PHP Finding how many hours of a timespan is within another timespan - php

I am trying to find a way to determine whether a timespan is partially or fully within another timespan. For example:
I have time entries of:
Monday 18:30:00 to Tuesday 05:00:00,
Monday 23:00:00 to Tuesday 05:00:00,
Monday 20:00:00 to Tuesday 08:00:00,
Monday 00:00:00 to Tuesday 08:00:00,
and need to find, for each one, how much of the time is within a timespan of 22:00:00 to 06:00:00. The output would need to be:
07:00:00,
06:00:00,
08:00:00,
06:00:00.

What you're looking for is DateTime::diff which returns an instance of an DateInterval
Here a little example:
$d1 = new DateTime("Monday 18:30:00");
$d2 = new DateTime("Tuesday 05:00:00");
$limit1 = new DateTime("Monday 22:00:00");
$limit2 = new DateTime("Tuesday 06:00:00");
$within1 = $d1->getTimestamp() < $limit1->getTimestamp() ? $limit1 : $d1;
$within2 = $d2->getTimestamp() < $limit2->getTimestamp() ? $d2 : $limit2;
$interval = $within1->diff($within2);
print_r($interval);
print_r($interval);
outputs:
DateInterval Object
(
[y] => 0
[m] => 0
[d] => 0
[h] => 7
[i] => 0
[s] => 0
[invert] => 0
[days] => 0
)
You can either read this attributes directly or you can use the DateInterval::format()

Related

PHP - Hours difference is not accurate using DateTime object

I am trying to get difference in hours between two dates using PHP DateTime object but the result is not accurate. One date is the current date time and second is the event date which comes from database. I don't understand on what logic the hours difference is calculated.
Here's my code:
<?php
$date1 = new DateTime();
$date2 = new DateTime("2018-09-04 20:37:06");
$interval = $date2->diff($date1);
echo "<pre>";
print_r($interval);
echo "</pre>";
echo $interval->format('%a Day and %h hours');
?>
Output:
DateInterval Object
(
[y] => 0
[m] => 0
[d] => 0
[h] => 3
[i] => 14
[s] => 13
[weekday] => 0
[weekday_behavior] => 0
[first_last_day_of] => 0
[invert] => 1
[days] => 0
[special_type] => 0
[special_amount] => 0
[have_weekday_relative] => 0
[have_special_relative] => 0
)
0 Day and 3 hours
The script is executed at 08:53 PM (India) i.e. 20:53:00 but the difference is 3 hours. Don't know why?
For Indian time this should help :-
<?php
$timezone = new DateTimeZone('Asia/Kolkata');
$date1 = new DateTime('now', $timezone);
$date2 = new DateTime("2018-09-04 20:37:06", $timezone);
$interval = $date2->diff($date1);
echo "<pre>";
print_r($interval);
echo "</pre>";
echo $interval->format('%a Day and %h hours');
?>
Just use the DateTimeZone('Zone') and it should set the new date to the zone where you are.

Calculate time difference in php

I am trying to calculate time different between 3 different dates
1. Start date
2. End date
3 current date
I have been researching on how to calculation but couldn't find any exact example.
Any assistance in resolving this would be appreciated.
function getweekSartEndDate($date){
$cur_date = strtotime($date); // Change to whatever date you need
// Get the day of the week: Sunday = 0 to Saturday = 6
$dotw = date('w', $cur_date);
if($dotw>1){
$pre_monday = $cur_date-(($dotw-1)*24*60*60);
$next_sunday = $cur_date+((7-$dotw)*24*60*60);
}
else if($dotw==1){
$pre_monday = $cur_date;
$next_sunday = $cur_date+((7-$dotw)*24*60*60);
}
else if($dotw==0){
$pre_monday =$cur_date - (6*24*60*60);;
$next_sunday = $cur_date;
}
$date_array = array();
$date_array['weekStart'] = $pre_monday;
$date_array['weekEnd'] = $next_sunday;
return $date_array;
}
The above is the example code i got so far, and i was able to get the start and end dates of a week as seen below:
$weekStart = date('Y-m-d H:i:s', $weekInfo['weekStart']);
$weekEnd = date('Y-m-d H:i:s', $weekInfo['weekEnd']);
My challenges is how to get the time difference in 'Y-m-d H:i:s' date format from the current time.
You can use
$currentDate = date('Y-m-d H:i:s');
$currentDate = new DateTime($currentDate);
$leaveDate = new DateTime($leaveFrom);
$difference = $currentDate->diff($leaveDate);
You will get result as follow
DateInterval Object ( [y] => 0 [m] => 0 [d] => 0 [h] => 0 [i] => 0 [s] => 0 [f] => 0 [weekday] => 0 [weekday_behavior] => 0 [first_last_day_of] => 0 [invert] => 0 [days] => 0 [special_type] => 0 [special_amount] => 0 [have_weekday_relative] => 0 [have_special_relative] => 0 )
You need basic knowledge on how to do number comparisons in PHP.
Convert your date strings to a UNIX-timestamp with strtotime
$d = strtotime("19/10/2016 14:48:21");
// 1519646232
When the dates are in UNIX-timestamp format, it's easy to compare them with any regular comparison operators as int numbers.
EDIT
Difference in seconds:
$diffBetweenStartAndNow = strtotime( $date_array['weekStart'] ) - time();
$diffBetweenEndAndNow = strtotime( $date_array['weekEnd'] ) - time();

How to calculate time difference between SQL time and PHP time

I have set times in SQL in this format: 2016-01-03 12:13:26.
I would like to calculate the number of hours and minutes (if hours<1) going from NOW() to that particular SQL time.
I've been looking at all the different threads here but I can't seem to grasp how to convert PHP different time formats to SQL's.
This is the code I've been using, but this will only give me back hours up to 12, and minutes also. Don't know how to use it with days.
$now = date("d/m/Y h:i:s");
$commentime = strtotime($SQLTIME);
$timetocomment = $now - $commentime;
For instance, this code will yield "12 hours ago" for data I posted 24 hours ago to SQL.
How can I do it? Thank you.
This is my suggestion to use date() in this format date("Y-m-d h:i:s"). Than you will get the complete difference in an array.
function dateDifference($date_1 ,$date_2)
{
$datetime1 = date_create($date_1);
$datetime2 = date_create($date_2);
$interval = date_diff($datetime1, $datetime2);
return $interval;
}
$now = date("Y-m-d h:i:s");
$sqlTime = "2016-01-03 12:13:26";
$DateDiffArr = dateDifference($now,$sqlTime);
echo "<pre>";
print_r($DateDiffArr);
Result Is:
DateInterval Object
(
[y] => 0
[m] => 0
[d] => 0
[h] => 22
[i] => 45
[s] => 55
[weekday] => 0
[weekday_behavior] => 0
[first_last_day_of] => 0
[invert] => 1
[days] => 0
[special_type] => 0
[special_amount] => 0
[have_weekday_relative] => 0
[have_special_relative] => 0
)
In resultant array, you can get the all difference as you need like in years, months, days, minutes, seconds etc.

filtering by date php for this month and last x days and this week

I have a date that returns in a string as 2012-03-19 05:00:32, its not coming from the database
I can use below to search for the last 30 days
$date = '2012-03-19 05:00:32';
if (strtotime($date) >= strtotime('-7 days')) {
// do something
}
Problem is if today is the 19th March, i was to search from the 11th to the 18th for the last 7 days and that seems to search for the last 7 days by calculating 24 hours * 7 by my searches need to start from 00:00:01 each day.
My plan is to break the date down into Year, Month and Day then check if year = 12, then check if month = 3, then check if date between 11 and 18.
Im just wondering if there is a more efficient way to do this or if im on the right track.
I also have the same issue with running a search on all info from this month and also want to search for all info this week starting on Monday.
So this is just asking if my method is sound or if there is a more efficient method.
$mytime = new DateTime('2012-03-19 05:00:32');
$mydate = new DateTime($mytime->format('Y-m-d')); //keep date only, exclude the time component
$now=new DateTime; //includes hours, minutes, seconds
$today=new DateTime($now->format('Y-m-d')); //time set to 0:00
$interval = $mydate->diff($today);
if($interval->format('d') <=7) { //assuming that $mydate isn't in the past
//do something
}
I'd suggest to use DateTime class ...
<?php
$d1=new DateTime("2012-07-08 11:14:15.638276");
$d2=new DateTime("2012-07-08 11:14:15.889342");
$diff=$d2->diff($d1);
print_r( $diff ) ;
/* returns:
DateInterval Object
(
[y] => 0
[m] => 0
[d] => 0
[h] => 0
[i] => 0
[s] => 0
[invert] => 0
[days] => 0
)
*/
?>

How to get current date/time as a date object in PHP

How do you get today's date, as a date object?
I'm trying to compute the difference between some start date and today. The following will not work, because getdate() returns an array and not a date object:
$today = getdate();
$start = date_create('06/20/2012');
$diff = date_diff($start, $today);
echo($today . '<br/>' . $start . '<br/>' . $diff);
Output:
Array ( [seconds] => 8 [minutes] => 1 [hours] => 16 [mday] => 11 [wday] => 1 [mon] => 6 [year] => 2012 [yday] => 162 [weekday] => Monday [month] => June [0] => 1339455668 )
DateTime Object ( [date] => 2012-06-20 00:00:00 [timezone_type] => 3 [timezone] => America/Los_Angeles )
new DateTime('now');
http://www.php.net/manual/en/datetime.construct.php
Comparing is easy:
$today = new DateTime('now');
$newYear = new DateTime('2012-01-01');
if ($today > $newYear) {
}
Op's edit
I just needed to call date_default_timezone_set, and then this code worked for me.
To get difference in days use this:
$today = new DateTime('today');
the time in this object eill be 00:00:00
If you want difference with hours minutes and seconds use this:
$now = new DateTime('now');
I ended up using the date_create constructor (no parameter) to get the current date.
$diff = date_diff(date_create('06/20/2012'), date_create());
print_r($diff);
Output:
DateInterval Object ( [y] => 0 [m] => 0 [d] => 8 [h] => 6 [i] => 30 [s] => 40 [invert] => 1 [days] => 8 )
I have no idea why, but Mike B's answer (and any constructor I tried for DateTime) threw an error for me in PHP5 / IIS.

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