I have a string number as below. When i add 1 to it, it changes to a scientific representation instead of a real number and also doesnot increment to the next number. Any reason why its not incrementing?
I want 4600004722057511 to become 4600004722057512
Thanks
Number is 4600004722057501
After adding 1 to it it becomes 4.6000047220575E+15
$val = $list[0]->getNextNumber();
$list[0]->setNextNumber($val+1);
use bcmath for high numbers
$val = $list[0]->getNextNumber();
$val = bcadd( $val, 1 ); // here you add 1 to a very high number
$list[0]->setNextNumber($val);
You can try with add “(int)” your code
$val = (int)$list[0]->getNextNumber();
$list[0]->setNextNumber($val+1);
Try this:
$val = (float)$list[0]->getNextNumber();
$list[0]->setNextNumber($val+1);
since PHP treat number as number, it won't be a problem, but if you want to display its value somewhere, cast it to string
$val = $list[0]->getNextNumber()+1;
$val = (string)$val
Try This
$val =$list[0]->getNextNumber();
$val=++$val;
$list[0]->setNextNumber($val);
If it not works, show your full code (might be a problem in function code).
Related
I'm looking to create a PHP Range loop
In a first and second number in the range, but have noticed the first number which is
00006
Is being rounded down / flattened to show "6".
So when I echo the first number value I get "6" back. I need it to be "00006"
Then the next number will need to be 00007 and so on, via the range loop.
My PHP code at present is :
$first_number = 00006;
$last_number = 11807;
foreach(range($first_number, $last_number) as $id)
{
echo $id;
}
How do I go about making sure that the number has the previous 0's in it?
You can do it by using printf() function.
See the documentation : printf
First of all in PHP, a number starting with zero is treated as octal number, But I guess range() function converts it as decimal. So if you want to start it with 20. Like $first_number = 00020; then the output will be start with 16 not 20.
So, if you want the output starting with 0's, then you can do like this:
$first_number = 6;
$last_number = 11807;
foreach(range($first_number, $last_number) as $id)
{
printf("%05d",$id);
}
Hi i need to save a 010 number in $number and if i do like this php will remove the starting 0
$number = 010
And echo of this will return 10 how can i make it not to remove the initial 0
BR
Martin
Use it as a String:
$number = '010';
Use str_pad() function.
echo str_pad('10',3,'0',STR_PAD_LEFT)
http://php.net/manual/en/function.str-pad.php
Do remember that numbers starting with 0 can also be treated as octal number notation by the PHP compiler, hence if you want to work with decimal numbers, simply use:
$num = '010';
This way the number is saved, can be stored in the database and manipulated like any other number. (Thx to the fact that PHP is very loosely typed language.)
Another method to use would be:
Save number as $num = 10;
Later while printing the value you can use sprintf, like:
sprintf("%03d", $i);
This will print your number in 3 digit format, hence 0 will be added automatically.
Another method:
<?php
$num = 10;
$zerofill = 3;
echo str_pad($num, $zerofill, "0", STR_PAD_LEFT);
/* Returns the wanted result of '010' */
?>
You can have a look at the various options available to you and make a decision. Each of the method given above will give you a correct output.
I have a e-commerce shop and on the shopping cart page it gives me a separate price for every product, but I need total price.
in order to do that, I need to calculate all these values together and that's fine.
But, what bugs me is that I should calculate the sum of variables that are given in this format:
$455.00
What is the best way to extract the value "455" so I could add it to another value afterwards?
I hope I made myself clear...
Don't use float, but instead use an integer in cent. Floats are not precise (see Floating Point Precision), so the calculation tend to fail if you use floats. That's especially a burden if it is related to payments.
$str = '$455.00';
$r = sscanf($str, '$%d.%d', $dollar, $cent);
if ($r <> 2 or $cent > 99 or $cent < 0 or $dollar > 9999 or $dollar < 0) throw new Exception(sprintf('Invalid string "%s"', $str));
$amountInDollarCents = $dollar * 100 + $cent;
echo $str, ' -> ', $amountInDollarCents;
Demo
If you need only the dollar sign removed, use str_replace. To convert that to int or float, typecast it. However, using float results in non-exact calculations so be careful with it!
$newval = (int)str_replace('$', '', '$455.00');
I think that your ECommerce site only has $ (USD)
$price= substr($string_price,1);
This will convert your string to a float:
$price = (float)substr("$455.00", 1);
echo($price);
For more information, you can see this answer, which has a couple of good links for you in it.
What about the following:
$amount = array();
$amount[0] = '$455.15';
$amount[2] = '$85.75';
$total = 0;
foreach ($amount AS $value) {
$value = str_replace('$', '', $value);
$total += $value;
}
echo $total . "\n";
The cleaning operation is:
$value = str_replace('$', '', $value);
You might want to extract it in a function, especially if you need to use it in more than one place.
Another thing to think about is, why do you have the value in such way? It's a display format and such conversion should be the last to be done, ideally by the template. Maybe, if possible, you should consider to fix the code before, instead of applying a patch like this one.
It really looks like your program is doing it wrong. You should really represent all prices as (double) instead of a string. Then only when you need to show the price to the user you would prepend the $ sign to it, converting it to a string. But your program should really treat prices as numbers and not strings.
If you storing your price in the database as a string "$5.99" then you are really doing it wrong.
It's been a long time since I worked with PHP, so I don't know what the best practice would be for working with currency. One quick method would be to remove "$" and ".", and just add together the resulting as integers.
use str_replace() for instance, and replace "$" and "." with an empty string: http://se2.php.net/manual/en/function.str-replace.php
This will give you the whole sum in cents (thus avoiding some potential rounding problems). You can then divide it by 100 and format it however you like to display the sum as dollars.
How do I output a value as a number in php? I suspect I have a php value but it is outputting as text and not as a number.
Thanks
Here is the code - Updated for David from question below
<?php
if (preg_match('/\-(\d+)\.asp$/', $pagename1, $a))
{
$pageNumber = $a[1];}
else
{ // failed to match number from URL}
}
?>
If I call it in: This code it does not seem to work.
$maxRows_rs_datareviews = 10;
$pageNum_rs_datareviews = $pagename1; <<<<<------ This is where I want to use it.
if (isset($_GET['pageNum_rs_datareviews'])) {
$pageNum_rs_datareviews = $_GET['pageNum_rs_datareviews'];
}
If I make page name a static number like 3 the code works, if I use $pagename1 it does not, this gives me the idea $pagename1 is not seen as a number?
My stupidity!!!! - I used $pagename1 instead of pageNumber
What kind of number? An integer, decimal, float, something else?
Probably the easiest method is to use printf(), eg
printf('The number %d is an integer', $number);
printf('The number %0.2f has two decimal places', $number);
This might be blindingly obvious but it looks like you want to use
$pageNum_rs_datareviews = $pageNumber;
and not
$pageNum_rs_datareviews = $pagename1;
echo (int)$number; // integer 123
echo (float)$number; // float 123.45
would be the easiest
I prefer to use number_format:
echo number_format(56.30124355436,2).'%'; // 56.30%
echo number_format(56.30124355436,0).'%'; // 56%
$num = 5;
echo $num;
Any output is text, since it's output. It doesn't matter what the type of what you're outputting is, since the human eye will see it as text. It's how you actually treat is in the code is what matters.
Converting (casting) a string to a number is different. You can do stuff like:
$num = (int) $string;
$num = intval($string);
Googling php string to number should give you a beautiful array of choices.
Edit: To scrape a number from something, you can use preg_match('/\d+/', $string, $number). $number will now contain all numbers in $string.
get this from my database:
252.587254564
Well i wanna remove the .587254564 and keep the 252, how can i do that?
What function should i use and can you show me an example?
Greetings
You can do it in PHP:
round($val, 0);
or in your MYSQL statement:
select round(foo_value, 0) value from foo
You can do a simply cast to int.
$var = 252.587254564;
$var = (int)$var; // 252
As Tricker mentioned you can round the value down or you can just cast it to int like so:
$variable = 252.587254564; // this is of type double
$variable = (int)$variable; // this will cast the type from double to int causing it to strip the floating point.
In PHP you would use:
$value = floor($value);
floor: Returns the next lowest integer value by rounding the value down if necessary.
If you wanted to round up it would be:
$value = ceil($value);
ceil: Returns the next highest integer value by rounding the value up if necessary.
You can just cast it to an int:
$new = (int)$old;
Convert the float number to string, and use intval to convert it to integer will give you 1990
intval(("19.90"*100).'')
Before using above answer what is your exact requirement please see bellow example output.
$val = 252.587254564;
echo (int)$val; //252
echo round($val, 0); //253
echo ceil($val); //253
$val = 1234567890123456789.512345;
echo (int)$val; //1234567890123456768
echo round($val, 0);//1.2345678901235E+18
echo ceil($val); //1.2345678901235E+18
$val = 123456789012345678912.512345;
echo (int)$val; //-5670419503621177344
echo round($val, 0);//1.2345678901235E+20
echo ceil($val); //1.2345678901235E+20
you can use echo (int) 252.587254564;
positive number:
round(252.587254564) // 253
floor(252.587254564) // 252
ceil(252.587254564) //252
(int)252.587254564 // 252
intval(252.587254564) // 252
~~252.587254564 // 252
negative number:
round(-252.587254564) // -253
floor(-252.587254564) // -253
ceil(-252.587254564) // -252
(int)-252.587254564 // -252
intval(-252.587254564) // -252
~~-252.587254564 // -252
if you want just remove decimals without round you can use one of above codes except round and floor(for negative number).
But I recommended the last one, it's simpler and faster using prefix ~~
And there is also a not quite advisable method:
strtok($value, ".");
This cuts of the first part until it encounters a dot. The result will be a string, not a PHP integer. While it doesn't affect using the result much, it's not the best option.
I see many answers, but the question is:
"Well i wanna remove the .587254564 and keep the 252, how can i do
that?"
Since the questioner is asking for php, the function in php will be the one for the job.
$newValue = floor($value);
In MySQL you can use:
select floor(field)
or in PHP you can use:
floor($value);