I'm using PHP and I do a mysql query and I save the result of this query in an array. Then, I use a loop and into the loop i do another mysql query using the values of the array in the where clause. It's right but if I try to get the result of the query outside the loop I can't.
Here an example code
$result=$mysqli->query("SELECT code FROM referee");
$i=0;
$arcode=array();
while($row=$result->fetch_array()){
$arcode[$i]=$row["code"];
$i++;
}
for($j=0;$j<sizeof($arcode);$j++){
$result2=$mysqli->query("SELECT code, time FROM match where referee_code IN ($arcode[$j])");
}
/*Here I can't get the result values*/
$matcode=array();
$hour=array();
$k=0;
while($row2=$result2->fetch_array()){
$matcode[$k]=$row2["code"];
$hour[$k]=$row2["time"];
}
If I put all in the same loop I get the result repeated (This code is one example of all my code but the idea is the same in the rest).
You are overwriting the result set values into $result2.
The correct method would be something like:
$matcode = array();
$hour = array();
$result2 = $mysqli->query("SELECT code,
time
FROM `match`
WHERE referee_code IN (SELECT code
FROM referee)");
while ($row2 = $result2->fetch_array())
{
$matcode[] = $row2["code"];
$hour[] = $row2["time"];
}
You may change the index values according to the way you want the array to look like.
Also match is a reserved word. So you would have to enclose it in backticks.
If you want to print complete data then try this :
$matcode = array();
$hour = array();
$result2 = $mysqli->query("SELECT code,
time
FROM `match`
WHERE referee_code IN (SELECT code
FROM referee)");
$completeData=array();
while ($row2 = $result2->fetch_array())
{
$completeData[] = $row2;
}
print_r($completeData);
Don forget to accept answer if it helps :)
Related
I created a script to get data from a mysql table for every year and put into array of respective year. I checked the sql and the while loop iteration is working.
<?php
mysql_select_db($database_hari,$hari);
$start=2013 ;
$end=2015;
$xdata=array();
for($year=$start;$year<=$end;$year++){
${"y".$year}=array();
$i=0;
$query=mysql_query("SELECT tld_master.location,tld_dose.year, AVG(tld_dose.dose)*4 as avgdose from tld_master left join tld_dose on tld_master.tldno=tld_dose.tldno where tld_master.site='F' and tld_dose.year=$year GROUP BY tld_dose.year, tld_dose.tldno");
while($result=mysql_fetch_array($query)){
$xdata[$i]=$result['location'];
${"y".$year."[".$i."]"}=$result['avgdose'];
$i++;
}
}
print_r($y2015);
?>
Print displays "Array()"
But if I am echoing each array value inside for loop it prints. Where is the mistake?
Although there are ways to solve your problem with variable variables, I suggest you take different approach. What if year is a value you do not expect? It can easily lead to confusion. Instead you can use an array that you can iterate through without knowing the exact value of the year.
$yearArray = array();
for($year=$start;$year<=$end;$year++){
$sql = "SELECT
tld_master.location,tld_dose.year, AVG(tld_dose.dose)*4 as avgdose
FROM tld_master
LEFT JOIN tld_dose on tld_master.tldno=tld_dose.tldno
WHERE tld_master.site='F' and tld_dose.year={$year}
GROUP BY tld_dose.year, tld_dose.tldno";
$query = mysql_query($sql);
$yearArray[$year] = array();
while($result=mysql_fetch_array($query)){
$xdata[] = $result['location'];
$yearArray[$year][] = $result['avgdose'];
}
}
Now you can print the $yearArray variable to see your actual results. And you can use it easily.
print_r($yearArray["2015"]);
${"y".$year} = array()
creates a variable named $y2015, holding an array. The code
${"y".$year."[".$i."]"} = ...
creates an oddly named variable $y2015[0], which is completely unrelated to the variable $y2015. You want:
${"y".$year}[$i] = ...
You override your array value with this statement ${"y".$year."[".$i."]"}=$result['avgdose']; Try to use this one instead: ${"y".$year."[".$i."]"}[]=$result['avgdose'];
I'm fairly new to php, and I don't know how to work with arrays very well. Here's the deal, I want to add into a multidimensional array three or more values I obtain from my database, then I want to sort them based on the timestamp (one of the values). After that, I want to show all of the sorted values. I can't seem to do this, here's the code
$queryWaitingPatients = 'SELECT ArrivalTime, TargetTime, Order, Classification FROM exams WHERE (CurrentState = "Pending")';
$results = mysql_query($queryWaitingPatients) or die(mysql_error());
if (mysql_num_rows($results) == 0) {
echo '<p>There\'s currently no patient on the waiting list.</p>';
return;
}
while ($rows = mysql_fetch_array($results)) {
extract($rows);
//now is the part that I don't know, putting the values into an array
}
// I'm also not sure how to sort this according to my $TargetTime
asort($sortedTimes);
//the other part I don't know, showing the values,
Thanks for the help!
Well, let's look at your code. First, you have a query that's returning a result set. I don't recommend using mysql_fetch_array because it's not only deprecated (use mysqli functions instead) but it tends to lend itself to bad code. It's hard to figure out what you're referencing when all your keys are numbers. So I recommend mysqli_fetch_assoc (be sure you're fully switched to the mysqli functions first, like mysql_connect and mysqli_query)
Second, I really dislike using extract. We need to work with the array directly. Here's how we do this
$myarray = array();
while ($rows = mysqlI_fetch_assoc($results)) {
$myarray[] = $rows;
}
echo $myarray[0]['ArrivalTime'];
So let's go over this. First, we're building an array of arrays. So we initialize our overall array. Then we want to push the rows onto this array. That's what $myarray[] does. Finally, the array we're pushing is associative, meaning all the keys of the row match up with the field names of your query.
Now, the sorting really needs to be done in your query. So let's tweak your query
$queryWaitingPatients = 'SELECT ArrivalTime, TargetTime, `Order`, Classification
FROM exams
WHERE CurrentState = "Pending"
ORDER BY TargetTime';
This way, when your PHP runs, your database now churns them out in the correct order for your array. No sorting code needed.
$arr = array();
while ($rows = mysql_fetch_array($results)) {
array_push ($arr, $row);
}
print_r($arr);
<?php
$queryWaitingPatients = ' SELECT ArrivalTime, TargetTime, Order, Classification, CurrentState
FROM exams
WHERE CurrentState = "Pending"
ORDER BY TargetTime ';
$results = mysql_query($queryWaitingPatients) or die(mysql_error());
if ($results -> num_rows < 1)
{
echo '<p>There\'s currently no patient on the waiting list.</p>';
}
else
{
while ($rows = mysqli_fetch_array($results))
{
$arrivaltime = $row['ArrivalTime'];
$targettime = $row['targettime'];
$order = $row['Order'];
$classification = $row['Classification'];
echo "Arrival: ".$arrivaltime."--Target time: ".$targettime."--Order: ".$order."--Classification: ".$classification;
}
}
echo "Done!";
//or you could put it in a json array and pass it to client side.
?>
I'm using this script to get data from a database
$sql = "SELECT * FROM items WHERE catid = 1";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result)){
echo $row['extra_fields'];
}
The output is:
[{"id":"1","value":"johndoe"},{"id":"2","value":"marydoe"}]
I want to extract/print only the value corresponding to "id":"1" (that in this case is 'johndoe'). I'm not able to extract it from the above data type.
To read JSON in PHP use
while($row = mysql_fetch_array($result)){
$array = json_decode($row['extra_fields'];
// Do something with $array['id']
}
Did you realise you can directly go for that data in MySQL?
SELECT value FROM items WHERE id = 2;
edit:
Basically your query is
SELECT comma-separated column names or star for all, use only what you really need to save bandwidth, e.g. SELECT id, value
FROM table-name, e.g. FROM mytable
WHERE columnname = desired value, e.g. WHERE id = 2
You want to query only the required columns in the required rows. Imagine one day you would have to parse 1 million users every time you want to get an id... :)
The output is JSON. Use PHP's json_decode function.
while($row = mysql_fetch_array($result)){
$array = json_decode($row['extra_fields']);
foreach($array AS $item) {
echo $item['id'];
}
}
Currently this is the code that fits my needs:
while($row = mysql_fetch_array($result)){
$array = json_decode($row['extra_fields']);
$value = $array[0]->value;
}
You should do it in the mysql query part. For example, set the ID = 1 in the query.
I need help in order to assign the results of a nested query into array. This is the scenario:
$Date_Collection = mysql_query("SELECT DISTINCT Date FROM TblDate");
while($date = mysql_fetch_array($Date_Collection)) // Loop through all the dates
{
$var_date = $date['Date'];
$result = mysql_query("select min(Speed) as Min_spd, max (Speed) as Max_spd, avg
(Speed) as Avg_spd from ... where Date= $var_date");
while($row = mysql_fetch_array($result))
{
echo "row[Min_spd]";
echo "row[Max_spd]";
echo "row[Avg_spd]";
}
}
The output from this query is like this:
Min_Spd |Max_Spd |Avg_Spd| Date|
12.0| 25.0| 20.4| 2012-10-01|
11.0| 28.0| 21.4| 2012-10-02|
10.0| 26.0| 23.4| 2012-10-05|
08.0| 22.0| 21.4| 2012-10-08|
I basically need to show the sum of Min_Spd, Sum of Max_spd, Sum of Avg_spd for all these dates. So, I thought that If I can assign these values into an array and later compute these sum from the array, it might be a good idea.
Can anyone please help me regarding this? Can I use an array to store the values and later access these values and calculate the sum of these values. If I can use an array, could anyone please show me the syntax of using array in PHP. I would really appreciate any help regarding this.
Is there any alternative way rather than using an array, such as creating a temporary table to save these values and later delete the temporary table. If a temporary table can be used, could you please show me how to do that. I could use the temptable for a single loop, but there is a nested loop and I don't exactly know what to do to create a temp table inside the nested loop to store all the values.
$data = array();
while ($row = mysql_fetch_assoc($result)) {
$data[] = $row;
}
then later on you can do
foreach($data as $row) {
echo $row['Min_spd'];
echo ...
...
}
I don't know if the MySQL SUM function can be used to do that on te query, try it. But on this example, using arrays you should store the values and then use array_sum to return the sum of the elements. Something like this:
$min_spd = array();
$max_spd = array();
$avg_spd = array();
while($row = mysql_fetch_assoc($result))
{
$min_spd[] = $row['Min_spd'];
$max_spd[] = $row['Max_spd'];
$avg_spd[] = $row['Avg_spd'];
}
echo array_sum($min_spd);
It can also be done using variables to store and add the values:
$min_spd = 0;
$max_spd = 0;
$avg_spd = 0;
while($row = mysql_fetch_assoc($result))
{
$min_spd += $row['Min_spd'];
$max_spd += $row['Max_spd'];
$avg_spd += $row['Avg_spd'];
}
echo $min_spd;
I would first of all save yourself a nested query by doing the first query as:
$result = mysql_query("select Date, min(Speed) as Min_spd, max (Speed) as Max_spd, avg(Speed) as Avg_spd from ... group by Date")
And then create a running total for the sums as you're looping through each row:
$sumMinSpeeds=0;
$sumMaxSpeeds=0;
$sumAvgSpeeds=0;
while($row = mysql_fetch_array($result))
{
echo row['Min_spd'];
echo row['Max_spd'];
echo row['Avg_spd'];
$sumMinSpeeds += $row['Min_spd'];
$sumMinSpeeds += $row['Max_spd'];
$sumMinSpeeds += $row['Avg_spd'];
}
echo $sumMinSpeeds;
echo $sumMaxSpeeds;
echo $sumAvgSpeeds;
Instead of doing several MySQL queries in a loop, consider constructing such a query, which will return all the results you need.
SQL
First of all, it would make sense to use the GROUP SQL construct.
SELECT
s.Date date,
MIN(s.Speed) min,
MAX(s.Speed) max,
AVG(s.Speed) avg
FROM speed_table s
WHERE s.Date IN (SELECT DISTINCT d.Date FROM date_table d)
GROUP BY s.Date
It is important to understand what each part of this query does. If you run into any problems, consult the MySQL reference manual.
PHP
Forget about using mysql_* functions: they are deprecated and better implementations have emerged: PDO and mysqli. My example uses PDO.
try {
$dbh = new \PDO('mysql:dbname=my_db_name;host=127.0.0.1', 'dbuser', 'dbpass');
} catch (\PDOException $e) {
echo 'Connection failed: ' . $e->getMessage();
}
$sql = '...'; // This is the query
$stmt = $pdo->prepare($sql);
$stmt->execute();
You can now either iterate over the returned result set
while ($row = $stmt->fetch()) {
printf("%s; %s; %s; %s\n", $row['date'], $row['min'], $row['max'], $row['avg']);
}
or have the Statement object return the whole array by using
$result = $stmt->fetchAll(\PDO::FETCH_ASSOC);
How can i get every row of a mysql table and put it in a php array? Do i need a multidimensional array for this? The purpose of all this is to display some points on a google map later on.
You need to get all the data that you want from the table. Something like this would work:
$SQLCommand = "SELECT someFieldName FROM yourTableName";
This line goes into your table and gets the data in 'someFieldName' from your table. You can add more field names where 'someFieldName' if you want to get more than one column.
$result = mysql_query($SQLCommand); // This line executes the MySQL query that you typed above
$yourArray = array(); // make a new array to hold all your data
$index = 0;
while($row = mysql_fetch_assoc($result)){ // loop to store the data in an associative array.
$yourArray[$index] = $row;
$index++;
}
The above loop goes through each row and stores it as an element in the new array you had made. Then you can do whatever you want with that info, like print it out to the screen:
echo $row[theRowYouWant][someFieldName];
So if $theRowYouWant is equal to 4, it would be the data(in this case, 'someFieldName') from the 5th row(remember, rows start at 0!).
$sql = "SELECT field1, field2, field3, .... FROM sometable";
$result = mysql_query($sql) or die(mysql_error());
$array = array();
while($row = mysql_fetch_assoc($result)) {
$array[] = $row;
}
echo $array[1]['field2']; // display field2 value from 2nd row of result set.
The other answers do work - however OP asked for all rows and if ALL fields are wanted as well it would much nicer to leave it generic instead of having to update the php when the database changes
$query="SELECT * FROM table_name";
Also to this point returning the data can be left generic too - I really like the JSON format as it will dynamically update, and can be easily extracted from any source.
while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
echo json_encode($row);
}
You can do it without a loop. Just use the fetch_all command
$sql = 'SELECT someFieldName FROM yourTableName';
$result = $db->query($sql);
$allRows = $result->fetch_all();
HERE IS YOUR CODE, USE IT. IT IS TESTED.
$select=" YOUR SQL QUERY GOOES HERE";
$queryResult= mysql_query($select);
//DECLARE YOUR ARRAY WHERE YOU WILL KEEP YOUR RECORD SETS
$data_array=array();
//STORE ALL THE RECORD SETS IN THAT ARRAY
while ($row = mysql_fetch_array($queryResult, MYSQL_ASSOC))
{
array_push($data_array,$row);
}
mysql_free_result($queryResult);
//TEST TO SEE THE RESULT OF THE ARRAY
echo '<pre>';
print_r($data_array);
echo '</pre>';
THANKS