Update multiple rows using for loop and array php - php

Question

I have this code:
$id1=array($aa1,$aa2,$aa3,$aa4,$aa5,$aa6,$aa7);
$rank1=array($a1,$a4,$a7,$a10,$a13,$a16,$a19);
require_once("connection.php");
for($i=0;$i<7;$i++){
$sql = "update live_tracking set swim_rank = '"$rank1[$i]."' where id = '".$id1[$i]."'";
}
I want to update multiple rows of my mysql database but using the code above only the first index is being updated. Any suggestions?

Answer 1

You can execute one query only by using this :
$sql = "update live_tracking set swim_rank = '".$rank1[$i]."' WHERE id IN (";
for($i=0;$i<7;$i++){
$sql .= $id1[$i].",";
}
$sql .= ")";
$query = mysql_query($sql) or die("error : ".mysql_error());
if($query){
echo "success";
}

Answer 2

Execute the query within the loop itself.
for($i=0;$i<7;$i++)
{
mysql_query("update live_tracking set swim_rank = '".$rank1[$i]."' where id = '".$id1[$i]."'");
}

Answer 3

I can see an error in the sql
$sql = "update live_tracking set swim_rank = '"$rank1[$i]."' where id = '".$id1[$i]."'";
The above should be
$sql = "update live_tracking set swim_rank = '".$rank1[$i]."' where id = '".$id1[$i]."'";
You were missing . in '".$rank1[$i]."'

Answer 4

It seems that you are on right track. but you need to execute query in the loop. like this:
$id1=array($aa1,$aa2,$aa3,$aa4,$aa5,$aa6,$aa7);
$rank1=array($a1,$a4,$a7,$a10,$a13,$a16,$a19);
require_once("connection.php");
for($i=0;$i<7;$i++){
$sql = "update live_tracking set swim_rank = '".$rank1[$i]."' where id = '".$id1[$i]."'";
if(!mysql_query($sql)){
echo "not updated".$id1[$i]; exit();
}
}