post from multiple checkboxes php mysql - php

Question

my form data im listed my table sample 10 records.
<td class='table-checkbox'><input type="checkbox" name="product[]" value="1" class='selectable-checkbox'></td>
<td><div class="input-mini">
<input type="text" id="spinnn" name="quantity[]" value="5" class='spinner'/>
</div>
</td>
</tr>
.....
.....
my php code
$carino = $_POST['carino'];
$quantity = $_POST['quantity'];
$product = $_POST['product'];
foreach($product as $product){
foreach($quantity as $quantity ){
$sql = "INSERT INTO mytable (product,quantity,cno) VALUES ('$product','$quantity','$carino')";
mysql_query($sql);
}}
i want to be insert this data my table. but my foreach is wrong how can i do ?
product is unique
my table
product - quantity - cno
1 5 2
2 10 2
http://pastie.org/private/nwrrinnxlrumt6p3kuyq#11,13-14,19

Answer 1

This:
<?php
if(isset($_POST['submit'])) {
$carino = "2";
$adet = $_POST['adet'];
$urunno = $_POST['urunno'];
$total = count($_POST['adet']);
echo '<hr>';
foreach ($urunno as $checked)
{
$value = $checked - 1;
echo "Value of Urunno: $checked: Adet: $adet[$value] <br>";
echo "INSERT INTO member_interests
(`urun`,`adet`,'carino')
VALUES
('$checked','$adet[$value]','$carino')<br>";
}
}
?>
<tr>
<form method="post" action="<?php $_SERVER['PHP_SELF']; ?>">
<td class='table-checkbox'><input type="checkbox" name="urunno[]" value="1">Product One</td>
<input type="text" id="spinnn" name="adet[]" class='spinner'/>
<td class='table-checkbox'><input type="checkbox" name="urunno[]" value="2">Product Two</td>
<input type="text" id="spinnn" name="adet[]" class='spinner'/>
<td class='table-checkbox'><input type="checkbox" name="urunno[]" value="3">Product Three</td>
<input type="text" id="spinnn" name="adet[]" class='spinner'/>
<td><div class="input-mini">
<input type="submit" name="submit" value="run" />
</form>
</div>
</td>
</tr>
</tbody>
</table>
</div>
Output:
Value of Urunno: 2: Adet: 2
INSERT INTO member_interests (`urun`,`adet`,'carino') VALUES ('2','2','2')
Value of Urunno: 3: Adet: 3
INSERT INTO member_interests (`urun`,`adet`,'carino') VALUES ('3','3','2')

Answer 2

The logic can be as follows (think of the code yourself, or search on the internet):
Make sure that all POST arrays are the same length (they should be)
Loop over the count from 0 to the length of the arrays
Insert the value at that point in each of the arrays into the database.
A quick tip: you are very susceptible to SQL injection. If this is production code, either use prepared queries, or use a PHP database wrapper like PDO to do it for you. The mysql_... functions are deprecated.

Answer 3

Try this one
<?php
//add the database connection
?>
<form name="myform" action="">
<table>
<?php
$length=//how many time below check box repeat in this page
for($i=0;$i<$length;$i++){?>
<tr>
<td class='table-checkbox'>
<input type="checkbox" name="urunno[]" value="<?php echo $i;?>" class='selectable-checkbox'>
</td>
<td>c1k</td>
<td>2147483647</td>
<td>520</td>
<td>435345345 A.Ş.</td>
<td>
<div class="input-mini">
<input type="text" id="spinnn" name="adet<?php echo $i;?>" class='spinner'/>
</div>
</td>
</tr>
<?php
}?>
</table>
<input type="submit" name="submit" value="Submit">
</form>
<?php
if(isset($_post['submit']))
{
$carino = $_POST['carino']; //here this element not present in question, i am also follow this
$adet = $_POST['adet'];
$urunno = $_POST['urunno'];
$length=sizeof($urunno);
for($i=0;$i<$length;$i++)
{
$urun1=$urunno[$i];
$adet1=$adet[$urun1];
$sql = "INSERT INTO table (urunno,adet,cno) VALUES ('$urun1','$adet1','$carino')";
mysql_query($sql);
//the above code insert sql work in every time //otherwise use batch insert
//refrer this link http://stackoverflow.com/questions/12960569/mysql-bulk-insert-via-php
}
}?>