This is my table
id | name | userid | score | date |
------------------------------------------------------------
1 | john | 1 | 44 | 2013-03-2
2 | mary | 2 | 59 | 2013-03-5
3 | john | 12 | 38 | 2013-03-8
4 | elvis | 3 | 19 | 2013-02-10
5 | john | 11 | 1002 | 2013-01-11
6 | johnah | 10 | 200 | 2013-01-11
I want to show number of position of my given userid order by highest score.
if i give userid 12 in my query then it show position number 5 for user 12 depend on highest score
I think this is what you want.
SELECT COUNT(*)+1 FROM table_name WHERE userid!=12 AND
score>(SELECT score FROM table_name WHERE userid=12);
Try This :
SELECT *
FROM table_name
WHERE id =(SELECT max( userid ) FROM table_name)
Related
Hello can you help me get the rank with custom ties?
i have a table of Scores stores all the scores given by the judges.
+----+----------+-------------+--------+
| Id | judge_id |performer_id | score |
+----+----------+-------------+--------+
| 1 | 1 | 1 | 98 |
| 2 | 1 | 2 | 98 |
| 3 | 1 | 3 | 94 |
| 4 | 1 | 4 | 96 |
| 5 | 2 | 1 | 93 |
| 6 | 2 | 2 | 80 |
+----+----------+-------------+--------+
heres what the code i have searched.
SELECT
id
, judge_id
, performer_id
, score
, FIND_IN_SET(
score
, (SELECT
GROUP_CONCAT(DISTINCT score ORDER BY score DESC)
FROM
scores
WHERE
judge_id = 1
)
) AS rank
FROM
scores
WHERE
judge_id = 1
ORDER BY rank ASC
and the output of this is:
+----+----------+-------------+--------+------+
| Id | judge_id |performer_id | score | rank |
+----+----------+-------------+--------+------+
| 1 | 1 | 1 | 98 | 1 |
| 2 | 1 | 2 | 98 | 1 |
| 3 | 1 | 4 | 96 | 3 |
| 4 | 1 | 3 | 94 | 4 |
+----+----------+-------------+--------+------+
it is working but the output is not what i want.
i want to get the ranking and ties like this.
+----+----------+-------------+--------+------+
| Id | judge_id |performer_id | score | rank |
+----+----------+-------------+--------+------+
| 1 | 1 | 1 | 98 | 1.5 |
| 2 | 1 | 2 | 98 | 1.5 |
| 3 | 1 | 4 | 96 | 3 |
| 4 | 1 | 3 | 94 | 4 |
+----+----------+-------------+--------+------+
where get all the rank of the tie then divide it by how many performer ties in the rank.
ex.
performer 1 score 98 rank 1
performer 2 score 98 rank 1
suppose that performer 2 should get rank 2
i want to compute it like
1+2 = 3 then divide it by 2 since 2 performers are tie in rank 1
1=2 = 3 / 2
answer is 1.5
im sorry for my english
but please can any one help me? im stuck at this problem.
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(performer_id SERIAL PRIMARY KEY
,score INT NOT NULL
);
INSERT INTO my_table VALUES
(1,98),
(2,98),
(3,94),
(4,96);
SELECT x.*
, y.rank
FROM my_table x
JOIN
( SELECT score
, SUM(i)/COUNT(*) rank
FROM
( SELECT score
, #i:=#i+1 i
FROM my_table x
ORDER
BY score DESC
, performer_id
) a
JOIN
( SELECT #i:=0 ) vars
GROUP
BY score
) y
ON y.score = x.score;
+--------------+-------+--------+
| performer_id | score | rank |
+--------------+-------+--------+
| 1 | 98 | 1.5000 |
| 2 | 98 | 1.5000 |
| 3 | 94 | 4.0000 |
| 4 | 96 | 3.0000 |
+--------------+-------+--------+
Note: For newer versions of MySQL, you would use Windowing functions/CTE (I'm not really sure of the correct terminology). I've written this for older versions, although MySQL can have issues when initializing variables this way. If that's a problem, here's another (slightly 'hackier' - and theoretically incorrect, but practically fine) way of initialising the variable...
SELECT x.*
, y.rank
FROM my_table x
JOIN
( SELECT score
, SUM(i)/COUNT(*) rank
FROM
( SELECT score
, #j:=#j+1 i
FROM my_table x
JOIN ( SELECT #j:=0 ) vars
ORDER
BY score DESC
, performer_id
) a
GROUP
BY score
) y
ON y.score = x.score;
+--------------+-------+------+
| performer_id | score | rank |
+--------------+-------+------+
| 1 | 98 | 1.5 |
| 2 | 98 | 1.5 |
| 3 | 94 | 4 |
| 4 | 96 | 3 |
+--------------+-------+------+
I'm trying to add a new page onto an old site, a records page that'd show which players won the most money or won the race when they were a certain age
The user table looks like this
***********************************
| id | name | age | bday |
| 1 | bob | 15 | 2000-07-30 |
| 2 | john | 14 | 2001-07-30 |
| 3 | mary | 13 | 2002-07-30 |
***********************************
the race_results table looks like this
************************************************************
| id | raceid | userid | place | winnings | date |
| 1 | 1 | 1 | 1 | 1000 | 2006-04-10 |
| 2 | 1 | 2 | 5 | 50 | 2005-02-15 |
| 3 | 1 | 3 | 6 | 50 | 2010-06-12 |
| 4 | 2 | 1 | 1 | 1000 | 2009-05-29 |
| 5 | 2 | 2 | 3 | 250 | 2003-01-12 |
************************************************************
What's the most practical approach to a query that'd calculate the year range when Bob was 3 years old and match that with the race results table to see how many times he won 1st place within that particular date range?
SELECT COUNT(*)
FROM 'race_results'
INNER JOIN 'user' on user.id = race_results.userid
WHERE user.name = 'bob'
AND race_results.place = 1
AND race_results.date >= ADDDATE(user.bday, INTERVAL 3 YEAR)
AND race_results.date < ADDDATE(user.bday, INTERVAL 4 YEAR);
To get a list of all 3 yr old 1st placers and how many times they won, not just for 'bob' ...
SELECT user.name, COUNT(*)
FROM 'race_results'
INNER JOIN 'user' on user.id = race_results.userid
WHERE race_results.place = 1
AND race_results.date >= ADDDATE(user.bday, INTERVAL 3 YEAR)
AND race_results.date < ADDDATE(user.bday, INTERVAL 4 YEAR)
GROUP BY user.name;
I have a table (url_analyst) with the following info:
id | user_id | url_id | date | visits
----------------------------------------------------
1 | 2 | 5 | 2015-10-25 | 15
2 | 2 | 6 | 2015-10-25 | 18
3 | 2 | 5 | 2015-10-25 | 11
4 | 3 | 8 | 2015-10-25 | 22
5 | 3 | 9 | 2015-10-27 | 30
6 | 5 | 15 | 2015-10-25 | 15
etc
What I want is a update/insert earning in a new table "earning"
earning calculate 1$/10 visits
id | user_id | total_urls | date | total_visits | earning
-------------------------------------------------------------------
1 | 2 | 3 | 2015-10-25 | 44 | 4.4$
2 | 3 | 1 | 2015-10-25 | 22 | 2.2$
3 | 3 | 1 | 2015-10-27 | 30 | 3.0$
4 | 5 | 1 | 2015-10-25 | 15 | 1.5$
How can I do this with CodeIgniter using the active record query method? Can this be done with COUNT Total URL then GROUP BY user_id AND Date , update earning?
Try this MySQL query:
SELECT
user_id, count(url_id), date, sum(visits) as
total_visits, concat(sum(visits)/10,'$') as earning
FROM
url_analyst
GROUP BY
user_id, date
Considering all group_by columns from url_analyst table,
$this->db->select("SUM(total_url)");//if required select other fields
$this->db->group_by("url_analyst.user_id");
$this->db->group_by("url_analyst.date");
If you want group_by on any column from earning, you can change the table name in group_by clause
I have table like this:
| ID | Team | User | Try1 | Try2 | Try3 |
| 1 | Black | Chris | 2 | 6 | 4 |
| 2 | Black | Brian | 10 | 8 | 10 |
| 3 | Red | Mark | 6 | 2 | 8 |
| 4 | Red | Andrew | 4 | 10 | 6 |
I needed to count team try points together to get total.
SELECT *, SUM(Try1 + Try2 + Try3) AS total FROM team_pts GROUP BY team ORDER BY total DESC
The question is - how do I output each teams total for each try?
Something like this:
| Pos | Team | Try1 | Try2 | Try3 | Total |
| 1 | Black | 12 | 14 | 14 | 40 |
| 2 | Red | 10 | 12 | 14 | 36 |
Sorry for my English!
You need to sum column before sum total:
SELECT *,
SUM(Try1),
SUM(Try2),
SUM(Try3),
SUM(Try1 + Try2 + Try3) AS total
FROM team_pts
GROUP BY team
ORDER BY total DESC
SELECT ID,Team,SUM(Try1) as Try1,SUM(Try2) as Try2,SUM(Try3) as Try3,SUM(Try1 + Try2 + Try3) AS Total FROM team_pts GROUP BY team ORDER BY total DESC
I have 2 MySQL tables, one of which has a numeric column to orgainise the order I need the items to be displayed:
item_names
menu_id | dish_id | section_id | item_name
--------------------------------------------------
1 | 23 | 2 | Pie
1 | 24 | 2 | Fish
1 | 25 | 3 | Apples
1 | 26 | 2 | Onions
1 | 27 | 2 | Chips
link_extras
extra_id | dish_id | sort
-----------------------------
1 | 23 | 2
2 | 23 | 2
3 | 23 | 2
1 | 24 | 0
5 | 24 | 0
6 | 26 | 3
12 | 26 | 3
1 | 27 | 1
1 | 25 | 0
Basically what I am trying to do is extract each dish with a certain menu_id and section_id from the table item_names and order the output in respect to the sort column in the link_extras table.
so far:
$query="SELECT a.item_name, a.dish_id, b.sort
FROM item_names AS a, link_extras AS b
WHERE a.menu_id='1'
AND a.section_id='2'
AND b.dish_id=a.dish_id
GROUP BY b.dish_id
ORDER BY b.sort";
I am quite new to databases so would appreciate any help. The result I am after is
Fish
Chips
Pie
Onions
Unfortunately just can't get the order correct.
You need to use a simple JOIN
SELECT a.item_name, a.dish_id, b.sort
FROM item_names AS a
JOIN link_extras AS b
ON a.dish_id = b.dish_id
WHERE menu_id = 1
AND section_id = 2
GROUP BY b.dish_id
ORDER BY b.sort
Output:
| ITEM_NAME | DISH_ID | SORT |
------------------------------
| Fish | 24 | 0 |
| Chips | 27 | 1 |
| Pie | 23 | 2 |
| Onions | 26 | 3 |
See this SQLFiddle
SELECT
in.item_name
FROM item_names AS in
LEFT JOIN link_extras AS le
ON le.dish_id = in.dish_id
WHERE in.menu_id = 1
AND in.section_id = 2
ORDER BY le.sort
Demo Here
Output
| ITEM_NAME |
-------------
| Fish |
| Chips |
| Pie |
| Onions |