Inserting multiple rows from php foreach - php

Question

I have an html form with dynamic (user-determined) number of rows, each with several inputs; I'm trying to achieve a MySQL query which will insert rows
into the db table, more or less row-for-row (although there is a value $_POSTing from outside this table which I will also add to the INSERT).
I'm retrieving these values like this:
<?php
if (isset($_POST['submit'])) {
$lineItems = array();
foreach ($_POST['date'] as $i => $value) {
$customer = $_POST['customer'][$i]; // this value is from *outside* the line items table
$date = $_POST['date'][$i];
$time = $_POST['time'][$i];
$fee = $_POST['fee'][$i];
$lineItems[] = "('$customer', '$date', '$time', '$fee')";
// I realize the query should be outside the loop, but what I'm trying to do is something like this (pseudo-code):
$query = "INSERT INTO Line_Items (CUSTOMER, DATE, TIME, FEE) VALUES ". implode(", ", $lineItems)
. "ON DUPLICATE KEY UPDATE
CUSTOMER = VALUES(CUSTOMER),
DATE = VALUES(DATE),
TIME = VALUES(TIME),
FEE = VALUES(FEE)
";
}
}
?>
With this query - inside or outside the loop - I'm only inserting values from the last row of inputs; can someone please explain with an example how
to construct a query to insert multiple line items and the appropriate query? Thank you so much.

Answer 1

Inside the loop you will get a row for each line in the post - outside the loop you will only insert the last row.
If you just need the last row - then there is no need to loop over the entire set to get to it.
You could count the rows - and then target the last row directly - see php
count()

Answer 2

Change line
$lineItems[] = "('$customer', '$date', '$time', '$fee')";
to
$lineItems[] = "(".$customer.",".$date.",".$time.",".$fee.")";