I want to check two arrays. If the value of one array anybody equal then $response:1 and otherwise for $response:0
example arrays:
{"data_comment":[{"name":"a"},{"address":"b"},{"age":"16"}]}
{"data_comment2":[{"name":"b"},{"address":"e"},{"age":"18"}]}
file php :
if($data_comment==$data_comment2){
$response2["success"] = "1";
// echoing JSON response
echo json_encode($response2);
} else {
$response2["success"] = "0";
$response2["message"] = "Error";
// echoing JSON response
echo json_encode($response2)
}
so , if any value of data_comment is same with data_comment2 value, then result will be false [$response2["success"] = "0"; ]..
but with my code, result always show [$response2["success"] = "1"; ] , there's is not same value at all between data_comment and data_comment2 .
thanks for any advice
Related
I echoed this and fetched in ajax .
$result= $this->mpesa->STKPushQuery($checkoutRequestID, 174379, "bfb279f9aa9bdbcf158e97dd71a467cd2e0c893059b10f78e6b72ada1ed2c919");
The results am getting in json is:
{"requestId":"","errorCode":"400.002.02","errorMessage":"Bad Request - Invalid CheckoutRequestID"}
Now in my php code I need to get the Keys of errorCode that sometimes is a successCode so when I try this:
if ($result->errorCode=="400.002.02"){
$Data = '{"status":"Submit payment before Checking for it"}';
echo $Data;
Its fine because the errorCode is found in Json. When there is a success message i.e:
if ($result->successCode=="0"){
$Data = '{"status":"Payment Successful"}';
echo $Data;
}
I get an error with the first statement. Because errorCode is not found in Json
So what I actually need is to get the key of json(which will be either errorCode or successCode)
i.e
$mystatusCode== Get the either the errorCode or SuccessCode (key in Json array[1])
if ($results->mystatusCode=="400.002.02"){
$Data = '{"status":"Submit payment before Checking for it"}';
echo $Data;
}else if ($results->mystatusCode=="0"){
$Data = '{"status":"Payment has been processed successfully"}';
echo $Data;
}
Using isset will accomplish your goal:
$mystatusCode = ( isset($result->errorCode) ? $result->errorCode :
( isset($result->successCode) ? $result->successCode :
NULL
)
);
Or you can just use it in the if statements directly without making a new single var:
if (isset($result->errorCode) && $result->errorCode == "400.002.02") {
...
}
elseif (isset($result->successCode) && $result->successCode == "0") {
...
}
I like to check if there is data in the repository:
$dataCollection = $this->em->getRepository(Data::class)->DataConnector($fieldId,$id);
if(isset($dataCollection)){
echo "this contains data";
} else {
echo "this does not contain data";
}
But even if no data is in the repository, I always get the message "this contains data".
The output ([]) is an empty array. An empty array IS set:
$x = [];
print_r(isset($x)); // 1
print_r(empty($x)); // 1
print_r(count($x)); // 0
You need either count or empty.
$dataCollection = $this->em->getRepository(Data::class)->DataConnector($fieldId,$id);
if(dataCollection != NULL){
echo "this contains data";
} else {
echo "this does not contain data";
}
I am receiving post values. I want a suggestion for logic to handle empty or not set post values.
Is there such a way if one of them receives empty post, the $Data array should not receive anymore values and make it empty. In other words, i am trying to immitate the try and catch feature. If on any POST is empty, ignore reading the rest of POST and make that array as empty
Is my second draft considred valid?
First draft
if(!empty(isset($_POST["SHOWSCHEDULE_SHOWTYPE"]))){
$DATA["SHOWSCHEDULE_SHOWTYPE"] = $_POST["SHOWSCHEDULE_SHOWTYPE"];
}
if(!empty(isset($_POST["SHOWSCHEDULE_SHOWTITLE"]))){
$DATA["SHOWSCHEDULE_SHOWTITLE"] = $_POST["SHOWSCHEDULE_SHOWTITLE"];
}
if(empty($DATA)){
//do something
}else{
//do something else
}
Second draft
try{
if(!empty(isset($_POST["SHOWSCHEDULE_SHOWTITLE"]))){
$DATA["SHOWTITLE"] = $_POST["SHOWSCHEDULE_SHOWTITLE"];
}else{
throw new Exception('POST SHOWSCHEDULE_SHOWTITLE');
}
if(!empty(isset($_POST["SHOWSCHEDULE_SHOWTYPE"]))){
$DATA["SHOWTYPE"] = $_POST["SHOWSCHEDULE_SHOWTYPE"];
}else{
throw new Exception('POST SHOWSCHEDULE_SHOWTYPE');
}
} catch (Exception $e) {
echo 'ERROR: ', $e->getMessage(), "\n";
unset($DATA);
}
You can use one if statement with all required POST parameters.
if(!empty($_POST['var1']) && !empty($_POST['var2']) && !empty($_POST['var3']) && !empty($_POST['var4'])):
/*and then assign all the POST values to a $DATA array as you want.*/
$DATA['var1'] = $_POST['var1'];
$DATA['var2'] = $_POST['var2'];/* and so on..*/
endif;
I personally prefer to white list values that I loop through and assign.
<?php
$valid_keys = ['SHOWSCHEDULE_SHOWTYPE', 'SHOWSCHEDULE_SHOWTITLE'];
$at_least_one_empty = false;
foreach($valid_keys as $data_key)
{
$data[$data_key] = isset($_POST[$data_key])
? trim($_POST[$data_key]) // Remove accidental user whitespace.
: ''; // If unsubmitted - set to empty string.
if($data[$data_key] === '')
$at_least_one_empty = true;
}
if($at_least_one_empty) {
unset($data);
} else {
process($data);
}
Note with the sample code above an unsubmitted value will be assigned the empty string. This might not be the behaviour you want.
However if you just want to assign and check you received all inputs this might do (no filtering or validation):
<?php
$valid_keys = ['SHOWSCHEDULE_SHOWTYPE', 'SHOWSCHEDULE_SHOWTITLE'];
foreach($valid_keys as $data_key)
$data[$data_key] = $_POST[$data_key] ?? null;
$not_all_received = in_array(null, $data, true);
I am trying to GET different rows from different columns in php/mysql, and pack them into an array. I am able to successfully GET a jason encoded array back IF all values in the GET string match. However, if there is no match, the code echos 'no match', and without the array. I know this is because of the way my code is formatted. What I would like help figuring out, is how to format my code so that it just displays "null" in the array for the match it couldn't find.
Here is my code:
include '../db/dbcon.php';
$res = $mysqli->query($q1) or trigger_error($mysqli->error."[$q1]");
if ($res) {
if($res->num_rows === 0)
{
echo json_encode($fbaddra);
}
else
{
while($row = $res->fetch_array(MYSQLI_BOTH)) {
if($_GET['a'] == "fbaddra") {
if ($row['facebook'] === $_GET['facebook']) {
$fbaddr = $row['addr'];
} else {
$fbaddr = null;
}
if ($row['facebookp'] === $_GET['facebookp']) {
$fbpaddr = $row['addr'];
} else {
$fbpaddr = null;
}
$fbaddra = (array('facebook' => $fbaddr, 'facebookp' => $fbpaddr));
echo json_encode($fbaddra);
}
}
}
$mysqli->close();
UPDATE: The GET Request
I would like the GET request below to return the full array, with whatever value that didn't match as 'null' inside the array.
domain.com/api/core/engine.php?a=fbaddra&facebook=username&facebookp=pagename
The GET above currently returns null.
Requests that work:
domain.com/api/core/engine.php?a=fbaddra&facebook=username or domain.com/api/core/engine.php?a=fbaddra&facebookp=pagename
These requests return the full array with the values that match, or null for the values that don't.
TL;DR
I need assistance figuring out how to format code to give back the full array with a value of 'null' for no match found in a row.
rather than assigning as 'null' assign null. Your full code as follows :
include '../db/dbcon.php';
$res = $mysqli->query($q1) or trigger_error($mysqli->error."[$q1]");
if ($res) {
if($res->num_rows === 0)
{
echo json_encode('no match');
}
else
{
while($row = $res->fetch_array(MYSQLI_BOTH)) {
if($_GET['a'] == "fbaddra") {
if ($row['facebook'] === $_GET['facebook']) {
$fbaddr = $row['dogeaddr'];
//echo json_encode($row['dogeaddr']);
} else {
$fpaddr = null;
}
if ($row['facebookp'] === $_GET['facebookp']) {
$fbpaddr = $row['dogeaddr'];
//echo json_encode($row['dogeaddr']);
} else {
$fbpaddr = null;
}
$fbaddra = (array('facebook' => $fbaddr, 'facebookp' => $fbpaddr));
echo json_encode($fbaddra);
}
}
}
$mysqli->close();
You can even leave else part altogether.
Check your code in this fragment you not use same names for variables:
if ($row['facebook'] === $_GET['facebook']) {
$fbaddr = $row['dogeaddr'];
//echo json_encode($row['dogeaddr']);
} else {
$fpaddr = 'null';
}
$fbaddr not is same as $fpaddr, this assign wrong result to if statement.
It was the mysql query that was the problem.
For those who come across this, and need something similar, you'll need to format your query like this:
** MYSQL QUERY **
if ($_GET['PUTVALUEHERE']) {
$g = $_GET['PUTVALUEHERE'];
$gq = $mysqli->real_escape_string($g);
$q1 = "SELECT * FROM `addrbook` WHERE `facebookp` = '".$gq."' OR `facebook` = '".$gq."'";
}
** PHP CODE **
if($_GET['PUTVALUEHERE']{
echo json_encode($row['addr']);
}
I am trying to check if the mysql_fetch_array() function returns an empty array or not. But my code doesn't seem to work. Here I want to ensure that if the array is empty I want to display under construction message.
Code :
$queryContents= queryMembers();
$exeQuery = mysql_query($queryContents);
while($fetchSet = mysql_fetch_array($exeQuery)) {
if(count($fetchSet) == 0) {
echo "This Page is Under Construction";
}else{
// something else to display the content
}
}
How do I check to acheive such feature ?
use mysql_num_rows to count number of rows. try this.
$exeQuery = mysql_query($queryContents);
if(mysql_num_rows($exeQuery)== 0){
echo "This Page is Under Construction";
}
else{
while($fetchSet = mysql_fetch_array($exeQuery)) {
// something else to display the content
}
}
You really should be using mysql_num_rows http://us2.php.net/manual/en/function.mysql-num-rows.php
However, on a side note, you should use php empty() instead. http://us2.php.net/empty
When you use mysql_fetch_array(), it returns the rows from the data
set one by one as you use the while loop.
If there will be no record, while loop wont execute. In this case, declare a boolean variable and make it true if it enters the while loop. Like:
$queryContents= queryMembers();
$exeQuery = mysql_query($queryContents);
$recordExists = 0;
while($fetchSet = mysql_fetch_array($exeQuery)) {
if($recordExists == 0 )
$recordExists = 1;
// something else to display the content
}
if($recordExists == 0 ){
echo "This Page is Under Construction";
}
Hope this works!
You can do it this way:
while($r[]=mysql_fetch_array($sql));
// now $r has all the results
if(empty($r)){
// do something
}
source: php doc
Your code inside the while loop never runs if there are no results. mysql_fetch_array returns null/false if there are no more results. What you need yo do is check with mysql_num_rows first, before the while.
$queryContents= queryMembers();
$exeQuery = mysql_query($queryContents);
if(mysql_num_rows ($exeQuery) == 0) {
echo "This Page is Under Construction";
}
while($fetchSet = mysql_fetch_array($exeQuery)) {
// something else to display the content
}
Try this
if(empty($fetchSet)
{
echo "This Page is Under Construction";
}
else
{
// something else to display the content
}