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How to get the previous and next month?
(8 answers)
Closed 8 years ago.
<?php
echo "\n";
echo $end_date = date('Y-m-d', strtotime('+1 month'));
echo "\n";
$today = date("Y-m-d"); // 2012-01-30
echo $next_month = date("Y-m-d", strtotime("$today +1 month"));
echo "\n";
$end_date = mktime(date("H"), date("i"), date("s"), date("n") + 1, date("j"), date("Y"));
echo "\n" . date('Y-m-d',$end_date);
http://codepad.org/bHiNFIBR
How can I get the correct date +1 months
I tried these options.
all returned 1 May but I need April 30
Try something like that..
if( date('d') == 31 || (date('m') == 1 && date('d') > 28)){
$date = strtotime('last day of next month');
} else {
$date = strtotime('+1 months');
}
echo date('Y-m-d', $date);
But just note that when you are 31st March as +1month its correct to target 1st of May not 30th April :)
I'd suggest this:
$next_month = date('Y-m-d', strtotime("+1 months", strtotime("NOW")));
EDIT
function addMonth($date) {
$date = new DateTime($date);
$day = $date->format('j');
$date->modify("+1 month");
$next_month_day = $date->format('j');
if ($day != $next_month_day)
$date->modify('last day of last month');
return $date;
}
$next_month = addMonth(time());
echo $next_month->format("Y-m-d");
hope this helps :-)
Try this solution:
echo "\n";
$today = date("Y-m-d");
$next_month = date("Y-m-d", strtotime("$today +1 month"));
echo "\n";
echo $next_month_last_day = date("Y-m-d",strtotime('-1 second',strtotime($next_month)));
Related
I have this code
<?php
$date =date(Y-m-d);
$day = 5;
$newdate= $date+$day
echo "today is:"$date;
echo "<br> and after 5 days is :"$newdate;
?>
I want the result is
today is :2016-11-2
and after 5 days is : 2016-11-7
Try this
$date = new DateTime(); // Creates new DatimeTime for today
$newdate = $date->modify( '+ 5 days' ); // Adds 5 days
echo $newdate->format( 'Y-m-d' ); // Echo and format the newdate to the wanted format
It should help you:
echo date('Y-m-d', strtotime($date. ' + 5 days'));
So it will be like follows:
<?php
$date = date('Y-m-d');
$newdate = date('Y-m-d', strtotime($date.' + 5 days'));
echo "today is: $date";
echo "<br> and after 5 days is: $newdate";
?>
You can use strtotime() function to add days to current date. Please see the below :
<?php
$date =date("Y-m-d");
$day = 5;
$newdate=date('Y-m-d', strtotime("+$day days"));
echo "today is:".$date;
echo "<br> and after 5 days is :".$newdate;
?>
it may help you
$date = "Mar 03, 2016";
$date = strtotime($date);
$date = strtotime("+7 day", $date);
echo date('M d, Y', $date);
I'm trying to subtract 1 month from a date.
$today = date('m-Y');
This gives: 08-2016
How can I subtract a month to get 07-2016?
<?php
echo $newdate = date("m-Y", strtotime("-1 months"));
output
07-2016
Warning! The above-mentioned examples won't work if call them at the end of a month.
<?php
$now = mktime(0, 0, 0, 10, 31, 2017);
echo date("m-Y", $now)."\n";
echo date("m-Y", strtotime("-1 months", $now))."\n";
will output:
10-2017
10-2017
The following example will produce the same result:
$date = new DateTime('2017-10-31 00:00:00');
echo $date->format('m-Y')."\n";
$date->modify('-1 month');
echo $date->format('m-Y')."\n";
Plenty of ways how to solve the issue can be found in another thread: PHP DateTime::modify adding and subtracting months
Try this,
$today = date('m-Y');
$newdate = date('m-Y', strtotime('-1 months', strtotime($today)));
echo $newdate;
Depending on your PHP version you can use DateTime object (introduced in PHP 5.2 if I remember correctly):
<?php
$today = new DateTime(); // This will create a DateTime object with the current date
$today->modify('-1 month');
You can pass another date to the constructor, it does not have to be the current date. More information: http://php.net/manual/en/datetime.modify.php
I used this to prevent the "last days of month"-error. I just use a second strtotime() to set the date to the first day of the month:
<?php
echo $newdate = date("m-Y", strtotime("-1 months", strtotime(date("Y-m")."-01")));
if(date("d") > 28){
$date = date("Y-m", strtotime("-".$loop." months -2 Day"));
} else {
$date = date("Y-m", strtotime("-".$loop." months"));
}
$lastMonth = date('Y-m', strtotime('-1 MONTH'));
First change the date format m-Y to Y-m
$date = $_POST('date'); // Post month
or
$date = date('m-Y'); // currrent month
$date_txt = date_create_from_format('m-Y', $date);
$change_format = date_format($date_txt, 'Y-m');
This code minus 1 month to the given date
$final_date = new DateTime($change_format);
$final_date->modify('-1 month');
$output = $final_date->format('m-Y');
Try this,
$effectiveDate = date('2018-01'); <br>
echo 'Date'.$effectiveDate;<br>
$effectiveDate = date('m-y', strtotime($effectiveDate.'+-1 months'));<br>
echo 'Date'.$effectiveDate;
$currentMonth = date('m', time());
$currentDay = date('d',time());
$currentYear = date('Y',time());
$lastMonth = $currentMonth -1;
$one_month_ago=mkdate(0,0,0,$one_month_ago,$currentDay,$currentYear);
This could be rewritten more elegantly, but it works for me
I realize this is an old post, but I've been solving the same issue, and here is what I came up with to account for all the variability. This function is just trying to get relative dates, so same day of prior month, or last day of month if you are on the last day, regardless of exactly how many days a month has. So goal is given '2010-03-31' and subtract a month, we should output '2010-02-28'.
private function subtractRelativeMonth(DateTime $incomingDate): DateTime
{
$year = $incomingDate->format('Y');
$month = $incomingDate->format('m');
$day = $incomingDate->format('d');
$daysInOldMonth = cal_days_in_month(CAL_GREGORIAN, $month, $year);
if ($month == 1) { //It's January, so we have to go back to December of prior year
$month = 12;
$year--;
} else {
$month--;
}
$daysInNewMonth = cal_days_in_month(CAL_GREGORIAN, $month, $year);
if ($day > $daysInNewMonth && $month == 2) { //New month is Feb
$day = $daysInNewMonth;
}
if ($day > 29 && $daysInOldMonth > $daysInNewMonth) {
$day = $daysInNewMonth;
}
$adjustedDate = new \DateTime($year . '-' . $month . '-' . $day);
return $adjustedDate;
}
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Sorry for my bad english.
As said in the title , i would to get array of dates in same week(between monday to friday) as a $date
exemple : if $date = 2015-05-05 => i would to have
array that contain : 2015-05-04 , 2015-05-05 ,2015-05-06 2015-05-07, 2015-05-08
Just change the date strings of "2015-05-05" to your desired date.
$day_of_week = date('N', strtotime('2015-05-05'));
$given_date = strtotime("05-05-2015");
$first_of_week = date('Y-m-d', strtotime("- {$day_of_week} day", $given_date));
$first_of_week = strtotime($first_of_week);
for($i=0 ;$i<=7; $i++) {
$week_array[] = date('Y-m-d', strtotime("+ {$i} day", $first_of_week));
}
print_r($week_array);
Date and strtotime are your friends on this:
$myDate = "2015-05-05";
echo date("Y-m-d", strtotime('monday this week', strtotime($myDate)))."\n";
echo date("Y-m-d", strtotime('tuesday this week', strtotime($myDate)))."\n";
echo date("Y-m-d", strtotime('wednesday this week', strtotime($myDate)))."\n";
echo date("Y-m-d", strtotime('thursday this week', strtotime($myDate)))."\n";
echo date("Y-m-d", strtotime('friday this week', strtotime($myDate)))."\n";
Output:
2015-04-05
2015-05-05
2015-06-05
2015-07-05
2015-08-05
Demo:
http://ideone.com/hEem8k
Yet another solution
$my_date = "2012-10-18";
$week = date("W", strtotime($my_date)); // get week
$y = date("Y", strtotime($my_date)); // get year
echo $first_date = date('d-m-Y',strtotime($y."W".$week)); //first date
echo $second_date = date("d-m-Y",strtotime("+1 day", strtotime($first_date)));
you can loop or add +1 to previous date and so on..
This function will return all dates of current week starting from monday to sunday
See Working Demo
function GetCurrentWeekDates()
{
if (date('D') != 'Mon') {
$startdate = date('Y-m-d', strtotime('last Monday'));
} else {
$startdate = date('Y-m-d');
}
//always next saturday
if (date('D') != 'Sat') {
$enddate = date('Y-m-d', strtotime('next Saturday'));
} else {
$enddate = date('Y-m-d');
}
$DateArray = array();
$timestamp = strtotime($startdate);
while ($startdate <= $enddate) {
$startdate = date('Y-m-d', $timestamp);
$DateArray[] = $startdate;
$timestamp = strtotime('+1 days', strtotime($startdate));
}
return $DateArray;
}
print_r(GetCurrentWeekDates());
I wish to rewrite a mysql query which use month() and year() functions to display all the posts from a certain month which goes to my function as a 'Y-m-d' parameter format, but I don't know how can I get the last day of the given month date.
$query_date = '2010-02-04';
list($y, $m, $d) = explode('-', $query_date);
$first_day = $y . '-' . $m . '-01';
You might want to look at the strtotime and date functions.
<?php
$query_date = '2010-02-04';
// First day of the month.
echo date('Y-m-01', strtotime($query_date));
// Last day of the month.
echo date('Y-m-t', strtotime($query_date));
I know this question has a good answer with 't', but thought I would add another solution.
$first = date("Y-m-d", strtotime("first day of this month"));
$last = date("Y-m-d", strtotime("last day of this month"));
Try this , if you are using PHP 5.3+, in php
$query_date = '2010-02-04';
$date = new DateTime($query_date);
//First day of month
$date->modify('first day of this month');
$firstday= $date->format('Y-m-d');
//Last day of month
$date->modify('last day of this month');
$lastday= $date->format('Y-m-d');
For finding next month last date, modify as follows,
$date->modify('last day of 1 month');
echo $date->format('Y-m-d');
and so on..
cal_days_in_month() should give you the total number of days in the month, and therefore, the last one.
// First date of the current date
echo date('Y-m-d', mktime(0, 0, 0, date('m'), 1, date('Y')));
echo '<br />';
// Last date of the current date
echo date('Y-m-d', mktime(0, 0, 0, date('m')+1, 0, date('Y')));
$month = 10; // october
$firstday = date('01-' . $month . '-Y');
$lastday = date(date('t', strtotime($firstday)) .'-' . $month . '-Y');
Basically:
$lastDate = date("Y-m-t", strtotime($query_d));
Date t parameter return days number in current month.
Print only current month week:
function my_week_range($date) {
$ts = strtotime($date);
$start = (date('w', $ts) == 0) ? $ts : strtotime('last sunday', $ts);
echo $currentWeek = ceil((date("d",strtotime($date)) - date("w",strtotime($date)) - 1) / 7) + 1;
$start_date = date('Y-m-d', $start);$end_date=date('Y-m-d', strtotime('next saturday', $start));
if($currentWeek==1)
{$start_date = date('Y-m-01', strtotime($date));}
else if($currentWeek==5)
{$end_date = date('Y-m-t', strtotime($date));}
else
{}
return array($start_date, $end_date );
}
$date_range=list($start_date, $end_date) = my_week_range($new_fdate);
## Get Current Month's First Date And Last Date
echo "Today Date: ". $query_date = date('d-m-Y');
echo "<br> First day of the month: ". date('01-m-Y', strtotime($query_date));
echo "<br> Last day of the month: ". date('t-m-Y', strtotime($query_date));
In case of name of month this code will work
echo $first = date("Y-m-01", strtotime("January"));
echo $last = date("Y-m-t", strtotime("January"));
i have one date.
example : $date='2011-21-12';
data format :yyyy-dd-mm;
IF date is Saturday or Sunday.
if Saturday add 2 day to the given date.
if Sunday add 1 day to the given date.
?
In a single line of code:
if (date('N', $date) > 5) $nextweekday = date('Y-m-d', strtotime("next Monday", $date));
If the day of week has a value greater than 5 (Monday = 1, Sat is 6 and Sun is 7) set $nextweekday to the YYYY-MM-DD value of the following Monday.
Editing to add, because the date format may not be accepted, you would need to reformat the date first. Add the following lines above my code:
$pieces = explode('-', $date);
$date = $pieces[0].'-'.$pieces[2].'-'.$pieces[1];
This will put the date in Y-m-d order so that strtotime can recognize it.
You can use the date and strtotime functions for this, like so:
$date = strtotime('2011-12-21');
$is_saturday = date('l', $date) == 'Saturday';
$is_sunday = date('l', $date) == 'Sunday';
if($is_saturday) {
$date = strtotime('+2 days', $date);
} else if($is_sunday) {
$date = strtotime('+1 days', $date);
}
echo 'Date is now ' . date('Y-m-d H:i:s', $date);
What about this:
$date='2011-21-12';
if (date("D", strtotime($date)) == "Sat"){
$new_date = date("Y-m-d", strtotime("+ 2 days",$date);
}
else if (date("D", strtotime($date)) == "Sun"){
$new_date = date("Y-m-d", strtotime("+ 1 day",$date);
}
The DateTime object can be really helpful for anything like this.
In this case.
$date = DateTime::createFromFormat('Y-d-m', '2011-21-12');
if ($date->format('l') == 'Sunday')
$date->modify('+1 day');
elseif ($date->format('l') == 'Saturday')
$date->modify('+2 days');
If you want to get the date back in that format.
$date = $date->format('Y-d-m');
$date = '2011-21-12'
$stamp = strtotime($date);
$day = date("l", $stamp);
if ($day == "Saturday"){
$stamp = $stamp + (2*+86400);
}elseif($day == "Sunday"){
$stamp = $stamp + 86400;
}
echo date("Y-d-m", $stamp);
The only reason i can think why this wouldnt work is strtotime not recognising that data format...
For sundays date('w',$date) will return 0, so the simplest test code is:
if(!date('w',strtotime($date)) { ... } //sunday
I just subtracted the difference from 8 an added it to the days.
if(date('N', strtotime($date)) >= 6) {
$n = (8 - date("N",strtotime($date)));
$date = date("Y-m-d", strtotime("+".$n." days");
}