I have a table xeon_users_rented, with: clicks0, clicks1, clicks2, clicks3, clicks4, clicks5, clicks6
Each day, clicks0 will increase, and every day at midnight, a cronjob will run, making clicks0 = clicks1 (setting todays clicks, to yesterday clicks), and then set clicks0 to zero.
What I am trying to achieve is I want to make a graph, that shows the sum of clicks0, clicks1 etc., where clicks0 is todays date.
I have the query below:
$data = array();
for ($x = 0; $x <= 6; $x++) {
$date = date("Y/m/d", time() - ($x * 86400));
$queryE = $dbh->prepare("SELECT SUM(clicks$x) FROM xeon_users_rented WHERE user_by=:username");
$queryE->bindParam(":username", $userdata['username']);
$queryE->execute();
$row = $queryE->fetch(PDO::FETCH_ASSOC);
$dates[] = date("Y/m/d", time() - ($x * 86400));
$data[] = ($row['clicks'.$x.''] > 0 ? $row['clicks'.$x.''] : 0);
}
$days = array('Today');
for ($i = 0; $i < 6; $i++) {
$days[$i] = date('d-m', strtotime('-'.($i + 0).' day'));
}
The $days is working perfectly - it will print out today, and the last couple of days.
The $data is not working. It is just printing out:
0,0,0,0,0,0,0
Can someone please help me out here.
The column from your SUM isn't going to be named clicks$x. It will be named something like SUM(clicks1).
Provide an explicit name in the SQL, like
SELECT SUM(clicks$x) as clickSum ...
Then reference it in row as
$row['clickSum']
Related
Starting with the number 9 and using php, I would like to be able to count up from there, and echo out the next number in increments of 1.
So, number 9, then after 1 month the number would change to 10, then another month 11, then 12 etc., with no maximum number/stop point.
How can I accomplish this? So far I have the below code.
$number = 9;
$output = $number + 1;
echo $output;
Is there a way to set this to increase once a month?
You can do this with the PHP date()-function. This is one example of doing it if you are not dependent on the day of the month, but adding day functionality is possible and should be quit easy.
$startNumber = 9;
$startYear = 2015;
$startMonth = 9;
$currentYear = intval( date( "Y" ) );
$currentMonth = intval( date( "n" ) );
$monthsToAdd = ( ( $currentYear - $startYear ) * 12 )
+ ( $currentMonth - $startMonth );
echo $startNumber + $monthsToAdd;
From your question, I'd say:
$number = 9;
$output = date('n') + $number;
echo $output;
But that depends on what you are trying to accomplish. You can also wrap the number around the date() with a modulo.
However this is nothing random. If you want to create a random number every month like your topic suggests, use the month as the random seed.
srand(date('n'));
$number = rand();
a very inefficient way would be
<?php
function increm($duration){
while ($i<$duration) {
$i++;
}
return true;
}
$number = 9;
$start = time();
$i = 0;
while (1){
increm(3600*24*30);
$i++;
// Do your code
}
?>
this script would have to be run continuously for months.
A better way would be
<?php
$number = 9;
if(!file_exists('date.txt')){
$date=date('n');
file_put_contents( (string)time());
$date = 0;
}
else{
$date= file_get_contents('date.txt');
$date= date()-(int)$date;
$date= floor($date/(24*3600*30));
}
// do whatever you may
?>
But this script would increase it whenever called as the first open date would be stored. Will work forever (till UNIX can timestamp).
for this purpose you have to store the number in the database, compare with current unix timestamp and update it when the new month is reached.
2 database columns: count_month int(10) and next_month int(10) where next_month will contain the unix timestamp of the first day of the next month. you can run it with cronjobs or on production.
<?php
$now = strtotime("now");
$next_month = strtotime("first day of next month");
if ($query = $dbconnect->prepare("SELECT next_month FROM table1")) {
$query->execute();
$query->bind_result($compare_time);
$query->store_result();
$row_count = $query->num_rows;
if ($row_count > 0) {
while ($query->fetch()) {
if ($compare_time < $now) { // you reached the 1th of the next month time to update
if ($query2 = $dbconnect->prepare("UPDATE table1 SET count_month=count_month +1, next_month=?")) {
$query2->bind_param('i', $next_month);
$query2->execute();
$query2->close();
}
}
}
}
$query->free_result();
$query->close();
}
?>
I have a calendar that I want to allow events to be repeated on a week day of the month. Some examples would be:
Repeat every 4th Tuesday of the month
Repeat every 2nd Friday of the month
And so on...
What I need is the ability to find out how many week days (for example Tuesday's) have passed this month so far.
I found some code that returns how many Monday's have passed.
$now=time() + 86400;
if (($dow = date('w', $now)) == 0) $dow = 7;
$begin = $now - (86400 * ($dow-1));
echo "Mondays: ".ceil(date('d', $begin) / 7)."<br/>";
This works well but how do I make it so that I can determine any week day? I cannot seem to get my head around the code to make this work.
strtotime is really useful for this kind of thing. Here are lists of the supported syntax. Using your example of repeat every 2nd Friday of the month I wrote the following simple snippet for you:
<?php
$noOfMonthsFromNow=12;
$dayCondition="Second Friday of";
$months = array();
$years = array();
$currentMonth = (int)date('m');
for($i = $currentMonth; $i < $currentMonth+$noOfMonthsFromNow; $i++) {
$months[] = date('F', mktime(0, 0, 0, $i, 1));
$years[] = date('Y', mktime(0, 0, 0, $i, 1));
}
for ($i=0;$i<count($months);$i++){
$d = date_create($dayCondition.' '.$months[$i].' '.$years[$i]);
if($d instanceof DateTime) echo $d->format('l F d Y H:i:s').'<br>';
}
?>
This can be tested at: http://www.phpfiddle.org/lite/
$beginningOfMonth = strtotime(date('Y-m-01')); // this will give you the timestamp of the beginning of the month
$numTuesdaysPassed = 0;
for ($i = 0; $i <= date('d'); $i ++) { // 'd' == current day of month might need to change to = from <= depending on your needs
if (date('w', $beginningOfMonth + 3600 * $i) == 2) $numTuesdaysPassed ++; // 3600 being seconds in a day, 2 being tuesday from the 'w' (sunday == 0)
}
Not sure if this will work, and there's probably a better way to do it; don't have the means to test it right now but hopefully this puts you on the right track! (I get tripped up on date math a bit too, especially with timezones)
I need to find date x such that it is n working days prior to date y.
I could use something like date("Y-m-d",$def_date." -5 days");, but in that case it wont take into consideration the weekend or off-date. Let's assume my working days would be Monday to Saturday, any idea how I can accomplish this?
Try this
<?php
function businessdays($begin, $end) {
$rbegin = is_string($begin) ? strtotime(strval($begin)) : $begin;
$rend = is_string($end) ? strtotime(strval($end)) : $end;
if ($rbegin < 0 || $rend < 0)
return 0;
$begin = workday($rbegin, TRUE);
$end = workday($rend, FALSE);
if ($end < $begin) {
$end = $begin;
$begin = $end;
}
$difftime = $end - $begin;
$diffdays = floor($difftime / (24 * 60 * 60)) + 1;
if ($diffdays < 7) {
$abegin = getdate($rbegin);
$aend = getdate($rend);
if ($diffdays == 1 && ($astart['wday'] == 0 || $astart['wday'] == 6) && ($aend['wday'] == 0 || $aend['wday'] == 6))
return 0;
$abegin = getdate($begin);
$aend = getdate($end);
$weekends = ($aend['wday'] < $abegin['wday']) ? 1 : 0;
} else
$weekends = floor($diffdays / 7);
return $diffdays - ($weekends * 2);
}
function workday($date, $begindate = TRUE) {
$adate = getdate($date);
$day = 24 * 60 * 60;
if ($adate['wday'] == 0) // Sunday
$date += $begindate ? $day : -($day * 2);
return $date;
}
$def_date="";//define your date here
$preDay='5 days';//no of previous days
date_sub($date, date_interval_create_from_date_string($preDay));
echo businessdays($date, $def_date); //date prior to another date
?>
Modified from PHP.net
Thanks for the help guys, but to solve this particular problem I wrote a simple code:
$sh_padding = 5; //No of working days to count backwards
$temp_sh_padding = 1; //A temporary holder
$end_stamp = strtotime(date("Y-m-d", strtotime($date_format)) . " -1 day"); //The date(timestamp) from which to count backwards
$start_stamp = $end_stamp; //start from same as end day
while($temp_sh_padding<$sh_padding)
{
$sh_day = date('w',$start_stamp);
if($sh_day==0){ //Skip if sunday
}
else
{
$temp_sh_padding++;
}
$start_stamp = strtotime(date("Y-m-d",$start_stamp)." -1 day");
}
$sh_st_dte = date("Y-m-d",$start_stamp); //The required start day
A quick bit of googling got me to this page, which includes a function for calculating the number of working days between two dates.
It should be fairly trivial to adjust that concept to suit your needs.
Your problem, however, is that the concept of "working days" being monday to friday is not universal. If your software is only ever being used in-house, then it's okay to make some assumptions, but if it's intended for use by third parties, then you can't assume that they'll have the same working week as you.
In addition, public holidays will throw a big spanner in the works, by removing arbitrary dates from various working weeks throughout the year.
If you want to cater for these, then the only sensible way of doing it is to store the dates of the year in a calendar (ie a big array), and mark them individually as working or non-working days. And if you're going to do that, then you may as well use the same mechanism for weekends too.
The down-side, of course, is that this would need to be kept up-to-date. But for weekends, at least, that would be trivial (loop through the calendar in advance and mark weekend days where date('w')==0 or date('w')==6).
Hey, my problem is as follows,
I am trying to create code where a set of sporting fixtures are created with dates on.
Say I have 8 teams, with 7 rounds of fixtures.
I have generated the fixtures, but want to add a date generation on them.
So if i had 7 rounds, I would put 28 days and it would make each round 4 days from now, 8 days from now, etc.
What would be the best way to go about doing this?
Thanks
This should do what you want and allows for an uneven number of teams. Dates might not be perfect because of the rounding down:
$teams = array("TEAM A","TEAM B","TEAM C","TEAM D","TEAM E", "TEAM F","TEAM G","TEAM H","TEAM I");
$days = 28;
$rounds = count($teams) -1;
//Number of Days Between Fixtures
$daysBetweenFixtures = floor($days / $rounds);
$fixtures = array();
for($i =0; $i < count($teams); $i++) {
//Calculate Date of this round of fixtures
$date = date("D d M Y",mktime(0, 0, 0, date("m") , date("d")+ ($i * $daysBetweenFixtures) , date("Y")));
$hasFixtureToday = array();
for($j=$i; $j<$i+count($teams); $j=$j+2) {
$homeTeam = $teams[$j % count($teams)];
$awayTeam = $teams[($j+1) % count($teams)];
if(!in_array($homeTeam,$hasFixtureToday) && !in_array($awayTeam,$hasFixtureToday)) {
$fixtures[$date][] = "{$homeTeam} vs {$awayTeam}";
$hasFixtureToday[] = $homeTeam;
$hasFixtureToday[] = $awayTeam;
}
}
}
print_r($fixtures);
Example using strtotime() from php-cli:
php > echo date("Y-m-d", strtotime("+4 days"));
2010-05-02
php > echo date("Y-m-d", strtotime("+8 days"));
2010-05-06
php > echo date("Y-m-d", strtotime("+12 days"));
2010-05-10
I have some code that generates fixtures, I am looking to add a fixture date to the code.
$totalRounds = $teams - 1;
$matchesPerRound = $teams / 2;
$rounds = array();
for ($i = 0; $i < $totalRounds; $i++) {
$rounds[$i] = array();
}
for ($round = 0; $round < $totalRounds; $round++) {
for ($match = 0; $match < $matchesPerRound; $match++) {
$home = ($round + $match) % ($teams - 1);
$away = ($teams - 1 - $match + $round) % ($teams - 1);
// Last team stays in the same place while the others
// rotate around it.
if ($match == 0) {
$away = $teams - 1;
}
$rounds[$round][$match] = "$user[$home]~$team[$home]#$user[$away]~$team[$away]";
}
}
$team is the amount of teams in the league.
I want to add a variable for every 4 days, and for every round of fixtures generated, I want to add 4 days onto the previous round.
For example, if today is 3rd may, i want 3rd may for first fixture, 7th may for second fixture, 11th may for third fixture.
By fixture i mean round which includes a set of fixtures!
How do I add 4 days to a strotime variable everytime the rounds increase?
Have you looked into strtotime? It allows syntax like the following:
$future_date = strtotime('+4 days');
$even_further_in_the_future = strtotime('+4 days', $future_date);
$arbitrary_start_date = strtotime('+4 days', strtotime('May 25th, 2010'));
If I understand your question correctly, you just want each round to have an associated date. You've got an array of $rounds, so could you not just create a correspondingly-keyed array to hold the round dates?
...
$rounds = array();
$roundDates = array();
$curTime = time();
for ($i = 0; $i < $totalRounds; $i++) {
$rounds[$i] = array();
$numDays = $i * 4;
$roundDates[$i] = strtotime("+".$numDays." days",$curTime);
}
foreach($roundDates as $time) echo date("Y-m-d",$time)."\n";
//gives
//2010-05-03
//2010-05-07
//2010-05-11
//etc