How can I check if my repository contains data? - php

I like to check if there is data in the repository:
$dataCollection = $this->em->getRepository(Data::class)->DataConnector($fieldId,$id);
if(isset($dataCollection)){
echo "this contains data";
} else {
echo "this does not contain data";
}
But even if no data is in the repository, I always get the message "this contains data".

The output ([]) is an empty array. An empty array IS set:
$x = [];
print_r(isset($x)); // 1
print_r(empty($x)); // 1
print_r(count($x)); // 0
You need either count or empty.

$dataCollection = $this->em->getRepository(Data::class)->DataConnector($fieldId,$id);
if(dataCollection != NULL){
echo "this contains data";
} else {
echo "this does not contain data";
}

Related

if print_r is empty conditional in PHP

I'm trying to get a n else statement working with a print_r such that if there's no value it outputs "no values".
In the code I'm getting values from json converted to an array.
The logic I'm trying to achieve is
IF fieldTag contains "i" THEN output the content associated with it
ELSE says its empty.
Right now blank is outputted as opposed to "no values".
Thanks
for($b=0; $b<count($res['entries'][$i]['bib']['varFields']); $b++) //loop thru the varFields
{
if($res['entries'][$i]['bib']['varFields'][$b]['fieldTag'] == "i")
{
$subfieldText2 = $res['entries'][$i]['bib']['varFields'][$b]['subfields'][0]['content']."<br>";
if(count($subfieldText2) > 0) {
print_r($subfieldText2);
} else {
echo "no values";
}
}
}
count() is for arrays, not strings, the way to get the length of a string is with strlen(). And if you want to check for an empty string, just compare it with $var == "", you don't need to get the length.
But you're concatenating "<br>" to the value, so the length will never be zero. You could check the length before concatenating.
$subfieldText2 = $res['entries'][$i]['bib']['varFields'][$b]['subfields'][0]['content'];
if($subfieldText2 != "") {
$subfieldText2 .= "<br>";
print_r($subfieldText2);
} else {
echo "no values";
}
And to avoid having to repeat that long expression to access the field, you could use foreach
for($res['entries'][$i]['bib']['varFields'] as $field) {
if ($field['fieldTag'] == "i") {
$subfieldText2 = $field['subfields'][0]['content'];
...
}
}
this worked for me thanks everyone
$subfieldText2="not detected";
echo "ISBN: ";
for($b=0; $b<count($res['entries'][$i]['bib']['varFields']); $b++) //loop thru the varFields
{
if($res['entries'][$i]['bib']['varFields'][$b]['fieldTag'] == "i")
{
$subfieldText2 = $res['entries'][$i]['bib']['varFields'][$b]['subfields'][0]['content'];
echo $subfieldText2.", ";
}
}
echo $subfieldText2;

Comparing array to string PHP

I want to check if the data is match between array and the string.
Im trying to check if the string is equals to each other but the problem is the condition is returning false and both value of $subex2[1] and $subdat is IT100. I think the problem is you can't compare an array to a string. Can someone help me about this?
here's the code
$subex = $objPHPExcel->getActiveSheet()->getCell('D8')->getValue();
$subex2 = explode(":", $subex);
$q = "select * from class where id='$id'";
$r = mysql_query($q);
$data = mysql_fetch_array($r);
$subdat = $data['subject'];
if($subdat == $subex2[1]) {
echo "Data matched";
}else {
echo "Data doesn't matched";
}
As mentioned in the comments. One value has an space before it. You can solve this kind of problems like this:
if(trim($subdat) == trim($subex2[1])) {
echo "Data matched";
} else {
echo "Data doesn't matched";
}
for case sensitive issue, this trick should apply.
if(strtolower(trim($subdat)) == strtolower(trim($subex2[1]))) {
echo "Data matched";
} else {
echo "Data doesn't matched";
}
this test works fine
$subdat = "IT100";
$subex2[1] = "IT100";
if($subdat == $subex2[1]) {
echo "Data matched";
}
You are not comparing same string
You first use array_map and trim values, delete space, next use in_array, example
$subex2 = array_map('trim',$subex2);
if( is_array($subex2) ){
if(in_array($subdata, $subex2)){
echo "Data matched";
} else {
echo "Data doesn't matched";
}
}
It's always good to check if it's actually an array, with is_array
Reference in_array https://www.w3schools.com/php/func_array_in_array.asp
try this:
$isMatched = strval($subex2[1]) === strval($subdat) ?: false;

$_POST Number and Character checker

This is a repeat question of Check $_POST['id'] is numeric then do this if not do otherwise
But..
The answers given do not answer the question IMHO.
The question is testing a $_POST string to see if it is a number or contains non-numeric characters. Not change the code to use $_GET.
The original question is as such:
if (!empty($_POST['id'])) {
echo "empty";
} else {
if (is_numeric($_POST['id'])) {
echo "numeric!";
} else {
echo "not empty but not numeric how come?";
}
}
I have tried, is_numeric() , but since $_POST delivers the variable as a string, even if it is a number this is useless.
I have tried, if(!preg_match('#[^0-9]#',$id)), but I have no idea why this doesn't work.
ctype_digit() I believe still has a problem with seeing all things from $_POST as strings, so no good.
There has to be a way, but I'm lost on how to do this. And no I can't use $_GET.
UPDATE ANSWER!!! (TYPO!!!!! god dammit!!!!):
// test.php
// testing with $_POST['id'] from forum with id = 5 and another test where id = new
$id = $_POST['editid'] ;
echo "<br>---".$id."---<br>";
if (empty($id)) {
echo "<br>1: empty";
} else {
if (!is_numeric($id)) {
echo "<br>2: This is the number 5";
} else {
echo "<br>3: the must be the word new";
}
}
// test 2 ... ctype_digit
if (empty($id)) {
echo "<br>4: empty";
} else {
if (!ctype_digit($id)) {
echo "<br>5: This is the number 5";
} else {
echo "<br>6: the must be the word new";
}
}
// test 3 ...
if (empty($id)) {
echo "<br>7: empty";
} else {
if (!preg_match('#[^0-9]#',$id)) {
echo "<br>8: This is the number 5";
} else {
echo "<br>9: the must be the word new";
}
}
/**
result from 5
---5---
3: the must be the word new
6: the must be the word new
8: This is the number 5
results from "new"
**/

How to check equal of value arrays in JSON by PHP

I want to check two arrays. If the value of one array anybody equal then $response:1 and otherwise for $response:0
example arrays:
{"data_comment":[{"name":"a"},{"address":"b"},{"age":"16"}]}
{"data_comment2":[{"name":"b"},{"address":"e"},{"age":"18"}]}
file php :
if($data_comment==$data_comment2){
$response2["success"] = "1";
// echoing JSON response
echo json_encode($response2);
} else {
$response2["success"] = "0";
$response2["message"] = "Error";
// echoing JSON response
echo json_encode($response2)
}
so , if any value of data_comment is same with data_comment2 value, then result will be false [$response2["success"] = "0"; ]..
but with my code, result always show [$response2["success"] = "1"; ] , there's is not same value at all between data_comment and data_comment2 .
thanks for any advice

why can't array_search find the value if the code of the key is "gb2312"?

my questions:
$state=array("你"=>1);
if(array_key_exists("你",$state))
{
$result = array_search("你",$state);echo $result;
}else
{
echo "No Exists";
}
i expect the result of "1", however the output is "No Exists", i don't know why the program can't get the value of the key "你".
array_search will search the given array by value. Try the following:
$state = array("你"=>1);
if(array_key_exists("你", $state)) {
echo $state["你"];
} else {
echo "No Exists";
}
// => 1
» demo
Hope below function will help.
<?php
$array = array('arr1'=>array('find_me'=>'yes you did.'));
function get_value_by_key($array,$key)
{
foreach($array as $k=>$each)
{
if($k==$key)
{
return $each;
}
if(is_array($each))
{
if($return = get_value_by_key($each,$key))
{
return $return;
}
}
}
}
echo get_value_by_key($array,'find_me');
?>
the encoding type of the show paper and the store paper is GB2312.
$state=array("你"=>1);
if(array_key_exists("你",$state))
{
$result1 = $state["你"];
echo $result1; // can get the value 111
}else
{
echo "No Exists";
}
the code above can be executed rightly. i can't show my problems accurately. Now i paste out my code , there is some questions.
<?php
$file = file("GB2312-HanZiBianMa.txt"); // file encoding type ANSI
foreach ($file as $line_num => $line)
{
list($no,$hex,$dec) = preg_split('[\t]',htmlspecialchars($line));;
$result[$hex] = $dec;
}
$result_2 = array_flip($result);
if(array_key_exists("你",$result_2)) // **can't find the value** 222
{
$state= $result_2["你"];
echo $state."<br/>";
}else
{
echo "No Exists<br/>";
}
foreach($result_2 as $k=>$each) //can get the value using the preg_match
{
if(preg_match('/你/', $k))
echo $k."\t".$each."<br/>";
}
?>
the format of GB2312-HanZiBianMa.txt is as follows:
1947 c4e3 你
1948 c4e4 匿
1949 c4e5 腻
1950 c4e6 逆
if your want to test the code , you can save the php code and save the GB2312.. file.
the question is:
why can't the following function get the right value ? the data comes from file and one stores together.
if(array_key_exists("你",$result_2)) // **can't find the value** 222
{
$state= $result_2["你"];
echo $state."<br/>";
}else
{
echo "No Exists<br/>";
}

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