Below is the source table and the output I am trying to achieve.
I would like each another_table.id to only appear once in the output, with subsequent values displaying in new columns
This will give you the output, given the table in your question. With CTEs instead of subqueries for added clarity...
with intials as(
SELECT id,
another_table.id as another_table_id,
value as field_1
FROM
main_table
WHEN
variable.id = 1),
finals as(
SELECT id,
another_table.id as another_table_id,
value as field_1
FROM
main_table
WHEN
variable.id = 2)
SELECT
initials.id,
initials.another_table_id
initials.value field_1,
finals.value field_2
FROM
initials
LEFT OUTER JOIN
finals on initials.another_table_id = finals.another_table_id;
Related
I have 2 tables let say table1 & table2
table1 contains uniqueId, name1, name2, value fields
table2 contains id, uniqueName, keywords fields
table2.keyworks have comma separate names.
So, what I am trying to do is below.
select * from table1
//1> replace table1.name1 with table2.uniqueName if table2.keywords has
//table1.name1
//2> replace table1.name2 with table2.uniqueName if table2.keywords has
//table1.name2
select *,(case when FIND_IN_SET(table.name1,table2.keywords)>0 then table1.name1
when FIND_IN_SET(table.name1,table2.keywords)>0 then table1.name2 end)from table1
Try this.
I would like to seek some help in my query...i want to do is if specific atic and oaic is empty in the table...the interview_sum or other_sum to that specific atic oaic should be empty too....can anyone know how to do that?
picture of current output:
current query: my query still gives numbers to other_sum or interview_sum even its empty.
SELECT DISTINCT
IF(t.inttotal=NULL,0,(SELECT SUM(t2.inttotal)
FROM app_interview2 AS t2
WHERE t2.atic = t.atic AND t2.inttotal>0)/7)
AS interview_sum,
IF(o.ototal=NULL,0,(SELECT SUM(o2.ototal)
FROM other_app2 AS o2
WHERE o2.oaic = o.oaic AND o2.ototal>0)/7)
AS other_sum,
atid,
atic,
atname,
region,
town,
uniq_id,
position,
salary_grade,
salary
FROM app_interview2 AS t, other_app2 AS o
GROUP BY t.atname HAVING COUNT(DISTINCT t.atic)
I made a few assumptions:
You probably have a table that app_interview2.atic and other_app2.oaic are the foreign keys of, but since you did not share it, I derived a table in the FROM clause.
This assumes atname is always the same for atid.
You are also dividing by 7 - which I assume is to get the average, so I used the AVG function.
Solution---
SELECT t1.id AS atid
,interview.atname AS atname
,COALESCE(interview.interviewsum, 0) AS interviewsum
,COALESCE(interview.interviewavg,0) AS interviewavg
,COALESCE(other.othersum, 0) AS othersum
,COALESCE(other.otheravg) AS otheravg
FROM (SELECT DISTINCT atid AS id
FROM app_interview2
UNION
SELECT DISTINCT oaic
FROM other_app2) AS t1
LEFT JOIN (SELECT atid, atname, SUM(inttotal) AS interviewsum, AVG(inttotal) AS interviewavg
FROM app_interview2
GROUP BY atid, atname) as interview
ON interview.atid = t1.id
LEFT JOIN (SELECT oaic, SUM(ototal) AS othersum, AVG(ototal) AS otheravg
FROM other_app2
GROUP BY oaic) AS other
ON other.oaic = t1.id;
--
If this gives the results your were hoping for, I would replace the t1 derived table in the FROM clause with the table whose primary key I described above AND probably has those columns (e.g., region, town, etc) that I did not include
How can I select one row from that table http://i.stack.imgur.com/27cu9.jpg where values of 'user_1' and 'user_2' may look like
user_1 user_2
1 2
2 1
In other words I want to select a field that contains 2 users with submitted=1 no matter in which field the value is.
Here is a simple query that does this:
select *
from t
where submitted = 1 and 2 in (user_1, user_2)
If I understood your question, I think you need to JOIN the table on itself if you are trying to return rows that have corresponding users (1,2) and (2,1):
select t1.*
from yourtable t1
join yourtable t2 on
t1.user_1 = t2.user_2 and t1.user_2 = t2.user_1
SQL Fiddle Demo
If however you are just trying to see if user 2 exists in either of the fields, then look at Gordon's post.
Use this:-
select * from tblname as t1, tblname as t2 where
t1.user_1 = t2.user_2 and t1.user_2 = t2.user_1 and t1.user_1<>t1.user_2
EDIT:-
Updated the query so that the rows with the same values do not appear in the result.
How do I select a column value as a column name and group the results as a row.
I have a table as such:
id articleId label value
1 1 title Example title
2 1 description This is the description
3 1 author Me
4 2 title Example of another type of article
5 2 description Short description
6 2 author Someone else
Is it possible to select all of the rows and use the label as the column name and the value as the value of that column name and then group them by the article name.
So how I would like to have it returned:
articleId title description author
1 Example title This is the.. Me
2 Example of an.. Short descr.. Someone else
I'm using this for a CMS where the user can define the fields for an article so we don't have to customize the table's. This is why i'm not making the tables as the I would like to have it returned. I am also aware that I can just as easily convert the result to this in php.
-- edit --
Can this be done without knowing what labels are added? In this example im using title, description and author. But it could very well be something totally different like title, shortDescription, availableTo, techInformation, etc.. The idea is that the article's are customizable for the user without needing to change the database and query's
I figured I'd better post as an answer, even if not what OP would like to hear. What you are asking to do is to populate a query with a variable number of columns based on the distinct values within column label, all associated with articleID. Taking your specific example, the following would be the resultant query that I would most likely go to in this instance (though the example from #Devart is equally valid)
SELECT
t.id,
t.articleId,
t1.value AS title,
t2.value AS description,
t3.value AS author
FROM `tableName` t
LEFT JOIN `tablename` t1
ON t1.article_id = t.article_id AND t1.label = 'title'
LEFT JOIN `tablename` t2
ON t2.article_id = t.article_id AND t2.label = 'description'
LEFT JOIN `tablename` t3
ON t3.article_id = t.article_id AND t3.label = 'author'
Now expanding this to account for up to n labels, we get the following query (metacode included, this query will NOT execute verbatim)
SELECT DISTINCT label FROM `tableName`;
SELECT
t.id,
t.articleId
// for (i=1;i<= number of distinct labels) {
,t[i].value AS [value[i]]
// }
FROM `tableName` t
// for (i=1;i<= number of distinct labels) {
LEFT JOIN `tablename` t[i]
ON t[i].article_id = t.article_id AND t[i].label = [value[i]]
// }
;
So what you can do is one of the following.
SELECT t.* FROM tablename t and then have PHP process it as required
SELECT DISTINCT label FROM tablename and have PHP build the second query with the many LEFT JOINs (or MAX / GROUP BY logic if preferred)
Create a Stored Procedure to do the same as #2. This would most likely be more efficient than #2 however may be less efficient overall than #1.
You can use pivote table trick -
SELECT
articleId,
MAX(IF(label = 'title', value, NULL)) AS title,
MAX(IF(label = 'description', value, NULL)) AS description,
MAX(IF(label = 'author', value, NULL)) AS author
FROM
table
GROUP BY
articleId
Try below :
select t1.articleId,t1.title,t1.description,t1.author
from tablename as t1
left join (select max(articleId) as articleId
from tablename
group by articleId ) as t2
on t1.articleId=tsm.articleId where [.....]
What i want, to display rows from a table which is selected by a field from other table single value, lets say to display images from a table by last category id.
I have this type of query, but this return me all matching keys rows, if i inset LIMIT 1 then it return one row...
SELECT i.prof_image FROM profile_images i
JOIN images_cat cat ON (cat.cat_id = i.cat_id)
GROUP BY i.prof_image;
//OR LIMIT 1;
Any idea to fix this problem. (i.e. displaying the latest category images)?
This will work for your specific example.. If you need to be more selective, then please post some more details..
SELECT i.prof_image
FROM profile_images i
WHERE cat_id = (select max(cat_id) from images_cat)
SELECT * FROM table_1
LEFT JOIN table_2 ON table_1.id = table_2.id
This query will grab all things in table_2 that have the same id value.
Note that it is a LEFT JOIN - which means that if there are no matching values in table_2, it will still return the values from table_1.
What is your intent with using last()?
Hope this helps.