How to assign a role to a user PHP - php

Question

Well I have this form that adds user, admin.I've given to user the right to add another user but not add an admin or so!
$roles = db_fetch_all("role") ;
$TabRoles = array(''=>'-- Choose --');
foreach($roles as $value)
{
$TabRoles[$value['rid']] = $value['name'];
}
and with print_array($TabRoles); it displays me :
Array
(
[] => -- Choose --
[admin] => Admin
[seo] => SEO
[user] => User
)
The condistion is if (user('rid') == 'admin'|'seo') . I tried this :
foreach($roles as $value)
{
if (user('rid') == 'admin'|'seo')
{
$TabRoles[$value['rid']] = $value['name'];
}else{
$TabRoles[$value['rid']] = $value['name'][2];
}
}
But it displays me the position "2" of the array !
Array
(
[] => -- Choose --
[admin] => m
[seo] => O
[user] => e
)
I want it to display like this :
Array
(
[] => -- Choose --
[user] => User
)
Any solution for this ? Many Thanks!
The solution : thanks to #DanFromGermany:
foreach($roles as $value)
{
if (user('rid') == 'admin' || user('rid') == 'seo')
{
$TabRoles[$value['rid']] = $value['name'];
}elseif (user('rid') == $value['rid']){
$TabRoles[$value['rid']] = $value['name'];
}
}

Answer 1

if (user('rid') == 'admin'|'seo')
| is a bitwise operator, but I guess you want a logical comparison here:
if (user('rid') == 'admin' || user('rid') == 'seo')
Explanation on using array brackets on strings:
$test = 'abcd';
echo $test[0]; // prints a
echo $test[1]; // prints b
echo $test[2]; // prints c
That's why you get only a letter instead of the element you want.
I think you are looking for something like:
foreach($roles as $value) {
if (user('rid') == $value['rid'])
$TabRoles[$value['rid']] = $value['name'];
}
}
or
foreach($roles as $value) {
$TabRoles[$value['rid']] = $value['name'];
}
if (user('rid') != 'seo' && user('rid') != 'admin')) { // inverse/negate the logic!
unset($TabRoles['seo']);
unset($TabRoles['admin']);
}