how to get the first and last days of a given month - php

I wish to rewrite a mysql query which use month() and year() functions to display all the posts from a certain month which goes to my function as a 'Y-m-d' parameter format, but I don't know how can I get the last day of the given month date.
$query_date = '2010-02-04';
list($y, $m, $d) = explode('-', $query_date);
$first_day = $y . '-' . $m . '-01';

You might want to look at the strtotime and date functions.
<?php
$query_date = '2010-02-04';
// First day of the month.
echo date('Y-m-01', strtotime($query_date));
// Last day of the month.
echo date('Y-m-t', strtotime($query_date));

I know this question has a good answer with 't', but thought I would add another solution.
$first = date("Y-m-d", strtotime("first day of this month"));
$last = date("Y-m-d", strtotime("last day of this month"));

Try this , if you are using PHP 5.3+, in php
$query_date = '2010-02-04';
$date = new DateTime($query_date);
//First day of month
$date->modify('first day of this month');
$firstday= $date->format('Y-m-d');
//Last day of month
$date->modify('last day of this month');
$lastday= $date->format('Y-m-d');
For finding next month last date, modify as follows,
$date->modify('last day of 1 month');
echo $date->format('Y-m-d');
and so on..

cal_days_in_month() should give you the total number of days in the month, and therefore, the last one.

// First date of the current date
echo date('Y-m-d', mktime(0, 0, 0, date('m'), 1, date('Y')));
echo '<br />';
// Last date of the current date
echo date('Y-m-d', mktime(0, 0, 0, date('m')+1, 0, date('Y')));

$month = 10; // october
$firstday = date('01-' . $month . '-Y');
$lastday = date(date('t', strtotime($firstday)) .'-' . $month . '-Y');

Basically:
$lastDate = date("Y-m-t", strtotime($query_d));
Date t parameter return days number in current month.

Print only current month week:
function my_week_range($date) {
$ts = strtotime($date);
$start = (date('w', $ts) == 0) ? $ts : strtotime('last sunday', $ts);
echo $currentWeek = ceil((date("d",strtotime($date)) - date("w",strtotime($date)) - 1) / 7) + 1;
$start_date = date('Y-m-d', $start);$end_date=date('Y-m-d', strtotime('next saturday', $start));
if($currentWeek==1)
{$start_date = date('Y-m-01', strtotime($date));}
else if($currentWeek==5)
{$end_date = date('Y-m-t', strtotime($date));}
else
{}
return array($start_date, $end_date );
}
$date_range=list($start_date, $end_date) = my_week_range($new_fdate);

## Get Current Month's First Date And Last Date
echo "Today Date: ". $query_date = date('d-m-Y');
echo "<br> First day of the month: ". date('01-m-Y', strtotime($query_date));
echo "<br> Last day of the month: ". date('t-m-Y', strtotime($query_date));

In case of name of month this code will work
echo $first = date("Y-m-01", strtotime("January"));
echo $last = date("Y-m-t", strtotime("January"));

Related

PHP subtract 1 month from date formatted with date ('m-Y')

I'm trying to subtract 1 month from a date.
$today = date('m-Y');
This gives: 08-2016
How can I subtract a month to get 07-2016?
<?php
echo $newdate = date("m-Y", strtotime("-1 months"));
output
07-2016
Warning! The above-mentioned examples won't work if call them at the end of a month.
<?php
$now = mktime(0, 0, 0, 10, 31, 2017);
echo date("m-Y", $now)."\n";
echo date("m-Y", strtotime("-1 months", $now))."\n";
will output:
10-2017
10-2017
The following example will produce the same result:
$date = new DateTime('2017-10-31 00:00:00');
echo $date->format('m-Y')."\n";
$date->modify('-1 month');
echo $date->format('m-Y')."\n";
Plenty of ways how to solve the issue can be found in another thread: PHP DateTime::modify adding and subtracting months
Try this,
$today = date('m-Y');
$newdate = date('m-Y', strtotime('-1 months', strtotime($today)));
echo $newdate;
Depending on your PHP version you can use DateTime object (introduced in PHP 5.2 if I remember correctly):
<?php
$today = new DateTime(); // This will create a DateTime object with the current date
$today->modify('-1 month');
You can pass another date to the constructor, it does not have to be the current date. More information: http://php.net/manual/en/datetime.modify.php
I used this to prevent the "last days of month"-error. I just use a second strtotime() to set the date to the first day of the month:
<?php
echo $newdate = date("m-Y", strtotime("-1 months", strtotime(date("Y-m")."-01")));
if(date("d") > 28){
$date = date("Y-m", strtotime("-".$loop." months -2 Day"));
} else {
$date = date("Y-m", strtotime("-".$loop." months"));
}
$lastMonth = date('Y-m', strtotime('-1 MONTH'));
First change the date format m-Y to Y-m
$date = $_POST('date'); // Post month
or
$date = date('m-Y'); // currrent month
$date_txt = date_create_from_format('m-Y', $date);
$change_format = date_format($date_txt, 'Y-m');
This code minus 1 month to the given date
$final_date = new DateTime($change_format);
$final_date->modify('-1 month');
$output = $final_date->format('m-Y');
Try this,
$effectiveDate = date('2018-01'); <br>
echo 'Date'.$effectiveDate;<br>
$effectiveDate = date('m-y', strtotime($effectiveDate.'+-1 months'));<br>
echo 'Date'.$effectiveDate;
$currentMonth = date('m', time());
$currentDay = date('d',time());
$currentYear = date('Y',time());
$lastMonth = $currentMonth -1;
$one_month_ago=mkdate(0,0,0,$one_month_ago,$currentDay,$currentYear);
This could be rewritten more elegantly, but it works for me
I realize this is an old post, but I've been solving the same issue, and here is what I came up with to account for all the variability. This function is just trying to get relative dates, so same day of prior month, or last day of month if you are on the last day, regardless of exactly how many days a month has. So goal is given '2010-03-31' and subtract a month, we should output '2010-02-28'.
private function subtractRelativeMonth(DateTime $incomingDate): DateTime
{
$year = $incomingDate->format('Y');
$month = $incomingDate->format('m');
$day = $incomingDate->format('d');
$daysInOldMonth = cal_days_in_month(CAL_GREGORIAN, $month, $year);
if ($month == 1) { //It's January, so we have to go back to December of prior year
$month = 12;
$year--;
} else {
$month--;
}
$daysInNewMonth = cal_days_in_month(CAL_GREGORIAN, $month, $year);
if ($day > $daysInNewMonth && $month == 2) { //New month is Feb
$day = $daysInNewMonth;
}
if ($day > 29 && $daysInOldMonth > $daysInNewMonth) {
$day = $daysInNewMonth;
}
$adjustedDate = new \DateTime($year . '-' . $month . '-' . $day);
return $adjustedDate;
}

Getting the next 10th of a month from now?

I am trying to find the next 10th of a month starting with today. So if today is the 27th of May, the next 10th is the 10th of June. If today is the 1st of August, the next 10th will be the 10th of August for example.
I know I can find the first day of the next month using
$firstDayNextMonth = date('Y-m-d', strtotime('first day of next month'));
Can I use that format for my case as well? If not, how could I achieve my goal?
Thanks a lot for helping! :)
strtotime is not able to do this in one call, but you could do something like:
<?php
$current_day = (int)date('j');
if ($current_day < 10) {
$firstDayNextMonth = date('Y-m-d', strtotime('+9 days', strtotime('first day of this month')));
} else {
$firstDayNextMonth = date('Y-m-d', strtotime('+9 days', strtotime('first day of next month')));
}
echo $firstDayNextMonth;
?>
Or simply just
$firstDayNextMonth = date('Y-m-d', strtotime('+9 days', strtotime('first day of ' . ((int)date('j') < 10 ? 'this' : 'next' ) . ' month')));
You can use the DateTime class:
$Date = new DateTime('first day of '.(date('j') < 10 ? 'this' : 'next').' month');
$Date->add(DateInterval::createFromDateString('9 days'));
var_dump($Date->format('Y-m-d'));
This will result in '2015-07-10' if it's '2015-06-10' today. Just use <= (or < 11) if it should return '2015-06-10' in that case.
Not sure if strtotime is able to do that.
A little trick can be:
$firstDayNextMonth = date('Y-m', strtotime('next month')) . '-10';
This might help a bit?
By using mktime you can simply define the day you want, even match more day sin a row more easely.
// set our day number
$daynum = 10;
$curDay = date('d');
// get current month
$curMonth = date('n');
// get current year
$curYear = date('Y');
$firstDayNextMonth = 'MissingNo';
if($curDay < $dayNum) {
$firstDayNextMonth = mktime(0, 0, 0, $curMonth, $daynum);
}
else {
// darnit, new year. but will we party?
if ($curMonth == 12) {
// use mktime to get a timestamp. We can become very precise with this...
$firstDayNextMonth = mktime(0, 0, 0, 0, $daynum, $curYear+1);
}
else {
$firstDayNextMonth = mktime(0, 0, 0, $curMonth+1, $daynum);
// let's test if we can have a little party or not.
}
}
echo date('D',$firstDayNextMonth) === date('D') ? 'matches! let\'s party!' : 'no match :( hide the beer';
$firstDayNextMonth = date('Y-m-d', strtotime('first day of next month'));
echo $firstDayNextMonth ."</br>";
$firstDayNextMonth = date('Y-m', strtotime('next month'));
echo $firstDayNextMonth."-10";
Is that what you want??
Very simple:
date('Y-m-d', strtotime('+9 days', strtotime('first day of this month', strtotime(sprintf('+%d days', (int) date('t') - 10)))));

how can I get last week' date range in php?

how can I get last week' date range in php ?
see my codes bellow:
<?php
function get_last_week_dates(){
// how can i get the date range last week ?
// ex: today is 2014-2-8
// the week date range of last week should be '2014-1-26 ~ 2014-2-1'
}
?>
You can use strtotime()
$previous_week = strtotime("-1 week +1 day");
$start_week = strtotime("last sunday midnight",$previous_week);
$end_week = strtotime("next saturday",$start_week);
$start_week = date("Y-m-d",$start_week);
$end_week = date("Y-m-d",$end_week);
echo $start_week.' '.$end_week ;
UPDATE
Changed the code to handle sunday. If the current day is sunday then - 1 week will be previous sunday and again getting previous sunday for that will go the one week back.
$previous_week = strtotime("-1 week +1 day");
In addition if we need to find the current week and next week date
range we can do as
Current week -
$d = strtotime("today");
$start_week = strtotime("last sunday midnight",$d);
$end_week = strtotime("next saturday",$d);
$start = date("Y-m-d",$start_week);
$end = date("Y-m-d",$end_week);
Next Week -
$d = strtotime("+1 week -1 day");
$start_week = strtotime("last sunday midnight",$d);
$end_week = strtotime("next saturday",$d);
$start = date("Y-m-d",$start_week);
$end = date("Y-m-d",$end_week);
Simply use
date("m/d/Y", strtotime("last week monday"));
date("m/d/Y", strtotime("last week sunday"));
It will give the date of Last week's Monday and Sunday.
you need you use strtotime function for this
<center>
<?php
function get_last_week_dates()
{
// how can i get the date range last week ?
// ex: today is 2014-2-8
// the week date range of last week should be '2014-1-26 ~ 2014-2-1'
$startdate = "last monday";
if (date('N') !== '1')
{
// it's not Monday today
$startdate .= " last week";
}
echo "<br />";
$day = strtotime($startdate);
echo date('r', $day);
echo "<br />";
$sunday = strtotime('next monday', $day) - 1;
echo date('r', $sunday);
}
get_last_week_dates();
?>
</center>
Well just for the fun of trying to solve this:
date_default_timezone_set('UTC');
$firstDayOfLastWeek = mktime(0,0,0,date("m"),date("d")-date("w")-7);
$lastDayOfLastWeek = mktime(0,0,0,date("m"),date("d")-date("w")-1);
echo("Last week began on: ".date("d.m.Y",$firstDayOfLastWeek));
echo("<br>");
echo("Last week ended on: ".date("d.m.Y",$lastDayOfLastWeek));
This should do the trick
$startWeek = date('Y-m-d',strtotime("Sunday Last Week"));
$endWeek = date('Y-m-d',strtotime("Sunday This Week"));
this would not work if ran on a Monday. It would get last Sunday (the day before) to the next Sunday. So using Abhik Chakraborty's method with the above:
$startTime = strtotime("last sunday midnight",$previous_week);
$endTime = strtotime("next sunday midnight",$startTime);
$startDate = date('Y-m-d 00:00:00',$startTime);
$endDate = date('Y-m-d 23:59:59',$endTime);
This will now give
start = 2014-08-10 00:00:00
endDate = 2014-08-17 23:59:59
I know this is old but here's a much more succinct way of doing it:
$startDate = date("m/d/y", strtotime(date("w") ? "2 sundays ago" : "last sunday"));
$endDate = date("m/d/y", strtotime("last saturday"));
echo $startDate . " - " . $endDate
This one will produce the proper result and handles the Monday issue
<?php
$monday = strtotime("last monday");
$monday = date('W', $monday)==date('W') ? $monday-7*86400 : $monday;
$sunday = strtotime(date("Y-m-d",$monday)." +6 days");
$this_week_sd = date("Y-m-d",$monday);
$this_week_ed = date("Y-m-d",$sunday);
echo "Last week range from $this_week_sd to $this_week_ed ";
?>
Most of those other solutions offered were off by one day.
If you want Sunday to Saturday for last week, this is the way to do it.
$start = date("Y-m-d",strtotime("last sunday",strtotime("-1 week")));
$end = date("Y-m-d",strtotime("saturday",strtotime("-1 week")));
echo $start. " to ".$end;
Carbon
$startOfTheWeek = Carbon::now()->subWeek(1)->startOfWeek();
$endOfTheWeek = Carbon::now()->subWeek(1)->endOfWeek();
From a specific date
$startOfTheWeek = Carbon::parse('2020-03-02')->subWeek(1)->startOfWeek();
$endOfTheWeek = Carbon::parse('2020-03-02')->subWeek(1)->endOfWeek();
Considering the week starts at Monday and ends at Sunday.
You can do this way.
First get the current timestamp and subtract the no.of days you want.
$curTime = time();
echo date("Y-m-d",$curTime);
echo "<br />";
echo date("Y-m-d",($curTime-(60*60*24*7)));
$lastWeekStartTime = strtotime("last sunday",strtotime("-1 week"));
$lastWeekEndTime = strtotime("this sunday",strtotime("-1 week"));
$lastWeekStart = date("Y-m-d",$lastWeekStartTime);
$lastWeekEnd = date("Y-m-d",$lastWeekEndTime);
In order to find the last week start date and end date you can follow up this code for doing it so.
It works on all intervals to find the date interval.
$Current = Date('N');
$DaysToSunday = 7 - $Current;
$DaysFromMonday = $Current - 1;
$Sunday = Date('d/m/y', strtotime("+ {$DaysToSunday} Days"));
$Monday = Date('d/m/y', strtotime("- {$DaysFromMonday} Days"));
If so you need to change it with the datatime() you can perform this function.
$date = new DateTime();
$weekday = $date->format('w');
$diff = 7 + ($weekday == 0 ? 6 : $weekday - 1); // Monday=0, Sunday=6
$date->modify("-$diff day");
echo $date->format('Y-m-d') . ' - ';
$date->modify('+6 day');
echo $date->format('Y-m-d');
Using Functions:
If you want to find the last week range with the help of the functions you can preform like this.
Function:
// returns last week's range
function last_week_range($date) {
$ts = strtotime("$date - 7 days");
$start = (date('w', $ts) == 0) ? $ts : strtotime('last sunday', $ts);
return array(
date('Y-m-d', $start),
date('Y-m-d', strtotime('next saturday', $start))
);
}
Usage:
$today=date();
print_r(last_week_range($today));
All the above functions that has been given will return the last week range irrespective of the start day of the week..

Get first day of week in PHP?

Given a date MM-dd-yyyy format, can someone help me get the first day of the week?
Here is what I am using...
$day = date('w');
$week_start = date('m-d-Y', strtotime('-'.$day.' days'));
$week_end = date('m-d-Y', strtotime('+'.(6-$day).' days'));
$day contains a number from 0 to 6 representing the day of the week (Sunday = 0, Monday = 1, etc.).
$week_start contains the date for Sunday of the current week as mm-dd-yyyy.
$week_end contains the date for the Saturday of the current week as mm-dd-yyyy.
Very simple to use strtotime function:
echo date("Y-m-d", strtotime('monday this week')), "\n";
echo date("Y-m-d", strtotime('sunday this week')), "\n";
It differs a bit across PHP versions:
Output for 5.3.0 - 5.6.6, php7#20140507 - 20150301, hhvm-3.3.1 - 3.5.1
2015-03-16
2015-03-22
Output for 4.3.5 - 5.2.17
2015-03-23
2015-03-22
Output for 4.3.0 - 4.3.4
2015-03-30
2015-03-29
Comparing at Edge-Cases
Relative descriptions like this week have their own context. The following shows the output for this week monday and sunday when it's a monday or a sunday:
$date = '2015-03-16'; // monday
echo date("Y-m-d", strtotime('monday this week', strtotime($date))), "\n";
echo date("Y-m-d", strtotime('sunday this week', strtotime($date))), "\n";
$date = '2015-03-22'; // sunday
echo date("Y-m-d", strtotime('monday this week', strtotime($date))), "\n";
echo date("Y-m-d", strtotime('sunday this week', strtotime($date))), "\n";
Againt it differs a bit across PHP versions:
Output for 5.3.0 - 5.6.6, php7#20140507 - 20150301, hhvm-3.3.1 - 3.5.1
2015-03-16
2015-03-22
2015-03-23
2015-03-29
Output for 4.3.5 - 5.0.5, 5.2.0 - 5.2.17
2015-03-16
2015-03-22
2015-03-23
2015-03-22
Output for 5.1.0 - 5.1.6
2015-03-23
2015-03-22
2015-03-23
2015-03-29
Output for 4.3.0 - 4.3.4
2015-03-23
2015-03-29
2015-03-30
2015-03-29
strtotime('this week', time());
Replace time(). Next sunday/last monday methods won't work when the current day is sunday/monday.
Keep it simple :
<?php
$dateTime = new \DateTime('2020-04-01');
$monday = clone $dateTime->modify(('Sunday' == $dateTime->format('l')) ? 'Monday last week' : 'Monday this week');
$sunday = clone $dateTime->modify('Sunday this week');
?>
Source : PHP manual
NB: as some user commented the $dateTime value will be modified.
$givenday = date("w", mktime(0, 0, 0, MM, dd, yyyy));
This gives you the day of the week of the given date itself where 0 = Sunday and 6 = Saturday. From there you can simply calculate backwards to the day you want.
This question needs a good DateTime answer:-
function firstDayOfWeek($date)
{
$day = DateTime::createFromFormat('m-d-Y', $date);
$day->setISODate((int)$day->format('o'), (int)$day->format('W'), 1);
return $day->format('m-d-Y');
}
var_dump(firstDayOfWeek('06-13-2013'));
Output:-
string '06-10-2013' (length=10)
This will deal with year boundaries and leap years.
EDIT: the below link is no longer running on the version of PHP stated. It is running on PHP 5.6 which improves the reliability of strtotime, but isn't perfect! The results in the table are live results from PHP 5.6.
For what it's worth, here is a breakdown of the wonky behavior of strtotime when determining a consistent frame of reference:
http://gamereplays.org/reference/strtotime.php
Basically only these strings will reliably give you the same date, no matter what day of the week you're currently on when you call them:
strtotime("next monday");
strtotime("this sunday");
strtotime("last sunday");
Assuming Monday as the first day of the week, this works:
echo date("M-d-y", strtotime('last monday', strtotime('next week', time())));
The following code should work with any custom date, just uses the desired date format.
$custom_date = strtotime( date('d-m-Y', strtotime('31-07-2012')) );
$week_start = date('d-m-Y', strtotime('this week last monday', $custom_date));
$week_end = date('d-m-Y', strtotime('this week next sunday', $custom_date));
echo '<br>Start: '. $week_start;
echo '<br>End: '. $week_end;
I tested the code with PHP 5.2.17 Results:
Start: 30-07-2012
End: 05-08-2012
How about this?
$first_day_of_week = date('m-d-Y', strtotime('Last Monday', time()));
$last_day_of_week = date('m-d-Y', strtotime('Next Sunday', time()));
This is what I am using to get the first and last day of the week from any date.
In this case, monday is the first day of the week...
$date = date('Y-m-d') // you can put any date you want
$nbDay = date('N', strtotime($date));
$monday = new DateTime($date);
$sunday = new DateTime($date);
$monday->modify('-'.($nbDay-1).' days');
$sunday->modify('+'.(7-$nbDay).' days');
Here I am considering Sunday as first & Saturday as last day of the week.
$m = strtotime('06-08-2012');
$today = date('l', $m);
$custom_date = strtotime( date('d-m-Y', $m) );
if ($today == 'Sunday') {
$week_start = date("d-m-Y", $m);
} else {
$week_start = date('d-m-Y', strtotime('this week last sunday', $custom_date));
}
if ($today == 'Saturday') {
$week_end = date("d-m-Y", $m);
} else {
$week_end = date('d-m-Y', strtotime('this week next saturday', $custom_date));
}
echo '<br>Start: '. $week_start;
echo '<br>End: '. $week_end;
Output :
Start: 05-08-2012
End: 11-08-2012
How about this?
$day_of_week = date('N', strtotime($string_date));
$week_first_day = date('Y-m-d', strtotime($string_date . " - " . ($day_of_week - 1) . " days"));
$week_last_day = date('Y-m-d', strtotime($string_date . " + " . (7 - $day_of_week) . " days"));
Just use date($format, strtotime($date,' LAST SUNDAY + 1 DAY'));
Try this:
function week_start_date($wk_num, $yr, $first = 1, $format = 'F d, Y')
{
$wk_ts = strtotime('+' . $wk_num . ' weeks', strtotime($yr . '0101'));
$mon_ts = strtotime('-' . date('w', $wk_ts) + $first . ' days', $wk_ts);
return date($format, $mon_ts);
}
$sStartDate = week_start_date($week_number, $year);
$sEndDate = date('F d, Y', strtotime('+6 days', strtotime($sStartDate)));
(from this forum thread)
This is the shortest and most readable solution I found:
<?php
$weekstart = strtotime('monday this week');
$weekstop = strtotime('sunday this week 23:59:59');
//echo date('d.m.Y H:i:s', $weekstart) .' - '. date('d.m.Y H:i:s', $weekstop);
?>
strtotime is faster than new DateTime()->getTimestamp().
$monday = date('d-m-Y',strtotime('last monday',strtotime('next monday',strtotime($date))));
You have to get next monday first then get the 'last monday' of next monday. So if the given date is monday it will return the same date not last week monday.
$string_date = '2019-07-31';
echo $day_of_week = date('N', strtotime($string_date));
echo $week_first_day = date('Y-m-d', strtotime($string_date . " - " . ($day_of_week - 1) . " days"));
echo $week_last_day = date('Y-m-d', strtotime($string_date . " + " . (7 - $day_of_week) . " days"));
Given PHP version pre 5.3 following function gives you a first day of the week of given date (in this case - Sunday, 2013-02-03):
<?php
function startOfWeek($aDate){
$d=strtotime($aDate);
return strtotime(date('Y-m-d',$d).' - '.date("w",$d).' days');
}
echo(date('Y-m-d',startOfWeek("2013-02-07")).'
');
?>
$today_day = date('D'); //Or add your own date
$start_of_week = date('Ymd');
$end_of_week = date('Ymd');
if($today_day != "Mon")
$start_of_week = date('Ymd', strtotime("last monday"));
if($today_day != "Sun")
$end_of_week = date('Ymd', strtotime("next sunday"));
If you want Monday as the start of your week, do this:
$date = '2015-10-12';
$day = date('N', strtotime($date));
$week_start = date('Y-m-d', strtotime('-'.($day-1).' days', strtotime($date)));
$week_end = date('Y-m-d', strtotime('+'.(7-$day).' days', strtotime($date)));
A smart way of doing this is to let PHP handle timezone differences and Daylight Savings Time (DST). Let me show you how to do this.
This function will generate all days from Monday until Friday, inclusive (handy for generating work week days):
class DateTimeUtilities {
public static function getPeriodFromMondayUntilFriday($offset = 'now') {
$now = new \DateTimeImmutable($offset, new \DateTimeZone('UTC'));
$today = $now->setTime(0, 0, 1);
$daysFromMonday = $today->format('N') - 1;
$monday = $today->sub(new \DateInterval(sprintf('P%dD', $daysFromMonday)));
$saturday = $monday->add(new \DateInterval('P5D'));
return new \DatePeriod($monday, new \DateInterval('P1D'), $saturday);
}
}
foreach (DateTimeUtilities::getPeriodFromMondayUntilFriday() as $day) {
print $day->format('c');
print PHP_EOL;
}
This will return datetimes Monday-Friday for current week. To do the same for an arbitrary date, pass a date as a parameter to DateTimeUtilities ::getPeriodFromMondayUntilFriday, thus:
foreach (DateTimeUtilities::getPeriodFromMondayUntilFriday('2017-01-02T15:05:21+00:00') as $day) {
print $day->format('c');
print PHP_EOL;
}
//prints
//2017-01-02T00:00:01+00:00
//2017-01-03T00:00:01+00:00
//2017-01-04T00:00:01+00:00
//2017-01-05T00:00:01+00:00
//2017-01-06T00:00:01+00:00
Only interested in Monday, as the OP asked?
$monday = DateTimeUtilities::getPeriodFromMondayUntilFriday('2017-01-02T15:05:21+00:00')->getStartDate()->format('c');
print $monday;
// prints
//2017-01-02T00:00:01+00:00
You parse the date using strptime() and use date() on the result:
date('N', strptime('%m-%d-%g', $dateString));
<?php
/* PHP 5.3.0 */
date_default_timezone_set('America/Denver'); //Set apprpriate timezone
$start_date = strtotime('2009-12-15'); //Set start date
//Today's date if $start_date is a Sunday, otherwise date of previous Sunday
$today_or_previous_sunday = mktime(0, 0, 0, date('m', $start_date), date('d', $start_date), date('Y', $start_date)) - ((date("w", $start_date) ==0) ? 0 : (86400 * date("w", $start_date)));
//prints 12-13-2009 (month-day-year)
echo date('m-d-Y', $today_or_previous_sunday);
?>
(Note: MM, dd and yyyy in the Question are not standard php date format syntax - I can't be sure what is meant, so I set the $start_date with ISO year-month-day)
I've come against this question a few times and always surprised the date functions don't make this easier or clearer. Here's my solution for PHP5 that uses the DateTime class:
/**
* #param DateTime $date A given date
* #param int $firstDay 0-6, Sun-Sat respectively
* #return DateTime
*/
function getFirstDayOfWeek(DateTime $date, $firstDay = 0) {
$offset = 7 - $firstDay;
$ret = clone $date;
$ret->modify(-(($date->format('w') + $offset) % 7) . 'days');
return $ret;
}
Necessary to clone to avoid altering the original date.
Another way to do it....
$year = '2014';
$month = '02';
$day = '26';
$date = DateTime::createFromFormat('Y-m-d H:i:s', $year . '-' . $month . '-' . $day . '00:00:00');
$day = date('w', $date->getTimestamp());
// 0=Sunday 6=Saturday
if($day!=0){
$newdate = $date->getTimestamp() - $day * 86400; //86400 seconds in a day
// Look for DST change
if($old = date('I', $date->getTimestamp()) != $new = date('I', $newdate)){
if($old == 0){
$newdate -= 3600; //3600 seconds in an hour
} else {
$newdate += 3600;
}
}
$date->setTimestamp($newdate);
}
echo $date->format('D Y-m-d H:i:s');
The easiest way to get first day(Monday) of current week is:
strtotime("next Monday") - 604800;
where 604800 - is count of seconds in 1 week(60*60*24*7).
This code get next Monday and decrease it for 1 week. This code will work well in any day of week. Even if today is Monday.
I found this quite frustrating given that my timezone is Australian and that strtotime() hates UK dates.
If the current day is a Sunday, then strtotime("monday this week") will return the day after.
To overcome this:
Caution: This is only valid for Australian/UK dates
$startOfWeek = (date('l') == 'Monday') ? date('d/m/Y 00:00') : date('d/m/Y', strtotime("last monday 00:00"));
$endOfWeek = (date('l') == 'Sunday') ? date('d/m/Y 23:59:59') : date('d/m/Y', strtotime("sunday 23:59:59"));
Here's a one liner for the first day of last week, and the last day of last week as a DateTime object.
$firstDay = (new \DateTime())->modify(sprintf('-%d day', date('w') + 7))
->setTime(0, 0, 0);
$lastDay = (new \DateTime())->modify(sprintf('-%d day', date('w') + 1))
->setTime(23, 59, 59);
Just to note that timestamp math can also be a solution. If you have in mind that 01.jan 1970 was a Thursday, then start of a week for any given date can be calculated with:
function weekStart($dts)
{ $res = $dts - ($dts+date('Z',$dts)+259200)%604800;
return $res + 3600*(date('I',$dts)-date('I',$res));
}
It is predictable for any timestamp and php version, using date-func ('Z', 'I') only for timezone and daylight-saving offsets. And it produces same results as:
strtotime(date('Y-m-d', $dts).' - '.(date('N', $dts)-1.' days');
and with (the best and the most elegant) mentioned:
strtotime('monday this week', $dts);

In PHP, is there an easy way to get the first and last date of a month?

I need to get the first and last day of a month in the format YYYY-MM-DD given only the month and year. Is there a good, easy way to do this?
$first = date('Y-m-d', mktime(0, 0, 0, $month, 1, $year));
$last = date('Y-m-t', mktime(0, 0, 0, $month, 1, $year));
See date() in PHP documentation.
First day is always YYYY-MM-01, isn't it? Example: date("Y-M-d", mktime(0, 0, 0, 8, 1, 2008))
Last day is the previous day of the next month's first day:
$date = new DateTime("2008-09-01");
$date->modify("-1 day");
echo $date->format("Y-m-d");
The first day of the month is always 1.
So it will become
YYYY-MM-01
the last day can be calculated as:
<?php
$num = cal_days_in_month(CAL_GREGORIAN, 8, 2003); // 31
echo "There was $num days in August 2003";
?>
OK, first is dead easy.
date ('Y-m-d', mktime(0,0,0,MM,01,YYYY));
Last is a little trickier, but not much.
date ('Y-m-d', mktime(0,0,0,MM + 1,-1,YYYY));
If I remember my PHP date stuff correctly...
**edit - Gah! Beaten to it about a million times...
Edit by Pat:
Last day should have been
date ('Y-m-d', mktime(0,0,0,$MM + 1,0,$YYYY)); // Day zero instead of -1
<?php
echo "Month Start - " . $monthStart = date("Y-m-1") . "<br/>";
$num = cal_days_in_month(CAL_GREGORIAN, date("m"), date("Y"));
echo "Monthe End - " . $monthEnd = date("Y-m-".$num);
?>
The easiest way to do this with PHP is
$dateBegin = strtotime("first day of last month");
$dateEnd = strtotime("last day of last month");
echo date("MYDATEFORMAT", $dateBegin);
echo "<br>";
echo date("MYDATEFORMAT", $dateEnd);
Or the last week
if (date('N', time()) == 7) {
$dateBegin = strtotime("-2 weeks Monday");
$dateEnd = strtotime("last Sunday");
} else {
$dateBegin = strtotime("Monday last week");
$dateEnd = strtotime("Sunday last week");
}
Or the last year
$dateBegin = strtotime("1/1 last year");
$dateEnd = strtotime("12/31 this year");
By the way #ZombieSheep solution
date ('Y-m-d', mktime(0,0,0,$MM + 1,-1,$YYYY));
does not work it should be
date ('Y-m-d', mktime(0,0,0,$MM + 1,0,$YYYY)); // Day zero instead of -1
Of course #Michał Słaby's accepted solution is the simplest.
Just to verify that I didn't miss any loose ends:
$startDay = 1;
if (date("m") == 1) {
$startMonth = 12;
$startYear = date("Y") - 1;
$endMonth = 12;
$endYear = date("Y") - 1;
}
else {
$startMonth = date("m") - 1;
$startYear = date("Y");
$endMonth = date("m") - 1;
$endYear = date("Y");
}
$endDay = date("d") - 1;
$startDate = date('Y-m-d', mktime(0, 0, 0, $startMonth , $startDay, $startYear));
$endDate = date('Y-m-d', mktime(0, 0, 0, $endMonth, $endDay, $endYear));
try this to get the number of days in the month:
$numdays = date('t', mktime(0, 0, 0, $m, 1, $Y));
Example; I want to get first day and last day of current month.
$month = (int) date('F');
$year = (int) date('Y');
date('Y-m-d', mktime(0, 0, 0, $month + 1, 1, $year)); //first
date('Y-m-d', mktime(0, 0, 0, $month + 2, 0, $year)); //last
When you run this for instance at date 2015-01-09, the first and last values will be sequentially;
2015-01-01
2015-01-31
Tested.
From here(get next month last day) that is marked as duplicated, so i can't add comment there, but people can got bad answers from there.
Correct one for last day of next month:
echo ((new DateTime(date('Y-m').'-01'))->modify('+1 month')->format('Y-m-t'));
Correct one for first day of next month:
echo ((new DateTime(date('Y-m').'-01'))->modify('+1 month')->format('Y-m-01'));
Code like this will be providing March from January, so that's not what could be expected.
echo ((new DateTime())->modify('+1 month')->format('Y-m-t'));
proper way to build a relative date from now is:
//bad example - will be broken when generated at 30 of December (broken February)
echo date("Y-m-d", strtotime("now"))."\n";
echo date("Y-m-d", strtotime("now + 1 month"))."\n";
echo date("Y-m-d", strtotime("now + 2 month"))."\n";
echo date("Y-m-d", strtotime("now + 3 month"))."\n";
//good example, you can change first day to last day or any day
echo date("Y-m-d", strtotime("first day of this month"))."\n";
echo date("Y-m-d", strtotime("first day of next month"))."\n";
echo date("Y-m-d", strtotime("first day of +2 month"))."\n";
echo date("Y-m-d", strtotime("first day of +3 month"))."\n";
and the result will be:
2021-12-30
2022-01-30
2022-03-02
2022-03-30
2021-12-01
2022-01-01
2022-02-01
2022-03-01

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