Can't display the query results [duplicate] - php

Question

This question already has answers here:
Single Value Mysqli [duplicate]
(8 answers)
Closed 3 years ago.
I can't seems to display the query results on my HTML. It displays nothing.
And I really don't know how to do that.
$qr1= mysqli_query($conn,"SELECT qr FROM `count` WHERE id=1;");
$qr2= mysqli_query($conn,"SELECT qr FROM `count` WHERE id=2;");
$qr3= mysqli_query($conn,"SELECT qr FROM `count` WHERE id=3;");
$qr4= mysqli_query($conn,"SELECT qr FROM `count` WHERE id=4;");
$qr5= mysqli_query($conn,"SELECT qr FROM `count` WHERE id=5;");
$total= $qr1 + $qr2 + $qr3 + $qr4 + $qr5;
My HTML :
<tbody>
<tr>
<th scope="row">QR1</th>
<td><?php echo $qr1 ?></td>
</tr>
<tr>
<th scope="row">QR2</th>
<td><?php echo $qr2 ?></td>
</tr>
<tr>
<th scope="row">QR3</th>
<td><?php echo $qr3 ?></td>
</tr>
<tr>
<th scope="row">QR4</th>
<td><?php echo $qr4 ?></td>
</tr>
<tr>
<th scope="row">QR5</th>
<td><?php echo $qr5 ?></td>
</tr>
</tbody>

Answer 1

what's missing is that you need to specify the column on your $qr.
Here's the shorter version of your code.
$total = 0;
$qr= mysqli_query($conn,"select qr, concat('QR', cast(id as varchar(3))) as id FROM `count` where id in (1,2,3,4,5) order by id;");
<tbody>
while ($row = mysqli_fetch_row($qr)) {
<tr>
<th scope="row">
<?php echo $row['id'] ?>
</th>
<td><?php echo $row['qr'] ?></td>
</tr>
$total = $total + $row['qr'];
}
</tbody>