Trying to remove the hyphens which come before start of the alphabet and after end of a alphabet, but not to lose the hyphens in between.
Example
this the string i have
---this-is-my-page--
output: this-is-my-page
Note( no of hyphen are different on each request, it may be many in numbers)
2. Example
how to do this,
---this-is-page---
i need to replace the hyphen which is in between string with empty space. but not to loose to the hyphens in start and end.
Use trim function it will work for any number of -(hyphen) at start or end of your string,
$str = "---this-is-my-page---";
echo $str = trim($str,"-");
Edit:
And than use str_replace,
$str = str_replace("-"," ",$str);
DEMO.
Use trim($string, $trimCharacters):
trim — Strip whitespace (or other characters) from the beginning and end of a string
<?php
$str = '---this-is-my-page---';
var_dump( trim($str, '-') ); //string(15) "this-is-my-page"
?>
DEMO
If you only want to replace the hyphens inside the string (and not in the start/end) you can use regex:
/^(-+)(.*?)(-+)$/
..and replace it with (first group)(second group with hyphens replaced)(third group).
In code:
<?php
$str = '---this-is-my-page---';
$str = preg_replace_callback('/^(-+)(.*?)(-+)$/', function($matches) {
return $matches[1] . str_replace('-', ' ', $matches[2]) . $matches[3];
}, $str);
var_dump( $str ); //string(21) "---this is my page---"
?>
DEMO
echo trim( "---this-is-my-page---","-");
trim removes a character at the and and begin
Related
I have the following string:
$thetextstring = "jjfnj 948"
At the end I want to have:
echo $thetextstring; // should print jjf-nj948
So basically what am trying to do is to join the separated string then separate the first 3 letters with a -.
So far I have
$string = trim(preg_replace('/s+/', ' ', $thetextstring));
$result = explode(" ", $thetextstring);
$newstring = implode('', $result);
print_r($newstring);
I have been able to join the words, but how do I add the separator after the first 3 letters?
Use a regex with preg_replace function, this would be a one-liner:
^.{3}\K([^\s]*) *
Breakdown:
^ # Assert start of string
.{3} # Match 3 characters
\K # Reset match
([^\s]*) * # Capture everything up to space character(s) then try to match them
PHP code:
echo preg_replace('~^.{3}\K([^\s]*) *~', '-$1', 'jjfnj 948');
PHP live demo
Without knowing more about how your strings can vary, this is working solution for your task:
Pattern:
~([a-z]{2}) ~ // 2 letters (contained in capture group1) followed by a space
Replace:
-$1
Demo Link
Code: (Demo)
$thetextstring = "jjfnj 948";
echo preg_replace('~([a-z]{2}) ~','-$1',$thetextstring);
Output:
jjf-nj948
Note this pattern can easily be expanded to include characters beyond lowercase letters that precede the space. ~(\S{2}) ~
You can use str_replace to remove the unwanted space:
$newString = str_replace(' ', '', $thetextstring);
$newString:
jjfnj948
And then preg_replace to put in the dash:
$final = preg_replace('/^([a-z]{3})/', '\1-', $newString);
The meaning of this regex instruction is:
from the beginning of the line: ^
capture three a-z characters: ([a-z]{3})
replace this match with itself followed by a dash: \1-
$final:
jjf-nj948
$thetextstring = "jjfnj 948";
// replace all spaces with nothing
$thetextstring = str_replace(" ", "", $thetextstring);
// insert a dash after the third character
$thetextstring = substr_replace($thetextstring, "-", 3, 0);
echo $thetextstring;
This gives the requested jjf-nj948
You proceeding is correct. For the last step, which consists in inserting a - after the third character, you can use the substr_replace function as follows:
$thetextstring = 'jjfnj 948';
$string = trim(preg_replace('/\s+/', ' ', $thetextstring));
$result = explode(' ', $thetextstring);
$newstring = substr_replace(implode('', $result), '-', 3, false);
If you are confident enough that your string will always have the same format (characters followed by a whitespace followed by numbers), you can also reduce your computations and simplify your code as follows:
$thetextstring = 'jjfnj 948';
$newstring = substr_replace(str_replace(' ', '', $thetextstring), '-', 3, false);
Visit this link for a working demo.
Oldschool without regex
$test = "jjfnj 948";
$test = str_replace(" ", "", $test); // strip all spaces from string
echo substr($test, 0, 3)."-".substr($test, 3); // isolate first three chars, add hyphen, and concat all characters after the first three
How can I put spaces to a long string that does not have spaces
Example : 5Bedroom.Apartment,in.NewYork>City
I want to put spaces after any dot and comma. Only if no space after dot and comma. If already have space, just ignore
you should replace the charector which u want
$str = preg_replace('/(?<!\d),|,(?!\d{3})/', ', ', $str);
Such regex ~(?<=[,.])(?=\S)~ matches position after comma or dot before not space
$str = preg_replace( ~(?<=[,.])(?=\S)~, " ", $str);
demo
Hi i'm trying to replace all digits or numbers in a string except digits after dash by blank space
For example I have this :
$string = "1234 Example-1234";
And I want to have only "Example-1234"
I tried preg_replace('/\-?\d+/','',$string); but even digits after dash are replaced
Edited: Thanks everyone i tried all of your answers and it works well !
If you want to just skip all digits preceded with - and remove all others, use
'~-\d+(*SKIP)(*F)|\d+~'
See the regex demo
Note you would like to trim the result or add \s* around \d+ pattern.
Pattern details:
-\d+(*SKIP)(*F) - match -, 1+ digits and skip this match
| - or
\d+ - 1 or more digits
See the PHP demo:
$str = '1234 Example-1234';
$res = preg_replace('/-\d+(*SKIP)(*F)|\s*\d+/', '', $str);
echo trim($res); // => Example-1234
The solution using regex negative lookbehind assertion (?<!a)b:
$str = "1234 Example-1234";
$str = preg_replace('/(?<![0-9-])\d+/', '', $str);
print_r($str);
The output:
Example-1234
Because you are looking for words that contain a dash, you can achieve this by to splitting the string via spaces, loop through the array values until you find a string with a dash, and then output from there onwards.
$string = "1234 Example-1234";
$words = explode(" ", $string);
foreach($words as $word) {
if (strpos($word, '-') !== false) {
echo $word;
break; // delete this line if there are multiple instances of words with dashes in your string
}
}
This will output Example-1234.
You can see a working example here
ONLINE Regex tester : https://regex101.com/r/ykUWfM/3
<?php
$string = "1234 Example-1234";
echo preg_replace('/-(\d+)/','',$string);
?>
OUTPUT: before - convert into string
1234 Example
NOTE: Before - its get the string before dash -
OR
Demo: https://regex101.com/r/ykUWfM/2
<?php
$string = "1234 Example-1234";
echo preg_replace('/(?<![0-9-])\s*\d+/','',$string);
?>
OUTPUT:
Example-1234
I'm making a function that that detect and remove all trailing special characters from string. It can convert strings like :
"hello-world"
"hello-world/"
"hello-world--"
"hello-world/%--+..."
into "hello-world".
anyone knows the trick without writing a lot of codes?
Just for fun
[^a-z\s]+
Regex demo
Explanation:
[^x]: One character that is not x sample
\s: "whitespace character": space, tab, newline, carriage return, vertical tab sample
+: One or more sample
PHP:
$re = "/[^a-z\\s]+/i";
$str = "Hello world\nhello world/\nhello world--\nhellow world/%--+...";
$subst = "";
$result = preg_replace($re, $subst, $str);
try this
$string = preg_replace('/[^A-Za-z0-9\-]/', '', $string); // Removes special chars.
or escape apostraphe from string
preg_replace('/[^A-Za-z0-9\-\']/', '', $string); // escape apostraphe
You could use a regex like this, depending on your definition of "special characters":
function clean_string($input) {
return preg_replace('/\W+$/', '', $input);
}
It replaces any characters that are not a word character (\W) at the end of the string $ with nothing. \W will match [^a-zA-Z0-9_], so anything that is not a letter, digit, or underscore will get replaced. To specify which characters are special chars, use a regex like this, where you put all your special chars within the [] brackets:
function clean_string($input) {
return preg_replace('/[\/%.+-]+$/', '', $input);
}
This one is what you are looking for. :
([^\n\w\d \"]*)$
It removes anything that is not from the alphabet, a number, a space and a new line.
Just call it like this :
preg_replace('/([^\n\w\s]*)$/', '', $string);
I am working with a slug function and I dont fully understand some of it and was looking for some help on explaining.
My first question is about this line in my slug function $string = preg_replace('# +#', '-', $string); Now I understand that this replaces all spaces with a '-'. What I don't understand is what the + sign is in there for which comes after the white space in between the #.
Which leads to my next problem. I want a trim function that will get rid of spaces but only the spaces after they enter the value. For example someone accidentally entered "Arizona " with two spaces after the a and it destroyed the pages linked to Arizona.
So after all my rambling I basically want to figure out how I can use a trim to get rid of accidental spaces but still have the preg_replace insert '-' in between words.
ex.. "Sun City West " = "sun-city-west"
This is my full slug function-
function getSlug($string){
if(isset($string) && $string <> ""){
$string = strtolower($string);
//var_dump($string); echo "<br>";
$string = preg_replace('#[^\w ]+#', '', $string);
//var_dump($string); echo "<br>";
$string = preg_replace('# +#', '-', $string);
}
return $string;
}
You can try this:
function getSlug($string) {
return preg_replace('#\s+#', '-', trim($string));
}
It first trims extra spaces at the beginning and end of the string, and then replaces all the other with the - character.
Here your regex is:
#\s+#
which is:
# = regex delimiter
\s = any space character
+ = match the previous character or group one or more times
# = regex delimiter again
so the regex here means: "match any sequence of one or more whitespace character"
The + means at least one of the preceding character, so it matches one or more spaces. The # signs are one of the ways of marking the start and end of a regular expression's pattern block.
For a trim function, PHP handily provides trim() which removes all leading and trailing whitespace.