How to use preg_replace to convert only matching hex values into text representation of hex?
$string = 'abcd'.hex2bin(23).'abc'.hex2bin(24);
For example str_replace('/[\x20-\x25]/', 'what here?', $string) would get output like:
abcd[HEX:23]abc[HEX:24]
What exactly I want to do: I'm looking for hidden characters, and want to display their hex values.
You need something like preg_replace_callback() to have a callback called against all matches.
Try:
$string = 'abcd'.hex2bin(23).'abc'.hex2bin(24);
$text = preg_replace_callback('/[\\x20-\\x25]/', function($matches) {
$string = bin2hex($matches[0]);
return "[HEX:{$string}]";
}, $string);
Related
i've scraped a html string from a website. In this string it contains multiple strings like color:#0269D2. How can i make str_replace code which replace this string with another color ?
For instance something like this just looping through all color:#0269D in the fulltext string variable?
str_replace("color:#0269D","color:#000000",$fulltext);
you pass array to str_replace function , no need to use loop
$a= array("color:#0269D","color:#000000");
$str= str_replace($a,"", $string);
You have the right syntax. I would add a check:
$newText = str_replace("color:#0269D", "color:#000000", $fulltext, $count);
if($count){
echo "Replaced $count occurrences of 'color'.";
}
This code might be too greedy for what you're looking to do. Careful. Also if the string differs at all, for example color: #0269D, this replacement will not happen.
’str_replace’ already replaces all occurrences of the search string with the replacement string.
If you want to replace all colors but aren't sure which hexcodes you'll find you could use preg_replace to match multiple occurrences of a pattern with a regular expression and replace it.
In your case:
$str = "String with loads of color:#000000";
$pattern = '/color ?: ?#[0-9a-f]{3,6}/i';
$replacement = "color:#FFFFFF";
$result = preg_replace($pattern, $replacement, $str);
I need to extract a project number out of a string. If the project number was fixed it would have been easy, however it can be either P.XXXXX, P XXXXX or PXXXXX.
Is there a simple function like preg_match that I could use? If so, what would my regular expression be?
There is indeed - if this is part of a larger string e.g. "The project (P.12345) is nearly done", you can use:
preg_match('/P[. ]?(\d{5})/',$str,$match);
$pnumber = $match[1];
Otherwise, if the string will always just be the P.12345 string, you can use:
preg_match('/\d{5}$/',$str,$match);
$pnumber = $match[0];
Though you may prefer the more explicit match of the top example.
Try this:
if (preg_match('#P[. ]?(\d{5})#', $project_number, $matches) {
$project_version = $matches[1];
}
Debuggex Demo
You said that project number is 4 of 5 digit length, so:
preg_match('/P[. ]?(\d{4,5})/', $tring, $m);
$project_number = $m[1];
Assuming you want to extract the XXXXX from the string and XXXXX are all integers, you can use the following.
preg_replace("/[^0-9]/", "", $string);
You can use the ^ or caret character inside square brackets to negate the expression. So in this instance it will replace anything that isn't a number with nothing.
I would use this kind of regex : /.*P[ .]?(\d+).*/
Here is a few test lines :
$string = 'This is the P123 project, with another useless number 456.';
$project = preg_replace('/.*P[ .]?(\d+).*/', '$1', $string);
var_dump($project);
$string = 'This is the P.123 project, with another useless number 456.';
$project = preg_replace('/.*P[ .]?(\d+).*/', '$1', $string);
var_dump($project);
$string = 'This is the P 123 project, with another useless number 456.';
$project = preg_replace('/.*P[ .]?(\d+).*/', '$1', $string);
var_dump($project);
use explode() function to split those
I have an alpha numeric string say for example,
abc123bcd , bdfnd567, dfd89ds.
I want to trim all the characters before the first appearance of any integer in the string.
My result should look like,
abc , bdfnd, dfd.
I am thinking of using substr. But not sure how to check for a string before first appearance of an integer.
You can easily remove the characters you don't want with preg_replace [docs] and a regular expression:
$str = preg_replace('#\d.*$#', '', $str);
\d matches a digit and .*$ matches any character until the end of the string.
Learn more about regular expressions: http://www.regular-expressions.info/.
DEMO
A possible non-Regex solution would be:
strcspn — Find length of initial segment not matching mask
substr — Return part of a string
Example:
$string = 'foo1bar';
echo substr($string, 0, strcspn($string, '1234567890')); // gives foo
$string = 'abc123bcd';
preg_replace("/[0-9]/", "", $string);
or
trim($string, '0123456789');
I believe you are looking for this?
$matches = array();
preg_match("/^[a-z]+/", "dfd89ds", $matches);
echo $matches[0]; // returns dfd
You can use a regex for this:
$string = 'abc123bcd';
preg_match('/^[a-zA-Z]*/i', $string, $matches);
var_dump($matches[0]);
will produce:
abc
To remove the +/- sign, you can simply use:
abs($number)
and get the absolute value.
e.g
$abs = abs($signed_integer);
I am trying to filter out all characters before the first / sign. I have strings like
ABC/123/...
and I am trying to filter out ABC, 123 and ... into separate strings. I have alsmost succeeded with the parsing of the first letters before the / sign except that the / sign is part of the match, which I don´t want to.
<?php
$string = "ABC/123/...";
$pattern = '/.*?\//';
preg_match($pattern, $string, $matches, PREG_OFFSET_CAPTURE);
print_r($matches);
?>
The letters before the first/ can differ both in length and characters, so a string could also look like EEEE/1111/aaaa.
If you are trying to split the string using / as the delimiter, you can use explode.
$array = explode("/", $string);
And if you are looking only for the first element, you can use array_shift.
$array = array_shift(explode("/", $string));
So this is a preg_replace associated question i guess,
I have a string with multiple repeating patterns
they all formated as:
some string :22: more text :12: etc
how do i replace the ":" around them with some different char?
You can do something like this:
$string = 'some string :22: more text :12: etc';
$regex = '/:(\d+):/';
$newString = preg_replace($regex, "#$1#", $string);
Note: You have to replace the '#' in the second parameter with the char you want (also different chars before and after the numbers).
Sbustitudes _ for : around numbers:
preg_replace('/:(\d+):/', '_$1_', 'some string :22: more text :12: etc');
EDIT: Misunderstood original question. However, is still a flexible option:
$result = str_replace(":22:", "tag", "some string :22: more text :12: etc");
$result = str_replace(":12:", "other_tag", $result);
Replace the ? character with your replacement character.