In Laravel, we can get route name from current URL via this:
Route::currentRouteName()
But, how can we get the route name from a specific given URL?
Thank you.
A very easy way to do it Laravel 5.2
app('router')->getRoutes()->match(app('request')->create('/qqq/posts/68/u1'))->getName()
It outputs my Route name like this slug.posts.show
Update: For method like POST, PUT or DELETE you can do like this
app('router')->getRoutes()->match(app('request')->create('/qqq/posts/68/u1', 'POST'))->getName()//reference https://github.com/symfony/http-foundation/blob/master/Request.php#L309
Also when you run app('router')->getRoutes()->match(app('request')->create('/qqq/posts/68/u1', 'POST')) this will return Illuminate\Routing\Route instance where you can call multiple useful public methods like getAction, getValidators etc. Check the source https://github.com/illuminate/routing/blob/master/Route.php for more details.
None of the solutions above worked for me.
This is the correct way to match a route with the URI:
$url = 'url-to-match/some-parameter';
$route = collect(\Route::getRoutes())->first(function($route) use($url){
return $route->matches(request()->create($url));
});
The other solutions perform bindings to the container and can screw up your routes...
I don't think this can be done with out-of-the-box Laravel. Also remember that not all routes in Laravel are named, so you probably want to retrieve the route object, not the route name.
One possible solution would be to extend the default \Iluminate\Routing\Router class and add a public method to your custom class that uses the protected Router::findRoute(Request $request) method.
A simplified example:
class MyRouter extends \Illuminate\Routing\Router {
public function resolveRouteFromUrl($url) {
return $this->findRoute(\Illuminate\Http\Request::create($url));
}
}
This should return the route that matches the URL you specified, but I haven't actually tested this.
Note that if you want this new custom router to replace the built-in one, you will likely have to also create a new ServiceProvider to register your new class into the IoC container instead of the default one.
You could adapt the ServiceProvider in the code below to your needs:
https://github.com/jasonlewis/enhanced-router
Otherwise if you just want to manually instantiate your custom router in your code as needed, you'd have to do something like:
$myRouter = new MyRouter(new \Illuminate\Events\Dispatcher());
$route = $myRouter->resolveRouteFromUrl('/your/url/here');
It can be done without extending the default \Iluminate\Routing\Router class.
Route::dispatchToRoute(Request::create('/your/url/here'));
$route = Route::currentRouteName();
If you call Route::currentRouteName() after dispatchToRoute call, it will return current route name of dispatched request.
Related
I have difficults to create a supplementing Resource in a controller laravel and insert it in the web.php for the routing.
I would to implement a search functions, in an Articles controller .Beyond the authomatic generated function like (index, show...) i have created another one:
public function search($title){
$articles = Article::findOrFail($title);
return $articles;
}
And I have added it in the web.php for the routing:
Route::resource('articles/{title}', 'ArticleController#search');
When I try to test this search, it doesn't work. All the implicit controller go well, I have problem only with this selfmade function.
How can I solve this issue?
thanks
You need to add another route before resource one to make it work:
Route::get('articles/{title}', 'ArticleController#search');
You also want to change the query if you want to find an article by it's slug, for example:
$article = User::where('slug', $title)->first();
I'm using Lumen for my project, currently the way I version my API is through prefixing and using a specific corresponding controller like so:
$api->get('/v1/users', 'App\Api\V1\Controllers\UserController#show');
$api->get('/v2/users', 'App\Api\V2\Controllers\UserController#show');
I want to change this, such that I take an argument from the user and use a controller based on that parameter.
This Route:
$api->get('/v{api_version}/users'...
Should use this controller:
'App\Api\V{api_version}\Controllers\UserController#show'
I'm currently using Dingo along side Lumen, is there anyway to do this with either Lumen or Dingo?
Yes, you can. But it's a little bit more complicated than in your example, but it's still a one-liner. Just define a closure and invoke your controller within it instead of passing the FQCN controller name directly.
routes/web.php
$app->get("api/v{version}/users", function ($version) use ($app) {
return $app->make("App\Api\V{$version}\Controllers\UserController")->show();
});
If someone else is interested (as I was) how to achieve the same in an laravel installation: Just use the method Controller::callAction() after the controller was resolved
Route::get("api/v{version}/test", function ($version) {
return app()->make('App\Api\V{$version}\Controllers\UserController')->callAction("show", [/* arguments */]);
});
I am new to Laravel 5 and I am trying to use the new Form Request to validate all forms in my application.
Now I am stuck at a point where I need to DELETE a resource and I created a DeleteResourceRequest for just to use the authorize method.
The problem is that I need to find what id is being requested in the route parameter but I cannot see how to get that in to the authorize method.
I can use the id in the controller method like so:
public function destroy($id, DeletePivotRequest $request)
{
Resource::findOrFail($id);
}
But how to get this to work in the authorize method of the Form Request?
That's very simple, just use the route() method. Assuming your route parameter is called id:
public function authorize(){
$id = $this->route('id');
}
You can accessing a Route parameter Value via Illuminate\Http\Request instance
public function destroy($id, DeletePivotRequest $request)
{
if ($request->route('id'))
{
//
}
Resource::findOrFail($id);
}
Depending on how you defined the parameter in your routes.
For my case below, it would be: 'user' not 'id'
$id = $this->route('user');
Laravel 5.2, from within a controller:
use Route;
...
Route::current()->getParameter('id');
I've found this useful if you want to use the same controller method for more than one route with more than one URL parameter, and perhaps all parameters aren't always present or may appear in a different order...
i.e. getParameter('id')will give you the correct answer, regardless of {id}'s position in the URL.
See Laravel Docs: Accessing the Current Route
After testing the other solutions, seems not to work for laravel 8, but this below works
Route::getCurrentRoute()->id
assuming your route is
Route::post('something/{id}', ...)
I came here looking for an answer and kind of found it in the comments, so wanted to clarify for others using a resource route trying to use this in a form request
as mentioned by lukas in his comment:
Given a resource controller Route::resource('post', ...) the parameter you can use will be named post
This was usefull to me but not quite complete. It appears that the parameter will be the singular version of the last part of the resource stub.
In my case, the route was defined as $router->resource('inventory/manufacturers', 'API\Inventory\ManufacturersController');
And the parameter available was manufacturer (the singular version of the last part of the stub inventory/manufacturers)
you will get parameter id if you call
request()->route('id')
OR
$this->route('id')
if you're using resource routing, you need to call with the resource name
// eg: resource
Route::resource('users', App\Http\Controllers\UserController::class);
$this->route('user')
in Terminal write
php artisan route:list
to see what is your param name
Then use
$this->route('sphere') to get param
In Laravel, we can get route name from current URL via this:
Route::currentRouteName()
But, how can we get the route name from a specific given URL?
Thank you.
A very easy way to do it Laravel 5.2
app('router')->getRoutes()->match(app('request')->create('/qqq/posts/68/u1'))->getName()
It outputs my Route name like this slug.posts.show
Update: For method like POST, PUT or DELETE you can do like this
app('router')->getRoutes()->match(app('request')->create('/qqq/posts/68/u1', 'POST'))->getName()//reference https://github.com/symfony/http-foundation/blob/master/Request.php#L309
Also when you run app('router')->getRoutes()->match(app('request')->create('/qqq/posts/68/u1', 'POST')) this will return Illuminate\Routing\Route instance where you can call multiple useful public methods like getAction, getValidators etc. Check the source https://github.com/illuminate/routing/blob/master/Route.php for more details.
None of the solutions above worked for me.
This is the correct way to match a route with the URI:
$url = 'url-to-match/some-parameter';
$route = collect(\Route::getRoutes())->first(function($route) use($url){
return $route->matches(request()->create($url));
});
The other solutions perform bindings to the container and can screw up your routes...
I don't think this can be done with out-of-the-box Laravel. Also remember that not all routes in Laravel are named, so you probably want to retrieve the route object, not the route name.
One possible solution would be to extend the default \Iluminate\Routing\Router class and add a public method to your custom class that uses the protected Router::findRoute(Request $request) method.
A simplified example:
class MyRouter extends \Illuminate\Routing\Router {
public function resolveRouteFromUrl($url) {
return $this->findRoute(\Illuminate\Http\Request::create($url));
}
}
This should return the route that matches the URL you specified, but I haven't actually tested this.
Note that if you want this new custom router to replace the built-in one, you will likely have to also create a new ServiceProvider to register your new class into the IoC container instead of the default one.
You could adapt the ServiceProvider in the code below to your needs:
https://github.com/jasonlewis/enhanced-router
Otherwise if you just want to manually instantiate your custom router in your code as needed, you'd have to do something like:
$myRouter = new MyRouter(new \Illuminate\Events\Dispatcher());
$route = $myRouter->resolveRouteFromUrl('/your/url/here');
It can be done without extending the default \Iluminate\Routing\Router class.
Route::dispatchToRoute(Request::create('/your/url/here'));
$route = Route::currentRouteName();
If you call Route::currentRouteName() after dispatchToRoute call, it will return current route name of dispatched request.
Laravel routing functionality allows you to name a resource and name a controller to go with it. I am new to Laravel and would like to know if anyone knows how to extend the resources method in the route class provided.
Basically say I have: (which works fine)
/invoices
But say I want:
/invoices/status/unpaid
How is this achievable?
To see the basics of what I am doing check:
http://laravel.com/docs/controllers#resource-controllers
Resource controllers tie you into a specific URLs, such as:
GET|POST /invoices
GET|PUT /invoices/{$id}
GET /invoices/create
and so on as documented.
Since, by convention, GET /invoices is used to list all invoices, you may want to add some filtering on that:
/invoices?status=unpaid - which you can then use in code
<?php
class InvoiceController extends BaseController {
public function index()
{
$status = Input::get('status');
// Continue with logic, pagination, etc
}
}
If you don't want to use filtering via a query string, in your case, you may be able to do something like:
// routes.php
Route::group(array('prefix' => 'invoice'), function()
{
Route::get('status/unpaid', 'InvoiceController#filter');
});
Route::resource('invoice', 'InvoiceController');
That might work as the order routes are created matter. The first route that matches will be the one used to fulfill the request.