I have an alpha numeric string say for example,
abc123bcd , bdfnd567, dfd89ds.
I want to trim all the characters before the first appearance of any integer in the string.
My result should look like,
abc , bdfnd, dfd.
I am thinking of using substr. But not sure how to check for a string before first appearance of an integer.
You can easily remove the characters you don't want with preg_replace [docs] and a regular expression:
$str = preg_replace('#\d.*$#', '', $str);
\d matches a digit and .*$ matches any character until the end of the string.
Learn more about regular expressions: http://www.regular-expressions.info/.
DEMO
A possible non-Regex solution would be:
strcspn — Find length of initial segment not matching mask
substr — Return part of a string
Example:
$string = 'foo1bar';
echo substr($string, 0, strcspn($string, '1234567890')); // gives foo
$string = 'abc123bcd';
preg_replace("/[0-9]/", "", $string);
or
trim($string, '0123456789');
I believe you are looking for this?
$matches = array();
preg_match("/^[a-z]+/", "dfd89ds", $matches);
echo $matches[0]; // returns dfd
You can use a regex for this:
$string = 'abc123bcd';
preg_match('/^[a-zA-Z]*/i', $string, $matches);
var_dump($matches[0]);
will produce:
abc
To remove the +/- sign, you can simply use:
abs($number)
and get the absolute value.
e.g
$abs = abs($signed_integer);
Related
I have a strings like this.
$str = "-=!#?Bob-Green_Smith";
$str = "-_#!?1241482";
How can I explode them at the first alphanumeric match.
eg:
$str = "-=!#?Bob-Green_Smith";
becomes:
$val[0] = "-=!#?";
$val[1] = "Bob-Green_Smith";
Quick thought some times the string won't contain the initial string of characters,
so I'd need to check if the first character is alphanumeric or not.. otherwise Bob-Green_Smith would get split when he shouldn't.
Thanks
You can use preg_match.
This will match "non word characters" zero or more as first group.
Then the rest as the second.
The output will have three items, the first is the full string, so I use array_shift to remove it.
$str = "-=!#?Bob-Green_Smith";
Preg_match("/(\W*)(.*)/", $str, $val);
Array_shift($val); // remove first item
Var_dump($val);
https://3v4l.org/m2MCg
You can do this like :
$str = "-=!#?1Bob-Green_Smith";
preg_match('~[a-z0-9]~i', $str, $match, PREG_OFFSET_CAPTURE);
echo $bubString = substr($str, $match[0][1]);
I would like to know how I can cut a string in PHP starting from the last character -> to a specific character. Lets say I have following link:
www.whatever.com/url/otherurl/2535834
and I want to get 2535834
Important note: the number can have a different length, which is why I want to cut out to the / no matter how many numbers there are.
Thanks
In this special case, an url, use basename() :
echo basename('www.whatever.com/url/otherurl/2535834');
A more general solution would be preg_replace(), like this:
<----- the delimiter which separates the search string from the remaining part of the string
echo preg_replace('#.*/#', '', $url);
The pattern '#.*/#' makes usage of the default greediness of the PCRE regex engine - meaning it will match as many chars as possible and will therefore consume /abc/123/xyz/ instead of just /abc/ when matching the pattern.
Use
explode() AND end()
<?php
$str = 'www.whatever.com/url/otherurl/2535834';
$tmp = explode('/', $str);
echo end ($tmp);
?>
Working Demo
This should work for you:
(So you can get the number with or without a slash, if you need that)
<?php
$url = "www.whatever.com/url/otherurl/2535834";
preg_match("/\/(\d+)$/",$url,$matches);
print_r($matches);
?>
Output:
Array ( [0] => /2535834 [1] => 2535834 )
With strstr() and str_replace() in action
$str = 'www.whatever.com/url/otherurl/2535834';
echo str_replace("otherurl/", "", strstr($str, "otherurl/"));
strstr() finds everything (including the needle) after the needle and the needle gets replaced by "" using str_replace()
if your pattern is fixed you can always do:
$str = 'www.whatever.com/url/otherurl/2535834';
$tmp = explode('/', $str);
echo $temp[3];
Here's mine version:
$string = "www.whatever.com/url/otherurl/2535834";
echo substr($string, strrpos($string, "/") + 1, strlen($string));
I am facing problem with a regular expression.
I have a string like ('A'&'B')
Now I want to convert it to CONCAT('A'&'B') which is simple and I have done using
str_replace("(", "CONCAT(", $subject)
But I want to replace "(" to "CONCAT(" if the string doesn't have prior string "extract_json_value".
So I don't want to replace extract_json_value('A'&'B') to extract_json_valueCONCAT('A'&'B') but it will stay as it is extract_json_value('A'&'B').
You can expand your regex with a negative lookbehind:
(?<!extract_json_value)\(
Here is a regex demo!
You could use strpos to do this.
if (strpos($subject, '(') === 0) {
$subject = str_replace('(', 'CONCAT(', $subject);
}
If your string contains other text you can use preg_replace() and use a word boundary \B for this.
$subject = preg_replace('/\B\(/', 'CONCAT(', $subject);
You can use negative lookbehind in order to match a group not preceded by a string.
First, let's have a regexp matching all strings but those containing "extract_json_value":
(?<!extract_json_value).*
Now, let's use preg_replace
$string = "extract_json_value('A'&'B')";
$pattern = '/^(?<!extract_json_value)(\(.+\))$/';
$replacement = 'CONCAT\1';
echo preg_replace($pattern, $replacement, $string);
// prints out "extract_json_value('A'&'B')"
It works too with
$string = "('A'&'B')";
...
// prints out "CONCAT('A'&'B')"
However, it does not work with
$string = "hello('A'&'B')";
...
// prints out "helloCONCAT('A'&'B')"
So, continue with a preg_replace_callback:
http://php.net/manual/fr/function.preg-replace-callback.php
I have a string that contains many underscores followed by words ex: "Field_4_txtbox" I need to find the last underscore in the string and remove everything following it(including the "_"), so it would return to me "Field_4" but I need this to work for different length ending strings. So I can't just trim a fixed length.
I know I can do an If statement that checks for certain endings like
if(strstr($key,'chkbox')) {
$string= rtrim($key, '_chkbox');
}
but I would like to do this in one go with a regex pattern, how can I accomplish this?
The matching regex would be:
/_[^_]*$/
Just replace that with '':
preg_replace( '/_[^_]*$/', '', your_string );
There is no need to use an extremly costly regex, a simple strrpos() would do the job:
$string=substr($key,0,strrpos($key,"_"));
strrpos — Find the position of the last occurrence of a substring in a string
You can also just use explode():
$string = 'Field_4_txtbox';
$temp = explode('_', strrev($string), 2);
$string = strrev($temp[1]);
echo $string;
As of PHP 5.4+
$string = 'Field_4_txtbox';
$string = strrev(explode('_', strrev($string), 2)[1]);
echo $string;
How can I get a portion of the string from the beginning until the first non-alphabetic character?
Example strings:
Hello World
Hello&World
Hello5World
I'd like to get the "Hello" part
You need to use the preg_split feature.
$str = 'Hello&World';
$words = preg_split('/[^\w]/',$str);
echo $words[0];
You can access Hello by $words[0], and World by $words[1]
You can use preg_match() for this:
if (preg_match('/^([\w]+)/i', $string, $match)) {
echo "The matched word is {$match[1]}.";
}
Change [\w]+ to [a-z]+ if you do not want to match the 5 or any numeric characters.
Use preg_split. Split string by a regular expression
If you only want the first part, use preg_match:
preg_match('/^[a-z]+/i', $str, $matches);
echo $matches[0];
Here's a demo.
Use preg_split to get first part of alpha.
$array = preg_split('/[^[:alpha:]]+/', 'Hello5World');
echo $array[0];