Getting two scripts to work together - php

Question

I'm trying to use the following scripts so that the result of the first one determines the output of the second one.
<?
$db = mysql_connect('localhost','username','pass') or die("Database error");
mysql_select_db('dbname', $db);
$query = "SELECT pool FROM winners";
$result = mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array($result))
if ( $row['pool'] % 2 )
{
echo "<h4>Result 1</h4>";
echo "<br />";
}
else
{
echo "<h4>Result 2</h4>";
echo "<br />";
}
?>
<?php
$db = mysql_connect('localhost','username','pass') or die("Database error");
mysql_select_db('dbnamesameasother', $db);
$query2 = "SELECT * FROM comments";
$result2 = mysql_query($query2);
while ($row2 = mysql_fetch_assoc($result2))
if ( $row2['commentid'] % 2 ==0 )
{
echo $row2['name'];
echo "<br />";
}
else
{
echo $row2['name'];
}
?>
So basically if the first script chooses Result 1 I only want to echo the names which associate with that result. The names are associated by commentid where an odd commentid would be result 2 and an even commentid would be result 1. Is there any way to do this without using a union statement?

Answer 1

It recommend that you to create a function and then call it.something like this :
<?php
$db = mysql_connect('localhost','username','pass') or die("Database error");
mysql_select_db('dbname', $db);
$query = "SELECT pool FROM winners";
$result = mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array($result))
if ( $row['pool'] % 2 )
{
echo "<h4>Result 1</h4>";
$names = get_names(1);
foreach ($names as $name) {
echo $name . "<br/>";
}
}
else
{
echo "<h4>Result 2</h4>";
$names = get_names(0);
foreach ($names as $name) {
echo $name . "<br/>";
}
}
Function get_names($pool_result)
{
$name_array = array();
$db = mysql_connect('localhost','username','pass') or die("Database error");
mysql_select_db('dbnamesameasother', $db);
$query = "SELECT * FROM comments WHERE commentid % 2 = $pool_result";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result))
{
array_push($name_array , $row['name']);
}
return $name_array;
}
?>
}