Populating an HTML table with MySQL data, linked by calendar date - php

Question

I am using the code below to generate a simple HTML table that displays the next 90 calendar days. Each day is a row in this simple table.
$now = time();
echo "<table>";
for ($i=0;$i<90;$i++)
{
$thisDate = date("d/m/Y",$now + ($i*86400));
echo "<tr><td>".$thisDate."</td></tr>\n";
}
echo "</table>";
Also, I have a MySQL table with the following fields:
event varchar(1000)
datescheduled date
How can I make a second column in the aforementioned HTML table, containing "event" from the MySQL table, matched by date?

Answer 1

This can be tackled in numerous ways. Consider this example:
PHP
<?php
$con = mysqli_connect("localhost","dbuser","dbpass","database");
$query = mysqli_query($con, "SELECT * FROM event");
// First build the array of events, put the dates in keys, then the values as events
$events = array();
while($result = mysqli_fetch_assoc($query)) {
$events[$result['datescheduled']] = $result['event'];
}
?>
// Structure should be something like this:
Array
(
[2014-05-02] => Day of lorem
[2014-06-02] => Day of ipsum
[2014-07-02] => Day of days
)
HTML
<!-- the compare selected values on the current loop, check its keys -->
<?php $now = time(); ?>
<table border="1" cellpadding="10">
<?php for($i=0;$i<90;$i++): ?>
<?php $thisDate = date("Y-m-d", $now + ($i*86400)); ?>
<tr>
<td><?php echo $thisDate; ?></td>
<td><?php echo array_key_exists($thisDate, $events) ? $events[$thisDate] : ''; ?></td>
</tr>
<?php endfor; ?>
</table>

Answer 2

$now = time();
echo "<table>";
for ($i=0;$i<90;$i++)
{
$thisDate = date("d/m/Y",$now + ($i*86400));
echo "<tr><td>".$thisDate."</td>";
$result_set = mysql_query("SELECT event FROM eventTable WHERE datescheduled = STR_TO_DATE('{$thisDate}','%d/%m/%Y')'",$connection);
$result = mysql_fetch_assoc($result_set);
echo "<td>{$result['event']}</td></tr>\n";
}
echo "</table>";
Its worth noting that you will need to use a string to date function in mysql depending on how the date is stored.
Edit: in case you need further hand holding, here is the STR_TO_DATE function done for you.
STR_TO_DATE('{$thisDate}','%d/%m/%Y')
I have edited my code above to reflect this as to not strain your brain.
Even tossed in some screenshots of the table and the output, just because you were kind of an ass in your comment. With 5 years of experience i would have thought you would know how to echo out a simple table like this, or at the very least, have a little common courtesy when someone tries to help you.