How can i get every row of a mysql table and put it in a php array? Do i need a multidimensional array for this? The purpose of all this is to display some points on a google map later on.
You need to get all the data that you want from the table. Something like this would work:
$SQLCommand = "SELECT someFieldName FROM yourTableName";
This line goes into your table and gets the data in 'someFieldName' from your table. You can add more field names where 'someFieldName' if you want to get more than one column.
$result = mysql_query($SQLCommand); // This line executes the MySQL query that you typed above
$yourArray = array(); // make a new array to hold all your data
$index = 0;
while($row = mysql_fetch_assoc($result)){ // loop to store the data in an associative array.
$yourArray[$index] = $row;
$index++;
}
The above loop goes through each row and stores it as an element in the new array you had made. Then you can do whatever you want with that info, like print it out to the screen:
echo $row[theRowYouWant][someFieldName];
So if $theRowYouWant is equal to 4, it would be the data(in this case, 'someFieldName') from the 5th row(remember, rows start at 0!).
$sql = "SELECT field1, field2, field3, .... FROM sometable";
$result = mysql_query($sql) or die(mysql_error());
$array = array();
while($row = mysql_fetch_assoc($result)) {
$array[] = $row;
}
echo $array[1]['field2']; // display field2 value from 2nd row of result set.
The other answers do work - however OP asked for all rows and if ALL fields are wanted as well it would much nicer to leave it generic instead of having to update the php when the database changes
$query="SELECT * FROM table_name";
Also to this point returning the data can be left generic too - I really like the JSON format as it will dynamically update, and can be easily extracted from any source.
while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
echo json_encode($row);
}
You can do it without a loop. Just use the fetch_all command
$sql = 'SELECT someFieldName FROM yourTableName';
$result = $db->query($sql);
$allRows = $result->fetch_all();
HERE IS YOUR CODE, USE IT. IT IS TESTED.
$select=" YOUR SQL QUERY GOOES HERE";
$queryResult= mysql_query($select);
//DECLARE YOUR ARRAY WHERE YOU WILL KEEP YOUR RECORD SETS
$data_array=array();
//STORE ALL THE RECORD SETS IN THAT ARRAY
while ($row = mysql_fetch_array($queryResult, MYSQL_ASSOC))
{
array_push($data_array,$row);
}
mysql_free_result($queryResult);
//TEST TO SEE THE RESULT OF THE ARRAY
echo '<pre>';
print_r($data_array);
echo '</pre>';
THANKS
Related
I need to select multiple comments (if there are any) based on the photo_id. As I understand it you can use the WHERE clause but I'm not exactly sure how to select multiple ones and store them in some kind of array?
e.g.
$result = mysqli_query($conn,"SELECT * FROM comments WHERE photo_id='$photo1id'");
$row = $result->fetch_assoc(); // but there's more than 1 row
If for example $photo1id == 21, how do I get all the comments (2 in this case)? Some kind of while loop?
At the end of the PHP file I have this:
echo json_encode(array('photo1id'=>$photo1id));
I need to store each row in that array somehow because I need to retrieve the data in another PHP file using $.getJSON. Or perhaps there is a better solution to this.
Loop through it and generate an array -
while($row = $result->fetch_assoc()) {
$comments[] = $row;
}
After that you can send the array as json.
echo json_encode($comments);
Is there is more rows, you need to use a loop.
while ($row = $result->fetch_assoc()) {
// your code here
}
Try the code below:
//Run query
$result = mysqli_query($conn,"SELECT * FROM comments WHERE photo_id='$photo1id'");
//While there is a result, fetch it
while($row = $result->fetch_assoc()) {
//Do what you need to do with the comment
}
If you don't want to print the code straight away you can just create an array:
$x=0;
while($row = $result->fetch_assoc()) {
$comment[$x]=$row['comment'];
$x++;
}
It's been a long while since I touched PHP so, I just need a refresher of sorts.
I have an HTML form that captures several lines of data (dataA, dataB, dataC & dataD) and inserts them into a database table (dataAll). I will be entering rows upon rows of data into "dataAll". What I'm looking to do is create a display.php page, where the code will take all of the data and place each cell into an array, or the row of an array, for example:
new Array = [["dataA", "dataA", "dataA", "dataA", "dataA"],
["dataB", "dataB", "dataB", "dataB", "dataB"],
["dataC", "dataC", "dataC", "dataC", "dataC"],
["dataD", "dataD", "dataD", "dataD", "dataD"]];
But I cannot remember the syntax on how to perform this task. Any help would be greatly appreciated.
The database is named 'compdata', the table is 'dataAll', and each row is 'dataA', 'dataB', 'dataC', 'dataD'.
Please let me know if I need to supply more information.
Since you asked for All rows, so the simple code for query is written below:
<?php
//after connection to mysql db using mysql_connect()
$sql = "Select dataA, dataB, dataC, dataD from `compdata`.`dataAll`" ;
$result = mysql_query($sql) ;
if(mysql_num_rows($result) > 0 ){
while($row = mysql_fetch_array($result)){
$dataArray[] = $row ;
}
}
echo '<pre>';
print_r($dataArray) ;//you got the desired 2D array with all results
?>
Assuming you are used to the old mysql_xxx functions:
$data = array ();
$result = mysql_query ('select * from dataAll');
while ($row = mysql_fetch_array ($restult, MYSQL_ASSOC))
$data [] = $row;
Result:
$data = array (
0=>array ('col_1'=>'dataA', 'col_2'=>dataB...),
1=>array ('col_1'=>'dataA', 'col_2'=>dataB...)
);
If you only want the numbers and not the column names, use MYSQL_NUM.
However, mysql functions are being replaced with the more generic PDO object so you might want to look into that.
$stmt = $pdo->query ('select * from dataAll');
$result = $pdo->fetchAll (PDO::FETCH_ASSOC); // Or PDO::FECTCH_NUM
Same results as above.
I have a table wherein I need to get all the data in one column/field, but I can't seem to make it work with the code I have below:
$con=mysqli_connect("localhost","root","","database");
$result = mysqli_query($con,"select * from client");
$row = mysqli_fetch_array($result111);
echo $row['name'];
With the code above, it only prints one statement, which happens to be the first value in the table. I have 11 more data in the table and they are not printed with this.
You need to loop through the recordsets .. (A while loop will do) Something like this will help
$con=mysqli_connect("localhost","root","","database");
$result = mysqli_query($con,"select * from client");
while($row = mysqli_fetch_array($result))
{
echo $row['name'];
}
The mysqli_fetch_array() function will return the next element from the array, and it will return false when you have ran out of records. This is how you can use while loops to loop through the data, like so:
while ($record = mysqli_fetch_array($result)) {
// do something with the data...
echo $record['column_name'];
}
I currently have a database like the picture below.
Where there is a query that selects the rows with number1 equaling 1. When using
mysql_fetch_assoc()
in php I am only given the first is there any way to get the second? Like through a dimesional array like
array['number2'][2]
or something similar
Use repeated calls to mysql_fetch_assoc. It's documented right in the PHP manual.
http://php.net/manual/function.mysql-fetch-assoc.php
// While a row of data exists, put that row in $row as an associative array
// Note: If you're expecting just one row, no need to use a loop
// Note: If you put extract($row); inside the following loop, you'll
// then create $userid, $fullname, and $userstatus
while ($row = mysql_fetch_assoc($result)) {
echo $row["userid"];
echo $row["fullname"];
echo $row["userstatus"];
}
If you need to, you can use this to build up a multidimensional array for consumption in other parts of your script.
$Query="select SubCode,SubLongName from subjects where sem=1";
$Subject=mysqli_query($con,$Query);
$i=-1;
while($row = mysqli_fetch_array($Subject))
{
$i++;
$SubjectCode[$i]['SubCode']=$row['SubCode'];
$SubjectCode[$i]['SubLongName']=$row['SubLongName'];
}
Here the while loop will fetch each row.All the columns of the row will be stored in $row variable(array),but when the next iteration happens it will be lost.So we copy the contents of array $row into a multidimensional array called $SubjectCode.contents of each row will be stored in first index of that array.This can be later reused in our script.
(I 'am new to PHP,so if anybody came across this who knows a better way please mention it along with a comment with my name so that I can learn new.)
This is another easy way
$sql_shakil ="SELECT app_id, doctor_id FROM patients WHERE doctor_id = 201 ORDER BY ABS(app_id) ASC";
if ($result = $con->query($sql_shakil)) {
while ($row = $result->fetch_assoc()) {
printf ("%s (%s)\n", $row["app_id"], $row["doctor_id"]);
}
Demo Link
It looks like the complete solution has not been suggested yet
$Query="select SubCode,SubLongName from subjects where sem=1";
$Subject=mysqli_query($con,$Query);
$Rows = array ();
while($row = mysqli_fetch_array($Subject))
{
$Rows [] = $row;
}
The $Rows [] = $row appends the row to the array. The result is a multidimensional array of all rows.
I need to have a single row of data "printed out" through php.
So, take this example from w3schools:
http://www.w3schools.com/PHP/php_mysql_select.asp
There is a cicle that goes through all the rows ( in this case, 2) and prints them out. The end result is:
Peter Griffin
Glenn Quagmire
What I want is to be able to select row 1 or 2 (or more) and just have that row of data selected. Then I could say something like (I know this doesent work, just an example):
echo $row["Name",2];
And get:
Glenn Quagmire
I believe I have to get a special parameter in mysql_fetch_array, but I cant find it anywhere, and I bet its something really simple. Please help me out, full examples/tutorials/guides links are preferred.
you have 2 options. First is edit your SQL query like exmaple below this will return just 2nd row from database.
$result = mysql_query("SELECT * FROM Persons" WHERE id = 2);
Or during the foreach loop fetch all result into another array.
$result = mysql_query("SELECT * FROM Persons");
$rows = array();
while($row = mysql_fetch_array($result))
{
$rows[] = $row['FirstName'] . " " . $row['LastName'];
}
As far as i know mysql doesnt have a function to return the entire query as an array.
So you can switch to using PDO (recommended):
$sth = $dbh->prepare("SELECT name, colour FROM fruit");
$sth->execute();
$result = $sth->fetchAll();
echo $result[1]['name'];
or if you must use the mysql_functions just create an array with the loop:
while($row = mysql_fetch_array($result)) {
$result[] = $row;
}
echo $result[1]['name'];
fetchall the results into an array and print the row you want.