I want to check is null or empty result in my DB, create this query
$query = "SELECT smtp_login FROM tbl_users WHERE id=". $id. " AND (smtp_login IS NULL OR TRIM(smtp_login)='')";
$list = Yii::app()->db->createCommand($query)->query();
foreach($list as $item){
for($i=0;$i<count($item);$i=$i+1)
{
if(is_null($item[$i]) & $item[$i]=='') { echo 'True'; }
else { echo 'False'; }
}
}
When item is null all is ok, getting True value, but when it isn't returned just empty popup not False.
Use or(||) instead of and(&)
if(is_null($item[$i]) || $item[$i]=='') { echo 'True'; }
Use queryAll() instead of query(). query() returns a single record, but queryAll() - all data matching criteria.
Related
Im writing a page in HTML/PHP that connects to a Marina Database(boats,owners etc...) that takes a boat name chosen from a drop down list and then displays all the service that boat has had done on it.
here is my relevant code...
if(isset($_POST['form1'])){//if there was input data submitted
$form1 = $_POST['form1'];
$sql1 = 'select Status from ServiceRequest,MarinaSlip where MarinaSlip.SlipID = ServiceRequest.SlipID and BoatName = "'.$form1.'"';
$form1 = null;
$result1 = $conn->query($sql1);
$test = 0;
while ($row = mysqli_fetch_array($result1, MYSQLI_ASSOC)) {
$values1[] = array(
'Status' => $row['Status']
);
$test = 1;
}
echo '<p>Service Done:</p><ol>';
if($test = 1){
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
echo '</ol>';
}else{
echo 'No service Done';
}
the issue im having is that some of the descriptions of sevice are simply Open which i do not want displayed as service done, or there is no service completed at all, which throws undefined variable: values1
how would I stop my script from adding Open to the values1 array and display a message that no work has been completed if values1 is empty?
Try this
$arr = array();
if (empty($arr))
{
echo'empty array';
}
We often use empty($array_name) to check whether it is empty or not
<?php
if(!empty($array_name))
{
//not empty
}
else
{
//empty
}
there is also another way we can double sure about is using count() function
if(count($array_name) > 0)
{
//not empty
}
else
{
//empty
}
?>
To make sure an array is empty you can use count() and empty() both. but count() is slightly slower than empty().count() returns the number of element present in an array.
$arr=array();
if(count($arr)==0){
//your code here
}
try this
if(isset($array_name) && !empty($array_name))
{
//not empty
}
You can try this-
if (empty($somelist)) {
// list is empty.
}
I often use empty（$arr) to do it.
Try this instead:
if (!$values1) {
echo "No work has been completed";
} else {
//Do staffs here
}
I think what you need is to check if $values1 exists so try using isset() to do that and there is no need to use the $test var:
if(isset($values1))
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
Or try to define $values1 before the while:
$values1 = array();
then check if it's not empty:
if($values1 != '')
foreach($values1 as $v1){
echo '<li>'.$v1['Status'].'</li>';
}
All you have to do is get the boolean value of
empty($array). It will return false if the array is empty.
You could use empty($varName) for multiple uses.
For more reference : http://php.net/manual/en/function.empty.php
I am trying to GET different rows from different columns in php/mysql, and pack them into an array. I am able to successfully GET a jason encoded array back IF all values in the GET string match. However, if there is no match, the code echos 'no match', and without the array. I know this is because of the way my code is formatted. What I would like help figuring out, is how to format my code so that it just displays "null" in the array for the match it couldn't find.
Here is my code:
include '../db/dbcon.php';
$res = $mysqli->query($q1) or trigger_error($mysqli->error."[$q1]");
if ($res) {
if($res->num_rows === 0)
{
echo json_encode($fbaddra);
}
else
{
while($row = $res->fetch_array(MYSQLI_BOTH)) {
if($_GET['a'] == "fbaddra") {
if ($row['facebook'] === $_GET['facebook']) {
$fbaddr = $row['addr'];
} else {
$fbaddr = null;
}
if ($row['facebookp'] === $_GET['facebookp']) {
$fbpaddr = $row['addr'];
} else {
$fbpaddr = null;
}
$fbaddra = (array('facebook' => $fbaddr, 'facebookp' => $fbpaddr));
echo json_encode($fbaddra);
}
}
}
$mysqli->close();
UPDATE: The GET Request
I would like the GET request below to return the full array, with whatever value that didn't match as 'null' inside the array.
domain.com/api/core/engine.php?a=fbaddra&facebook=username&facebookp=pagename
The GET above currently returns null.
Requests that work:
domain.com/api/core/engine.php?a=fbaddra&facebook=username or domain.com/api/core/engine.php?a=fbaddra&facebookp=pagename
These requests return the full array with the values that match, or null for the values that don't.
TL;DR
I need assistance figuring out how to format code to give back the full array with a value of 'null' for no match found in a row.
rather than assigning as 'null' assign null. Your full code as follows :
include '../db/dbcon.php';
$res = $mysqli->query($q1) or trigger_error($mysqli->error."[$q1]");
if ($res) {
if($res->num_rows === 0)
{
echo json_encode('no match');
}
else
{
while($row = $res->fetch_array(MYSQLI_BOTH)) {
if($_GET['a'] == "fbaddra") {
if ($row['facebook'] === $_GET['facebook']) {
$fbaddr = $row['dogeaddr'];
//echo json_encode($row['dogeaddr']);
} else {
$fpaddr = null;
}
if ($row['facebookp'] === $_GET['facebookp']) {
$fbpaddr = $row['dogeaddr'];
//echo json_encode($row['dogeaddr']);
} else {
$fbpaddr = null;
}
$fbaddra = (array('facebook' => $fbaddr, 'facebookp' => $fbpaddr));
echo json_encode($fbaddra);
}
}
}
$mysqli->close();
You can even leave else part altogether.
Check your code in this fragment you not use same names for variables:
if ($row['facebook'] === $_GET['facebook']) {
$fbaddr = $row['dogeaddr'];
//echo json_encode($row['dogeaddr']);
} else {
$fpaddr = 'null';
}
$fbaddr not is same as $fpaddr, this assign wrong result to if statement.
It was the mysql query that was the problem.
For those who come across this, and need something similar, you'll need to format your query like this:
** MYSQL QUERY **
if ($_GET['PUTVALUEHERE']) {
$g = $_GET['PUTVALUEHERE'];
$gq = $mysqli->real_escape_string($g);
$q1 = "SELECT * FROM `addrbook` WHERE `facebookp` = '".$gq."' OR `facebook` = '".$gq."'";
}
** PHP CODE **
if($_GET['PUTVALUEHERE']{
echo json_encode($row['addr']);
}
My code is always returning true when I'm comparing these variables.
What am I doing wrong?
<?php
$postuser = (integer)bp_activity_user_id(); //echos 1int(0)
$posteduser = (integer)bp_activity_comment_user_id(); //echos 3int(0)
if ( $postuser === $posteduser) {
echo 'true';
} else {
echo 'false';
}
?>
You need to use the function that RETURNs the value, not outputs it.
From docs I found for whatever this is,
bp_activity_user_id() X-Ref
Output the activity user ID.
bp_get_activity_user_id() X-Ref
Return the activity user ID.
return: int The activity user ID.
The function you are using echoes the variable, NOT returns it and therefore you can't set a variable with that function. Same for the this function.
bp_activity_comment_user_id() X-Ref
Output the ID of the author of the activity comment currently being displayed.
bp_get_activity_comment_user_id() X-Ref
Return the ID of the author of the activity comment currently being displayed.
return: int|bool $user_id The user_id of the author of the displayed
To use in an assignment, the function has to return a value. That's why your values are always (int)0: the functions you are using have no return value. So, it returns null which is cast to 0.
<?php
$postuser = bp_get_activity_user_id();
$posteduser = bp_get_activity_comment_user_id();
//no need to cast: these functions return integers
if ( $postuser === $posteduser) {
echo 'true';
} else {
echo 'False';
Just use intval and == i think it should work and evaluate it fine
<?php
$postuser = intval(bp_activity_user_id()); //echos 1int(0)
$posteduser = intval(bp_activity_comment_user_id()); //echos 3int(0)
if ( $postuser == $posteduser) {
echo 'true';
} else {
echo 'False';
}
?>
Your prbolems are probably the wrong typecasts:
Change (integer) to (int)
$postuser = (int)bp_activity_user_id(); //echos 1int(0)
$posteduser = (int)bp_activity_comment_user_id();
http://php.net/manual/en/language.types.integer.php
I wanted to make sure there are results before running the while loop but all the methods I am trying seem to remove the first result.
$nearbyResult = mysqli_query($con,$sqlNearby);
if(mysqli_fetch_array($nearbyResult) == 0) {
echo '<p>No results found, Add your property here.</p>';
} else {
while($rowNearby = mysqli_fetch_array($nearbyResult)) {
}
}
This line will take the first row of your result set and chuck it in the bin:
if(mysqli_fetch_array($nearbyResult) == 0) {
Change to:
if( ! mysqli_num_rows($nearbyResult) ) {
And check your freakin function returns:
if( ! $nearbyResult = mysqli_query($con,$sqlNearby) ) {
echo "Mysql error: " . mysqli_error($con);
}
You can use the mysql_row_count method to count how many rows are returned in your query http://php.net/manual/en/mysqli-result.num-rows.php
Try assigning the results to a variable as part of your if statement. If mysqli_fetch_array() has no result set to work with it will return false.
if($rowNearby = mysqli_fetch_array($nearbyResult)) {
//There was a result, work with it here
doStuffWith($rowNearby);
} else {
//No records in your result set, handle as desired
}
I am trying to check if the mysql_fetch_array() function returns an empty array or not. But my code doesn't seem to work. Here I want to ensure that if the array is empty I want to display under construction message.
Code :
$queryContents= queryMembers();
$exeQuery = mysql_query($queryContents);
while($fetchSet = mysql_fetch_array($exeQuery)) {
if(count($fetchSet) == 0) {
echo "This Page is Under Construction";
}else{
// something else to display the content
}
}
How do I check to acheive such feature ?
use mysql_num_rows to count number of rows. try this.
$exeQuery = mysql_query($queryContents);
if(mysql_num_rows($exeQuery)== 0){
echo "This Page is Under Construction";
}
else{
while($fetchSet = mysql_fetch_array($exeQuery)) {
// something else to display the content
}
}
You really should be using mysql_num_rows http://us2.php.net/manual/en/function.mysql-num-rows.php
However, on a side note, you should use php empty() instead. http://us2.php.net/empty
When you use mysql_fetch_array(), it returns the rows from the data
set one by one as you use the while loop.
If there will be no record, while loop wont execute. In this case, declare a boolean variable and make it true if it enters the while loop. Like:
$queryContents= queryMembers();
$exeQuery = mysql_query($queryContents);
$recordExists = 0;
while($fetchSet = mysql_fetch_array($exeQuery)) {
if($recordExists == 0 )
$recordExists = 1;
// something else to display the content
}
if($recordExists == 0 ){
echo "This Page is Under Construction";
}
Hope this works!
You can do it this way:
while($r[]=mysql_fetch_array($sql));
// now $r has all the results
if(empty($r)){
// do something
}
source: php doc
Your code inside the while loop never runs if there are no results. mysql_fetch_array returns null/false if there are no more results. What you need yo do is check with mysql_num_rows first, before the while.
$queryContents= queryMembers();
$exeQuery = mysql_query($queryContents);
if(mysql_num_rows ($exeQuery) == 0) {
echo "This Page is Under Construction";
}
while($fetchSet = mysql_fetch_array($exeQuery)) {
// something else to display the content
}
Try this
if(empty($fetchSet)
{
echo "This Page is Under Construction";
}
else
{
// something else to display the content
}