Query on PHP, web development - php

Question

I have made a connection to mysql database and echoing values from a table.
while($data = mysql_fetch_array($res))
{
?>
<a href="nextpage.php"<?php echo $data['rowname'] ?></a>
<?php
}
?>
Problem is when I click on the particular link, on the nextpage.php, it should display only the result of the value of a href clicked. So on the nextpage.php, I have defined something like SELECT * from tablename where rowname = 'a href value'.
What's happening now is that it displays only the last rowname value regardless of whichever link I click on, very obvious!
I have tried forms, arrays, SESSIONS but to no avail. How do I fix this?

Answer 1

the href should be like this
<?php echo $data['rowname']; ?>
and then on next page you can use $_GET['val'] and pass it to SELECT query

Answer 2

Try example as below
page1.php
while($data = mysql_fetch_array($res))
{
echo "<a href='nextpage.php?id=".$data['rowname']." >". $data['rowname'] ."</a>";
}
?>
your href will look like nextpage.php?id=[your value]
nextpage.php
$qry = mysql_query("select * from [table_name] where id = ".$_GET['id']."",$con);
while($data = mysql_fetch_array($res))
{
echo $data[0];
}
on nextpage pass value using $_GET['id'] to sql query.