I have a breadcrumb in a child view, but it is not showing any pages.
When I show it in the root view, everything is working correct
controller:
public function categoriesAction()
{
$view = new ViewModel();
$heading = new ViewModel(array(
'headTitle' => 'Categorieën'
));
$heading->setTemplate('templates/head');
$view->addChild($heading, 'header')
->addChild($storecontent, 'content');
return $view;
}
templates/head.phtml
<?php echo $this->navigation()->breadcrumbs()->setPartial('Application/partials/breadcrumbs'); ?>
When I place the above code in the root view, it is working. But I want it in the head so I can use it in more actions.
Related
I use this partial to generate my submenu.
<?php foreach ($this->container as $page): ?>
<?php foreach ($page->getPages() as $child): ?>
<a href="<?php echo $child->getHref(); ?>" class="list-group-item">
<?php echo $this->translate($child->getLabel()); ?>
</a>
<?php endforeach; ?>
<?php endforeach; ?>
Which is called like this:
$this->navigation('navigation')->menu()->setPartial('partial/submenu')->render();
But when i render the menu the "$child->getHref()" renders the url without the needed "slug/id" parameter.
I tried to create the url with "$this->url()" in ZF1 you could pass the params in an array to the partial but in ZF2 that doesn't seem to work anymore.
Can anybody tell me how to add the params to the menu urls?
Thanks in advance!
PS!
I'm not referring to $this->Partial, i'm talking about $this->navigation('navigation')->menu()->setPartial('partial/submenu')->render() which apparently doesn't support a param array.
If I'm understanding your question, yes, you can pass params to partials. Example:
<?php echo $this->partial('partial.phtml', array(
'from' => 'Team Framework',
'subject' => 'view partials')); ?>
See http://framework.zend.com/manual/2.3/en/modules/zend.view.helpers.partial.html
I'm not sure this completely solves your issue, since you are not showing what the menu helper is. Is it your own view helper? Are you saying that setPartial method only accepts one argument?
All that said, have you considered Spiffy Navigation?
https://github.com/spiffyjr/spiffy-navigation
It's been sometime since this question was asked, however today I came across the same problem (using version 2.4).
If you have a segment route to be included within the menu that requires some parameters there is no way to pass these through to the navigation's view partial helper.
The change I've made allows a ViewModel instance to be passed to the menu navigation helper's setPartial() method. This view model will be the context for the navigation's partial template rendering; therefore we can use it to set the variables we need for the route creation and fetch them just like within other views using $this->variableName.
The change requires you to extend the Menu helper (or which ever navigation helper requires it).
namespace Foo\Navigation;
use Zend\Navigation\AbstractContainer;
use Zend\View\Model\ViewModel;
class Menu extends \Zend\View\Helper\Navigation\Menu
{
public function renderPartial($container = null, $partial = null)
{
if (null == $container) {
$container = $this->getContainer();
}
if ($container && $partial instanceof ViewModel) {
$partial->setVariable('container', $container);
}
return parent::renderPartial($container, $partial);
}
public function setPartial($partial)
{
if ($partial instanceof ViewModel) {
$this->partial = $partial;
} else {
parent::setPartial($partial);
}
return $this;
}
}
Because this extends the default implementation of the helper updated configuration is required in module.config.php to ensure the extend class is loaded.
'navigation_helpers' => [
'invokables' => [
'Menu' => 'Foo\Navigation\Menu',
],
],
The menu helper will then accept a view model instance.
$viewModel = new \Zend\View\Model\ViewModel;
$viewModel->setTemplate('path/to/partial/template')
->setVariable('id', $foo->getId());
echo $this->navigation()
->menu()
->setPartial($viewModel)
->render();
The only change in the actual partial script will require you to create the URL's using the URL view helper.
foreach ($container as $page) {
//...
$href = $this->url($page->getRoute(), ['id' => $this->id]);
//...
}
I have a view section in my project,and using CGridView to list all the data from table,also have an edit and delete option within the grid to edit and delete specific row.
I am stuck with the edit section.I am working on how to get a specific row data dispalyed in editjob.php,I have done a few things,but no use.My codes are as follows,
In my view job section using CgridView,
'buttons' =>array('update'=>array(
'label'=>'edit',
'url'=>'Yii::app()->controller->createUrl("UpdateJob",array("id"=>$data["id"]))',
))
In Model UpdateJob:
public function edit()
{
$criteria=new CDbCriteria;
$criteria->find('id','Admin',true);
return new CActiveDataProvider('viewjob', array(
'criteria'=>$criteria,
// 'sort'=>array(
// 'defaultOrder'=>'key_skills ASC',
// ),
));
in controller:
public function actionUpdateJob()
{
if(isset($_GET['id']))
{
$id=$_GET['id'];
}
$model = new UpdateJob('edit');
$params = array('model' => $model,'id' => $id //passing the id like this
);
$this->render('update', $params);
}
And finaly in view written something like ,but showing error
<div class="row">
<?php echo $form->labelEx($model,'Company Name'); ?>
<?php echo Chtml::textField('posted_by',UpdateJob::model()->FindByPk($model->id)->posted_by); ?>
<?php echo $form->error($model,'posted_by'); ?>
</div>
am I on right track.
Youre loading a fresh model instead of fetching an existing one. Replace this line:
$model = new UpdateJob('edit');
By this line:
$model = UpdateJob::model()->findByPk($id);
To save the data you do this:
if(isset($_POST['UpdateJob'])) {
$model->scenario='edit';
$model->attributes=$_POST['UpdateJob'];
if($model->save())
$this->redirect(array('admin');
}
This is a custom CMS where menu list can be edited in backend and then need to be displayed in front end layout.
Menu controller is in -/application/modules/admin/controllers
and the code for render action is :
<?php
class Admin_MenuController extends CMS_Controller_AdminbaseController
{
public function renderAction()
{
$menu = $this->_request->getParam('menu');
$mdlMenuItems = new Model_MenuItems();
$menuItems = $mdlMenuItems->getItemsByMenu($menu);
if(count($menuItems)>0){
foreach($menuItems as $item){
$label = $item->label;
if(!empty($item->link)){
$uri = $item->link;
}else{
$uri = '/page/open/id/' . $item->pageId;
}
$itemArray[] = array(
'label' => $label,
'uri' => $uri
);
}
$container = new Zend_Navigation($itemArray);
$this->view->navigation()->setContainer($container);
}
}
}
When rendered in - /application/modules/admin/views/scripts/menu/render.phtml using
<? echo $this->navigation()->menu(); ?>
it renders fine, but instead I want to render it in /application/layouts/scripts.
Any help is much appreciated.
go to Zend_View_Helper create exapmle.php as an example;
on it insert function
public function abc()
{
//insert your code here
}
then go to layout.phtml and call it
echo $this->abc();
You can render it in layout this way <?= $this->action('render', 'menu', 'admin');?>
Additionally you can pass some parametrs in array.
Hope this helps you.
I don't want to add child to the viewModel in action controller:
// action controller
public function indexAction() {
$result = new ViewModel();
$result->setTemplate('application/view/another-action');
$comments = new ViewModel();
$comments->setTemplate('application/view/child-comments');
$result->addChild($comments, 'child_comments');
return $result;
}
...
// View
<div>
<?php echo $this->child_comments ?>
</div>
I want to include view in another view:
<div>
<?php
$view = new ViewModel();
$view->setVariables($this->var);
$view->setTemplate('page_nav.phtml');
// here I want to render view
?>
</div>
Is it possible?
This is what the Partial view helper does (docs seem to be outdated, but I'll link them anyway here):
<div>
<?php echo $this->partial('page_nav', array('var' => $this->var)) ?>
<div>
Obviously, your page_nav should be known by your view resolver.
I know this is old, but you can also simply call $this->render('path/to/view-script')
Given an html/javascript 'widget' which needs to have certain fields customized before use. For example, the css class ids need to be unique as the widget may appear more than once on the same page.
Let's say I want to keep the markup (js/html) of the widget stored as a template so that I can fill in the values that need to be customized during resuse.
I know that Zend Framework's views give you at least part of this functionality, but each view is generally associated with a particular controller. Given that this widget could be created from any controller, yes still needs to be able to access some properties stored in a controller (or model). Where should I put the widget markup and how then do I fill in the custom values?
Can I create a custom view that can be reused within the same page (appear more than once) as well as on other pages? If so, how do I set that up?
Sounds like you need a ViewHelper http://framework.zend.com/manual/en/zend.view.helpers.html. Create a custom helper that will fetch the data from a model and just simply output it. This way it won't depend on any controller, can be called in either the layout or in any view script. Example:
// views/helpers/Widget.php
class Zend_View_Helper_Widget extends Zend_View_Helper_Abstract
{
protected $_model = null;
protected $_view = null;
public function widget()
{
$data = $this->_getDataFromModel();
return $this->_view->partial('widget.phtml', array('data' => $data));
}
public function setView(Zend_View_Interface $view)
{
if($this->_view === null) {
$this->_view = $view;
}
return $this->_view;
}
protected function _getDataFromModel()
{
$this->_model = $this->_getModel();
return $this->_model->getDataForWidget();
}
protected function _getModel()
{
if($this->_model === null) {
$this->_model = new Model_Widget(); // or whatever it's called
}
return $this->_model;
}
The partial script:
// views/scripts/widget.phtml
<div class="widget-class"><?php echo $this->data; ?></div>
And when you need it in your views just call it like <?php echo $this->widget(); ?>
Note that I'm rendering the widget in a separate partial view script, just to avoid having html/css in the helper itself.
Hope this helps to get you started :)
Zend_View_Helper_Partial
Example:
<?php echo $this->partial('partial.phtml', array(
'css_id' => 'foobar')); ?>
To run this from any other module:
<?php echo $this->partial('partial.phtml', 'partials_module', array(
'css_id' => 'foobar')); ?>
In your partial view script (partial.html) you would then have access to $this->css_id.