sql server update when WHERE exist - php

Question

I have sql + php query and i need inform user when update fail exmpl:
$sql = "UPDATE db SET
date = GetDate(),
...
...
...
WHERE name = '$name1' and code = '$code' and value1 = '$value1' and value2='$value2'
";
sqlsrv_query( $con, $sql);
And now if php variables values not 100% match values in db update fails but users cant see that. He can check records and try again. I would like inform him when query update nothing.

Answer 1

Like GOB commented, you can use the PHP sqlsrv_rows_affected function to retrieve the number of affected rows. For example:
$stmt = sqlsrv_query( $conn, $sql , $params, $options );
$row_count = sqlsrv_rows_affected( $stmt );
if ($row_count === false)
echo "Error in retrieving row count.";
else
echo $row_count;

Answer 2

Before directly executing update query,check whether condition in update query exists or not. This can be done by selecting count of that condition.
Try below code:
$sql = "select count(*) as count from db WHERE name = '$name1' and code = '$code' and value1 = '$value1' and value2='$value2' ";
while($row = mysqli_fetch_array($sql))
{
$count = $row['count'];
}
if($count == 0)
{
echo 'update will fail';
}
else
{
$sql = "UPDATE db SET
date = GetDate(),
...
...
...
WHERE name = '$name1' and code = '$code' and value1 = '$value1' and value2='$value2'
";
}