Detect whether a time was specified in a DateTime object - php

Question

I have a list of dates, some with times:
01/03/2014
02/01/2014 02:00 PM
02/02/2014 1:00 PM
03/01/2014
I am going through all of these and turning them into new DateTime objects, sending them to JavaScript, then using moment.js to display them.
moment(data.date).format('L LT')
This displays the dates in the following format:
01/03/2014 12:00 AM
02/01/2014 02:00 PM
02/02/2014 01:00 PM
03/01/2014 12:00 AM
Is there a way to detect, without regex (or whatever string manipulation), that the DateTime constructor was called with just a date (without a time)?

Answer 1

I don't think DateTime class provides a way to detect if the object was actually created from just a date. That information is lost once the object is created. A small-work around is to use date_parse() to check for absent date time fields (as #salathe mentioned in the comments).
If the DateTime doesn't contain a hour, minute or second part, then it means it only has a date part in it. Using the above logic, your code would look like:
$datetimes = [
'01/03/2014',
'02/01/2014 02:00 PM',
'02/02/2014 1:00 PM',
'03/01/2014'
];
$withTime = array();
$withoutTime = array();
foreach ($datetimes as $dt) {
$parts = date_parse($dt);
if ($parts['hour'] === FALSE &&
$parts['minute'] === FALSE &&
$parts['second'] === FALSE) {
$withoutTime[] = $dt;
} else {
$withTime[] = $dt;
}
}
print_r($withTime);
print_r($withoutTime);
Outputs:
Array
(
[0] => 02/01/2014 02:00 PM
[1] => 02/02/2014 1:00 PM
)
Array
(
[0] => 01/03/2014
[1] => 03/01/2014
)
Demo