Editing a specific record in yii - php

Question

I have a view section in my project,and using CGridView to list all the data from table,also have an edit and delete option within the grid to edit and delete specific row.
I am stuck with the edit section.I am working on how to get a specific row data dispalyed in editjob.php,I have done a few things,but no use.My codes are as follows,
In my view job section using CgridView,
'buttons' =>array('update'=>array(
'label'=>'edit',
'url'=>'Yii::app()->controller->createUrl("UpdateJob",array("id"=>$data["id"]))',
))
In Model UpdateJob:
public function edit()
{
$criteria=new CDbCriteria;
$criteria->find('id','Admin',true);
return new CActiveDataProvider('viewjob', array(
'criteria'=>$criteria,
// 'sort'=>array(
// 'defaultOrder'=>'key_skills ASC',
// ),
));
in controller:
public function actionUpdateJob()
{
if(isset($_GET['id']))
{
$id=$_GET['id'];
}
$model = new UpdateJob('edit');
$params = array('model' => $model,'id' => $id //passing the id like this
);
$this->render('update', $params);
}
And finaly in view written something like ,but showing error
<div class="row">
<?php echo $form->labelEx($model,'Company Name'); ?>
<?php echo Chtml::textField('posted_by',UpdateJob::model()->FindByPk($model->id)->posted_by); ?>
<?php echo $form->error($model,'posted_by'); ?>
</div>
am I on right track.

Answer 1

Youre loading a fresh model instead of fetching an existing one. Replace this line:
$model = new UpdateJob('edit');
By this line:
$model = UpdateJob::model()->findByPk($id);
To save the data you do this:
if(isset($_POST['UpdateJob'])) {
$model->scenario='edit';
$model->attributes=$_POST['UpdateJob'];
if($model->save())
$this->redirect(array('admin');
}