e_day_1);
$graph_e_day_1_count = $graph_e_day_1_row['num'];
$graph_e_total_count = $graph_e_day_1_count;
I will then print the two total counts for each day

Answer 1

Here's what you would want to do:
$today = time(); // or use your upper / lower bounds
$daysToShow = 7;
$dayData = array();
for($i = 0; $i < $daysToShow; $i++){
$dateToCheck = $today + ($i * 24 * 60 * 60); // add a day each time $i goes up
$dataArray = mysql_fetch_assoc($yourDataHere); // replace with your mysqli query using $dateToCheck
$dayData[] = $dataArray; // add to array
}
foreach($dayData as $day){
echo $day['name']; // print out your info here
}