Fetching data from a table and storing in variables - php

Question

I have website settings stored in a table like this:
+---------+-------------+
| id | value |
+---------+-------------+
| 1 | title |
| 2 | description |
| 3 | email |
| 4 | keywords |
+---------+-------------+
How can I select them and assign them to variables ($title, $desc, $email, $key)
// Get Website Infos
$result=$db->query("SELECT `value` FROM `settings`");
if($result->num_rows >= 1){
$row=$result->fetch_assoc();
$otitle=$row['value'];
$odescription=$row['value'];
$oemail=$row['value'];
$okeywords=$row['value'];
}
but it only get the first row 'title',any idea how to do it or better way to save settings.
UPDATE:
If you are reading this question now, don't use this structure to store your settings, use the one suggested by Yellow Bird in the answers.

Answer 1

You have to loop with your fetch_assoc() method :
$result = $db->query("SELECT `value` FROM `settings`");
if ($result->num_rows >= 1){
$data = array();
while ($row = $result->fetch_assoc()) {
$data[] = $row['value'];
}
}
var_dump($data);
As DanFromGermany noticed in comments, your db structure is probably not done the right way. You should have a design like this :
+---------+-------------+--------------+
| id | key | value |
+---------+-------------+--------------+
| 1 | title | title value |
| 2 | description | desc value |
| 3 | email | email value |
| 4 | keywords | keyw value |
+---------+-------------+--------------|
And then, your code would look like this :
$result = $db->query("SELECT key, value FROM `settings`");
if ($result->num_rows >= 1) {
$data = array();
while ($row = $result->fetch_assoc()) {
$data[$row['key']] = $row['value'];
}
}