Handling three while loops in PHP MYSQL - php

Question

I'm new to PHP and struck with a while loop. Please throw some lights here.
I'm showing some information related to books vs author vs isbn number.
There are two tables: book and author. The book name and ISBN number comes from book table. The author name comes from author table.
Here is my poor php code(please dont laugh)
<?php
mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("test") or die(mysql_error());
$result1 = mysql_query("SELECT book_name FROM book where status='1'") or die(mysql_error());
$result2 = mysql_query("SELECT FName FROM author") or die(mysql_error());
$result3 = mysql_query("SELECT book_isbn_number FROM book where status='1'") or die(mysql_error());
?>
<table style="margin-top:40px" border="1" width="100%">
<tr style="background-color:#909F51">
<td>Book List</td>
<?php while($row1 = mysql_fetch_array( $result1 )) { ?>
<td><?php echo $row1['book_name']; ?></td>
<?php } ?>
</tr>
<?php while($row2 = mysql_fetch_array( $result2 )) { ?>
<tr>
<td><?php echo $row2['author_name']; ?></td>
<?php while($row3 = mysql_fetch_array( $result3 )) { ?>
<td><?php echo $row3['book_isbn_number']; ?></td>
<?php } ?>
</tr>
<?php } ?>
</table>
I'm not able to loop through the third while condition. I know the basic code structure is wrong.
Could someone help me out in getting the result.
Tables:
book
b_id
book_name
isbn_number
status
author
a_id
author_name
Expected Output:
<table width="100%" border="1">
<tr>
<td></td>
<td>Author Name 1</td>
<td>Author Name 2</td>
</tr>
<tr>
<td>Book Name 1</td>
<td>ISBN Number 1</td>
<td>ISBN Number 2</td>
</tr>
<tr>
<td>Book Name 2</td>
<td>ISBN Number 3</td>
<td>ISBN Number 4</td>
</tr>
</table>

Answer 1

You are using $row3['isbn_number'] when the column you are selecting is "book_isbn_number". Try changing that line to be <td><?php echo $row3['book_isbn_number']; ?></td>. The loops themselves, while using the old, deprecated mysql_* functions, should be working fine.

Answer 2

<td><?php echo $row3['isbn_number']; ?></td>
replace it with
<td><?php echo $row3['book_isbn_number']; ?></td>

Answer 3

$result3 = mysql_query("SELECT book_isbn_number FROM book where status='1'") or die(mysql_error());
Should be
$result3 = mysql_query("SELECT isbn_number FROM book where status='1'") or die(mysql_error());**
OR
<td><?php echo $row3['isbn_number']; ?></td>
Should be
<td><?php echo $row3['book_isbn_number']; ?></td>
Whichever fits your need