I have a tags_ids array 1,3,2 and
data in my table:
+---------+----------+
| user_id | tag_id |
+---------+----------+
| 1 | 1 |
| 1 | 2 |
| 2 | 1 |
| 2 | 2 |
+---------+----------+
I want to get the users ids into array, but not working:
foreach ($tags_ids as $i)
{
if ($result = $mysqli->prepare("SELECT `user_id` FROM `mytable` WHERE `tag_id`=?"))
{
$result->bind_param("i",$i);
$result->execute();
$result->bind_result($d);
$result->fetch();
$result->close();
}
if (!in_array($d,$users_ids)) $users_ids[] = $d;
}
My result is always 1. Whats I'm doing wrong, and can I do it in a more simple way?
you need a while loop, you can find it here for full assist:http://www.youtube.com/watch?v=hO0YOOeJrOE
be sure to watch the other video's too, very helpfull.
goodluck,
PHPNoob
Related
i have a datastructure similar to this
+---------+---------+
| id | value |
+---------+---------+
| 1 | value |
1 | value |
| 1 | value |
| 1 | value |
| 1 | value |
| 2 | value |
| 2 | value |
| 2 | value |
| 3 | value |
| 3 | value |
| 3 | value |
| | |
+---------+---------+
I am trying to update this table to look something like this
+---------+---------+
| id | value |
+---------+---------+
| 1 | value 0 |
1 | value 1 |
| 1 | value 2 |
| 1 | value 3 |
| 1 | value 4 |
| 2 | value 0 |
| 2 | value 1 |
| 2 | value 2 |
| 3 | value 0 |
| 3 | value 1 |
| 3 | value 2 |
| | |
+---------+---------+
To achieve this, i have written php script that looks like this
$query = "select count(*) as count,id, value from foo group by id";
$sql=$con->prepare($query);
$sql->execute();
$sql->setFetchMode(PDO::FETCH_ASSOC);
while($row=$sql->fetch()){
$id[] = $row['id'];
$count[] = $row['count'];
$value[] = $row['value'];
echo "<pre>";
}
$c=array_combine($id, $count);
foreach ($c as $key=>$value){
for($i=0;$i<=$value;$i++){
$postid = $key;
if($i==0){
$multiple = "multiple";
$newvalue= $value;
}
else{
$x=$i-1;
$multiple = "multiple_".$x;
echo $multiple . "<br>";
$query2 = "update foo set value = :multiple";
$sql2=$con->prepare($query2);
$sql2->bindValue(':multiple', $multiple);
$sql2->execute();
}
}
}
The problem is that the code returns the following results
+---------+---------+
| id | value |
+---------+---------+
| 1 | value_1 |
1 | value_1 |
| 1 | value_1 |
| 1 | value_1 |
| 1 | value_1 |
| 2 | value_1 |
| 2 | value_1 |
| 2 | value_1 |
| 3 | value_1 |
| 3 | value_1 |
| 3 | value_1 |
| | |
+---------+---------+
What can i be possibly be doing wrong?
Thanks #Shadow
Your query runs fine but returns the following results
+------+-----------------------------------------------+
| id | value |
+------+-----------------------------------------------+
| 1 | multiple_1_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0 |
| 1 | multiple_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1 |
| 1 | multiple_1_2_2_2_2_2_2_2_2_2_2_2_2_2_2_2_2 |
| 1 | multiple_1_3_3_3_3_3_3_3_3_3_3_3_3_3_3_3_3 |
| 2 | multiple_1_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0 |
| 2 | multiple_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1 |
| 2 | multiple_1_2_2_2_2_2_2_2_2_2_2_2_2_2_2_2_2 |
| 2 | multiple_1_3_3_3_3_3_3_3_3_3_3_3_3_3_3_3_3 |
| 3 | multiple_1_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0 |
| 3 | multiple_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1 |
| 3 | multiple_1_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0 |
+------+-----------------------------------------------+
You can do the update iterating and creating data in such a way:
<?php
$pdo = new PDO('mysql:host=localhost;dbname=test', 'root', '');
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sth = $pdo->prepare("SELECT * FROM foo");
$sth->execute();
$data = $sth->fetchAll(PDO::FETCH_ASSOC);
$response = array();
foreach ($data as $dataIndex => $dataValue) {
if (!isset($response[$dataValue["id"]]["count"])) {
$response[$dataValue["id"]]["count"] = 0;
} else {
$response[$dataValue["id"]]["count"] ++;
}
$response[$dataValue["id"]]["values"][$dataValue["pid"]] = "value_" . $response[$dataValue["id"]]["count"];
$sth = $pdo->prepare("UPDATE foo SET value = '{$response[$dataValue["id"]]["values"][$dataValue["pid"]]}' WHERE pid = {$dataValue["pid"]}");
$sth->execute();
}
?>
But try to do an update using the least iteration not to create as many database queries , example:
<?php
$pdo = new PDO('mysql:host=localhost;dbname=test', 'root', '');
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sth = $pdo->prepare("SELECT * FROM foo");
$sth->execute();
$data = $sth->fetchAll(PDO::FETCH_ASSOC);
$response = array();
$update = array();
foreach ($data as $dataIndex => $dataValue) {
$response[$dataValue["id"]]["id"] = $dataValue["id"];
if (!isset($response[$dataValue["id"]]["count"])) {
$response[$dataValue["id"]]["count"] = 0;
} else {
$response[$dataValue["id"]]["count"] ++;
}
$response[$dataValue["id"]]["values"][$dataValue["pid"]] = "value_" . $response[$dataValue["id"]]["count"];
$update[] = "UPDATE foo SET value = '{$response[$dataValue["id"]]["values"][$dataValue["pid"]]}' WHERE pid = {$dataValue["pid"]};";
}
$update = implode("",$update);
$sth = $pdo->prepare($update);
$sth->execute();
?>
Your update query
$query2 = "update foo set value = :multiple";
does not contain any where criteria, each time you call this query it updates the value field's value in all records.
Honestly, I would not really involve php in this update, would do it purely in sql using user defined variables and multi-table join syntax in the update:
update foo inner join (select #i:=0, #previd:=-1) as a
set foo.value=concat(foo.value,'_',#i:=if(id=#previd,#i+1,0),if(#previd:=id,'',''))
The subquery in the inner join initialises #i and #previd user defined variables. The 3rd parameter of the concat function determines the value #i to be concatenated to the value field. The 4th parameter of concat sets the #previd variable and returns an empty string not to affect the overall concatenation. Unfortunately, I do not have access to MySQL to test the query, but it should be a good starting point anyway.
UPDATE
The OP claims in the updated question that the query I provided creates the below resultset:
+------+-----------------------------------------------+
| id | value |
+------+-----------------------------------------------+
| 1 | multiple_1_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0 |
| 1 | multiple_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1 |
| 1 | multiple_1_2_2_2_2_2_2_2_2_2_2_2_2_2_2_2_2 |
| 1 | multiple_1_3_3_3_3_3_3_3_3_3_3_3_3_3_3_3_3 |
| 2 | multiple_1_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0 |
| 2 | multiple_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1 |
| 2 | multiple_1_2_2_2_2_2_2_2_2_2_2_2_2_2_2_2_2 |
| 2 | multiple_1_3_3_3_3_3_3_3_3_3_3_3_3_3_3_3_3 |
| 3 | multiple_1_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0 |
| 3 | multiple_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1_1 |
| 3 | multiple_1_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0_0 |
+------+-----------------------------------------------+
Tested my solution in sqlfiddle. I had to remove the order by clause, otherwise the query produced the results in line with the requirements stated in the question. See sqlfiddle for details.
The results in the updated question are likely the result of running the query in a loop multiple times. In simple words: you just copy pasted the query into your code and did not remove the loop, even when I pointed out, that this may be the reason of the results you received.
Hello I have actually asked a similar question a while ago but only just realized I did not get an answer that solves my problem.
I have 2 tables in a MySQL DB, that are connected by the same main id, the following code is just a simplified example of the original code:
table1:
+-----------------------+
| main_id | name | type |
+-----------------------+
table2:
+----------------------------------------+
| main_id | secondary_id | color | price |
+----------------------------------------+
the result I want to achieve is to get every row of table 1, and under each one list all the linked by main id rows from table2, for example:
table1 rows:
+-------------------+
| 1 | name1 | type1 |
| 2 | name2 | type2 |
| 3 | name3 | type3 |
+-------------------+
table2 rows:
+----+------+----------+------+
| 1 | 23 | red | 500 |
| 1 | 24 | blue | 600 |
| 1 | 25 | green | 700 |
| 2 | 26 | pink | 400 |
| 2 | 27 | purple | 200 |
| 3 | 28 | white | 100 |
+----+------+----------+------+
result in display:
<h1 class="1">name1, type1</h1>
<div class="23">red,500</div>
<div class="23">red,500</div>
<div class="24">green,700</div>
<h1 class="2">name2, type2</h1>
<div class="25">pink,400</div>
<div class="26">purple,200</div>
And so on...I was using a while loop inside a while loop which wasn't giving me the required result, then I was advised to use MySQL JOIN, but when I do I get all values of the matching ids and cant display the headings only once and then list the related results under it, can someone please help me?
this is a simplified query i was using:
while($rows = $headings->fetch_array(MYSQLI_BOTH))
{
$id = $rows['id'];
$conts_q = $mysqli->query("SELECT * FROM `table2` WHERE id='$id'");
$conts_numr = $conts_q->num_rows;
if($conts_numr==0)
{
//Display empty
}
else
{
while($row2 = $conts_q->fetch_array(MYSQLI_BOTH))
{
//Get details and display
}
}
}
In your description, you use main_id, but in the code you use just id. Not sure which you're really using here - you will have to edit the code below to match your actual column names. If the database column name is actually main_id, then for instance the line with $id = $rows['id'] would have to be $rows['main_id']. Or it won't work.
while($rows = $headings->fetch_array(MYSQLI_BOTH))
{
echo '<h1 class="'.$rows['id'].'">'.$rows['name1'].', '.$rows['type'].'</h1>';
$id = $rows['id'];
$conts_q = $mysqli->query("SELECT * FROM `table2` WHERE id='$id'");
$conts_numr = $conts_q->num_rows;
if($conts_numr==0)
{
//Display empty
}
else
{
while($row2 = $conts_q->fetch_array(MYSQLI_BOTH))
{
if ($row2['id'] == $id) {
echo '<div class="'.$row2['secondary_id'].'">'.$row2['color'].', '.$row2['price'].'</div>';
}
}//while
}//else
}//while
I have this scenario.
I input $groupid="1";
main table
----------------------
| groupid | postid |
|---------------------|
| 1 | 1 |
| 2 | 2 |
| 1 | 3 |
$query = "SELECT postid FROM `mainl` WHERE groupid='$groupid'";
$result = mysql_query($query);
// a group of postids belonging to that groupid which should hold [1, 3] for groupid=1
while($row = mysql_fetch_array($result)) {
$postids[] = $row["postid"];
}
second table
-------------------------------------------
| postid | commentid | comment |
-------------------------------------------
| 1 | 1 | testing 1 |
| 1 | 2 | testing 2 |
| 1 | 3 | what? |
| 2 | 1 | hello |
| 2 | 2 | hello world |
| 3 | 1 | test 3 |
| 3 | 2 | begin |
| 3 | 3 | why? |
| 3 | 4 | shows |
$query = "SELECT * FROM `second`";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result)) {
if (in_array($row["postid"], $postids)) {
$comments[$row["postid"]] = $row["comment"];
But how should I take care of commented
I want the postid array to be [1,3] and my comment array to be
[commentid: comment] [1:testing1, 2: testing2, 3: what?] for postid=1
and
[1:test3, 2:begin, 3: why? 4:shows] for postid=3
how should be arrange everything such comment are associated with commentid and postid?
First I would follow rokdd suggestion and make 1 query
SELECT m.groupid , s.postid, s.commentid, s.comment FROM `main1` m JOIN `second` s USING (postid) where m.groupid = 1
Then I would make a multi-dimensional array
while ($row = mysql_fetch_array($result))
$groups[$row['groupid'][$row['postid']][$row['commentid']=$row['comment'];
then to iterate through the array
foreach($groups as $group)
foreach($group as $post)
foreach($post as $comment)
echo $comment;
This will keep track of groups also (if you ever want to select by more than 1 group.
If you don't care about groups just drop off the first part of the array.
while ($row = mysql_fetch_array($result))
$posts[$row['postid']][$row['commentid']=$row['comment'];
foreach($posts as $post)
foreach($post as $comment)
echo $comment;
I guess to use the join in sql so that you will have one statement:
SELECT * FROM second as second_tab LEFT join main as main_table ON main_table.post_id=second_table.post_id WHERE main_table.group_id="3"
Well not tested now but thats a way to solve some of your problems!
I have tables illustrated below
//reference type table
+---+-----------+---------+
|ID |Article_ID |Ref_Types|
+---+-----------+---------+
| 1 | 1 | article |
| 2 | 1 | book |
| 3 | 1 | article |
| 4 | 1 | article |
| 5 | 2 | book |
+---+-----------+---------+
//book references table
+---+-----------+--------+
|ID |Article_ID |Title |
+---+-----------+--------+
| 1 | 1 | book1 |
| 2 | 1 | book2 |
| 3 | 2 | book3 |
| 4 | 2 | book4 |
| 5 | 2 | book5 |
+---+-----------+--------+
//article references table
+---+-----------+-----------+
|ID |Article_ID |Title |
+---+-----------+-----------+
| 1 | 1 | article1 |
| 2 | 1 | article2 |
| 3 | 2 | article3 |
| 4 | 2 | article4 |
| 5 | 2 | article5 |
+---+-----------+-----------+
I have to look into first table and check the reference, of which type it is;
for each reference type, I have get reference table from related table
I have to output in order, as shown in table one.
1:
$data=array();
$sql=mysql_query("SELECT * FROM reftypes
WHERE Article_ID=1 ORDER BY ID ASC");
while($row = mysql_fetch_array($sql)){
$data[]=$row[2]; // i store in an array so that i can use later..
}
2:
foreach ($data as $ref) {
$counter=1;
switch ($ref) {
case "article":
$sqlarticle= mysql_query("SELECT Title
FROM book WHERE Article_ID=1 ORDER BY ID ASC");
echo mysql_result($sqlarticle, $counter); //i want to get only one out of book table
$counter++;
break;
...
...
But $sqlarticle does not seem to work.
I want to display as:
+-----------+----------+
|Article_ID |Reference |
+-----------+----------+
| 1 | article1 |
| 1 | book1 |
| 1 | article2 |
| 1 | article3 |
+-----------+----------+
I know it is a long question and for experts or experienced people it is very trivial, but that is where I'm stuck.
SELECT
*
FROM
reftypes R
WHERE
Article_ID=your_id
LEFT JOIN books B ON (B.Article_ID = R.Article_ID AND R.Ref_Types = 'book')
LEFT JOIN articles A ON (A.Article_ID = R.Article_ID AND R.Ref_Types = 'article')
ORDER BY
R.id ASC;
Even if the database is wrongly modeled, I think.
What about the followin model instead?
""although especially question owners should respect any kind of effort and input, -i am thankful- i can not understand why some people try to think of question's holder as well-informed or experienced as themselves, or worse comment from higher level. ""
anyway, my question was about to get values one by one, here is how i did it;
$data=array();
$sql=mysql_query("SELECT * FROM reftypes
WHERE Article_ID=1 ORDER BY ID ASC");
while($row = mysql_fetch_array($sql)){
$data[]=$row[2]; // i store in an array so that i can use later..
}
$articlecount=0;
$bookcount=0;
foreach ($data as $value) {
switch ($value) {
case "article":
$sqlarticle=mysql_query("SELECT RefArticleTitle
FROM ref_article
WHERE $article_ID=Article_ID
ORDER BY ID ASC");
$articles= mysql_result($sqlarticle, $articlecount);
echo $articles;
echo "\n";
$articlecount++;
break;
case "book":
$sqlbook=mysql_query("SELECT RefBookName
FROM ref_book
WHERE $article_ID=Article_ID
ORDER BY ID ASC");
$books= mysql_result($sqlbook, $bookcount);
echo $books;
echo "\n";
$bookcount++;
break;
...
...
as a result, i got what i required..
+-----------+----------+
|Article_ID |Reference |
+-----------+----------+
| 1 | article1 |
| 1 | book1 |
| 1 | article2 |
| 1 | article3 |
+-----------+----------+
thanks to whoever interested in the topic..
$result=mysqli_query("select ref_types from reference type");
while($row=mysqli_fetch_array($result))
{
$table=$row[0];
$result1=mysqli_query("select * from $table");
while($row1=mysqli_fetch_array($result1))
{
var_dump($row1);
}
}
I have a table that like this.
+-----------+-----------+-----------+-----------+-----------+-----------+
|id | parent_id | name | order | status | date_add |
+-----------+-----------+-----------+-----------+-----------+-----------+
|1 | 0 | shoes | 1 | 1 | 2011-04-02|
+-----------+-----------+-----------+-----------+-----------+-----------+
|2 | 1 | male | 2 | 1 | 2011-04-02|
+-----------+-----------+-----------+-----------+-----------+-----------+
|3 | 1 | female | 3 | 1 | 2011-04-02|
+-----------+-----------+-----------+-----------+-----------+-----------+
|4 | 3 | red shoes | 4 | 1 | 2011-04-02|
+-----------+-----------+-----------+-----------+-----------+-----------+
I want to select only the leaf children, with their path.
I want to come to the result as follows:
+------+-------------------------------------+
| 2 | shoes/male |
+------+-------------------------------------+
| 4 | shoes/female/red shoes |
+------+-------------------------------------+
if this does not only sql can also be php + sql
Please help me.
Very simple solution to print out id and path to all last child nodes using PHP as I am not aware of a way of doing this within MySQL. Hope this helps!
function getChildren($parent= "", $x = 0) {
$sql = "SELECT id, name FROM recurr WHERE parentId = $x";
$rs = mysql_query($sql);
//echo "Name: $parent has ". mysql_num_rows($rs)." children<br/>";
while ($obj = mysql_fetch_object($rs)) {
if (hasChildren($obj->id)) {
getChildren($parent."/".$obj->name, $obj->id);
} else {
echo $obj->id .", ".$parent."/".$obj->name."<br/>";
}
}
}
function hasChildren($x) {
$sql = "SELECT * FROM recurr WHERE parentId = $x";
$rs = mysql_query($sql);
if (mysql_num_rows($rs) > 0) {
return true;
} else {
return false;
}
}
To run just call:
getChildren();
I highly recommend implementing nested set model for hierarchical MySQL data. Here is the link for more info: http://mikehillyer.com/articles/managing-hierarchical-data-in-mysql/. In the link, you will also find the answer to your question (under "The Adjacency List Model", "Finding all the Leaf Nodes" section)