codeigniter mysql query output data display with specific condition - php

Question

here are the following codes:
controller.php
function getchart() {
$prac = $this->input->post('prac_name');
$datee = $this->input->post('datee');
$this->load->model('appoint');
$results['appoint'] = $this->appoint->getappoint($prac , $datee);
$this->load->view('ajax/getappchart' , $results);
}
model.php
function getappoint($prac , $datee) {
$this->db->select('rdv.id as rdvid, startTime, endTime, day, firstname, lastname');
$this->db->from('rdv');
$this->db->join('contact', 'contact.id = rdv.contact_id');
$this->db->where('people_id',$practicien);
$this->db->where('DATE(day)', $datee);
$this->db->order_by('TIME(startTime)', 'ASC');
$query = $this->db->get();
//print_r($this->db->last_query());
return $query;
}
view.php
if ($appoint->num_rows() > 0) {
foreach($appoint->result() as $sub_row)
{
// display output.
}
} else {
echo 'No Appointments on Above Date.';
}
?>
what i need is, there are appointments with sametime and day(mostly 2 same).
if there is morethan 2, i need to set two different class style for both the appointment.
how can i achieve this ?
Thanks.

Answer 1

Final answer: done it with the help of #minhaz-ahmed
if ($appoint->num_rows() > 0) {
$appoint_counter = array();
foreach ($appoint->result() as $sub_row) {
//i am assuming your startTime is H:M:S, and day Y-M-D format
$key = strtotime($sub_row['day'] . ' ' . $sub_row['startTime']);
if (!isset($appoint_counter[$key])) {
$appoint_counter[$key] = 0;
}
$appoint_counter[$key] ++;
$style_class = 'YOUR_1ST_CLASS';
if ($appoint_counter[$key] > 2) {
$style_class = 'YOUR_2ND_CLASS';
}
//REST VIEW CODE
}
}
else {
echo 'No Appointments on Above Date.';
}

Answer 2

You can do like this
if ($appoint->num_rows() > 0) {
$appoint_counter = array();
foreach ($appoint->result() as $sub_row) {
//i am assuming your startTime is H:M:S, and day Y-M-D format
$key = strtotime($sub_row['day'] . ' ' . $sub_row['startTime']);
if (!isset($appoint_counter[$key])) {
$appoint_counter[$key] = 0;
}
$appoint_counter[$key] ++;
}
foreach ($appoint->result() as $sub_row) {
//i am assuming your startTime is H:M:S, and day Y-M-D format
$key = strtotime($sub_row['day'] . ' ' . $sub_row['startTime']);
$style_class = 'YOUR_1ST_CLASS';
if ($appoint_counter[$key] > 2) {
$style_class = 'YOUR_2ND_CLASS';
}
//YOUR REST VIEW
}
} else {
echo 'No Appointments on Above Date.';
}

Answer 3

What do you mean by class style? Anyway, the code below assumes you will put the results in a datagrid.
$prev_date = "";
$prev_time = "";
$results = $query->result();
foreach($results as $appointment) {
if ($prev_date != $appointment->day) // Assuming "day" is tables date
# Display output here
if ($prev_time != $appointment->startTime) // Logically, display should sort appointments by their starting time
# Display output here
# Display appointment rows here
$prev_date = $appointment->day;
$prev_time = $appointment->startTime;
}
if (empty($results)) {
# Display "no appointments found" output here
}