hello i have been trying to use multiple checkboxes to input info to a db i used [] with checkbox name but "array" is saved to db. What code and where should i input for this to work correctly? thank you!
this is my form code:
<?php
require_once('connection.php');
if(isset($_GET['process']))
{
$query = "Insert INTO `lista_precios` (Marca) values('$_POST[Marca]')";
//echo $query; exit;
$result = mysql_query($query) or die(mysql_error());
if(!$result)
{
$msg = "not Inserted";
}
else
{
$msg = "Inserted";
header("location:form.php?m=".$msg);
}
}
?>
<method="post" action="form.php?process">
<p>MARCA: <br><br>
<input type="checkbox" name="Marca" value="ACER">ACER
<input type="checkbox" name="Marca" value="AOC">AOC
<input type="checkbox" name="Marca" value="APPLE">APPLE
<input type="submit" name="Submit" value="Submit" />
</form>
And this is my connection:
<?php
$link=mysql_connect("xxxx","xxxx","xxxx");
$database='xxxxxxx';
if (!$link)
die('Failed to connect to Server'.mysql_error());
$db=mysql_select_db($database, $link);
session_start();
if(!$db)
die('Failed to select Data Base '.mysql_error());
?>
First off you need to set your checkboxes names and turn them to name=Marca[]
<form method="post" action="form.php?process">
<p>MARCA: <br><br>
<input type="checkbox" name="Marca[]" value="ACER">ACER
<input type="checkbox" name="Marca[]" value="AOC">AOC
<input type="checkbox" name="Marca[]" value="APPLE">APPLE
<input type="submit" name="Submit" value="Submit" />
</form>
Then on your form.php process the values:
Note: You have to understand, you can't just put $_POST['Marca'] and concatenate them into the string, you have to get each value and build the insert query.
if(isset($_GET['process'])) {
$marca = isset($_POST['Marca']) ? $_POST['Marca'] : null;
if(count($marca) < 3) {
// your validation that no checkboxes were selected
$msg = 'You need to select at least 3 values';
header("Location: form.php?m=".$msg);
}
$values = implode(',', $marca);
$statement = "INSERT INTO `lista_precios` (`Marca`) VALUES ('$values');";
// should result into
// INSERT INTO `lista_precios` (`Marca`) VALUES ('ACER,AOC,APPLE');
// then continue on your query code
$query = mysql_query($statement);
$msg = ($query && mysql_affected_rows() > 0) ? 'Inserted' : 'Not Inserted';
header("Location: form.php?m=".$msg);
}
you can try this...
<?php
require_once('connection.php');
if(isset($_GET['process']))
$marc = implode(", ", $_POST['Marca']); <== add this
{
$query = "Insert INTO `lista_precios` (Marca) values('" . $marc . "')"; <== change this
//echo $query; exit;
$result = mysql_query($query) or die(mysql_error());
if(!$result)
{
$msg = "not Inserted";
}
else
{
$msg = "Inserted";
header("location:form.php?m=".$msg);
}
}
?>
<method="post" action="form.php?process">
<p>MARCA: <br><br>
<input type="checkbox" name="Marca[]" value="ACER">ACER <==change this
<input type="checkbox" name="Marca[]" value="AOC">AOC <==change this
<input type="checkbox" name="Marca[]" value="APPLE">APPLE <==change this
<input type="submit" name="Submit" value="Submit" />
</form>
Use at least MySQLi instead of deprecated MySQL. Try this:
connection.php:
<?php
$con=mysqli_connect("YourHost","YourUsername","YourPassword","YourDatabase");
if(mysqli_connect_errno()){
echo "Error".mysqli_connect_error();
}
?>
Your main file:
<html>
<body>
<?php
include('connection.php');
if(isset($_POST['Submit'])){ /* IF FORM IS SUBMITTED */
if(!empty($_POST['Marca'][0])){ /* IF THE SUBMITTED CHECKBOX IS SELECTED */
$acer=mysqli_real_escape_string($con,$_POST['Marca'][0]); /* ESCAPE STRING */
} /* END OF IF NOT EMPTY MARCA 0 */
else { $acer=""; }
if(!empty($_POST['Marca'][1])){ /* IF THE SUBMITTED CHECKBOX IS SELECTED */
$aoc=mysqli_real_escape_string($con,$_POST['Marca'][1]); /* ESCAPE STRING */
} /* END OF IF NOT EMPTY MARCA 1 */
else { $aoc=""; }
if(!empty($_POST['Marca'][2])){ /* IF THE SUBMITTED CHECKBOX IS SELECTED */
$apple=mysqli_real_escape_string($con,$_POST['Marca'][2]); /* ESCAPE STRING */
} /* END OF IF NOT EMPTY MARCA 2 */
else { $apple=""; }
$overalldata=$acer.", ".$aoc.", ".$apple;
$query = "INSERT INTO lista_precios (Marca) VALUES ('$overalldata')";
$result = mysqli_query($con,$query); /* INSERT QUERY */
echo "Inserted data properly.<br>";
} /* END OF ISSET SUBMIT */
?>
<form method="POST" action=""> <?php /* SUBMIT PAGE ON ITSELF */ ?>
<p>MARCA: <br><br>
<?php
echo "<input type='checkbox' name='Marca[0]' value='ACER'>ACER";
echo "<input type='checkbox' name='Marca[1]' value='AOC'>AOC";
echo "<input type='checkbox' name='Marca[2]' value='APPLE'>APPLE";
?>
<input type="submit" name="Submit" value="Submit" />
</form>
</body>
</html>
Related
I have a list of items in one file (fruit.php):
<form action="delete_items.php" method="post">
<input type="radio" value="apple" name="fruit">Apple<br>
<input type="radio" value="pear" name="fruit">Pear<br>
<input type="radio" value="banana" name="fruit">Banana<br>
<input type="submit" value="delete" name="deleteButton"><br>
</form>
In the delete_items.php, I have a variable that stores the selection:
<?php
$selection = $_POST["fruit"];
echo "are you sure you want to delete it?";
echo '<form action="delete_confirmation.php" method="post"><br>';
echo '<input type="submit" name="deleteYes" value="Yes"><br>';
echo '<input type="submit" name="deleteNo" value="No"><br>';
echo '</form>';
?>
Than in the confirmation file (delete_confirmation.php):
<?php
include 'delete_items.php';
if($_POST["deleteYes"]){
$query = 'DELETE FROM databaseName WHERE fruitName="' . $selection . '"';
$result = mysqli_query($connection, $query);
if(!$result){
die("Delete after check query failed!");
} else {
echo "Delete after check query success!";
}
} elseif($_POST["deleteNo"]){
echo "The course was not deleted!";
}
?>
But the varibale $selection in the delete_confirmation.php file is always null even though i included the delete_items.php file (when i echo it, nothing is shown). Is there a way to pass the selection variable from delete_items.php to the delete_confirmation.php file?
I've created a mysql table with two columns. One is ID and other is Heading. I have a textarea on which I run UPDATE code and whenever someone submits a form its being updated in the datebase column under heading. And that works fine but I want to show the last inputted submit inside my textarea.
My code is showing the last inputted value but when I reset the page it all turns out blank and its not showing anymore. I looked out in datebase and the heading is still there so I don't know why its dissapearing from the front end.
My page:
<?php
$title = 'Admin Panel - Edit';
include '../config.php';
$heading = mysqli_real_escape_string($link, $_REQUEST['heading']);
$sql = "UPDATE content SET heading='$heading' WHERE id = 1 ";
if(mysqli_query($link, $sql) == false){
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
$value=mysqli_query($link, "SELECT heading FROM content WHERE id = 1");
$currentText = mysqli_fetch_row($value);
?>
<form action="edit.php">
<?php echo $currentText[0]; ?>
<input type="text" name="heading" id="heading" value='<?php echo $currentText[0]; ?>' />
<input type="submit" value="Submit" name="submit" />
</form>
So for example if I type Aleksa, after submit it will get url like edit.php?heading=Aleksa&submit=Submit. And then when I delete url just to edit.php, the value is missing.
You can test the page here: https://www.easybewussterschaffen.com/admin/edit.php
This is happening, because it's always trying to insert the heading when you refresh the page. You should check to see if the request is GET or the request is POST, and only insert it if they're submitting the form.
Update your form method, specify it to POST, and specifically check the method or check for the existance of $_POST['submit'] as shown below:
<?php
$title = 'Admin Panel - Edit';
include '../config.php';
// Use one of the 2 if statements:
if ($_SERVER['REQUEST_METHOD'] === 'POST') { // Trying to insert a new heading
if (isset($_POST['submit'])) { // Alternative
$heading = mysqli_real_escape_string($link, $_REQUEST['heading']);
$sql = "UPDATE content SET heading='$heading' WHERE id = 1 ";
if(mysqli_query($link, $sql) == false){
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
}
$value=mysqli_query($link, "SELECT heading FROM content WHERE id = 1");
$currentText = mysqli_fetch_row($value);
?>
<form action="edit.php" method="POST">
<?php echo $currentText[0]; ?>
<input type="text" name="heading" id="heading" value='<?php echo $currentText[0]; ?>' />
<input type="submit" value="Submit" name="submit" />
</form>
Alternatively, if you still wish to make a GET request, you should check to make sure that the heading is set:
<?php
$title = 'Admin Panel - Edit';
include '../config.php';
if (isset($_GET['submit'])) {
$heading = mysqli_real_escape_string($link, $_GET['heading']);
$sql = "UPDATE content SET heading='$heading' WHERE id = 1 ";
if(mysqli_query($link, $sql) == false){
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
}
$value=mysqli_query($link, "SELECT heading FROM content WHERE id = 1");
$currentText = mysqli_fetch_row($value);
?>
<form action="edit.php" method="GET">
<?php echo $currentText[0]; ?>
<input type="text" name="heading" id="heading" value='<?php echo $currentText[0]; ?>' />
<input type="submit" value="Submit" name="submit" />
</form>
I did it like this, is this good tho? Its working
<?php
$sql = "SELECT * FROM content";
if($result = mysqli_query($link, $sql)){
if(mysqli_num_rows($result) > 0){
echo '';
while($row = mysqli_fetch_array($result)){
echo $row['heading'];
}
// Free result set
mysqli_free_result($result);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
?>
I'm trying to display some information stored in MySQL comments table to an input but I'm having issues with that. Input named enterComment inserts data to my DB and I want it to redirect back to showComment input.
HTML:
form action='takedata.php' method='POST'>
<input type='text' id='enterComment' name='enterComment' width='400px' placeholder='Write a comment...'>
<input type='submit' id='combuton' name='comButon' value='Comment!'>
<input type='text' id='showComment' name='showComment'>
</form>
PHP:
<?php include "mysql.php"; ?>
<?php
if (isset($_POST['comButon'])){
$enterComment = strip_tags($_POST['enterComment']);
if($enterComment){
$addComment = mysql_query("INSERT INTO comments(comment) VALUES('$enterComment')");
if($addComment==1)
//INSERT INTO showComment input;
}
}
?>
try this, and use mysqli instead of mysql
include "dbconnect.php";
if (isset($_POST['comButon'])){
$enterComment = strip_tags($_POST['enterComment']);
if($enterComment){
$addComment = mysqli_query($conn, "INSERT INTO comments(comment) VALUES('$enterComment')");
if($addComment) {
$sql = "select comment from comments order by id desc limit 1";
$result = mysqli_query($conn, $sql);
while($row = $result->fetch_assoc()) { ?>
<input type="text" value="<?php echo $row['comment']; ?>">
<?php }
}
}
}
your form
<form action='' method='POST'>
<input type='text' id='enterComment' name='enterComment' width='400px' placeholder='Write a comment...'>
<input type='submit' id='combuton' name='comButon' value='Comment!'>
<?php if(!isset($_POST['comButon'])) { ?>
<input type="text" value="">
<?php } ?>
</form>
So I'm just making a simple program that puts names into a database. I got that part down, I can enter a name into a form, then display it on the page, but now I'd like to know how to delete them from the database, and no longer show them on the page.
I added a button next to each name that triggers the third if statement (with the commented out query), and from what I can tell it's best to run a query based on the element's id (my primary key that auto increments), but I have no idea how to get the id from the element who's button I'm clicking on.
How do I get the id from one of the elements in my while loop? Or if there's a better way to delete them, what's that?
if (mysqli_connect_errno()) {
die('could not connect');
}
if (isset($_POST['first_name'], $_POST['last_name'])){
$first_name = trim($_POST['first_name']);
$last_name = trim($_POST['last_name']);
$putitin = mysqli_query($db, "INSERT INTO names (first_name, last_name) VALUES ('$first_name', '$last_name')");
}
if (isset($_POST['del'])){
//$takeitout = mysqli_query($db, "DELETE FROM names WHERE id = ");
}
?>
<html>
<head>
</head>
<body>
<form action='' method='post'>
<div>
<label for "first_name">First name</label>
<input type="text" name="first_name">
</div>
<div>
<label for "last_name">Last name</label>
<input type="text" name="last_name">
</div>
<div>
<input type="submit" value="Insert">
</div>
</form>
<hr>
<?php
$resultset = $db->query('SELECT * FROM names');
if($resultset->num_rows != 0){
while($rows = $resultset->fetch_assoc()) {
$fname = $rows['first_name'];
$lname = $rows['last_name'];
$id = $rows['id'];
echo "<form action='' method='post'><p>Name: $fname $lname $id<input type='submit' name='del'></form></p>";
}
} else {
echo 'No results';
}
?>
</body>
</html>
This is one way.
change your html part to
<form action='' method='post'>
<input type='hidden' name='id' value='$id' />
<p>Name: $fname $lname $id
<input type='submit' name='del' value=''>
</form></p>
and your php
if (isset($_POST['del'])){
$id = $_POST['id'];
$takeitout = mysqli_query($db, "DELETE FROM names WHERE id = '$id'");
}
Note:
What you can do is to put all your input fields inside your while loop. Then assign values to each of them, but we have to use array to store them accordingly.
We can use checkbox to store the IDs.
What will happen, is user can select from the list of names they wanted to delete by ticking the corresponding checkbox, then pressing the Delete button below.
Your code
<form action="" method="POST">
<?php
$resultset = $db->query('SELECT * FROM names');
if($resultset->num_rows != 0){
while($rows = $resultset->fetch_assoc()) {
$fname = $rows['first_name'];
$lname = $rows['last_name'];
$id = $rows['id'];
echo '<input type="checkbox" name="id[]" value="'.$id.'">'.$fname.' '.$lname.'<br>';
} /* END OF WHILE LOOP */
?>
<input type="submit" value="Delete" name="delete">
</form>
And your PHP that will process the form:
<?php
if(isset($_POST["delete"])){
$counter = count($_POST["id"]);
for($x = 0; $x<$counter; $x++){
if(!empty($_POST["id"][$x])){ /* CHECK IF AN ITEM IS SELECTED */
/* DELETE QUERY */
if($stmt = $db->prepare("DELETE FROM names WHERE id = ?")){
$stmt->bind_param("i",$_POST["id"][$x]);
$stmt->execute();
$stmt->close();
} /* END OF PREPARED STATEMENT */
} /* END OF IF; CHECKING IF IT IS SELECTED */
} /* END OF FOR LOOP */
} /* END OF ISSET DELETE */
?>
I do have programming experience, but new to php. I do have an issue with an example I was doing from this tutorial. I looked over it millions of times, googled, ect ect. I don't have an idea why my code isnt working.
The purpose is to basically just test inserting and deleting in sql from php, using a button for Add Record and Delete Record. The Add record button works perfectly, but delete doesnt do a thing other than reload the page. Heres the code...
<?php // sqltest.php
require_once 'login.php';
$db_server = mysql_connect($db_hostname, $db_username, $db_password);
if (!$db_server) die("Unable to connect to MySQL: " . mysql_error());
mysql_select_db($db_database, $db_server)
or die("Unable to select database: " . mysql_error());
if (isset($_POST['author']) &&
isset($_POST['title']) &&
isset($_POST['type']) &&
isset($_POST['year']) &&
isset($_POST['isbn']))
{
$author = get_post('author');
$title = get_post('title');
$type = get_post('type');
$year = get_post('year');
$isbn = get_post('isbn');
if (isset($_POST['delete']) && $isbn != "")
{
echo "worked!!!!!!!!!!!!!!";
$query = "DELETE FROM classics WHERE isbn='$isbn'";
$result = mysql_query($query) or die(mysql_error());
if(mysql_affected_rows($result) > 0) echo 'user deleted';
//if (!mysql_query($query, $db_server))
//echo "DELETE failed: $query" . mysql_error();
}
else
{
echo "nooooooooooooooooooo";
$query = "INSERT INTO classics VALUES" .
"('$author', '$title', '$type', '$year', '$isbn')";
if (!mysql_query($query, $db_server))
{
echo "INSERT failed: $query" . mysql_error();
}
}
}
echo <<<_END
<form action="sqltest.php" method="post"><pre>
Author <input type="text" name="author" />
Title <input type="text" name="title" />
Type <input type="text" name="type" />
Year <input type="text" name="year" />
ISBN <input type="text" name="isbn" />
<input type='submit' value='ADD RECORD' />
</pre></form>
_END;
$query = "SELECT * FROM classics";
$result = mysql_query($query);
if (!$result) die ("Database access failed: " . mysql_error());
$rows = mysql_num_rows($result);
for ($j = 0 ; $j < $rows ; ++$j)
{
$row = mysql_fetch_row($result);
echo <<<_END
<pre>
Author $row[0]
Title $row[1]
Type $row[2]
Year $row[3]
ISBN $row[4]
<form action="sqltest.php" method="post">
<input type="hidden" name="delete" value="yes" />
<input type="hidden" name='isbn' value="$row[4]" />
<input type='submit' value='DELETE RECORD' />
</form>
</pre>
_END;
}
mysql_close($db_server);
function get_post($var)
{
return mysql_real_escape_string($_POST[$var]);
}
?>
I have looked over this many times, still no idea why this won't work. Is it the for loop that is making this button not work? Note, you will see echo "worked!!!"; and in the else echo "noooooooo"; that was for me to test whether the button was being tested, yet nothing prints. So maybe i missed something in the button code itself? Also, no errors are printed, and my editor (and myself) have missed the syntax error (if thats the case).
The code for the delete button is at the end, before I closed the DB.
Thanks for your help in advance.
Your problem is your first if block.
You're checking for the presence of the posted variables author title type year isbn. Whereas in your delete code the only variables sent are delete and isbn. Therefore the first if block is completely missed (including the delete code).
You need to modify your first if to be if(isset($_POST)) { // a form has been posted. Then it should work.
Another way to do it:
if(isset($_POST['delete']) && isset($_POST['isbn']) && !empty($_POST['isbn'])){
//delete code here
}
if(isset($_POST['author']) && isset($_POST['title']) && isset....){
// insert code here
}
EDIT: rewritten code:
<?php // sqltest.php
// I don't know what's in here, so I've left it
require_once 'login.php';
$db_server = mysql_connect($db_hostname, $db_username, $db_password);
if (!$db_server) die("Unable to connect to MySQL: " . mysql_error());
mysql_select_db($db_database, $db_server)
or die("Unable to select database: " . mysql_error());
if (isset($_POST))
{
if (isset($_POST['delete']) && !empty($_POST['isbn']))
{
echo "Deleting";
$query = "DELETE FROM classics WHERE isbn='".mysql_real_escape_string($_POST['isbn'])."'";
$result = mysql_query($query) or die(mysql_error());
if(mysql_affected_rows($result) > 0) echo 'user deleted';
}
else
{
echo "Inserting";
$query = "INSERT INTO classics VALUES ('".mysql_real_escape_string($_POST['author'])."', '".mysql_real_escape_string($_POST['title'])."', '".mysql_real_escape_string($_POST['type'])."', '".mysql_real_escape_string($_POST['year'])."', '".mysql_real_escape_string($_POST['isbn'])."')";
if (!mysql_query($query))
{
echo "INSERT failed: $query" . mysql_error();
}
}
}
// you don't need echo's here... just html
?>
<form action="sqltest.php" method="post">
<pre>
Author <input type="text" name="author" />
Title <input type="text" name="title" />
Type <input type="text" name="type" />
Year <input type="text" name="year" />
ISBN <input type="text" name="isbn" />
<input type='submit' value='ADD RECORD' />
</pre>
</form>
<?php
$query = "SELECT * FROM classics";
$result = mysql_query($query);
if (!$result) die ("Database access failed: " . mysql_error());
// a better way to do this:
while($row = mysql_fetch_array($result)){
?>
<pre>
Author <?php echo $row[0]; ?>
Title <?php echo $row[1]; ?>
Type <?php echo $row[2]; ?>
Year <?php echo $row[3]; ?>
ISBN <?php echo $row[4]; ?>
<form action="sqltest.php" method="post">
<input type="hidden" name="delete" value="yes" />
<input type="hidden" name='isbn' value="<?php echo $row[4]; ?>" />
<input type='submit' value='DELETE RECORD' />
</form>
</pre>
<?php
}
mysql_close($db_server);
?>
Verify the method you used in your form. Make sure it's POST like this:
Form action="yourpage.php" method="POST"
and in your code above, replace the following:
$author = get_post('author');
$title = get_post('title');
$type = get_post('type');
$year = get_post('year');
$isbn = get_post('isbn');
with
$author = $_POST['author'];
$title = $_POST['title'];
$type = $_POST['type'];
$year = $_POST['year'];
$isbn = $_POST['isbn'];
Finally, there is no need to check again if the $isbn is not null as you did it in your isset() method. So remove $isbn!="" in the if below:
if (isset($_POST['delete']) && $isbn != "")
{
}
becomes:
if (isset($_POST['delete']))
{
}
Since you are testing, checking if the user clicked the delete button is of less importance. So you can also remove it for a while and add it later because you are sure that, that code is accessible after clicking the delete button.
You have no form field named delete, so it is impossible for your delete code path to ever be taken.
I'm guessing you're tryign to use the value of the submit button to decide what to do? In that case, you're also missing a name attribute on the submit button - without that, it cannot submit any value with the form. You probably want:
<input type="submit" name="submit" value="DELETE RECORD" />
and then have
if (isset($_POST['submit']) && ($_POST['submit'] == 'DELETE RECORD')) {
...
}