I have an table like this
I have been try this sql code
SELECT id,lat,lng,name,MIN(hitung) AS Smallest FROM open_list;
but the result give me wrong query
what i wanna do is being like this :
You could do this:
SELECT id,lat,lng,name,hitung
FROM open_list
ORDER BY hitung ASC
LIMIT 1
Or, if you want to do more complex stuff, start with this:
SELECT id,lat,lng,name,hitung
FROM open_list
JOIN (
SELECT MIN(hitung) as hitung
FROM open_list
) tmp USING (hitung)
When you do not GROUP BY non-aggregate values from your SELECT list, the returned values are arbitrary. You can add a GROUP BY but that will return multiple records, you can use ORDER BY and LIMIT to get what you're after:
SELECT id,lat,lng,name,hitung
FROM open_list
GROUP BY id,lat,lng,name
ORDER BY hitung ASC
LIMIT 1;
Related
Hi i have this sql code i want to query in phpmyadmin
SELECT DISTINCT `unit`,`location` FROM `myasset` ORDER BY `unit` asc
It is possible to add custom number in my sql result
I tried something like below..its not working ..i received message row_number function does not exist
SELECT DISTINCT Row_Number(),`unit`,`location` FROM `myasset` ORDER BY `unit`
SELECT Row_Number() DISTINCT`unit`,`location` FROM `myasset` ORDER BY `unit`
First you have to set a value like
SET #rnum = 0;
then
SELECT #rnum:=#rnum+1 AS row_num, DISTINCT unit,location FROM myasset ORDER BY unit asc
Hope it will solve your issue.
Thanks
You could do
select #rownum:=#rownum+1 No,DISTINCT unit,location FROM myasset ORDER BY unit, (SELECT #rownum:=0);
I am trying to get data from my table using group by . using group by works correctly but i need to take only last inserted item of every group but its not work. my query always return first item of each group.
my query
SELECT id,type,userId,performDate,eventId FROM
`user_marker` where `eventId`='842' and DATE_FORMAT(from_unixtime(performDate),'%Y%c%d')
=DATE_FORMAT(now(),'%Y%c%d')
and `visibility`='1'GROUP BY type ORDER BY id DESC
Please try
SELECT a.* FROM ( SELECT id,type,userId,performDate,eventId FROM
`user_marker` where `eventId`='842' and DATE_FORMAT(from_unixtime(performDate),'%Y%c%d')
=DATE_FORMAT(now(),'%Y%c%d') and `visibility`='1' ORDER BY id DESC ) as a GROUP BY a.type
You can try as per below-
SELECT b.id,b.type,b.userId,b.performDate,b.eventId
FROM user_marker b
JOIN (SELECT `type`,MAX(performDate)
FROM user_marker
WHERE `eventId`='842' AND DATE(FROM_UNIXTIME(performDate))=CURDATE() AND `visibility`='1'
GROUP BY `type`) a ON a.type=b.type AND a.performDate=b.performDate
ORDER BY b.`type`;
I have a table structure which looks like as follows
In the above table I need the team_id for which win+runs_scored is maximum.
I know that task can be accomplished by PHP code but if there is any query possible for this then it would be easier for me and also main thing is that in real table contains more then 15000 rows so please if some can can provide me a better solution then it would be great
select t.team_id
from YourTable t
order by t.win + t.run_scored desc
limit 1
SELECT teamid FROM
(
SELECT max(win+run_scored),teamid FROM YOUR_TABLE GROUP BY teamid
ORDER BY max(win+run_scored) desc
)
WHERE rownum <= 1
select max(t.win + t.run_scored) ,t.team_id
from YourTable t
group by t.team_id
Limit 1
i have a MySql table that consists of 2 basic things:
The id and a value.
To show that on my page, i need to select, for example, the last 100 rows on reversed order.
So imagine that someone is putting data on it:
Id, value
1, 10
2, 9
3, 21
4, 15
i need, to select the last "3" rows (LIMIT + ORDER Clause), but not like this: 4,3,2 but like this: 2,3,4.
I know how to do that on code, but maybe there is a simple solution for that on Mysql and i don`t know.
Thanks
My SQL Query is like this right now:
SELECT `Data`.`id`, `Data`.`log_id`, `Data`.`value`, `Data`.`created` FROM `control_panel`.`datas` AS `Data` WHERE `Data`.`id` > 1000 AND `Data`.`log_id` = (2) ORDER BY `Data`.`id` DESC LIMIT 100
You need to wrap the first ORDER BY in a subselect which will return a limited selection ordered in descending order, then you can order that result in the outer query in ascending order:
SELECT
a.*
FROM
(
SELECT id, value
FROM tbl
ORDER BY id DESC
LIMIT 3
) a
ORDER BY
a.id
One way to do this would be with a sub-select.
SELECT *
FROM (SELECT * FROM table_name ORDER BY id DESC LIMIT 3) tmp
ORDER BY id ASC
simply
SELECT t.*
(SELECT * FROM table_name
ORDER BY column_name DESC
LIMIT 0,3) t
ORDER BY t.column_name ASC
use DESC to descending order, ASC to increasing order
I need to order my query by date first...
So I used this:
SELECT * FROM `mfw_navnode` order by `id` DESC
I wanted to order my results from last to first.
Then what I am trying to do
is to add a query over it, which would group my results by node_name..
The result should be..all the top nodes grouped by "category/node name type", while the first node that I see is was ordered the highest for its category in the first query..
I thought to do something like this:
SELECT * FROM(
SELECT * FROM `mfw_navnode` order by `id` DESC) AS DD
WHERE (node_name='Eby' OR node_name='Laa' OR node_name='MIF' OR node_name='Amaur' OR node_name='Asn' )
GROUP BY DD.node_name
I get no result..or any response from phpmyadmin when I input that result..
Where do I get wrong?
Note , I dont want to group my results and then order them..
I want them to be ordered, and then grouped. After being grouped..I want the result of each group to have the highest value ..from the other rows in the group
It is not sufficient to perform the ordering first, as even then MySQL makes no guarantee over which record it will select for each group. From the manual:
The server is free to choose any value from each group, so unless they are the same, the values chosen are indeterminate.
You must instead identify the records of interest with a subquery, then join the result with your table again in order to obtain the related values:
SELECT *
FROM mfw_navnode NATURAL JOIN (
SELECT node_name, MAX(id) AS id FROM mfw_navnode GROUP BY node_name
) AS DD
WHERE node_name IN ('Eby', 'Laa', 'MIF', 'Amaur', 'Asn')
Ordered by ID and group by node_name
SELECT * FROM `mfw_navnode`
WHERE (node_name='Eby' OR node_name='Laa' OR node_name='MIF' OR node_name='Amaur' OR node_name='Asn' )
GROUP BY DD.node_name
ORDER BY `id` DESC
Grouping is used commonly when You are using some aggregate function (sum, max, min, count, etc). If You don't use such function in Your query then why do You want to group the results?
Anyway, this should do the trick:
SELECT *
FROM mfw_navnode
WHERE id IN (SELECT id
FROM mfw_navnode
WHERE node_name IN ('Eby', 'Laa', 'MIF', 'Amaur', 'Asn')
GROUP BY node_name)
ORDER BY id
The following SQL may yield you the required output:
SELECT node_name, MAX(id)
FROM mfw_navnode
GROUP BY node_name
ORDER BY node_name
I see two problems with your SQL.
1) placing the order by in the inline select does nothing (and is probably causing an error)
2) you are grouping on node_name but you are not aggregating anything
SELECT COUNT(id) as row_count, node_name FROM( SELECT * FROM mfw_navnode ) AS DD
WHERE (node_name='Eby' OR node_name='Laa' OR node_name='MIF' OR node_name='Amaur' OR node_name='Asn' )
GROUP BY DD.node_name
order by node_name desc
further I am not sure why you need the inline select as the where could simply be on the original select ( perhaps you have something more complex going on that you didn't show )
SELECT COUNT(id) as row_count, node_name
from mfw_navnode
WHERE node_name='Eby' OR node_name='Laa' OR node_name='MIF' OR node_name='Amaur' OR node_name='Asn'
GROUP BY node_name
order by node_name desc