Prepared statement error with insert - php

Question

I tried to use, for the first time, prepared statement in order to avoid sql injection but it seems i have a problem when i try to insert or update my database i use these lines to do what i want:
Insert:
$stmt = $con->prepare("INSERT INTO my_array (image1,image2,image3,image4, info, type, lat, lng, date_created, status, created_by, closed_by, date_finished) VALUES ( ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)") ;
$stmt->bind_param('bbbbssddsssss', $image1, $image2, $image3, $image4, $info, $type, $lat, $long, $date, $opened, $user, $closed_by, $closed_by, $date_finished);
$stmt->execute();
$result = $stmt->get_result();
Update:
$stmt = $con->prepare("UPDATE users SET fullname = IF(LENGTH(?) = 0, fullname, ?), email = IF(LENGTH(?) = 0, email, ?), phone_num = IF(LENGTH(?) = 0, phone_num, ?) , address = IF(LENGTH(?) = 0, address, ?) WHERE username = '$user'") ;
$stmt->bind_param('ssssiiss',$fullname, $fullname, $email, $email, $phone_number , $phone_number, $address, $address);
$stmt->execute();
$result = $stmt->get_result();
in both i get a "false" result.

Answer 1

In the first you have $closed_by duplicate.
In the second you have $user in the prepared statement. That must be a parameter.

Answer 2

use proper error handling in each of your statements:
if(!($stmt = $con->prepare("INSERT INTO my_array (image1,image2,image3,image4, info, type, lat, lng, date_created, status, created_by, closed_by, date_finished) VALUES ( ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)"))
{
echo "Prepare failed: (" . $con->errno . ") " . $con->error;
}
if(!$stmt->bind_param('bbbbssddsssss', $image1, $image2, $image3, $image4, $info, $type, $lat, $long, $date, $opened, $user, $closed_by, $closed_by, $date_finished))
{
echo "Binding parameters failed: (" . $stmt->errno . ") " . $stmt->error;
}
if(!$stmt->execute())
{
echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;
}
if(!($result = $stmt->get_result())
{
echo "Getting result set failed: (" . $stmt->errno . ") " . $stmt->error;
}