I've just started learning php and I'm having trouble finding the problem when I get it to connect to the database and run an 'INSERT' query. I think the problem is in my connection.php file.
insert.php:
<?PHP
echo "into";
include("connection.php");
echo "connected";
$table = blog;
$sql = "INSERT INTO $table SET
Title = '$_POST[title]',
Description = '$_POST[description]',
Content = '$_POST[content]'";
$query = #mysql_query($sql);
echo "complete";
echo $_POST[title];
echo $_POST[description];
echo $_POST[content];
?>
connection.php:
<?php
echo "connection file reached";
$conn = mysql_connect(localhost, user, pass);
mysql_select_db(test, $conn);
echo "connected";
?>
Any advice on my code, or how I could solve this problem would be much appreciated.
EDIT: I'm thinking that it never gets to the connection.php file because it shows the "into" at the top of insert.php but not the "connection file reached" at the top of connection.php. Is that call correct to that file?
Thanks
Readup on php constants, variables and strings!
define('foo','bar'); // foo == 'bar';
$foo = 'bar'; // $foo == 'bar'
Please use mysqli_* as mysql_* is depreciated.
$conn = mysql_connect(localhost, user, pass);
probably should be
$conn = mysql_connect('localhost', 'user', 'pass');
you have written
#mysql_query($sql)
as well as a lot other problem it's structure is also wrong the problem might be from version of your language as recommendation of php you should not use mysql any more use mysqli or PDO
Related
I'm coding a web service for iOS in Php. I'm trying to retrieve data from server through php but the response is null.The server is MSSql Server 2014.
<?php
define ('DB_HOST', '****.net');
define ('DB_USER', '****');
define ('DB_PASS', '******');
define ('DB_NAME', '*******');
$dbc = mysql_connect(DB_HOST, DB_USER, DB_PASS);
mysql_select_db(DB_NAME, $dbc);
if (mysql_select_db){
echo "Done";
}else{
echo "Die";
}
$sql_select = "SELECT * from ClientChk";
$records = mysql_query($sql_select);
$count= 1;
while($result = mysql_fetch_array($records))
{
if ($result == nil){
echo "Nil!";
}
}
echo json_encode($result['Id']);
?>
This is a bad example of doing this.
1) You have to check if the connection was successful.
2) If use MSSQL, then you can't use mysql_ commands.
3) nill doesn't exist in php, should be 'null'
$SERVER = '127.0.0.1';
$DB = 'test';
$USER = 'username';
$PASSWORD = 'password';
$db = new PDO("sqlsrv:server=$SERVER;database=$DB;", $USER, $PASSWORD);
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
try {
$query = "SELECT * FROM ClientChk";
$result = $db->query($query)->fetchAll(PDO::FETCH_ASSOC);
} catch (PDOException $ex) {
$ex->getMessage();
echo $ex;
}
echo json_encode($result);
So, the problem is, that you try to connect to a MSSQL database, with a MySQL database connector.
To connect to a MSSQL database, you can use the following methods:
mssql_connect(): It uses a quite similar syntax to mysql, but it is removed as of php 7.0, so I advice against it's usage even if you using an earlier version of php.
PDO class: It's differs a lot from the older function style sql connectors, but it is the preferred way by many.
sqlsvr_connect(), obdc_connect(): If you prefer a function based connector instead of the PDO class, and you don't want to use the deprecated mssql_connect, I recommend choosing one of these.
I hope, I could be of any help.
GYZ i dont know why data is not inserting in my data base #Mysql
. infact im using mysqli_connect and mysql_connect both ,I'm still facing same prob ..this is my code:
<?php
$servername = 'localhost';
$username = 'root';
$password = '';
$db='school';
#mysqli_connect($servername, $username, $password);
#mysqli_select_db($db); //or die ('not Connect to db ');
if(isset($_GET['submit'])) {
$sid= $_GET['sid'];
$sname= $_GET['sname'];
$fname= $_GET['fname'];
$order= #mysqli_query("insert into school (sid,sname,fname) values ('$sid','$sname','$fname');");
if ($order) {
echo '<br>Input data is successful';
} else {
echo '<br>Input data is not valid';
}
} ?>
I revisited the question and posted the following, seeing that nobody posted one.
You didn't pass the db connection to mysqli_select_db() nor for mysqli_query() and need to assign a variable to the connection first.
Both of those require it in mysqli_ and you may have been accustomed to mysql_ in the past. MySQLi_ is different than MySQL_ when it comes to certain functions that needs a connection.
Sidenote: The # symbol is an error suppressor. Remove it during testing/development.
Another sidenote: Both your database and table bear the same name of school. Make sure that this is correct.
<?php
$servername = 'localhost';
$username = 'root';
$password = '';
$db='school';
$connect = mysqli_connect($servername, $username, $password, $db);
if($connect){
echo "Connected";
}
else {
echo "Error: " . mysqli_error($connect);
}
// This isn't needed. You can pass all 4 parameters in one shot.
// $database = mysqli_select_db($connect, $db); //or die ('not Connect to db ');
if(isset($_GET['submit'])) {
$sid= $_GET['sid'];
$sname= $_GET['sname'];
$fname= $_GET['fname'];
$order= mysqli_query($connect, "INSERT INTO school (sid,sname,fname) VALUES ('$sid','$sname','$fname');");
if ($order) {
echo '<br>Input data is successful.';
} else {
// Uncomment the one below once everything is ok.
// echo '<br>Input data is not valid.';
// Comment this below once there are no errors.
echo "There was an error: " . mysqli_error($connect);
}
}
References:
http://php.net/manual/en/function.mysqli-connect.php
http://php.net/manual/en/mysqli.select-db.php
http://php.net/manual/en/mysqli.query.php
Check for errors also via PHP and the query:
http://php.net/manual/en/mysqli.error.php
http://php.net/manual/en/function.error-reporting.php
And make sure you're running this off a webserver, or if local that PHP/MySQL are installed, running properly and using http://localhost as opposed to file:///.
Your code is also open to an SQL injection, use a prepared statement.
References:
https://en.wikipedia.org/wiki/SQL_injection
https://en.wikipedia.org/wiki/Prepared_statement
Footnotes:
You seem to want to use this in a table. <form> cannot be child of <table> if you are using those tags outside of the form which wasn't posted in your question; there are stray <td></td> tags.
Im trying to create a login for my website and i need to store emails, usernames, passwords, ect in a database i have created already using phpMyAdmin. I have gone through article after article and nothing seems to be working. i have my connect.php like this:
<?
$hostname = "localhost";
$username = "username";
$password = "password";
$databaseName = "_mySiteUserDataBase";
mysql_connect($hostname, $username, $password) or die("Cannot connect to server");
mysql_select_db($databaseName) or die("Cannot select database");
?>
And my main.php like this:
<?
include("connect.php");
$tableName = "myUsers";
$sql = "SELECT * FROM $tableName";
$result = mysql_query($sql);
?>
And i have created a simple form in my html like this:
<html>
<head></head>
<body>
<form>
<input type = "submit" action = "main.php" method = "post" value = "Login">
</form>
</body>
</html>
After submitting the form it says cannot connect to server. I am new to php and mysql and i dont understand what each parameter in the mysql_connect is, and i dont know what they do therefore im not sure what im supposed to enter in but everyone i keep reading about seems to be inputing random values? I could use a brief explanation on that, because i am stuck at connecting and cant even get past this point sadly enough. Also i have been reading that mysql_connect is deprecated and isnt valid anymore but i dont understand what im supposed to use as an alternative. I know its mysqli but thats it and im unclear of the syntax.
mysqli:
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
echo "start<br/>";
try {
$mysqli= new mysqli('localhost', 'myusername', 'mypassword', 'dbname');
if ($mysqli->connect_error) {
die('Connect Error (' . $mysqli->connect_errno . ') '
. $mysqli->connect_error);
}
echo "I am connected and feel happy.<br/>";
$mysqli->close();
} catch (mysqli_sql_exception $e) {
throw $e;
}
?>
If you need to know how to create users, what the heck the hostname is, how to grant access (often useful after the connect :>), just ask.
Try this code in 'connect.php'
<?php
error_reporting(0);
$con=mysql_connect('localhost','root','');// here 'root' is your username and "" is password
if(!$con)
{
echo 'not connect';die;
}
mysql_select_db('dbname',$con);// here 'dbname' is your database name
?>
And also try following code to include sql connection in your other php file(main.php)
<?php
include 'connect.php';
$sql = "SELECT * FROM myUsers";
$result=mysql_query($sql);
?>
Let me convert it to mysqli for you and maybe that will fix the problem. Also, make sure the username, password, and database name are correct.
Try this code. At very least, it will provide a better error message for debugging.
<?
$hostname = "localhost";
$username = "username";
$password = "password";
$databaseName = "_mySiteUserDataBase";
$con = mysqli_connect($hostname, $username, $password, $databaseName) or die(mysqli_error($con));
?>
Main.php
<?
include("connect.php");
$tableName = "myUsers";
$sql = "SELECT * FROM $tableName";
$result = mysqli_query($con,$sql);
?>
I'm in a bit of a pickle with freshening up my PHP a bit, it's been about 3 years since I last coded in PHP. Any insights are welcomed! I'll give you as much information as I possibly can to resolve this error so here goes!
Files
config.php
database.php
news.php
BLnews.php
index.php
Includes
config.php -> news.php
database.php -> news.php
news.php -> BLnews.php
BLnews.php -> index.php
Now the problem with my current code is that the database connection is being made but my database refuses to be selected. The query I have should work but due to my database not getting selected it's kind of annoying to get any data exchange going!
config.php
<?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$dbname = "test";
?>
database.php
<?php
class Database {
//-------------------------------------------
// Connects to the database
//-------------------------------------------
function connect() {
if (isset($dbhost) && isset($dbuser) && isset($dbpass) && isset($dbname)) {
$con = mysql_connect($dbhost, $dbuser, $dbpass) or die("Could not connect: " . mysql_error());
$selected_db = mysql_select_db($dbname, $con) or die("Could not select test DB");
}
}// end function connect
} // end class Database
?>
News.php
<?php
// include the config file and database class
include 'config.php';
include 'database.php';
...
?>
BLnews.php
<?php
// include the news class
include 'news.php';
// create an instance of the Database class and call it $db
$db = new Database;
$db -> connect();
class BLnews {
function getNews() {
$sql = "SELECT * FROM news";
if (isset($sql)) {
$result = mysql_query($sql) or die("Could not execute query. Reason: " .mysql_error());
}
return $result;
}
?>
index.php
<?php
...
include 'includes/BLnews.php';
$blNews = new BLnews();
$news = $blNews->getNews();
?>
...
<?php
while($row = mysql_fetch_array($news))
{
echo '<div class="post">';
echo '<h2> ' . $row["title"] .'</h2>';
echo '<p class="post-info">Posted by | <span class="date"> Posted on ' . $row["date"] . '</span></p>';
echo $row["content"];
echo '</div>';
}
?>
Well this is pretty much everything that should get the information going however due to the mysql_error in $result = mysql_query($sql) or die("Could not execute query. Reason: " .mysql_error()); I can see the error and it says:
Could not execute query. Reason: No database selected
I honestly have no idea why it would not work and I've been fiddling with it for quite some time now. Help is most welcomed and I thank you in advance!
Greets
Lemon
The values you use in your functions aren't set with a value. You likely need to convert the variables used to $this->dbName etc or otherwise assign values to the variables used.
Edit for users comment about variables defined in config.php:
You really should attempt to get the data appropriate for each class inside that class. Ultimately your variables are available to your entire app, there's no telling at this point if the variable was changed by a file including config.php but before database.php is called.
I would use a debugging tool and verify the values of the variables or just var_dump() them before the call.
Your Database class methods connect and selectDb try to read from variables that are not set ($dbhost, $dbname, $con, etc). You probably want to pass those values to a constructor and set them as class properties. Better yet, look into PDO (or an ORM) and forget creating your own db class.
I'm new to PHP and have installed on Linux to boot (also a newbie).
Anyway, PHP is working...
<?
$myVar = "test";
echo($myVar);
?>
... works just fine.
But...
<?
$dbhost = "localhost";
$dbuser = "myuser";
$dbpass = "mypass";
$dbname = "mydb";
echo($dbhost . "-" . $dbuser . "-" . $dbpass . "-" . $dbname);
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die("Unable to connect to MySQL");
print $conn;
mysql_close($conn);
phpInfo();
?>
... does nothing. Nor errors, nothing. Its as if the code isn't even there.
Any help?
Try to do the following:
First make sure display_errors is turned on in your php configuration file. Also set the level of error_reporting to show all errors, including strict (error_reporting = E_ALL|E_STRICT). After you make changes, restart your webserver.
Run phpinfo(), and check that the mysql extension is installed and working. If it isn't make sure that you uncommented it in the php configuration file (again, remember to restart apache after each change to the configuration file).
At this point MySQL should be loaded and working, and you should be able to tell from the error (if it persists) what's the problem.
Try also dumping the contents of the connection result ($conn) to see what it contains.
In general, I'd recommend using long php tags (<?php and not <?) since it is more portable (short tags are off by default in PHP 5 installations).
Try adding this to the top of your code:
error_reporting(E_ALL);
If it does nothing, doesn't that mean that it connected fine? What output do you expect out of that statement?
You could try
error_reporting(E_ALL);
$conn = mysql_connect("localhost", "myusername", "mypassword");
if(!$conn) {
echo 'Unable to connect';
} else {
echo 'Connected to database';
}
var_dump($conn);
edit: Addressing the comment saying that you have a mysql query setup, if you are not seeing "success" it means something is wrong with your query. Add to the above
$sth = mysql_query("SELECT * FROM tablename");
if(!$sth) {
echo 'unable to query: ' . mysql_error();
} else {
echo 'success';
}
Is there more code than you're showing us? The block you have just sets up a connection. You won't see anything at all if it succeeds, you have to use $conn to do something.
To confirm, try changing your password to a deliberately wrong value, and then see if you get an error. If you do, the code works just fine.
Connecting to a database with
$conn = mysql_connect("localhost", "myusername", "mypassword") or die("Unable to connect");
will have no (visible( results if the connection was made succesfully. However, once you run this statement, you can use the other mysql functions to make make queries to the database.
Connecting to a database tells your program "hey, I want to talk to this database".
This code is supposed to create a db connection, nothing else. What do you expect to see?
Try this
<?php
$conn = mysql_connect("localhost", "myusername", "mypassword")
or die("Unable to connect");
print("code sample");
print $conn;
?>
It should print you something like "resource #1"...
And then you may use that connection to communicate with db server