I have a list of items in one file (fruit.php):
<form action="delete_items.php" method="post">
<input type="radio" value="apple" name="fruit">Apple<br>
<input type="radio" value="pear" name="fruit">Pear<br>
<input type="radio" value="banana" name="fruit">Banana<br>
<input type="submit" value="delete" name="deleteButton"><br>
</form>
In the delete_items.php, I have a variable that stores the selection:
<?php
$selection = $_POST["fruit"];
echo "are you sure you want to delete it?";
echo '<form action="delete_confirmation.php" method="post"><br>';
echo '<input type="submit" name="deleteYes" value="Yes"><br>';
echo '<input type="submit" name="deleteNo" value="No"><br>';
echo '</form>';
?>
Than in the confirmation file (delete_confirmation.php):
<?php
include 'delete_items.php';
if($_POST["deleteYes"]){
$query = 'DELETE FROM databaseName WHERE fruitName="' . $selection . '"';
$result = mysqli_query($connection, $query);
if(!$result){
die("Delete after check query failed!");
} else {
echo "Delete after check query success!";
}
} elseif($_POST["deleteNo"]){
echo "The course was not deleted!";
}
?>
But the varibale $selection in the delete_confirmation.php file is always null even though i included the delete_items.php file (when i echo it, nothing is shown). Is there a way to pass the selection variable from delete_items.php to the delete_confirmation.php file?
Related
I'm relativity new to php and just testing out some code. The odd thing is that the code both does/doesn't work. The code should check a MySQLi database to determine the state of the check box and then apply that state to the checkbox. What the code currently does is designate the checkbox state based solely off the value of the if condition, regardless of the MySQLi database values.
Here is the code for the html page, it's the if statement near the bottom that's causing issues;
<?php
include_once 'includes/dbh.inc.php';
?>
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<?php
$sql_1 = "SELECT * FROM test2;";
$results = mysqli_query($conn, $sql_1) or die('Error getting data.');
echo(string) "<table>";
echo "<tr><th>state</th><th>id</th></tr>";
while($row = mysqli_fetch_array($results, MYSQLI_ASSOC)) {
echo "<tr><td>";
echo $row['state'];
echo "</td><td>";
echo $row['id'];
echo "</td></tr>";
}
echo "</table>";
?>
<form action="includes/checkbox.inc.php" method="post">
<input type="hidden" name="checkbox1" value="0">
<input type="checkbox" name="checkbox1" value="1"
<?php
$sql_2 = mysqli_query($conn, "SELECT state FROM test2 WHERE id = '0'") or die('Error getting data.');
if ($sql_2 == "0") {
echo "checked";
} else {
echo " ";
}
mysqli_close($conn);
?>
> Item 1<br>
<input type="hidden" name="checkbox2" value="0">
<input type="checkbox" name="checkbox2" value="1" checked> Item 2<br>
<input type="submit" name="Submit" value="Submit">
</form>
<br>
Reset<br>
</body>
</html>
The odd thing about this code is that the if ($sql_2 == "0") results in the checkbox remaining unchecked, but changing the 0 to a 1, if ($sql_2 == "1") results in the checkbox remaining checked. Both results are regardless of what the database shows.
I know all the other bits of code work, because when I check the checkbox and submit, it updates the database and displays it correctly (the reverse is also true).
If anyone knows why if ($sql_2 == "0") is not working, please let me know. I've even checked other stack overflow postings, and as far as I can tell, everything should be coded properly.
Edit:
I should have stated that in the above question, changing the = to == or reversing the order doesn't fix the problem. The if statement still only returns the else statement.
I've done additional research and think that the issue is related to the use of mysqli_query to retrieve the data, as it should likely be mysqli_fetch_row.
if ($sql_2 = "0") will make the value of $sql2 to '0' and this condition will be always true
change it to
if ($sql_2 == "0")
to prevent the accidental assignment you can do like below
if ("0"==$sql_2)
ISSUE FIXED
The solution was to add a mysqli_data_seek() to the php, below is the working code.
<?php
include_once 'includes/dbh.inc.php';
?>
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<?php
$sql_1 = "SELECT * FROM test2;";
$result_1 = mysqli_query($conn, $sql_1) or die('Error getting data.');
echo(string) "<table>";
echo "<tr><th>state</th><th>id</th></tr>";
while($row = mysqli_fetch_array($result_1, MYSQLI_ASSOC)) {
echo "<tr><td>";
echo $row['state'];
echo "</td><td>";
echo $row['id'];
echo "</td></tr>";
}
echo "</table>";
$query_1 = "SELECT state, id FROM test2 ORDER BY id";
$sql_3 = mysqli_query($conn, $query_1) or die('Error getting data.');
if ($result_2 = $sql_3) {
mysqli_data_seek($result_2, 0);
$row_1 = mysqli_fetch_row($result_2);
}
if ($result_3 = $sql_3) {
mysqli_data_seek($result_3, 1);
$row_2 = mysqli_fetch_row($result_3);
}
?>
<form action="includes/checkbox.inc.php" method="post">
<input type="hidden" name="checkbox1" value="0">
<input type="checkbox" name="checkbox1" value="1"
<?php
if ($row_1[0]=="1") {
echo "checked";
} else {
echo " ";
}
?>
> Item 1<br>
<input type="hidden" name="checkbox2" value="0">
<input type="checkbox" name="checkbox2" value="1"
<?php
if ($row_2[0]=="1") {
echo "checked";
} else {
echo " ";
}
?>
> Item 2<br>
<input type="submit" name="Submit" value="Submit">
</form>
<br>
Reset
<br>
<?php
mysqli_close($conn);
?>
</body>
</html>
I am loading some data from a db table to checkboxes. When a user checks boxes and submits, the values from these checkboxes need to be added to a different table. With the code I have now, I am able to send values of one checked box. What am I missing in sending the values of all the checked checkboxes?
<table>
<?php
$q5=mysqli_query($link,"SELECT * FROM brands_offer WHERE Brand_Id='$bid' AND Published='1' ");
while($row5 = mysqli_fetch_array($q5)){
$catid= $row5['Catg_Id'];
$subcatid= $row5['Subcatg_Id'];
$pid= $row5['Product_Id'];
?><tr><td>
<form action="store-admin.php?search=<?php echo $stname;?>#stock" method="post">
<input type="checkbox" name="checkbox" value="<?php echo "$bname,$catid,$subcatid,$pid";?>" >
<?php
echo $bname;
echo " -> ";
echo $catid;
echo ", ";
echo $subcatid;
echo ", ";
echo $pid;
echo " ";
}
?></td></tr>
<input type="submit" value="Save Changes" name="add" >
</form>
</table>
<?php
if(isset($_POST['add']))
{
$chk = $_POST['checkbox'];
$val = explode(",",$chk);
$bn = $val[0];
$cid= $val[1];
$scid= $val[2];
$prid= $val[3];
echo "<script type='text/javascript'>alert('brand: ". $bn."')</script>";
echo "<script type='text/javascript'>alert('cat: ". $cid."')</script>";
echo "<script type='text/javascript'>alert('sub: ". $scid."')</script>";
echo "<script type='text/javascript'>alert('pr: ". $prid."')</script>";
}?>
Use brackets in your checkbox name attribute name="checkbox[]" and your post variable will be an array of selected values.
Edit: I noticed you have form opening tag inside the while loop. You need to put it before while loop otherwise its generating tons of opening form tags.
So it looks like you have only one checkbox. If you want to POST the values of all the checkboxes as an array I believe you need to add [] to the name of your input field. So:
<input type="checkbox" name="checkbox[]" value="<?php echo "$bname";?>"/>
<input type="checkbox" name="checkbox[]" value="<?php echo "$catid";?>"/>
<input type="checkbox" name="checkbox[]" value="<?php echo "$subcatid";?>"/>
<input type="checkbox" name="checkbox[]" value="<?php echo "$pid";?>"/>
Hopefully I understood your question.
I'm trying to delete some information from the database, but when I ask the user to confirm action, something goes wrong. Can you help me?
The script prints the categories to choose if nothing is settled. Then, It asks the user to delete or not delete the categories chosen. In the end, it deletes what was chosen.
But there's some error in the last part(first in the script) and I cannot understad where it's going wrong:
<?php
//If the user confirm to delete...
if(isset($_POST['eliminazione_conferma']) and $_POST['eliminazione_conferma']=='conferma'){
//if conferma_eliminazione=1, don't delete
if(isset($_POST['conferma_eliminazione']) and $_POST['conferma_eliminazione']=='1'){
echo 'Eliminazione annullata';
}else{//Delete if conferma_eliminazione=0
while($row=$categoria){
$delete= "DELETE FROM categorie WHERE $row = category_id";
$query=mysql_query($delete);
echo "$row eliminato\n";
}
}
}else{//ELSE, print the form to confirm action
if(isset($_POST['eliminazione']) and $_POST['eliminazione']=='delete'){
//Array with the chosen "categories"
$categoria=isset($_POST['categoria']) ? $_POST['categoria'] : array();
//Print the chosen categories to ask confirmation
echo'Sicuro di voler eliminare le seguenti categoire?<br />';
foreach($categoria as $row){
echo "$row<br />\n";
}
//Yes = 0, No = 1
echo '<form method="post" action="',$_SERVER['REQUEST_URI'],'">
<input type="radio" name="conferma_elimiazione" value="0" />Si<br />
<input type="radio" name="conferma_eliminzione" value="1" />No<br />
<input type="hidden" name="eliminazione_conferma" value="conferma" />';
foreach($categoria as $row){
echo'<input type="hidden" name="categoria[]" value="',$row,'" />',"\n",'' ;
}
echo'
<input type="submit" value="Conferma" />
</form>';
}else{//In the end, if nothing is settled, print the form to check the category to delete
//Select the categories from the database
echo'<form method="post" action="',$_SERVER['REQUEST_URI'],'" />',"\n",'';
$select = "SELECT nome,category_id FROM categorie ORDER BY category_id" ;
$select_result=mysql_query($select) or die("Mysql Error: ".mysql_error());
while($row = mysql_fetch_assoc($select_result)){
echo '<input type="checkbox" name="categoria[]" value="',$row['category_id'],'">',$row['nome'],'<br />';
}
echo'<input type="hidden" name="eliminazione" value="delete" />
<input type="submit" name="submit" value="Elimina" />
</form>';
}
}
The problem with the query
$delete= "DELETE FROM categorie WHERE $row = category_id";
is
here
WHERE $row = category_id";
What is category_id?
Do you have a value for that?
Probably you want WHERE category_id=/*something here like $row['column_name']*/
Thanks everyone for the help, but I've solved my problem in this way(the script wasn't transformig the value of "conferma_eliminazione" in the integer type):
<h2>Modifica o Elimina Categoria </h2>
<?php
if(isset($_POST['eliminazione_conferma']) and $_POST['eliminazione_conferma']=='conferma'){
$categoria=isset($_POST['categoria']) ? $_POST['categoria'] : array();
$a=(int)$_POST['eliminazione'];
if($a=='1'){
echo 'Eliminazione annullata';
echo "\n";
}elseif($a=='0'){
foreach($categoria as $row){
$delete= "DELETE FROM categorie WHERE $row = category_id";
$query=mysql_query($delete);
echo "$row eliminato\n";
}
}
}else{
if(isset($_POST['eliminazione']) and $_POST['eliminazione']=='delete'){
$categoria=isset($_POST['categoria']) ? $_POST['categoria'] : array();
echo'Sicuro di voler eliminare le seguenti categoire?<br />';
foreach($categoria as $row){
echo '',$row,'<br />',"\n";
}
echo '<form method="post" name="form_eliminazione_categoria" action="',$_SERVER['REQUEST_URI'],'">',"\n",'
<input type="radio" name="eliminazione" value="0" />Si<br />' ,"\n",'
<input type="radio" name="eliminazione" value="1" />No<br />',"\n",'
<input type="hidden" name="eliminazione_conferma" value="conferma" />',"\n",'';
foreach($categoria as $row){
echo '<input type="hidden" name="categoria[]" value="',$row,'" /><br />',"\n",'';
}
echo'
<input type="submit" value="Conferma" />
</form>';
}else{
echo'<form method="post" action="',$_SERVER['REQUEST_URI'],'" />',"\n",'';
$select = "SELECT nome,category_id FROM categorie ORDER BY category_id" ;
$select_result=mysql_query($select) or die("Mysql Error: ".mysql_error());
while($row = mysql_fetch_assoc($select_result)){
echo '<input type="checkbox" name="categoria[]" value="',$row['category_id'],'">',$row['nome'],'<br />';
echo "\n";
}
echo'<input type="hidden" name="eliminazione" value="delete" />',"\n",'
<input type="submit" name="submit" value="Elimina" />',"\n",'
</form>';
}
}
It is simple but I am not getting values of radio buttons for updation when I press submit.
It is giving an error in foreach statement like :Warning: Invalid argument supplied for foreach() Please say how to get the values of radio button after pressing submit button,
here I am updating the status of state .
<?php
include("db.php");
?>
<html>
<body>
<?php
$state=$_POST['state'];
if(isset($_POST['submit']))
{
$result1 = mysql_query("select state,id,status from states ");
while($rr1=mysql_fetch_array($result1))
{
//getting values of radio buttons
$myval=$rr1['id'];
echo $myval;
$val=$_POST['yes.$rr1["id"]'];
echo $val;
$val1=$val.$myval;
$vall=yes.$rr1['id'];
foreach($vall as $values)
{
echo $values;
$update=mysql_query("UPDATE states SET status='". $values."'
WHERE id='$myval' ");
}
}
}
echo "ok";
?>
<form action="" name="form" id="form" method="post" >
<?php
//session_start();
include("db.php");
$result = mysql_query("select state,id,status from states ");
while($info1=mysql_fetch_assoc( $result))
{
echo $info1['city'];
echo "<br>";
/*echo "<br>";
echo "company Name:".$info1['company_name'];
echo "<br>";
echo "salary:".$info1['maxsalary'];
echo "<br>";
//echo $info1['company_name'];*/
?>
<label><?php echo $info1['state']; ?></label>
<input type="radio" <?php if($info1['status']=="yes"){ echo
"checked='checked'"; } ?> name="yes.<?php echo $info1[ 'id']; ?>[]"
value="yes">Yes
<input type="radio" <?php if($info1['status']=="no"){ echo
"checked='checked'"; } ?> name="yes.<?php echo $info1[ 'id']; ?>[]"
value="no">no
<br/>
<?php } ?>
<br />
<input type="submit" name="submit" value="submit" />
</form>
</body>
</html>
I think you need to write
$vall=yes.$rr1['id'];
to
$vall="yes".$rr1['id'];
Thanks
I want two radio buttons on a webpage (written in php) representing "yes" and "no". When I load the page I want it to fetch a value from a mysql db and set the corresponding radio button. And when I click on the other button, I want it to update the database and reload the page.
I'm trying to do this with a simple html form, but no luck. The code I have so far (that is not working at all :( is:
if (!isset($_POST['submit'])) {
$sql = "SELECT challenge_me FROM contestants WHERE id=$id";
$res = (mysql_fetch_assoc(mysql_query($sql, $db)));
$challenge_me = $res["challenge_me"];
}else{
$sql = "UPDATE contestants SET challenge_me='" . $_POST['YesNo'] . "' WHERE id='$id'";
if(!mysql_query($sql, $db))
echo mysql_error(), "<br/>Query '$sql'";
$challenge_me = $_POST['YesNo'];
}
echo'<form method="post" action="' . $PHP_SELF . '">';
echo '<input type="hidden" name="submit" value="submit">';
if($challenge_me == 1){
echo'<input type="radio" name="YesNo" value="1" onClick="this.form.submit();" checked>Yes ';
echo'<input type="radio" name="YesNo" value="0" onClick="this.form.submit();">No ';
}else{
echo'<input type="radio" name="YesNo" value="1" onClick="this.form.submit();">Yes ';
echo'<input type="radio" name="YesNo" value="0" onClick="this.form.submit();" checked>No ';
}
echo'</form>';
Your script doesnt seem to define $id, where does $id get its value from? That could be the source of your problem. Your script might not be passing any value in $id