php insert sql issue while loop / foreach - php

Question

The following code from my data between tables, but for some reason only one value is inserted to database
<?php
DEFINE("DB_SERVER", "localhost"); //LOCALHOST
DEFINE("DB_USER", "user");
DEFINE("DB_PASS", "pass");
DEFINE("DB_NAME", "table");
$connect = mysql_connect(DB_SERVER,DB_USER,DB_PASS) or die("connect issue". ' ' . mysql_error());
mysql_query('SET NAMES utf8');
$db = mysql_select_db(DB_NAME,$connect) or die("connect issue". ' ' . mysql_error());
mysql_query('SET NAMES utf8');
if (!$db){
echo "connect issue";
}
$sql = "SELECT id, column2 FROM tablea";
$result = mysql_query($sql) or die(mysql_error());
$set = date("Y-m-d H:i:s", time());
while ($row = mysql_fetch_array($result)) {
$id = $row['id'];
$list = $row['column2'];
echo "user_id: $id";
echo "<br/><br/>";
$makes = explode (";", $row['column2']);
$i = 0;
foreach ($makes as $make) {
$sql2 = "SELECT url FROM tableb WHERE id = '$make'";
$result2 = mysql_query($sql2) or die(mysql_error());
while ($row2 = mysql_fetch_array($result2)) {
echo $row2[0];
echo $row2[1];
echo $row2[2];
echo $row2[3];
echo $row2[4];
echo $row2[5];
echo $row2[6];
echo $row2[7];
$m1 = $row2[0];
$m2 = $row2[1];
$m3 = $row2[2];
$m4 = $row2[3];
$m5 = $row2[4];
$m6 = $row2[5];
$m7 = $row2[6];
$m8 = $row2[7];
echo "<br/>";
}
if (++$i == 8) break;
}
$sql3 = "INSERT INTO tablec (partner_id, make1, make2, make3, make4, make5, make6, make7, make8, saved) VALUES ('$id', '$m1', '$m2', '$m3', '$m4', '$m5', '$m6', '$m7', '$m8', '$set')";
$result3 = mysql_query($sql3) or die(mysql_error());
var_dump($sql3);
var_dump($result3);
if($result3) {
echo "done";
}
else {
echo "fail";
}
echo "<pre>";
var_dump($row);
echo "</pre>";
echo "<hr/>";
}
?>
var_dump sql:
string(186) "INSERT INTO tablec (partner_id, make1, make2, make3, make4, make5, make6, make7, make8, saved) VALUES ('75', 'opel', '', '', '', '', '', '', '', '2014-02-06 18:20:14')"
it works fine, but the only 1 variable inserted the table "$row2[0];"
whats the problem? thank you for your help!

Answer 1

You only ever fetch one field from your tableb:
$sql2 = "SELECT url FROM tableb WHERE id = '$make'";
^^^^---- here
If you want more fields, you need to specify them:
SELECT url, field1, field2, etc...