<script type="text/javascript">
function removeLink()
{
document.getElementById("tab2").deleteRow(i);
}
</script>
</head>
<body>
<form action="forth.php" method="post">
<table width="600" border="1" id="tab2">
<?php
foreach($_POST as $post2)
{
?>
<tr>
<td>
<?php
echo $post2.'<br />';
?>
</td>
<td>Remove</td>
</tr>
<?php
}
?>
<tr>
<td><input type="submit" value="Next" /></td>
<td> </td>
</tr>
</table>
</form>
</body>
this is my page third.php it redirect user to new page forth.php on forth.php i have following code
<?php
print_r($_POST);
foreach($_POST as $key_post)
{
echo $key_post.'<br>';
}
?>
the issue is on page forth.php it doesn't print anything even when I did print_r($_POST); it returned me empty array like Array(), and help why data is not saved.
I assume it's empty because you don't actually have any <input name="foo" type="bar /> fields other than the submit button, so nothing is actually being posted.
You'll need to add some hidden fields:
foreach($_POST as $key => $post2)
{
?>
<tr>
<td>
<?php echo $post2.'<br />'; ?>
<input type="hidden" name="<?php echo $key;?>" value="<?php echo $post2;?>" />
</td>
</tr>
... etc
Related
I can't seem to delete row in database by id in php
I think the the id is not passed to the $_POST['delete']
however, the popup "Your data is deleted" is displayed, but the data is not deleted.
So I'm not sure where is the error in this code.
I also try to delete the data by its id
for example: Delete book where no='4';
and the code seems to run fine because the data is deleted in the database.
<html>
<script>
function confirmDelete() {
return confirm('Are you sure?');
}
</script>
<!DOCTYPE html>
<head>
<form action="test.php" method="POST">
<br><br><br>
<table bordercolor="#FFCC66" align="center" bgcolor="#FFFFFF">
<tr>
<th>No</th>
<th>Title</th>
<th>Author</th>
<th>Year</th>
<th>Donor's Name</th>
<th>Call Number</th>
<th>Date Received</th>
<th>Handled By</th>
<th></th>
<th></th>
</tr>
<?php
include ('config.php');
$view=mysqli_query($conn,"SELECT * FROM book");
?>
<?php while($v=mysqli_fetch_array($view)){ ?>
<tr>
<td>
<?php echo $v["no"];?>
</td>
<td>
<?php echo $v["title"];?>
</td>
<td>
<?php echo $v["author"];?>
</td>
<td>
<?php echo $v["year"];?>
</td>
<td>
<?php echo $v["donorname"];?>
</td>
<td>
<?php echo $v["callnum"];?>
</td>
<td>
<?php echo $v["datereceived"];?>
</td>
<td>
<?php echo $v["handledby"];?>
</td>
<td><input type="submit" name="delete" value="Delete" onclick="return confirmDelete('Are you sure?');" /></td>
</tr>
<?php
} ?>
</tr>
</table>
<br><br>
</form>
</body>
</html>
<?php
if(isset($_POST['delete']))
{
include('config.php');
$no =$v["no"];
$d=mysqli_query($conn,"DELETE FROM `book` WHERE no='$no'");
if ($d)
{
echo "<script type='text/javascript'> alert('Your data is deleted!'); </script>";
echo"<meta http-equiv='Refresh' content='0' >";
}
else
{
echo "<script type='text/javascript'> alert('Your data cannot delete!'); </script>";
}
mysqli_close($conn);
}
?>
Change the submit element to
<td>
<input type="submit" name="delete" value="<?php echo $v['no'];?>" onclick="return confirmDelete('Are you sure?');" />
</td>
and
$no = $_POST["delete"];
Another solution si to add a hidden input with your value.
<td>
<?php echo $v["no"];?>
<input type="hidden" value="<?php echo $v["no"];?>" />
</td>
In your php you will find the value in $_POST['no']
This solution is better to pass multiple arguments in POST like a captcha or a confirmation (checkbox).
logic is not correct, while you press the delete button, all the data will be passed along with submitting because your tag is outside of the loop.
As my opinion, you should use ajax like functionality here, or follow this method.
<?php while($v=mysqli_fetch_array($view)){ ?>
<form action="test.php" method="POST">
<tr>
<td>
<?php echo $v["no"];?>
<input type="hidden" value="<?php echo $v["no"];?>" name="no" >
</td>
<td><input type="submit" name="delete" value="Delete" onclick="return confirmDelete('Are you sure?');" /></td>
</tr>
</form>
<?php } ?>
and in your post call use $no = $_POST['no']; instead of $no =$v["no"];
I have some combobox with onchange event, and they're reset each other when selected the orther one of them, does any suggest how to retain the value on the page? this my script :
<form method="POST" name="form1" action="<?php $_SERVER['PHP_SELF'];?>">
<table border="0">
<tr>
<td colspan="6"></td>
</tr>
<tr>
<td>
<select name="select_petugas1" style="width:18px;" onchange="this.form.submit('select_petugas1');"> //first combobox
<option></option>
<?php include 'dbconn.php';
$sql_peg1="SELECT * FROM users"; $result_peg1=$conn->query($sql_peg1);
while( $row_peg1=$result_peg1->fetch_assoc() ){
echo "<option>".$row_peg1['nama']."</option>";
}
?>
</select>
</td>
<td>
<?php
if(isset($_POST['select_petugas1'])){
$select_petugas1=$_POST['select_petugas1'];
echo "<input type='text' name='select_petugas1' value='".$select_petugas1."'>"; // Throw 1st result into the text box
$sql_NIP1="SELECT NIP FROM users WHERE nama='$select_petugas1'";
$result_NIP1=$conn->query($sql_NIP1);
$row_NIP1=$result_NIP1->fetch_assoc();
$NIP1=$row_NIP1['NIP'];
?>
</td>
<td> NIP</td>
<td>:</td>
<td><input type="text" name='NIP1' value="<?php echo $NIP1; ?>"></td>
</tr> <!-- child of first result -->
<tr>
<td colspan="5" bgcolor="blue"></td>
</tr>
<tr>
<td>
<select name="peg_2" style="width:18px;" onchange="submit(this)"><!--2nd combobox-->
<option></option>
<?php
$sql_peg2="SELECT nama FROM users";
$result_peg2=$conn->query( $sql_peg2 );
while ($row_peg2=$result_peg2->fetch_assoc()){
echo "<option value='".$row_peg2['nama']."'>".$row_peg2['nama']."</option>";
}
?>
</select>
</td>
<td>
<?php
if( isset($_POST['peg_2']) ){
$peg_2=$_POST['peg_2'];
echo "<input type='text' name='peg2' value='".$peg_2."'>"; // 2nd result throw into 2nd texbox
$sql_NIP2="SELECT NIP FROM users WHERE nama='$peg_2'";
$result_NIP2=$conn->query($sql_NIP2);
$row_NIP2=$result_NIP2->fetch_assoc();
?>
</td>
<td> NIP</td>
<td>:</td>
<td><input type='text' name='NIP2' value="<?php echo $row_NIP2['NIP'];?>"> <!--2nd child of result-->
<?php
}
}
if(isset($_POST['NIP2'])){
$NIP2=$_POST['NIP2'];
echo "<br /> NIP2 :".$NIP2."<br />";
}
mysqli_close($conn);
?>
</td>
</tr>
</table>
</form>
<form method="POST" name="wilayah" id="wilayah" action="<?php $_SERVER['PHP_SELF'];?>">
<table border="1">
<tr>
<td>
<select name="select_provinsi" onchange="submit(this)" style="width:18;">
<option selected>PROVINSI</option>
<?php
include 'dbconn.php';
$sql_prov="SELECT * FROM wilayah GROUP BY provinsi";
$result_prov=$conn->query($sql_prov);
echo "";
while($row_prov=$result_prov->fetch_assoc()){
$provinsi=$row_prov['provinsi'];
echo "<option value='".$provinsi."'>".$provinsi."</option>";
}
?>
</select>
<?php
if(isset($_POST['select_provinsi'])){
$select_provinsi=$_POST['select_provinsi'];
echo "
<input type='text' name='select_provinsi' value='".$select_provinsi."' placeholder='PROVINSI'>
</td>
</tr>";
$sql_kabkota="SELECT * FROM wilayah WHERE provinsi='$select_provinsi' GROUP BY kab_kota";
$result_kabkota=$conn->query($sql_kabkota);
?>
<tr>
<td>
<select name="select_kabkota" style="width:18px;" onchange="submit(this)"><option>KAB/KOTA</option>
<?php
while($row_kabkota=$result_kabkota->fetch_assoc()){
echo "<option>".$row_kabkota['kab_kota']."</option>";
}
?>
</select>
<?php
}
if(isset($_POST['select_kabkota'])){
$select_kabkota=$_POST['select_kabkota'];
?>
<input type="text" name="kab_kota" value="<?php echo $select_kabkota;?>">
<?php
}
mysqli_close($conn);
?>
</td>
</tr>
</table>
</form>
hope any suggestion for resolved of my problem with them,,
onchange="submit(this)" means that you want to submit the form when the value of the combobox changes. So, when the form is sent, the page reloads and you get the default value of your form.
To restore the chosen value, I would do something like :
<select name="select_kabkota" style="width:18px;" onchange="submit(this)">
<option>KAB/KOTA</option>
<?php
if(isset($_POST['select_kabkota']))
$select_kabkota=$_POST['select_kabkota'];
while($row_kabkota=$result_kabkota->fetch_assoc())
{
$selected = $select_kabkota == $row_kabkota['kab_kota'] ? 'selected="selected"' : '';
echo "<option ".$selected." >".$row_kabkota['kab_kota']."</option>";
}
?>
</select>
I want to call php function in form action and i want to pass id as a argument. What I am doing is, in html form database column values will be displayed in text boxes, If I edit those values and click 'update' button values in database should be updated and 'Record updated successfully'message should be displayed in same page. I tried below code but not working. Let me know the solution. Thanks in advance.
<html>
<head>
<link rel="stylesheet" type="text/css" href="cms_style.css">
</head>
<?php
$ResumeID = $_GET['id'];
$con = mysql_connect("localhost", "root", "");
mysql_select_db("engg",$con);
$sql="SELECT * from data WHERE ResumeID=$ResumeID";
$result = mysql_query($sql);
$Row=mysql_fetch_row($result);
function updateRecord()
{
//If(!isset($_GET['id']))
//{
$NameoftheCandidate=$_POST[NameoftheCandidate];
$TelephoneNo=$_POST[TelephoneNo];
$Email=$_POST[Email];
$sql="UPDATE data SET NameoftheCandidate='$_POST[NameoftheCandidate]', TelephoneNo='$_POST[TelephoneNo]', Email='$_POST[Email]' WHERE ResumeID=$ResumeID ";
if(mysql_query($sql))
echo "<p>Record updated Successfully</p>";
else
echo "<p>Record update failed</p>";
while ($Row=mysql_fetch_array($result)) {
echo ("<td>$Row[ResumeID]</td>");
echo ("<td>$Row[NameoftheCandidate]</td>");
echo ("<td>$Row[TelephoneNo]</td>");
echo ("<td>$Row[Email]</td>");
} // end of while
} // end of update function
?>
<body>
<h2 align="center">Update the Record</h2>
<form align="center" action="updateRecord()" method="post">
<table align="center">
<input type="hidden" name="resumeid" value="<? echo "$Row[1]"?>">
<? echo "<tr> <td> Resume ID </td> <td>$Row[1]</td> </tr>" ?>
<div align="center">
<tr>
<td> Name of the Candidate</td>
<td><input type="text" name="NameoftheCandidate"
size="25" value="<? echo "$Row[0]"? >"></td>
</tr>
<tr>
<td>TelephoneNo</td>
<td><input type="text" name="TelephoneNo" size="25" value="<? echo "$Row[1]"?>"></td>
</tr>
<tr>
<td>Email</td>
<td><input type="text" name="Email" size="25" value="<? echo "$Row[3]"?>">
</td>
</tr>
<tr>
<td></td>
<td align="center"><input type="submit" name="submitvalue" value="UPDATE" ></td>
</tr>
</div>
</table>
</form>
</body>
</html>
try this way
HTML
<form align="center" action="yourpage.php?func_name=updateRecord" method="post">
PHP
$form_action_func = $_POST['func_name'];
if (function_exists($form_action_func)) {
updateRecord();
}
write form action="" and then write your php code as below
note : use form method as get
<?php
if(isset($_GET['id']))
{
call your function here
}
?>
in function access all values using $_GET['fieldname']
simple way make your "Submit " and "Update" action performed on same page then
if(isset($_POST['update']))
{
//perform update task
update($var1,var2,$etc); // pass variables to function
header('Location: http://www.example.com/');// link to your form
}
else if(isset($_POST['submit']))
{
//perform update task
submit($var1,$var2,$etc);// pass variables to function
header('Location: http://www.example.com/'); // link to next page after submit successfully
}
else
{
// display form
}
I'm trying to get the emails corresponding to the checkbox using the following codes. But, I'm not getting the correct checked emails in the new variable. Can anyone please check ??
<?php
include("connection.php");
$username=$_SESSION['username'];
$query=mysql_query("SELECT * FROM contacts WHERE username='$username'");
$num=mysql_num_rows($query);
$info=mysql_fetch_array($query);
$i=0;
$msg='';
?>
<table width="672" border="0">
<?php
$i=0;
while($info)
{
?>
<form action="compose.php" method="post">
<tr style="font-size:14px;">
<td width="21" bgcolor="#f2f2f2"> <input type="checkbox" name="add" onSelect="<?php $msg=$msg.$info['email'].", ";?>"/> </td>
<td width="229" bgcolor="#f2f2f2"> <?php echo $info['email']; ?> </td>
<td width="408" bgcolor="#f2f2f2"> <?php echo $info['name']; ?> </td>
</tr>
<?php
$info=mysql_fetch_array($query);
$i++;
}
$_SESSION['contacts']=$msg;
?>
<tr><td></td><td></td><td><br />
<input class="new-button" type="submit" value="Insert & Compose" name="submit" /></td>
</tr>
</form>
</table>
To get any value back for checkboxes they must have a value=. In your case you probably would want the value to be the according email address.
One problem with your code is using onSelect= instead of value=, and second you didn't print the actual value into the page. Rewrite it to:
<td width="21" bgcolor="#f2f2f2">
<input type="checkbox" name="add"
value="<?php print $info['email']; ?>"/> </td>
If you need the $msg variable to do something, assemble it after the output.
<input type="checkbox" name="add" value="<?php echo $msg.$info['email'];?>"/>
checkbox does not have onSelect event probobly you got value in mind and in PHP code you should echo and what .", " is for?
I just don't see the problem. Need some new eyes to review it. Two files included test.php and test2.php to var_dump. Help!! Cut, Paste and Run - Thanks
test.php:
<?php
ini_set('error_reporting', E_ALL );
ini_set('display_errors', "1");
?>
<style type="text/css">
div.tabcontent{
visibility: hidden;
position:absolute;
left:20px;
}
</style>
<script type="text/javascript">
function switch_div(){
val=document.form1.a_type.selectedIndex;
if (val < 3){
val="a0";
data=document.getElementById("data_types").innerHTML+document.getElementById(val).innerHTML;
}else if (val==3){
val="a"+document.form1.a_type.selectedIndex;
data=document.getElementById("data_types").innerHTML+document.getElementById(val).innerHTML;
}else{
val="a"+document.form1.a_type.selectedIndex;
data=document.getElementById(val).innerHTML;
}
document.getElementById('anw_wksp').innerHTML=data;
}
</script>
<html>
<body>
<form name="form1" action="test2.php" method="post" >
<table>
<th >Enter Anwsers</th>
<tr>
<td>Anwser Type</td>
</tr>
<tr>
<td><select name="a_type" onChange="switch_div()"/>
<option value='radio'>radio</option>
<option value='checkbox'>checkbox</option>
<option value='select'>select</option>
<option value='text'>text</option>
<option value='textarea'>textarea</option>
</select>
</td>
</tr>
<div id="anw_wksp" style="border:1px solid gray; margin-bottom: 1em; padding: 10px">
</div>
<div id="data_types" class="tabcontent">
<table>
<th colspan="3">Data type</th>
<tr><td>
<input type="radio" name="a_data_type" value="text" selected>text<br>
<input type="radio" name="a_data_type" value="int">int </td>
</td>
</tr>
</table>
</div>
<div id="a0" class="tabcontent"> <!--radio/checkbox/select button-->
<table>
<th>Readable Anwser</th><th>DB Value</th><th>Default</th>
<? $i=0;
while($i < 10){
echo "<tr><td><input type=\"text\" name=\"a_r_$i\" /></td>
<td><input type=\"text\" name=\"a_db_$i\" /></td>
<td><input type=\"radio\" name=\"default\" value=\"$i\" /></td></tr>";
$i++;
}
?>
</table>
</div>
<div id="a3" class="tabcontent">
<table>
<th>Readable Anwser</th><th>DB Value</th><th>Default</th>
<tr><td><input type="text" name="a_r_text"></td>
<td><input type="text" name="a_db_text"></td>
<td><input type="text" name="default_text" ></td></tr>
</table>
</div>
<div id="a4" class="tabcontent">
<table>
<th>Readable Anwser</th><th>Default</th>
<tr><td><input type="text" name="a_r_textarea"></td>
<td><textarea name="default_textarea" rows="5" cols="30"></textarea></td></tr>
</table>
</div>
</td>
</tr>
</td>
</tr>
<tr>
<td><input type="submit" value="Enter" name="submit">
</td>
</table>
</form>
</body>
</html>
<script language="javascript">switch_div();</script>
-------------------------------------------------------------------
test2.php:
<?php
$data = file_get_contents('php://input');
if(empty($_SERVER['CONTENT_TYPE'])){
$type = "application/x-www-form-urlencoded";
$_SERVER['CONTENT_TYPE'] = $type;
}
print "_POST = <br />";
var_dump($_POST);
print "<br />";
print " DATA = <br />";
var_dump($data);
?>
You don't have a <head>
You can't have <script> tags outside of your <html>. Perhaps you want external JS files?
You can't have <style> tags outside of your <html>. Perhaps you want external CSS files?
Your scripts/styles, or their external <link>'s, should probably be inside your <head>
You can't have <th> or <td> outside of a <tr>. Proper example.
You don't declare a doctype.
You can't have <div>'s randomly between table rows.
Your method for echoing <tr>'s is, well, sloppy...
Instead of:
<? $i=0;
while($i < 10){
echo "<tr><td><input type=\"text\" name=\"a_r_$i\" /></td>
<td><input type=\"text\" name=\"a_db_$i\" /></td>
<td><input type=\"radio\" name=\"default\" value=\"$i\" /></td></tr>";
$i++;
}
?>
Consider something like:
<? for($i = 0; $i < 10; $i++) { ?>
<tr>
<td><input type="text" name="a_r_<?=$i?>" /></td>
<td><input type="text" name="a_db_<?=$i?>" /></td>
<td><input type="radio" name="default" value="<?=$i?>" /></td>
</tr>
<? } ?>
Finally, to try debugging your problem, use a tool like Firebug for Chrome/Firefox to ensure you're submitting POST data as expected.
I know this is a lame answer but just want to throw it out there to make sure we aren't looking over the simplest things. Did you check the form tag in the html to make sure it is set to POST?
I would recommend checking that the request method is in fact a post on the test2.php script.
<?php
if (strtolower($_SERVER["REQUEST_METHOD"]) == "post") {
$data = file_get_contents('php://input');
if(empty($_SERVER['CONTENT_TYPE'])){
$type = "application/x-www-form-urlencoded";
$_SERVER['CONTENT_TYPE'] = $type;
}
print "_POST = <br />";
var_dump($_POST);
print "<br />";
print " DATA = <br />";
var_dump($data);
}
?>