PHP submit form not working - php

Question

Below is a piece of the code that input the results of a query into radio buttons. Then, when the user pushes one of the buttons in the form, it moves to the pages test.php. I have run into a problem though that the second code (which is on test.php) doesn't seem to work although I can't see any reason that it shouldn't. Any ideas are awesome. Thanks.
<?php while($row = mysql_fetch_assoc($result)): ?>
<tr>
<td><input type="radio" name="server" value="<?php echo $row['serverId']; ?>" /></td>
<td><?php echo $row['userName']; ?></td>
<td><?php echo $row['dateCreated']; ?></td>
<td><?php echo $row['serverName']; ?></td>
<td><?php echo $row['serverId']; ?></td>
<td><?php echo $row['publicDNS'] ?></td>
<td><?php echo $row['isRunning']; ?></td>
</tr>
<?php endwhile; ?>
</table>
<br>
<?php endif; ?>
<form method="post" name="server_information" id="server_information" action="test.php">
<input type="submit" name="server_stop" value="Stop Server"/>
<input type="submit" name="server_terminate" value="Terminate Server"/>
</form>
</body>
</html>
Second Code:
<?php
if (isset($_POST['server_stop'])) {
echo "Server Stopped";
}
if (isset($_POST['server_terminate'])) {
echo "Server Terminated"
}
?>

Answer 1

$_POST['submit'] has to be $_POST['server_stop']
<?php
if (isset($_POST['server_stop'])) {
echo "Server Stopped";
}
if (isset($_POST['server_terminate'])) {
echo "Server Terminated";
}
?>

Answer 2

Your code:
<?php
if (isset($_POST['server_stop'])) {
echo "Server Stopped";
}
if (isset($_POST['server_terminate'])) {
echo "Server Terminated"
}
?>
Both of these conditions are true on form submit. If you want to differentiate between which submit button was pressed, you'll need to make a hidden input and use some javascript:
<form method="post" name="server_information" id="server_information" action="test.php">
<input type="submit" name="server_stop" value="Stop Server" onclick="whatwasclicked(this);" />
<input type="submit" name="server_terminate" value="Terminate Server" onclick="whatwasclicked(this);" />
<input type="hidden" name="clicked" id="clicked" />
</form>
Your javascript will be:
function whatwasclicked(c) {
$("#clicked").val() = c.value;
}
Now on the PHP side, you'll check $_POST['clicked'] and see which button was pressed.
EDIT:
Be aware there is Jquery being used here... so be sure to load that library.

Answer 3

If you don't want to use javascript at all, and you're only going to have those submit buttons in the form, you could also do this:
<form method="post" name="server_information" id="server_information" action="test.php">
<input type="submit" name="clicked" value="Stop Server"/>
</form>
<form method="post" name="server_information" id="server_information" action="test.php">
<input type="submit" name="clicked" value="Terminate Server"/>
</form>
Now just check for $_POST['clicked'] and you'll see which button was pressed.

Answer 4

if (isset($_POST['submit'])){
$name =trim($_POST['name']);
if (empty($name)){
echo "please input name";
}
else if (!preg_match("/^[a-zA-Z ]*$/",$name)){
$namerr = "Only letters and white space allowed";
}
}