assign data from one table to a specific table (group) - php

I have a classrooms in schools and when I click on a certain classroom, I want to add students into it but my actual code is doing something stupid. It adds a student but i can see the student in all classrooms, not just in the one that i added him into. So when Im in classroom number 1, I see a form in there, I can add a student there, ... see how it works here:
here is the code: http://www.xxxx.xx/projekt/
here is my code in file trieda.php
<table align="center"><tr><td>
<form action="vlozit2.php" method="post">
Meno: <input type="text" name="meno" placeholder="Janko" maxlength="15" required>
Priezvisko: <input type="text" name="priezvisko" placeholder="Hruška" maxlength="20" required>
<input type="hidden" name="id_triedy" value="<?= $trieda['id_triedy'] ?>" />
<input type="submit" name="submit" value="Pridať študenta do triedy">
</form>
</td></tr></table>
<?php
$result = mysqli_query($prip,"SELECT * FROM student ORDER BY meno");
while($student = mysqli_fetch_array($result))
{
echo "<br /><table cellspacing='1' cellpadding='1' class='tabulka1' align='center'><tr>";
echo "<td width='200'><a href='student.php?id_triedy=".$trieda['id_triedy']."".id_student=".$student['id_student']."'>".$student['meno']." ".$student['priezvisko']."</a></td>";
?>
<td width='300px' align='right' bgcolor="#fbfbfb">Zmazať</td>
</tr></table>
<?php
}
?>
here is vlozit2.php (a code that works for the form to add a student)
if(isset($_POST['submit']))
{
//meno a priezvisko
$student = $_POST['meno'];
$student = $_POST['priezvisko'];
$trieda = $_POST['id_triedy'];
//connect to the database
include 'config.php';
//insert results from the form input
$sql = "INSERT INTO student (meno, priezvisko, id_triedy) VALUES('$_POST[meno]', '$_POST[priezvisko]', '$_POST[id_triedy]')";
$add = "<table align='center'>
<tr>
<td> Študent bol úspešne pridaný do triedy. </td>
</tr>
<tr>
<td><a href='./trieda.php'><strong>Späť</strong></a></td>
</tr>
</table>";
$not_add = "<table align='center'>
<tr>
<td> Študent s týmto menom a priezviskom už je v tejto triede. </td>
</tr>
<tr>
<td><a href='./trieda.php'><strong>Späť</strong></a></td>
</tr>
</table>";
if (mysqli_query($prip, $sql)) {
echo $add;
}else{
echo $not_add;
}
mysqli_close($prip);
}
?>

Try to replace your part of code with these snipets:
1) in trieda.php
<form action="vlozit2.php?id_triedy=<?php echo $_GET["id_triedy"];?>" method="post">
Meno: <input type="text" name="meno" placeholder="Janko" maxlength="15" required>
Priezvisko: <input type="text" name="priezvisko" placeholder="Hruška" maxlength="20" required>
<input type="submit" name="submit" value="Pridať študenta do triedy">
</form>
2) in vlozit2.php
$student = $_POST['meno'];
$priezvisko = $_POST['priezvisko'];
$id_trieda = $_GET['id_triedy'];
and
$sql = "INSERT INTO student (meno, priezvisko, id_triedy) VALUES( '{$student}', '{$priezvisko}', {$id_trieda} )";
Hopefully you store your id_trieda as INT type.

In your vlozit2.php file is nothing about inserting of class id. So put
<input type="hidden" name="classId" value="<?= $trieda['id'] ?>" />
to your form and in vlozit2.php get this value from $_POST['classId'] and insert it with other students data or anywhere you want to have it.

Related

Insert data from while loop into a table with php

I'm creating a form using HTML and PHP. I have created a form which I want to submit and save that data in database.
I'm trying to submit a form with data that comes from a while loop. All input values are getting generated by while loop.
The code looks like this.
<table width="1348" border="0" class="table table-striped" >
<tr>
<td width="106"> </td>
<td width="332"><strong>Product Code</strong></td>
<td width="375"><strong>Product Name</strong></td>
<td width="211"><strong>QTY</strong></td>
</tr>
<?php
$i = 0;
$rowset = mysql_query("select * from product_detail where productID='".$data['productCode']."'");
while($stuff = mysql_fetch_array($rowset)){
?>
<tr>
<td><input type="text" name="code[<?php echo $i?>]" value="<?php enter code hereecho $stuff['code'];?>"/></td>
<td><input type="text" name="name[<?php echo $i?>]" value="<?php echo $stuff['name'];?>" size="50"/></td>
<td><input type="text" name="qty[<?php echo $i?>]" value="<?php echo $stuff['qty'];?>" size="10"/></td>
</tr>
<?php $i++; }?>
<tr id="last">
</table>
<input type="submit" name="save id="save" class="btn btn-primary btn-lg"/>
This is the code to add the data to database.
$code=$_POST['code'.$i];
$name=$_POST['name'.$i];
$qty=$_POST['qty'.$i];
$query = mysqli_query($con,"insert into stock(productCode, productName, qty) values ('".$code."', '".$name."','".$qty."')") or die(mysqli_error($con));
First, use prepared statement with bind_param as your script is totally exposed to sql injection.
Second, you can add input type hidden for the number of rows
<form action="" method="POST">
<table width="1348" border="0" class="table table-striped" >
<tr>
<td width="106"> </td>
<td width="332"><strong>Product Code</strong></td>
<td width="375"><strong>Product Name</strong></td>
<td width="211"><strong>QTY</strong></td>
</tr>
<?php
$data['productCode'] = "1"; // sample data
$stmt = $con->prepare("SELECT * FROM product_detail WHERE productID = ?");
$stmt->bind_param("i", $data['productCode']);
$stmt->execute();
$result = $stmt->get_result();
$i = 0;
while($stuff = $result->fetch_assoc()) {
?>
<tr>
<td></td>
<td><input type="text" name="code[<?php echo $i; ?>]" value="<?php echo $stuff['code'];?>"/></td>
<td><input type="text" name="name[<?php echo $i; ?>]" value="<?php echo $stuff['name']; ?>" size="50" /></td>
<td><input type="text" name="qty[<?php echo $i; ?>]" value="<?php echo $stuff['qty']; ?>" size="10" /></td>
</tr>
<?php
$i++;
}
?>
<input type="hidden" name="count" value="<?php echo $i; ?>" />
<tr id="last">
</table>
<input type="submit" name="save" id="save" class="btn btn-primary btn-lg"/>
</form>
post count with the form
<?php
if (isset($_POST['save'])) {
$count = $_POST['count'];
for ($i = 0; $i < $count; $i++) {
$code = $_POST['code'][$i]; // check empty and check if interger
$name = $_POST['name'][$i]; // check empty and strip tags
$qty = $_POST['qty'][$i]; // check empty and check if interger
$stmt = $con->prepare("INSERT INTO stock (productCode, productName, qty) VALUES (?, ?, ?)");
$stmt->bind_param("iss",$code,$name,$qty);
$stmt->execute();
}
}
?>
You may also want to check if post values are empty with other necessary validation before insert
Since the table is dynamically filled, you need to use an array as the name attribute
<table>
<tr>
<th>Name</th>
<th>Present</th>
<th>Excused</th>
<th>Unexcused</th>
<th>Ext</th>
</tr>
<?php
$query = "select * from TbCard";
$sql = mysqli_query($connect, $query);
$count = 0;
while ($data = mysqli_fetch_array($sql)) {
?>
<tr>
<td>
<input name="tableRow[<?php echo $count; ?>]['dataName']" id='name' type='text' value="<?php echo $data['Name'];?>" readonly style='border:none;width:350px'></input>
</td>
<td>
<input name="tableRow[<?php echo $count; ?>]['status']" type="radio" value="Present"> Present
</td>
<td>
<input name="tableRow[<?php echo $count; ?>]['status']" type="radio" value="Excused"> Excused
</td>
<td>
<input name="tableRow[<?php echo $count; ?>]['status']" type="radio" value="Unexcused"> Unexcused
</td>
</tr>;
<?php
$count++;
}
?>
</table>
The php would be something like this, assuming that the data has values in it:
$tableRow = $_POST['tableRow'];
foreach($tableRow as $row){
/* here insert data from post */
echo $row['dataName'].' '.$row['status'].'<br/>';
}
To see the content of the array, use print_r($tableRow)
in this case i use a name tableRow

How to insert multiple row to new table using single submit button

I am try to inset multiple rows to new table fetched from other table, but problem is that only last single row is being inserted and no other now is getting insert, so please tell the issue where i am lacking
<?php
error_reporting(1);
session_start();
$s=$_SESSION['username'];
//connect database
$con=mysql_connect("localhost","root","") or die(mysql_error());
// select database
mysql_select_db("education",$con);
$date= date("Y/m/d");
//select all values from empInfo table
$data="SELECT * FROM student";
$val=mysql_query($data);
?>
<html>
<body>
<table>
</table>
<form action="submit.php" method="post" >
<table>
<tr>
<th>Teacher name</th>
<th>Date</th>
<th>Roll No</th>
<th>Student name</th>
<th>Father name</th>
<th>Addhaar No</th>
<th>Status(P)</th>
<th>Status(A)</th>
<th>Status(L)</th>
</tr>
<?php while($r=mysql_fetch_array($val))
{?>
<tr style="border:2px solid black;">
<td><input type="text" name="teacher" value="
<?php echo $s; ?>"></td>
<td><input type="text" name="date" value="
<?php echo $date; ?>"></td>
<td ><input name="roll_no" value="
<?php echo $r['roll_no']; ?>">
</td>
<td><input name="student_name" value="
<?php echo $r['student_name'] ?>">
</td>
<td><input name="father_name" value="
<?php echo $r['father_name'] ?>">
</td>
<td>
<input name="addhaar_no" value="
<?php echo $r['addhaar_no'] ?>">
</td>
<td>
<input type="checkbox" value="present" name="status"> Present
</td>
<td>
<input type="checkbox" name="status" value="absent">Absent
</td>
<td>
<input type="checkbox" name="status" value="leave">Leave
</td>
</tr>
</table>
<?
}
?>
<input type="submit" name="submit" value="submit">
</form>
</body>
</html>
submit.php -
<?php
error_reporting(1);
$con=mysql_connect("localhost","root","") or die(mysql_error());
// select database
mysql_select_db("education",$con);
//get data from html form
$roll_no=$_POST['roll_no'];
$student_name=$_POST['student_name'];
$father_name=$_POST['father_name'];
$addhaar_no=$_POST['addhaar_no'];
$status=$_POST['status'];
//Insert values in empInfo table with column name
$query="INSERT INTO attandance
VALUES ('', '$roll_no','$student_name','$father_name','$addhaar_no','$status'),
VALUES ('', '$roll_no','$student_name','$father_name','$addhaar_no','$status')";
echo $query;
die();
mysql_query($query);
?>
page
You need to have unique name for each fields. What you can do is have a counter in loop and add it the names of the fields to make it unique.
Sample:
$ctr = 0;
while($r=mysql_fetch_array($val)){
echo "<input type="text" name='teacher_".$ctr."'>";
$ctr++;
}
Or make the names array, and loop through the values in saving the data.
while($r=mysql_fetch_array($val)){
echo "<input type="text" name='teacher[]'>";
}
I think you should study PHP a bit more... As i can see in your code, you haven't understood fundamentals of PHP.
1: Normally, you won't mix up HTML and PHP like you did in your first code. Its just confusing and really annoying to read the code later.
2: When you post your form, for example the variable $_POST['student_name']; will just contain the value of the last row (your problem). So, why? Because you can't assign more than one value to a variable. Or at least, not the way you tried it. Array would be a good keywoard for this problem.
3: Please check your SQL syntax... Thats why i'm saying you haven't understand fundamentals... http://www.w3schools.com/sql/sql_insert.asp
Why you're repeating your values? You think the second time the variables will contain the values of the next row? Thats just false. A Variable contains everytime the same value, as long as you don't assign a new value to it.
4: mysql is depracted. Use mysqli or PDO instead.
My tip: You need to have unique input names. Just take a look at PHP, how for/while loops work, study a bit more and try it again. It's not difficult to solve, but i think you'll learn a lot more if we don't give you the direct solution.
Now mysql is depracted. So, you can use mysqli or PDO instead.
I can use now PDO. Please follow bellow code carefully:
<?php
$user = 'root';
$pass = '';
$dbh = new PDO('mysql:host=localhost;dbname=education', $user, $pass);
try {
$select = $dbh->query('SELECT * from student');
} catch (PDOException $e) {
print "Error!: " . $e->getMessage() . "<br/>";
die();
}
?>
<html>
<body>
<form action="submit.php" method="post" >
<table>
<tr>
<th>Teacher name</th>
<th>Date</th>
<th>Roll No</th>
<th>Student name</th>
<th>Father name</th>
<th>Addhaar No</th>
<th>Status(P)</th>
<th>Status(A)</th>
<th>Status(L)</th>
</tr>
<?php
foreach($select as $val) {
?>
<tr style="border:2px solid black;">
<td><input type="text" name="teacher" value="<?php echo $s; ?>"></td>
<td><input type="text" name="date" value="<?php echo $date; ?>"></td>
<td><input name="roll_no" value="<?php echo $r['roll_no']; ?>"></td>
<td><input name="student_name" value="<?php echo $r['student_name'] ?>"></td>
<td><input name="father_name" value="<?php echo $r['father_name'] ?>"></td>
<td><input name="addhaar_no" value="<?php echo $r['addhaar_no'] ?>"></td>
<td><input type="checkbox" value="present" name="status"> Present</td>
<td><input type="checkbox" name="status" value="absent">Absent</td>
<td><input type="checkbox" name="status" value="leave">Leave</td>
</tr>
<?php
}
?>
</table>
<input type="submit" name="submit" value="submit">
</form>
</body>
</html>
For submit.php code bellow
<?php
$user = 'root';
$pass = '';
$dbh = new PDO('mysql:host=localhost;dbname=education', $user, $pass);
$stmt = $dbh->prepare("INSERT INTO attandance (roll_no, student_name, father_name, addhaar_no, status) VALUES (?, ?, ?, ?, ?)");
$stmt->bindParam(1, $roll_no);
$stmt->bindParam(2, $student_name);
$stmt->bindParam(2, $father_name);
$stmt->bindParam(2, $addhaar_no);
$stmt->bindParam(2, $status);
//if you insert 2 time then
for($x=0; $x<2; $x++) {
$roll_no = $_POST['roll_no'];
$student_name = $_POST['student_name'];
$father_name = $_POST['father_name'];
$addhaar_no = $_POST['addhaar_no'];
$status = $_POST['status'];
$stmt->execute();
}
?>

database field data not appearing in form textbox in PHP

i have this code in PHP and a database sql.. the situation is .. if i type the 1, 2 or 3 (productID) .. the textbox will be populated and field with database values.. but when i run the program.. fortunately it has no errors.. but when i type the id or 1 and click the submit button.. it doesnt get the neccessary values.. sorry for this im a complete newbie and im practicing PHP for a while now.. any help will do.. thank you..
<?php
session_start();
include_once 'dbconnect.php';
if(!isset($_SESSION['user'])){
header("Location: index.php");
}
$res = mysql_query("SELECT * FROM users WHERE user_id=".$_SESSION['user']);
$userRow = mysql_fetch_array($res);
?>
<?php
require('dbconnect.php');
$id = (isset($_REQUEST['productID']));
$result = mysql_query("SELECT * FROM tblstore WHERE productID = '$id'");
$sql = mysql_fetch_array($result);
if(!$result){
die("Error: Data not found");
} else {
$brandname = $sql['brandname'];
$price = $sql['price'];
$stocks = $sql['stocks'];
}
?>
<html>
<body>
<p>
hi' <?php echo $userRow['username']; ?> Sign Out
</p>
<form method="post">
<table align="center">
<tr>
<td>Search Apparel:</td>
<td><input type="text" name="search" name="productID" /></td>
</tr>
<tr>
<td>Brandname:</td>
<td><input type="text" name="brandname" value="<?php echo $brandname; ?>"/ </td>
</tr>
<tr>
<td>Price:</td>
<td><input type="text" name="price" value="<?php echo $price; ?>"/></td>
</tr>
<tr>
<td>Stocks:</td>
<td><input type="text" name="stocks" value="<?php echo $stocks; ?>"/></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="Search" /></td>
</tr>
</table>
</form>
</body>
</html>
your getting the id incorrectly, you have:
<?php
$_REQUEST['productID']=8; //for testing
$id = (isset($_REQUEST['productID']));
if you check it you will find the output is true\false as returned by isset
var_dump($id); //true
what you should use is:
<?php
if(isset($_REQUEST['productID'])){ //maybe also check its a number and or valid range
$id=$_REQUEST['productID'];
}

Php form update in update the form

I am running while loop and fetch 3 records from database. and then update it on same page. Every record have submit button. But after edit when i submit the form it catchs the values of last record only and update other rows with the last record values. Please if somebody help me out i'll be very thankful. Remember it catches the exact (id) but the other parameters are only of last row.
<form method="post" action="">
<table width="700" border="1">
<tr><th><?php echo $_SESSION['teamtwo']; ?></th></tr>
<tr>
<th>Player Name</th>
<th>Runs</th>
<th>Edit</th>
<th>Save</th>
</tr>
<?php
$team = new DBConnection();
$condition = "WHERE teamname = '".$_SESSION['teamtwo']."' and datecreated = CURDATE()";
$sel_player = $team->SelectRecord(array("*"),"`match`","$condition");
//$sel_player = mysql_query("SELECT * FROM `match` WHERE teamname = '$team1' and datecreated = CURDATE()") or die(mysql_error());
while($get_player = mysql_fetch_array($sel_player))
{
$totalruns = $get_player['runs_bat'];
$totalballs = $get_player['ball_bat'];
#$strike = $totalruns / $totalballs * 100;
?>
<tr>
<td><input type="text" name="player_name" value="<?php echo $get_player['player_name']; ?>" disabled="disabled" /></td>
<td><input type="text" name="runs" value="<?php echo $get_player['runs_bat']; ?>" size="1" /></td>
<td><button>Edit</button></td>
<td><input type="submit" value="Save" name="team" /></td>
</tr>
<?php
} ?>
</table>
</form>
<?php } ?>
</div>
</div>
</body>
</html>
<?php
if(isset($_POST['team'])){
$runs = $_POST['runs'];
$balls = $_POST['ball'];
$object = new DBConnection();
$arr_Field=array("runs_bat","ball_bat","player_status","how_out","opposite_bowl","opposite_player","sr","overs","bowl_ball","runs_ball","extra","madien");
$arr_Values=array("$runs","$balls","$status","$how_out","$opposite_bowler","$opposite_player","$sr","$over","$bowls","$score","$extra","$madien");
$condition = "WHERE id = '".$_REQUEST['player']."'";
//echo $_REQUEST['player'];
//echo $runs.$balls;
$object->UpdateRecord("`match`",$arr_Field,$arr_Values,"$condition") or die(mysql_error());
//header("Location:extra.php?update");
}
the problem is you are having one form and when you submit the form it will submit the last rows values because you are having same name for all 3 rows inside 1 form.
Solution:-
Create form element inside the while loop and close it inside the while loop itself . Like this you will have 3 forms each for 3 rows.
Code Example:-
while($get_player = mysql_fetch_array($sel_player))
{
$totalruns = $get_player['runs_bat'];
$totalballs = $get_player['ball_bat'];
#$strike = $totalruns / $totalballs * 100;
?>
<form>
<tr>
<td><input type="text" name="player_name" value="<?php echo $get_player['player_name']; ?>" disabled="disabled" /></td>
<td><input type="text" name="runs" value="<?php echo $get_player['runs_bat']; ?>" size="1" /></td>
<td><button>Edit</button></td>
<td><input type="submit" value="Save" name="team" /></td>
</tr>
</form>
<?php
} ?>
1.
you need to make input array in while because name attribute is overwriting in loop
<td><input type="text" name="player_name[<?php echo $get_player['id']?>]" value="<?php echo $get_player['player_name']; ?>" disabled="disabled" /></td>
<td><input type="text" name="runs[<?php echo $get_player['id']?>]" value="<?php echo $get_player['runs_bat']; ?>" size="1" /></td>
2.
you have all text boxes mean if press submit button of one row, then also you will get all textboxes as php side so make hidden variable in form to get which button clicked
//write javascript in your page
<script>
function setPlayerId(id) {
document.getElementById('playerid').value=id;
}
</script>
//take hidden field into form
<input type='hidden' name='playerid' value='0'>
//write down onlick button event
<input type="submit" value="Save" name="team" onClick="setPlayerId('<?php <?php echo $get_player['id']?>?>')"/>
3.
Now in php you will get that as below
echo $_POST['player_name'][$_POST['playerid']];
// same way you can do your insert or update.
this code must work
<form method="post" action="">
<table width="700" border="1">
<tr><th><?php echo $_SESSION['teamtwo']; ?></th></tr>
<tr>
<th>Player Name</th>
<th>Runs</th>
<th>Edit</th>
<th>Save</th>
</tr>
<?php
$team = new DBConnection();
$condition = "WHERE teamname = '".$_SESSION['teamtwo']."' and datecreated = CURDATE()";
$sel_player = $team->SelectRecord(array("*"),"`match`","$condition");
//$sel_player = mysql_query("SELECT * FROM `match` WHERE teamname = '$team1' and datecreated = CURDATE()") or die(mysql_error());
while($get_player = mysql_fetch_array($sel_player))
{
$totalruns = $get_player['runs_bat'];
$totalballs = $get_player['ball_bat'];
#$strike = $totalruns / $totalballs * 100;
?>
<tr>
<td><input type="text" name="player_name" value="<?php echo $get_player['player_name']; ?>" disabled="disabled" /></td>
<td><input type="text" name="runs<?=$get_player['id']?>" value="<?php echo $get_player['runs_bat']; ?>" size="1" /></td>
// you didnt write this i added
<input type="text" name="ball<?=$get_player['id']?>" value="<?php echo $get_player['ball_bat']; ?>" size="1" />
<td><button>Edit</button></td>
<td><input type="submit" value="Save" name="team" /></td>
</tr>
<?php
} ?>
</table>
</form>
<?php } ?>
</div>
</div>
</body>
</html>
<?php
if(isset($_POST['team'])){
$runsname = 'runs'.$_GET['player'];
$ballsname = 'ball'.$_GET['player'];
$runs = $_POST[$runsname];
$balls = $_POST[$ballsname];
$object = new DBConnection();
$arr_Field=array("runs_bat","ball_bat","player_status","how_out","opposite_bowl","opposite_player","sr","overs","bowl_ball","runs_ball","extra","madien");
$arr_Values=array("$runs","$balls","$status","$how_out","$opposite_bowler","$opposite_player","$sr","$over","$bowls","$score","$extra","$madien");
$condition = "WHERE id = '".$_REQUEST['player']."'";
//echo $_REQUEST['player'];
//echo $runs.$balls;
$object->UpdateRecord("`match`",$arr_Field,$arr_Values,"$condition") or die(mysql_error());
//header("Location:extra.php?update");
}

php $_get variable gone after submitting form

my problem goes like this:
my home page has tables with rows pulled from the database (while loops)
each row has a - cell in which he can add an event to that specific row
in order to do that i send the row id as a $_GET variable from the home page table
and in the "add event" page i store it as a variable
but when i submit my addevent form without filling it properly (as i coded) it simply refreshes the form only without the row id in the url therefor also the query i do in the beginning of the page for pulling the row data can no longer execute and that pops a PHP error
for the id variable which i sign it the $_GET and the query (mysql fetch array).
also of course all the data which i display in the form from that query is gone.
any suggestions on how to approach this ? thanks in advance, Regards.
EDIT:** kill the new guy! -Sorry i guess
home page where i send the id :
$sql = "SELECT * FROM alarms WHERE alarmstatus = 'OFF' and starttime='::' ORDER BY clientid ASC";
$query = mysql_query($sql);
echo "<table cellpadding='1px' border='1px' bordercolor='#0066FF' cellspacing='0'>
<form action='hpage.php' method='get'>";
while($fetch = mysql_fetch_array($query)) {
echo "<tr>
<td>
".$fetch['clientid']."</td>
<td>".$fetch['controller']."</td>
<td>".$fetch['typeid']."</td>
<td style='color: red'>".$fetch['alarmstatus']."</td>
<td>".$fetch['starttime']."</td>
<td>".$fetch['endtime']."</td>
<td><a href='includes/editalarm.php?id=".$fetch['id']."'>Edit</a></td>
<td><a href='includes/addevent.php?id=".$fetch['id']."'>Add event</a></td>
<td><a href='includes/deletealarm.php?id=".$fetch['id']."'>Delete</a></td>
</tr>";
}
the add event where i get the variable and make the query:
$alarmid = $_GET['id'];
$sql = "SELECT * FROM alarms WHERE id=".$alarmid;
$query = mysql_query($sql);
$fetch = mysql_fetch_array($query);
?>
the form:
<table cellpadding="2px" cellspacing="0" >
<form action="addevent.php" method="post">
<tr>
<td>סניף:</td>
<td><input style="width:200px; background-color: #d6d6d6;" readonly name="client" value="<?php echo $fetch['clientid']; ?>" /></td>
</tr>
<tr>
<td>בקר:</td>
<td><input style="width:200px; background-color: #d6d6d6;" readonly name="controller" value="<?php echo $fetch['controller']; ?>" /></td>
</tr>
<tr>
<td>אזעקה:</td>
<td><input style="width:200px; background-color: #d6d6d6;" readonly name="controller" value="<?php echo $fetch['typeid']; ?>" /></td>
</tr>
<tr>
<td>מוקדן:</td>
<td>
<?php
$sql = "SELECT * FROM users WHERE privilege = '2'";
$query = mysql_query($sql);
echo "<select name='user' style='width:207px;'>";
echo "<option>..</option>";
while ($fetch2 = mysql_fetch_array($query)){
echo "<option>".$fetch2['username']."</option>";
}
echo "</select>";
?>
</td>
</tr>
<tr>
<td>איש קשר:</td>
<td><input type="text" name="contact" /></td>
</tr>
<tr>
<td>הודעה:</td>
<td><input type="text" style="width:200px; height:100px" name="message" /></td>
</tr>
<tr>
<td>תשובה:</td>
<td><input type="text" style="width:200px; height:100px" name="answer" /></td>
</tr>
<tr>
<td>שעה:</td>
<td>
<select name="eventhour">
<option value ="default"></option>
<?php
for($i = 0; $i<60; $i++){
$value = $i;
if($i<=9){
$value= "0".$i;
}
echo "<option>".$value."</option>";
}
?>
</select>
<select name="eventminute">
<option value ="default"></option>
<?php
for($i = 0; $i<24; $i++){
$value = $i;
if($i<=9){
$value= "0".$i;
}
echo "<option>".$value."</option>";
}
?>
</select>
</td>
</tr>
<tr>
<td>
<input type="submit" name="save" value="שמור" />
<input type="submit" name="cancell" value="בטל" />
</td>
<td></td>
</tr>
</form>
Your form action is POST. If you change that to GET then you will have the form as $_GET.

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