How do I echo out every column's data of a row from MYSQL results?
I do not know what the rows are as the query is dynamically created.
Here's what I have:
$query = $_POST['query'];
// Create connection
$con=mysqli_connect($db_host, $db_user, $db_pass, $db_name);
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$results = mysqli_query($con, $query);
while ($row = mysqli_fetch_array($results)) {
}
$row is just an array. Like any other array you can do fun things like iterate over it:
while ($row = mysqli_fetch_array($results)) {
foreach ($row as $key => $value) {
echo 'Key: ' . $key . ', Value: ' . $value;
}
echo "<br><br>\n"
}
Related
I am new to php. I have the following code that auto fetches all the rows and columns from the db. I want to make the script to fetch a particular row using its ID column. for example: www.site.com/view.php?id=22
I am trying to get it work with the $_GET['link']; variable like this:
if (isset($_GET['id'])) {
$result = mysqli_query($connection,"SELECT * FROM $_GET['link']");
} else {
$result = mysqli_query($connection,"SELECT * FROM reservations");
}
But I am unable to get it work.
The complete code is as below:
<?php
$host = "localhost";
$user = "user";
$pass = "Pass1";
$db_name = "test";
//create connection
$connection = mysqli_connect($host, $user, $pass, $db_name);
//test if connection failed
if(mysqli_connect_errno()){
die("connection failed: "
. mysqli_connect_error()
. " (" . mysqli_connect_errno()
. ")");
}
//get results from database
$result = mysqli_query($connection,"SELECT * FROM reservations");
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table" border="1">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
array_push($all_property, $property->name); //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
?>
Any help would be appreciated..
You can do this
Add
$query = 'SELECT * FROM reservations';
if (!empty($_GET['id']) and ($id = (int)$_GET['id']))
$query .= " WHERE id = {$id} LIMIT 1";
and change this
mysqli_query($connection,"SELECT * FROM reservations");
to this
$result = mysqli_query($connection, $query);
In the above code I added a bit of security so that if $_GET['id'] is not a valid integer it will revert to query where it fetches all the data. I added that because you should never put $_GET directly into your query.
Here is a your code I have modified it to your requirements
<?php
$host = "localhost";
$user = "user";
$pass = "Pass1";
$db_name = "test";
//create connection
$connection = mysqli_connect($host, $user, $pass, $db_name);
//test if connection failed
if(mysqli_connect_errno()){
die("connection failed: "
. mysqli_connect_error()
. " (" . mysqli_connect_errno()
. ")");
}
$query = 'SELECT * FROM reservations';
if (!empty($_GET['id']) and ($id = (int)$_GET['id']))
$query .= " WHERE id = {$id} LIMIT 1";
//get results from database
$result = mysqli_query($connection, $query);
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table" border="1">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
array_push($all_property, $property->name); //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
if(isset($_GET['id'])) {
$id = $_GET['id'];
} else {
$id=NULL;
}
$sql = "SELECT * FROM reservations WHERE id = '".$id."'";
$result = mysqli_query($connection,$sql);
$row = mysqli_fetch_assoc($result);
if(mysqli_num_rows($result) == 1) {
dd($row);
} else {
echo "no records found with this id";
}
Hope this script meets your answer
The below code works perfectly and gives me the "id" "firstname" and "lastname". What I want is to use a loop to echo all the field values in the result row without having to quote each column name like
$row["id"]
below is the working code
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, firstname, lastname FROM MyGuests";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<br> id: ". $row["id"]. " - Name: ". $row["firstname"]. " " .
$row["lastname"] . "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
any thoughts please
This should work..
while($row = $result->fetch_array()) {
$i=0;
while($i<count($row)){
echo $row[$i];
$i++;
}
}
just use a foreach loop inside while like this
foreach($row as $key=>$value){
echo "<br> $key: ". $value. "<br>";
}
If I understand what you want to do is automate the output of the name of each column with its value (independent of the number of columns you get).
So do it like this :
if ($result->num_rows > 0) {
foreach($result->fetch_assoc() as $row) { // browse each records
foreach($row as $col => $value) { // browse each columns on a record
echo "<br>$col: $value<br>";
}
}
}
else {
echo "no result";
}
I am trying to get my PHP script to print all rows i have in my database in a neat order. Currently Im not getting anything. My table has 4 columns, Name, Address, Long and Lat, and 2 rows with data. The table is called Locations. I am using the following code but im not getting to to work:
<?php
$con=mysqli_connect("localhost","user","pass","db");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT * FROM `Locations` ";
if ($result = mysqli_query($con, $sql))
{
$resultArray = array();
$tempArray = array();
while($row = $result->fetch_object())
{
$tempArray = $row;
array_push($resultArray, $tempArray);
}
echo json_encode($resultArray);
}
// Close connections
mysqli_close($con);
?>
Here is a simple example using pdo instead of mysqli
$dbHOST = 'localhost';
$dbNAME = 'nilssoderstrom_';
$dbUSER = 'nilssoderstrom_';
$dbPASS = 'Durandal82!';
$pdo = new PDO('mysql:host=' . $dbHOST . ';dbname=' . $dbNAME, $dbUSER, $dbPASS); // create connection
$stmt = $pdo->prepare("SELECT Name, Address, Long, Lat FROM Locations");
//you should never use *, just call each field name you are going to use
$stmt->execute(); // run the statement
$arr = $stmt->fetchAll(PDO::FETCH_ASSOC); // fetch the rows and put into associative array
print_r($arr); // print all array items, unformatted
and you can echo out the data and format it yourself using a for loop like so
for($i=0; $i<sizeof($arr); $i++) { // this will loop through each row in the database. i prefer this method over while loops as testing has shown this is much faster for large scale tables
echo 'Name: ' . $arr[$i]['Name'] . '<br />'; // $arr is the array name, $i is the number of the array item, or iterator, ['Name'] is the field name
echo 'Address: ' . $arr[$i]['Address'] . '<br>';
echo 'Long: ' . $arr[$i]['Long'] . '<br>';
echo 'Lat: ' . $arr[$i]['Lat'] . '<br>';
}
If the names are correct, this would echo out your row ID and row CITY. Just change the names to your field names. If you want further assistance, feel free to ask.
However, if you want to stick with mysqli, give the following code a wirl.
$dbHOST = 'localhost';
$dbNAME = 'nilssoderstrom_';
$dbUSER = 'nilssoderstrom_';
$dbPASS = 'Durandal82!';
$mysqli = mysqli_connect($dbHOST, $dbUSER, $dbPASS, $dbNAME);
$query = "SELECT Name, Address, Long, Lat FROM Locations";
$result = mysqli_query($mysqli, $query);
if($result) {
while($row = mysqli_fetch_assoc($result)) {
echo 'Name: ' . $row['Name'] . '<br />';
echo 'Address: ' . $row['Address'] . '<br>';
echo 'Long: ' . $row['Long'] . '<br>';
echo 'Lat: ' . $row['Lat'] . '<br>';
}
}
change fieldname to the field you want to display
EDIT: Paste the following code. It will echo out the number of rows. This will tell you if the query statement is correct.
$dbHOST = 'localhost';
$dbNAME = 'nilssoderstrom_';
$dbUSER = 'nilssoderstrom_';
$dbPASS = 'Durandal82!';
$pdo = new PDO('mysql:host=' . $dbHOST . ';dbname=' . $dbNAME, $dbUSER, $dbPASS);
$stmt = $pdo->query("SELECT Name, Address, Long, Lat FROM Locations");
echo $stmt->rowCount();
Fetch query result as associative array and use for each to print all results
<?php
$con=mysqli_connect("localhost","user","pass","db");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT * FROM `Locations` ";
if ($result = mysqli_query($con, $sql))
{
while($rows = mysqli_fetch_assoc($result)) {
foreach($rows as $key => $val)
{
echo $val;
}
}
}
mysqli_close($con);
?>
I want to retrieve each row from one column in one table and put all of them in a element.
I'm pretty much flailing in the dark right now, what am I doing wrong/missing?
$db_connect = mysql_connect("$host", "$db_username", "$db_password");
$db_select = mysql_select_db("$db_name");
mysql_set_charset('utf8', $db_connect);
$db_query_project="SELECT * FROM $tbl_name";
print('<form name="report" method="post" action="">');
print('<label for="project">Projekt </label>');
print('<select name="project_select">');
print('<option>Test</option>');
foreach ($db_query_project as $key => $value){
print('<option>'.$key['project_name'].'</option>');
}
print('</select>');
print('</form>');
Is there a better way to go about doing this?
You need to connect to the database and perform the query in order to retrieve the data and fetch it. To do so, you can use either mysqli or PDO. Here's an example on how to fetch data from a table $tbl_name with a column project_name using mysqli.
$mysqli = new mysqli("localhost", "user", "password", "database");
if ($mysqli->connect_errno) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ")";
exit();
}
$query = "SELECT * FROM `$tbl_name`";
if ($result = $mysqli->query($query)) {
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
printf ("%s \n", $row["project_name"]);
}
/* free result set */
$result->free();
}
/* close connection */
$mysqli->close();
i prefer this one:
function getFieldSelect($name, $selected, $values, $attributes) {
$r = "<select name=\"$name\" $attributes>";
foreach ($values as $k => $v) {
if ($k == $selected) {
$sel = "selected";
} else {
$sel = "";
}
$r .= "<option value=\"$k\" $sel>$v</option>\n";
}
$r .= "</select>";
return $r;
}
i got the values from DB and give it to my function in array format. I think this is the most flexible way to print a select field. You can use a database to get the values or any array.
<?php
$db_query_project= mysql_query("SELECT * FROM $tbl_name");
echo '<form name="report" method="post" action="">';
echo '<label for="project">Projekt </label>';
echo '<select name="project_select">';
echo '<option>Test</option>';
while( $row = mysql_fetch_assoc( $db_query_project ) )
{
echo '<option>'.$row['project_name'].'</option>';
}
echo '</select>';
echo '</form>';
This is the structure in the database:
items |itemLink
----------------------
Kill Bill|Kill Bill link
Preman |Preman link
This is the code:
$db = new PDO("mysql:host=$hostname;dbname=$database", $username, $password);
$items = 'SELECT items FROM menus';
$itemLink = 'SELECT itemLink FROM menus';
$itemQuery = $db->query($items);
$linkQuery = $db->query($itemLink);
$fetchItem = $itemQuery->fetchAll(PDO::FETCH_ASSOC);
$fetchLink = $linkQuery->fetchAll(PDO::FETCH_ASSOC);
$merged = array_merge($fetchItem,$fetchLink);
foreach($merged as $entry) {
foreach( $entry as $key => $value ) {
}
}
From the above code, how do I output only the items' datas?
Using the example above you could then do something like this to answer you question
$result = mysql_query('Select * from names');
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo $row["FirstName"] . " " . $row["LastName"] . "<br>";
}
mysql_close($conn);
?>
I would use something like this, not two arrays for something that could be one query. I have shown three methods, using var_dump or print_r will show how each works.
$conn = mysql_connect($hostname, $username, $password);
if (!$conn) {
die('Could not connect to MySQL: ' . mysqli_connect_error());
}
$db_selected = mysql_select_db('sample', $conn);
if (!$db_selected) {
die("Can\t use db : ' . mysql_error()");
}
$result = mysql_query('Select * from names');
while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
print_r($row);
}
$result = mysql_query('Select * from names');
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
print_r($row);
}
$result = mysql_query('Select * from names ');
while ($row = mysql_fetch_array($result, MYSQL_BOTH)) {
print_r($row);
}
mysql_close($conn);