data from sql database not showing properly in php - php

Question

hi i got a sql database table which has some images and some description. i need to be able to display everything but is not working properly. i got 2 different pages. where all the database staff is and the index page. here is the function from the first page
function get_image() {
global $db;
$query = 'SELECT * FROM table ';
try {
$statement = $db->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
$statement->closeCursor();
return $result;
} catch (PDOException $e) {
$error_message = $e->getMessage();
display_db_error($error_message);
}
Here is index.php:
//on the index page i set up an array to display all the images but all i get is a 404 not found. this is the index page
<?php
require_once('model/database.php');
require_once('model/image_db.php');
// Set the array to display the images
$image_ids = array(1,2,3,4,5);
$images = array();
foreach ($image_ids as $image_id) {
$image = get_image();
$images[] = $image; // add images to array
}
// Display the home page
include('home_view.php');
?>
and on the home page i display everything but is not showing.. any ideas
<table>
<?php foreach ($images as $image) :
// Get image data
$imaget_price = $image['Price'];
$description = $image['description'];
// Get first paragraph of description
$description = add_tags($description);
$i = strpos($description, "</p>");
$description = substr($description, 3, $i-3);
?>
<tr>
<td id="image_column">
<img src="images/<?php echo $image['ID']; ?>.jpg"
alt=" ">
</td>
</tr>
<?php endforeach; ?>
</table>
?>

Answer 1

Edit:
You are binding values to a query that takes no values.
$statement->bindValue(1, $image_id);
You probably want something like this:
$query = 'SELECT * FROM table WHERE image_id = ?';