on the same page I have
$sql = "SELECT * FROM `joedoe` ";
$result = mysql_query($sql);
$id = 'id';
<?php echo "<a href=\'page.php?id=$rows[$id]\'>View</a>" ?>
<?php echo " <div id=\'productId\' >$_GET[id]</div>" ?>
please tell me, how to retrieve the id from link to div using $_GET
You need single quotes inside your array selector, around id index...
$_GET['id']
Related
I am trying to show it all with while loop on a dynamic page, but it wont show anything at all..
if (isset($_GET['id'])) {
$genre = $_GET['id'];
$sql = "SELECT * FROM movstream_genre WHERE ID = '$genre'";
$result = $db->query($sql);
$row = $result->fetch_assoc();
}else{
$sql = "SELECT ID, genre FROM movstream_genre";
$result = $db->query($sql);
}
<html>
<body>
<ul>
<?php while ( $row = $result->fetch_assoc() ): ?>
<li><?=$row['genre'];?></li>
<?php endwhile; ?>
</ul>
</body>
</html>
Anyone know why it wont show anything on the dynamic page, but if the page is not dynamic it works fine :)
Thanks.
If dynamic page means that your sending an id in Url an you are not getting result.
I think that the problem is that you are using $row = $result->fetch_assoc(); in if condition and also in while.
Please use fetching in one place. Better be in while loop.
Hope it helps.
I figured it out
if (isset($_GET['id'])) {
$genre = $_GET['id'];
$sql = "SELECT ID, genre FROM movstream_genre";
$result = $db->query($sql);
}
This it how it needs to look when its a dynamic page :)
well i think it is, it works now.
please echo the result ...
<li><?php echo $row['genre'];?></li>
And in href, it is only genre OR genre.php
In the first query..
$sql = "SELECT * FROM movstream_genre WHERE ID = '$genre'";
$result = $db->query($sql);
$row = $result->fetch_assoc();// this line not required
comment this line
$row = $result->fetch_assoc();
It looks like you haven't enclosed the first part of your PHP code in <?php ?> tags
I have made a connection to mysql database and echoing values from a table.
while($data = mysql_fetch_array($res))
{
?>
<a href="nextpage.php"<?php echo $data['rowname'] ?></a>
<?php
}
?>
Problem is when I click on the particular link, on the nextpage.php, it should display only the result of the value of a href clicked. So on the nextpage.php, I have defined something like SELECT * from tablename where rowname = 'a href value'.
What's happening now is that it displays only the last rowname value regardless of whichever link I click on, very obvious!
I have tried forms, arrays, SESSIONS but to no avail. How do I fix this?
the href should be like this
<?php echo $data['rowname']; ?>
and then on next page you can use $_GET['val'] and pass it to SELECT query
Try example as below
page1.php
while($data = mysql_fetch_array($res))
{
echo "<a href='nextpage.php?id=".$data['rowname']." >". $data['rowname'] ."</a>";
}
?>
your href will look like nextpage.php?id=[your value]
nextpage.php
$qry = mysql_query("select * from [table_name] where id = ".$_GET['id']."",$con);
while($data = mysql_fetch_array($res))
{
echo $data[0];
}
on nextpage pass value using $_GET['id'] to sql query.
I currently have this code which displays all required information on the page:
$sql = "select * from livecalls ORDER BY Completion_Date ";
$query = mysql_query( $sql );
while( $row = mysql_fetch_assoc($query) )
{
echo "<tr><td>$row[ID]</td>";
echo "<td>$row[Type]</td>";
echo "<td>$row[VNC_Number]</td>";
echo "<td>$row[Completion_Date]</td>";
echo "<td>$row[Logged_By]</td></tr>";
}
echo "</table>";
This works fine, however I am wanting to be able to click the $row[ID] section to open a new window and display the $row[Problem] which is related to that ID number..
I'm struggling to think how to get the ID information across to a new page to be able to search for the right Problem information to display and the code to do this?
Any help would be appreciated.
You can use a anchor tag for this purpose like
echo "<tr><td><a href='yourpage.php?id=".$row[ID]."'>".$row[ID]."</a></td>";
and in new page, you can use
$_GET['id'] for getting the id.
Also while echoing html along with php variable try to do like this:
while( $row = mysql_fetch_assoc($query) )
{
echo "<tr><td><a href='yourpage.php'>".$row['ID']."</a></td>";
echo "<td>".$row['Type']."</td>";
echo "<td>".$row['VNC_Number']."</td>";
echo "<td>".$row['Completion_Date']."</td>";
echo "<td>".$row['Logged_By']."</td></tr>";
}
I guess your not using any php framework (ex. codeigniter). Because if you do,this is easy using routing.
The very basic solution is Passing variables in a URL
http://html.net/tutorials/php/lesson10.php
Then if you want it to open in a new window instead of current window use
Use _blank in your a href
Visit W3Schools!
$sql = "select * from livecalls ORDER BY Completion_Date ";
$query = mysql_query( $sql );
while( $row = mysql_fetch_assoc($query) )
{
echo "<tr><td><a href='your_url/?id=".$row[ID]."'>$row[ID]</a>`enter code here`</td>";
echo "<td>$row[Type]</td>";
..
...
....
I am having some difficulty using PHP with jQTouch. I am fairly
confident with JavaScript however my PHP skills are little to none.
I am creating an application for my final year project at University
what displays football rumours posted by different users. My problem
is as follows:
I have one screen that displays each individual rumour, using a while
loop in PHP I am able to get each rumour from the database and display
them correctly. However I want to be able to click on one rumour which
then displays this rumour in a different screen, along with options to
reply/share etc. However I do not know how to tell which rumour has
been clicked on.
Snippets of my code:
All rumours page:
<?php
$q1 = "SELECT * FROM tblrumours;";
$r1 = mysql_query($q1);
while( $row1 = mysql_fetch_assoc($r1) ){
?>
<a class="rumourTag submit" id="<?php echo $row1['rumourID']; ?>">
<div class='oneRumour'>
<div class='standardBubble'>
<p>
<?php
$userID = $row1['userID'];
$q2 = "SELECT * FROM tblusers WHERE userID = $userID;";
$r2 = mysql_query($q2);
while( $row2 = mysql_fetch_array($r2) ){
$username = $row2['username'];
$teamID = $row2['teamID'];
}
$q5 = "SELECT * FROM tblteams WHERE teamID = $teamID;";
$r5 = mysql_query($q5);
while( $row5 = mysql_fetch_array($r5) ){
echo "<img src='img/".$row5['teamPicture']."' alt=''
class='teamImg' />";
}
?>
<span class='username'>
<?php
echo $username;
?>
</span>
<br/>
<span class='rumourMsg'><?php echo $row1['rumourText']; ?></
span>
</p>
</div>
</a>
SINGLE RUMOURS PAGE:
<?php
$q1 = "SELECT * FROM tblrumours WHERE rumourID = 1;"; /* NEED
TO SELECT WHERE RUMOUR ID IS THE ONE THAT IS CLICKED */
$r1 = mysql_query($q1);
while( $row1 = mysql_fetch_array($r1) ){
?>..........
I have tried using Session variables, storing the ID's in an array,
creating a separate php file for the single rumour page, and all to no
avail. I am guessing I have to use AJAX in some way, but I have no
idea where to even begin. Any help is greatly appreciated!
Thanks!
If you need to click on a rumour to see more details about it, you could always output in the HTML a unique value used to reference that rumour in the DB.
e.g. have <span class='rumourMsg' id='rumourName'> where rumourName is a unique value stored in your database to reference that rumour. Then when a user clicks to see more details, you can make a request to the PHP page with that value and return the content.
e.g. rumourDetails?rumourName=uniqueRumourName
(make sure to escape all your data properly to avoid SQL injection vulnerabilities.)
I've scoured the web for a tutorial about this simple task, but to no avail. And so I turn to you helpful comrades. Here's what I need to do:
I have a MySQL database with an Events table. I need to create a PHP web page with a list of the Event titles, and each title must be a link to the full details of the Event. But I want to avoid having to create a static page for each event, primarily because I don't want the data entry volunteer to have to create these new pages. (Yes, I realize that static pages are more SEO friendly, but I need to forego that in this case for the sake of efficiency.)
I've seen PHP url syntax with something like this:
pagename.php?id=20
but I don't know how to make it work.
Any and all help greatly appreciated.
Thanks!
Kip
This is basic php. You would simply query the DB for the event details before the page headers are written and write the html accordingly.
The first thing I would ask you is if you know how to connect to your database. From there, you query based on the $_GET['id'] value and use the results to populate your html.
Not to be rude, but the question itself suggests you're new to PHP, right? So in order to provide a solution that works we might want to know just how far you got.
Also, you can rewrite your dynamic urls to appear like static ones using apache's mod_rewrite. It's probably a novice level thing if you're interested in "pretty" url's.
MODIFIED ANSWER:
In your loop you would use the id from the query result (assuming your primary key is id)...
while($field = mysql_fetch_array($result)) {
echo "<p class='date'>";
echo $field['month']." ".$field['day'].", ".$field['year'];
echo "</p>";
echo "<h3>";
echo ''.$field['event_name'].'';
echo "</h3>";
}
Then on somepage.php you would use the get var id to pull the relevant info...
$result = mysql_query("SELECT * FROM `calendar` WHERE `id` = '".mysql_real_escape_string($_GET['id'])."');
don't forget to look into mysql_real_escape_string() for cleaning entries.
It's wise to take extra care when you are using $_GETvariables, because them can be easily altered by a malicious user.
Following with the example, you could do:
$foo = (int)$_GET['id'];
So we are forcing here the cast of the variable to a integer so we are sure about the nature of the data, this is commonly used to avoid SQL injections.
lets say you have the php file test.php
<?php
$conn = mysql_connect("localhost", "root", "");
mysql_select_db("db", $conn);
$id = $_GET['id'];
$sql = "select * from table where id = $id";
$result = mysql_query($sql, $conn);
if ($result){
$row = mysql_fetch_row($result);
$title = $row[0];
$content = $row[1];
}
?>
<html>
<head>
<title><?php echo $title ?></title>
</head>
<body>
<h1><?php echo $title ?></h1>
<p><?php echo $content ?></p>
</body>
</html>
a dynamic page would be something like that..
Here is the pertinent code for extracting a list of events in November from a table named calendar, with each event having a link to a page called event.php and with the event's id field appended to the end of the url:
$result = mysql_query("SELECT * FROM calendar WHERE sort_month='11'");
while($row = mysql_fetch_array($result))
{echo
"<a href='event.php?id=".$row['id']."'>".$row['event_name']."</a>"
;}
And here is the pertinent code on the event.php page. Note the row numbers in brackets depends on the placement of such in your table, remembering that the first row (field) would have the number 0 inside the brackets:
$id = $_GET['id'];
$sql = "select * from calendar where id = $id";
$result = mysql_query($sql, $con);
if ($result){
$row = mysql_fetch_row($result);
$title = $row[12];
$content = $row[7];
}
?>
<html>
<head>
<title><?php echo $title ?></title>
</head>
<body>
<h1><?php echo $title ?></h1>
<p><?php echo $content ?></p>
</body>
</html>
This works for me, thanks to the help from those above.
$foo=$_GET['id'];
in your example $foo would = 20