Print same code twice in two locations in one php file - php

Question

I need two print the same rows which retrieved from the db, in two different locations in same php file.
I know it is better to have a function. It tried, It doesn't work properly.
I am using the below code print the said rows/
$get_g = "SELECT * FROM profile_groups";
$get_gr = mysqli_query($condb ,$get_g);
if(mysqli_num_rows($get_gr) > 0)
{
while($groups = mysqli_fetch_array($get_gr))
{
echo "<option value='".$groups['profile_gid']."'>".$groups['profile_gname']."</option>";
}
}
else
{
echo '<option value="">Empty - No Groups!!</option>';
}
I need to print exactly the same code twice in two different location in a php file.
I think it is not a good idea to retrieve data twice from the server by pasting the above code twice.
Is there any way to recall or reprint the retrieved data in second place which I need to print.
Edit : Or else, if someone can help me to convert this to a function?
I converted this into a function. It prints only first row.
Edit 2 : Following is my function
unction getGroup($dbconn)
{
$get_g = "SELECT * FROM profile_groups";
$get_gr = mysqli_query($dbconn ,$get_g);
if(mysqli_num_rows($get_gr) > 0)
{
while($groups = mysqli_fetch_array($get_gr))
{
$groupData = "<option value='".$groups['profile_gid']."'>".$groups['profile_gname']."</option>";
}
}
else
{
echo '<option value="">Empty - No Groups!!</option>';
}
return $groupData;

Answer 1

You can store the records coming from the DB in array and use a custom function to render the element
$get_g = "SELECT * FROM profile_groups";
$get_gr = mysqli_query($condb ,$get_g);
$options = []; //store in an array
if(mysqli_num_rows($get_gr) > 0)
{
while($groups = mysqli_fetch_array($get_gr))
{
$options[$groups['profile_gid']] = $groups['profile_gname'];
}
}
Now you can use the $options array many times in your page
echo renderElement($options);
function renderElement($ops){
$html = '';
foreach($ops as $k => $v){
$html .= "<option value={$k}>{$v}</option>";
}
return $html;
}

Answer 2

If the data is same for both places, put the entire string into variable, then echo it on those two places.
instead of
echo "here\n";
echo "there\n";
do
$output = "here\n";
$output .= "there\n";
then somewhere
echo $output
on two places....

Answer 3

Values are being stored in groups array, hence you can use a foreach loop elsewhere to get values from the array:
$groups = array();
$get_g = "SELECT * FROM profile_groups";
$get_gr = mysqli_query($condb ,$get_g);
if(mysqli_num_rows($get_gr) > 0)
{
while($groups = mysqli_fetch_array($get_gr))
{
echo "<option value='".$groups['profile_gid']."'>".$groups['profile_gname']."</option>";
}
}
else
{
echo '<option value="">Empty - No Groups!!</option>';
}
// use here
foreach($groups as $group)
{
echo $group['profile_gid'] . " ". $group['profile_gname'] . "<br/>";
}

Answer 4

class ProfileGroups
{
public $profile_groups_options;
public static function get_profile_groups_options($condb) {
$get_g = "SELECT * FROM profile_groups";
if( isset( $this->profile_groups_options ) && $this->profile_groups_options != '') {
return $this->profile_groups_options;
}
$get_gr = mysqli_query($condb ,$get_g);
if(mysqli_num_rows($get_gr) > 0)
{
while($groups = mysqli_fetch_array($get_gr))
{
$this->profile_groups_options .= "<option value='".$groups['profile_gid']."'>".$groups['profile_gname']."</option>";
}
}
else
{
$this->profile_groups_options .= '<option value="">Empty - No Groups!!</option>';
}
return $this->profile_groups_options;
}
}
ProfileGroups::get_profile_groups_options($condb);