Get number after number in PHP - php

I doubt if it is possible but I'm looking for the following:
E.g. $number's value is 1, can I get the next number, in this case 2, to be the value of another variable, e.g. $newnumber?
I prefer to do this in SQLite, so the numbers are stored in a database.

Try: $newnumber = ((int) ($number)) + 1, if this is for a primary key though just set the column to auto increment

$newnumber=$number+1;
I think it can't get more simpler than that.

Without knowing the larger scope of what you're trying to accomplish, my suggestion would be to use the increment operator in PHP.
Original answer:
Something like:
$number = 1;
$newNumber = $number++;
Correct answer (above gives wrong result):
$number = 1;
$number++;
$newNumber = $number;
From there you can do whatever you want with the second variable.

Related

Number does not change to next number

I have a string number as below. When i add 1 to it, it changes to a scientific representation instead of a real number and also doesnot increment to the next number. Any reason why its not incrementing?
I want 4600004722057511 to become 4600004722057512
Thanks
Number is 4600004722057501
After adding 1 to it it becomes 4.6000047220575E+15
$val = $list[0]->getNextNumber();
$list[0]->setNextNumber($val+1);
use bcmath for high numbers
$val = $list[0]->getNextNumber();
$val = bcadd( $val, 1 ); // here you add 1 to a very high number
$list[0]->setNextNumber($val);
You can try with add “(int)” your code
$val = (int)$list[0]->getNextNumber();
$list[0]->setNextNumber($val+1);
Try this:
$val = (float)$list[0]->getNextNumber();
$list[0]->setNextNumber($val+1);
since PHP treat number as number, it won't be a problem, but if you want to display its value somewhere, cast it to string
$val = $list[0]->getNextNumber()+1;
$val = (string)$val
Try This
$val =$list[0]->getNextNumber();
$val=++$val;
$list[0]->setNextNumber($val);
If it not works, show your full code (might be a problem in function code).

Use numbers starting with 0 in a variable in php

Hi i need to save a 010 number in $number and if i do like this php will remove the starting 0
$number = 010
And echo of this will return 10 how can i make it not to remove the initial 0
BR
Martin
Use it as a String:
$number = '010';
Use str_pad() function.
echo str_pad('10',3,'0',STR_PAD_LEFT)
http://php.net/manual/en/function.str-pad.php
Do remember that numbers starting with 0 can also be treated as octal number notation by the PHP compiler, hence if you want to work with decimal numbers, simply use:
$num = '010';
This way the number is saved, can be stored in the database and manipulated like any other number. (Thx to the fact that PHP is very loosely typed language.)
Another method to use would be:
Save number as $num = 10;
Later while printing the value you can use sprintf, like:
sprintf("%03d", $i);
This will print your number in 3 digit format, hence 0 will be added automatically.
Another method:
<?php
$num = 10;
$zerofill = 3;
echo str_pad($num, $zerofill, "0", STR_PAD_LEFT);
/* Returns the wanted result of '010' */
?>
You can have a look at the various options available to you and make a decision. Each of the method given above will give you a correct output.

Php set value as a number

How do I output a value as a number in php? I suspect I have a php value but it is outputting as text and not as a number.
Thanks
Here is the code - Updated for David from question below
<?php
if (preg_match('/\-(\d+)\.asp$/', $pagename1, $a))
{
$pageNumber = $a[1];}
else
{ // failed to match number from URL}
}
?>
If I call it in: This code it does not seem to work.
$maxRows_rs_datareviews = 10;
$pageNum_rs_datareviews = $pagename1; <<<<<------ This is where I want to use it.
if (isset($_GET['pageNum_rs_datareviews'])) {
$pageNum_rs_datareviews = $_GET['pageNum_rs_datareviews'];
}
If I make page name a static number like 3 the code works, if I use $pagename1 it does not, this gives me the idea $pagename1 is not seen as a number?
My stupidity!!!! - I used $pagename1 instead of pageNumber
What kind of number? An integer, decimal, float, something else?
Probably the easiest method is to use printf(), eg
printf('The number %d is an integer', $number);
printf('The number %0.2f has two decimal places', $number);
This might be blindingly obvious but it looks like you want to use
$pageNum_rs_datareviews = $pageNumber;
and not
$pageNum_rs_datareviews = $pagename1;
echo (int)$number; // integer 123
echo (float)$number; // float 123.45
would be the easiest
I prefer to use number_format:
echo number_format(56.30124355436,2).'%'; // 56.30%
echo number_format(56.30124355436,0).'%'; // 56%
$num = 5;
echo $num;
Any output is text, since it's output. It doesn't matter what the type of what you're outputting is, since the human eye will see it as text. It's how you actually treat is in the code is what matters.
Converting (casting) a string to a number is different. You can do stuff like:
$num = (int) $string;
$num = intval($string);
Googling php string to number should give you a beautiful array of choices.
Edit: To scrape a number from something, you can use preg_match('/\d+/', $string, $number). $number will now contain all numbers in $string.

Random generation number doubt

Is there is any way to avoid duplication in random number generation .
I want to create a random number for a special purpose. But it's should be a unique value. I don't know how to avoid duplicate random number
ie, First i got the random number like 1892990070. i have created a folder named that random number(1892990070). My purpose is I will never get that number in future. I it so i have duplicate random number in my folder.
A random series of number can always have repeated numbers. You have to keep a record of which numbers are already used so you can regenerate the number if it's already used. Like this:
$used = array(); //Initialize the record array. This should only be done once.
//Do like this to draw a number:
do {
$random = rand(0, 2000);
}while(in_array($random, $used));
$used[] = $random; //Save $random into to $used array
My example above will of course only work across a single page load. If it should be static across page loads you'll have to use either sessions (for a single user) or some sort of database (if it should be unique to all users), but the logic is the same.
You can write a wrapper for mt_rand which remembers all the random number generated before.
function my_rand() {
static $seen = array();
do{
$rand = mt_rand();
}while(isset($seen[$rand]));
$seen[$rand] = 1;
return $rand;
}
The ideas to remember previously generated numbers and create new ones is a useful general solution when duplicates are a problem.
But are you sure an eventual duplicate is really a problem? Consider rolling dice. Sometimes they repeat the same value, even in two sequential throws. No one considers that a problem.
If you have a controlled need for a choosing random number—say like shuffling a deck of cards—there are several approaches. (I see there are several recently posted answer to that.)
Another approach is to use the numbers 0, 1, 2, ..., n and modify them in some way, like a Gray Code encoding or exclusive ORing by a constant bit pattern.
For what purpose are you generating the random number? If you are doing something that generates random "picks" of a finite set, like shuffling a deck of cards using a random-number function, then it's easiest to put the set into an array:
$set = array('one', 'two', 'three');
$random_set = array();
while (count($set)) {
# generate a random index into $set
$picked_idx = random(0, count($set) - 1);
# copy the value out
$random_set []= $set[$picked_idx];
# remove the value from the original set
array_splice($set, $picked_idx, 1);
}
If you are generating unique keys for things, you may need to hash them:
# hold onto the random values we've picked
$already_picked = array();
do {
$new_pick = rand();
# loop until we know we don't have a value that's been picked before
} while (array_key_exists($new_pick, $already_picked));
$already_picked[$new_pick] = 1;
This will generate a string with one occurence of each digit:
$randomcharacters = '0123456789';
$length = 5;
$newcharacters = str_shuffle($randomcharacters);
$randomstring = substr($newcharacters, 0, $length);

How to get a random value from 1~N but excluding several specific values in PHP?

rand(1,N) but excluding array(a,b,c,..),
is there already a built-in function that I don't know or do I have to implement it myself(how?) ?
UPDATE
The qualified solution should have gold performance whether the size of the excluded array is big or not.
No built-in function, but you could do this:
function randWithout($from, $to, array $exceptions) {
sort($exceptions); // lets us use break; in the foreach reliably
$number = rand($from, $to - count($exceptions)); // or mt_rand()
foreach ($exceptions as $exception) {
if ($number >= $exception) {
$number++; // make up for the gap
} else /*if ($number < $exception)*/ {
break;
}
}
return $number;
}
That's off the top of my head, so it could use polishing - but at least you can't end up in an infinite-loop scenario, even hypothetically.
Note: The function breaks if $exceptions exhausts your range - e.g. calling randWithout(1, 2, array(1,2)) or randWithout(1, 2, array(0,1,2,3)) will not yield anything sensible (obviously), but in that case, the returned number will be outside the $from-$to range, so it's easy to catch.
If $exceptions is guaranteed to be sorted already, sort($exceptions); can be removed.
Eye-candy: Somewhat minimalistic visualisation of the algorithm.
I don't think there's such a function built-in ; you'll probably have to code it yourself.
To code this, you have two solutions :
Use a loop, to call rand() or mt_rand() until it returns a correct value
which means calling rand() several times, in the worst case
but this should work OK if N is big, and you don't have many forbidden values.
Build an array that contains only legal values
And use array_rand to pick one value from it
which will work fine if N is small
Depending on exactly what you need, and why, this approach might be an interesting alternative.
$numbers = array_diff(range(1, N), array(a, b, c));
// Either (not a real answer, but could be useful, depending on your circumstances)
shuffle($numbers); // $numbers is now a randomly-sorted array containing all the numbers that interest you
// Or:
$x = $numbers[array_rand($numbers)]; // $x is now a random number selected from the set of numbers you're interested in
So, if you don't need to generate the set of potential numbers each time, but are generating the set once and then picking a bunch of random number from the same set, this could be a good way to go.
The simplest way...
<?php
function rand_except($min, $max, $excepting = array()) {
$num = mt_rand($min, $max);
return in_array($num, $excepting) ? rand_except($min, $max, $excepting) : $num;
}
?>
What you need to do is calculate an array of skipped locations so you can pick a random position in a continuous array of length M = N - #of exceptions and easily map it back to the original array with holes. This will require time and space equal to the skipped array. I don't know php from a hole in the ground so forgive the textual semi-psudo code example.
Make a new array Offset[] the same length as the Exceptions array.
in Offset[i] store the first index in the imagined non-holey array that would have skipped i elements in the original array.
Now to pick a random element. Select a random number, r, in 0..M the number of remaining elements.
Find i such that Offset[i] <= r < Offest[i+i] this is easy with a binary search
Return r + i
Now, that is just a sketch you will need to deal with the ends of the arrays and if things are indexed form 0 or 1 and all that jazz. If you are clever you can actually compute the Offset array on the fly from the original, it is a bit less clear that way though.
Maybe its too late for answer, but I found this piece of code somewhere in my mind when trying to get random data from Database based on random ID excluding some number.
$excludedData = array(); // This is your excluded number
$maxVal = $this->db->count_all_results("game_pertanyaan"); // Get the maximum number based on my database
$randomNum = rand(1, $maxVal); // Make first initiation, I think you can put this directly in the while > in_array paramater, seems working as well, it's up to you
while (in_array($randomNum, $excludedData)) {
$randomNum = rand(1, $maxVal);
}
$randomNum; //Your random number excluding some number you choose
This is the fastest & best performance way to do it :
$all = range($Min,$Max);
$diff = array_diff($all,$Exclude);
shuffle($diff );
$data = array_slice($diff,0,$quantity);

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