PHP SQL query to print results in webpage - php

Question

I am trying to get my PHP script to print all rows i have in my database in a neat order. Currently Im not getting anything. My table has 4 columns, Name, Address, Long and Lat, and 2 rows with data. The table is called Locations. I am using the following code but im not getting to to work:
<?php
$con=mysqli_connect("localhost","user","pass","db");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT * FROM `Locations` ";
if ($result = mysqli_query($con, $sql))
{
$resultArray = array();
$tempArray = array();
while($row = $result->fetch_object())
{
$tempArray = $row;
array_push($resultArray, $tempArray);
}
echo json_encode($resultArray);
}
// Close connections
mysqli_close($con);
?>

Answer 1

Here is a simple example using pdo instead of mysqli
$dbHOST = 'localhost';
$dbNAME = 'nilssoderstrom_';
$dbUSER = 'nilssoderstrom_';
$dbPASS = 'Durandal82!';
$pdo = new PDO('mysql:host=' . $dbHOST . ';dbname=' . $dbNAME, $dbUSER, $dbPASS); // create connection
$stmt = $pdo->prepare("SELECT Name, Address, Long, Lat FROM Locations");
//you should never use *, just call each field name you are going to use
$stmt->execute(); // run the statement
$arr = $stmt->fetchAll(PDO::FETCH_ASSOC); // fetch the rows and put into associative array
print_r($arr); // print all array items, unformatted
and you can echo out the data and format it yourself using a for loop like so
for($i=0; $i<sizeof($arr); $i++) { // this will loop through each row in the database. i prefer this method over while loops as testing has shown this is much faster for large scale tables
echo 'Name: ' . $arr[$i]['Name'] . '<br />'; // $arr is the array name, $i is the number of the array item, or iterator, ['Name'] is the field name
echo 'Address: ' . $arr[$i]['Address'] . '<br>';
echo 'Long: ' . $arr[$i]['Long'] . '<br>';
echo 'Lat: ' . $arr[$i]['Lat'] . '<br>';
}
If the names are correct, this would echo out your row ID and row CITY. Just change the names to your field names. If you want further assistance, feel free to ask.
However, if you want to stick with mysqli, give the following code a wirl.
$dbHOST = 'localhost';
$dbNAME = 'nilssoderstrom_';
$dbUSER = 'nilssoderstrom_';
$dbPASS = 'Durandal82!';
$mysqli = mysqli_connect($dbHOST, $dbUSER, $dbPASS, $dbNAME);
$query = "SELECT Name, Address, Long, Lat FROM Locations";
$result = mysqli_query($mysqli, $query);
if($result) {
while($row = mysqli_fetch_assoc($result)) {
echo 'Name: ' . $row['Name'] . '<br />';
echo 'Address: ' . $row['Address'] . '<br>';
echo 'Long: ' . $row['Long'] . '<br>';
echo 'Lat: ' . $row['Lat'] . '<br>';
}
}
change fieldname to the field you want to display
EDIT: Paste the following code. It will echo out the number of rows. This will tell you if the query statement is correct.
$dbHOST = 'localhost';
$dbNAME = 'nilssoderstrom_';
$dbUSER = 'nilssoderstrom_';
$dbPASS = 'Durandal82!';
$pdo = new PDO('mysql:host=' . $dbHOST . ';dbname=' . $dbNAME, $dbUSER, $dbPASS);
$stmt = $pdo->query("SELECT Name, Address, Long, Lat FROM Locations");
echo $stmt->rowCount();

Answer 2

Fetch query result as associative array and use for each to print all results
<?php
$con=mysqli_connect("localhost","user","pass","db");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT * FROM `Locations` ";
if ($result = mysqli_query($con, $sql))
{
while($rows = mysqli_fetch_assoc($result)) {
foreach($rows as $key => $val)
{
echo $val;
}
}
}
mysqli_close($con);
?>